When trying to find the best deals for items, you should what?

Answer:

8-2x

Step-by-step explanation:

2 distributed over the entire expression equals 8-2x

Answer:

the answer is b

Step-by-step explanation:

Answer:

7/11 = 0.6363...

Step-by-step explanation:

7 + 4 = 11

probability of winning: 7/11 = 0.6363...

The probability that the horse will in the race is [tex]\mathbf{\dfrac{7}{11}}[/tex]

Given that the odds  of the horse winning the race is 7:4

Assuming the ratio is in form of a:b, the probability of winning the race can be computed as:

[tex]\mathbf{P(A) = \dfrac{a}{a+b}}[/tex]

From the given question;

The probability of the horse winning the race is:

[tex]\mathbf{P(A) = \dfrac{7}{7+4}}[/tex]

[tex]\mathbf{P(A) = \dfrac{7}{11}}[/tex]

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Answer:

F /T = Z

Step-by-step explanation:

F/Z=T

Multiply each side by Z

F/Z *Z=T*Z

F = ZT

Divide each side by T

F /T = ZT/T

F /T = Z

Answer:

[tex]\boxed{\red{ z = \frac{f}{t} }}[/tex]

Step-by-step explanation:

[tex] \frac{f}{z} = t \\ \frac{f}{z} = \frac{t}{1} \\ zt = f \\ \frac{zt}{t} = \frac{f}{t} \\ z = \frac{f}{t} [/tex]

Answer:

The corresponding graph is Graph A.

Step-by-step explanation:

Part 1: Rewriting the inequality and solving for d

To start, the inequality will need simplified.

[tex]9-4d\geq -3\\\\-4d\geq -12\\\\\frac{-4d}{-4} \geq \frac{-12}{-4} \\\\d \leq 3[/tex]

Because simplifying the inequality involved dividing by a negative number, the sign must be flipped.

Part 2: Determining the graph for the inequality

Now, refer to the rules for graphing inequalities.

Therefore, because [tex]d \leq 3[/tex], the graph will start at 3 as a closed dot. Then, it will go left because values must be equal to 3 or less than 3.

Therefore, the graph that represents this is Graph A.

Answer:

Graph A

I hope this helps!

Answer:

Step-by-step explanation:

Given that:

population mean [tex]\mu[/tex] = 47600

population standard deviation [tex]\sigma[/tex] = 2000

sample size n = 49

Sample mean [tex]\over\ x[/tex] = 48000

Level of significance = 0.05

The null and the alternative hypothesis can be computed as follows;

[tex]H_0 : \mu = 47600 \\ \\ H_1 : \mu \neq 47600[/tex]

Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.

The test statistics can be calculated by using the formula:

[tex]z= \dfrac{\overline X - \mu }{\dfrac{\sigma}{ \sqrt{n}}}[/tex]

[tex]z= \dfrac{ 48000-47600 }{\dfrac{2000}{ \sqrt{49}}}[/tex]

[tex]z= \dfrac{400 }{\dfrac{2000}{ 7}}[/tex]

[tex]z= 1.4[/tex]

Conclusion:

Since 1.4 is lesser  than 1.96 , we fail to reject the null hypothesis and  that there is insufficient information to conclude that the   mean gross income is not equal to $47600

The P-value is being calculate as follows:

P -value = 2P(Z>1.4)

P -value =  2 (1 - P(Z< 1.4)

P-value = 2 ( 1 - 0.91924)

P -value = 2 (0.08076 )

P -value = 0.16152

Answer:

The expectation is  [tex]E(1 )= -\$ 1[/tex]

Step-by-step explanation:

From the question we are told that  

     The first offer is  [tex]x_1 = \$ 8000[/tex]

     The second offer is  [tex]x_2 = \$ 4000[/tex]

      The third offer is  [tex]\$ 1600[/tex]

      The number of tickets is  [tex]n = 5000[/tex]

      The  price of each ticket is  [tex]p= \$ 5[/tex]

Generally expectation is mathematically represented as

             [tex]E(x)=\sum x * P(X = x )[/tex]

     [tex]P(X = x_1 ) = \frac{1}{5000}[/tex]    given that they just offer one

    [tex]P(X = x_1 ) = 0.0002[/tex]    

 Now  

     [tex]P(X = x_2 ) = \frac{1}{5000}[/tex]    given that they just offer one

     [tex]P(X = x_2 ) = 0.0002[/tex]    

 Now  

      [tex]P(X = x_3 ) = \frac{5}{5000}[/tex]    given that they offer five

       [tex]P(X = x_3 ) = 0.001[/tex]

Hence the  expectation is evaluated as

       [tex]E(x)=8000 * 0.0002 + 4000 * 0.0002 + 1600 * 0.001[/tex]

      [tex]E(x)=\$ 4[/tex]

Now given that the price for a ticket is  [tex]\$ 5[/tex]

The actual expectation when price of ticket has been removed is

      [tex]E(1 )= 4- 5[/tex]

      [tex]E(1 )= -\$ 1[/tex]

Answer:

25= q+20

25 - 20 =q

5 = q

Hi there! Hopefully this helps!

-------------------------------------------------------------------------------------------

[tex]25 = q + 20[/tex]

Swap sides so that all variable terms are on the left hand side.

[tex]q + 20 = 25[/tex]

Subtract 20 from both sides.

[tex]q = 25 - 20[/tex]

Answer:

A) distribution of x2 = ( 0.4167 0.25 0.3333 )

B) steady state distribution = [tex]\pi a \frac{4}{9} , \pi b \frac{2}{9} , \pi c \frac{3}{9}[/tex]

Step-by-step explanation:

Hello attached is the detailed solution for problems A and B

A) distribution states for A ,B, C:

Po = ( 1/3, 1/3, 1/3 )  we have to find the distribution of x2 as attached below

after solving the distribution

x 2 = ( 0.4167, 0.25, 0.3333 )

B ) finding the steady state distribution solving

[tex]\pi p = \pi[/tex]

below is the detailed solution and answers

Answer:

{(2,3), (-5,2), (1,8), (6,3), (-6, 2)

Step-by-step explanation:

The domain is the input and the range is the output

We need inputs of -6 -5 1 2 6

and outputs of 2 3 and 8

Answer:

x = 10

Step-by-step explanation:

2x/3 + 1 = 7x/15 + 3

(times everything in the equation by 3 to get rid of the first fraction)

2x + 3 = 21x/15 + 9

(times everything in the equation by 15 to get rid of the second fraction)

30x+ 45 = 21x + 135

(subtract 21x from 30x; subtract 45 from 135)

9x = 90

(divide 90 by 9)

x = 10

2x/3 + 1 = 7x/15 + 3

(find the LCM of 3 and 15 = 15)

(multiply everything in the equation by 15, then simplify)

10x + 15 = 7x + 45

(subtract 7x from 10x; subtract 15 from 45)

3x = 30

(divide 30 by 3)

x = 10

Answer:

30,455

Step-by-step explanation:

Exponential decay

y = a(1 - b)^x

y = final amount

a = initial amount

b = rate of decay

x = time

We are looking for the rate of decay, b.

900 = 450000(1 - b)^30

1 = 500(1 - b)^30

(1 - b)^30 = 0.002

1 - b = 0.002^(1/30)

1 - b = 0.81289

b = 0.1871

The equation for our case is

y = 450000(1 - 0.1871)^x

We are looking for the amount in 13 hours, so x = 13.

y = 450000(1 - 0.1871)^13

y = 30,455

Answer:

D ). (-7,-4)

Step-by-step explanation:

To locate the position or the location of the centre of the circle we have to bear in mind that the center of the circle is the midpoint of the diameter line.

Formula for midpoint of a line is given below

Midpoint= (X1+x2)/2 ,(y1+y2)/2

Where X1= -2,y1= -3

X2= -12, y2= -5

The midpoint= (-2+(-12))/2,(-3+(-5))/2

Midpoint= (-2-12)/2,(-3-5)/2

Midpoint= (-14)/2,(-8)/2

Midpoint=( -7,-4)

The center of the circle is located at the point (-7,-4)

Answer:

The answer is: Leo's phone had the greater initial trade-in value. Tonya's phone decreases at an average rate slower than the trade in value of Leo's phone.

Step-by-step explanation:

I got it right. Hope this helps.

The initial trade-in value of Tonia's phone is greater when compared with Leo's    

There is a decrease in the trade-in value of Leo's phone at an average slower rate

[tex]f(x) = 490\times 0.88[/tex]

[tex](x)[/tex] ⇒ [tex]g(x)[/tex]

[tex]0[/tex] ⇒ [tex]480[/tex]

[tex]2[/tex] ⇒ [tex]360[/tex]

[tex]4[/tex] ⇒ [tex]470[/tex]

Now we will solve with the greater initial value

The initial value is when x = 0. So, we have

[tex]f(x) = 490 \times o.88^x\\\ f(o) = 490 \times 0.88 ^0\\f(0 =490 \times 1 \\f(o) = 490[/tex]

From leos table

[tex]g(0) = 480\\f(0) > g(o)\\i.e \\490 > 480[/tex]

So Tonia had a greater initial value

Solving (b): The phone with a lesser rate

y [tex]y = a b ^ x[/tex]

An exponential function is:

where [tex]b \rightarrow rate[/tex]

For Tonia

[tex]b = o.88[/tex]

For Leo we have

[tex](x_{1} , y_{1} )= (0,480)\\(x_{1}, y_{1} ) = (2, 360)[/tex]

So the equation becomes

[tex]y = ab ^x \\480 = ab ^0 \\and \\360 = ab ^2[/tex]

On solving

[tex]480 = a \times 1\\a = 480[/tex]

[tex]360 = ab ^ 2[/tex]

so it becomes

[tex]480 = 360 \times b ^2 \\[/tex]

On dividing both sides by [tex]480[/tex]  we get

[tex]b ^ 2 = 0.87[/tex]

[tex]b ^ 2 = 0.75[/tex]

On taking square root we get

[tex]b = 0.87[/tex]

In comparison, we get Leo's rate is slower.

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# SPJ2

Answer:

y = x-4

Step-by-step explanation:

The y intercept is -4

We have 2 points so we can find the slope

( 0,-4) and(4,0)

m = ( y2-y1)/(x2-x1)

    = ( 0- -4)/ (4-0)

    = 4/4

   =1

The slope intercept form is

y = mx+b

y = 1x-4

y = x-4

Answer:

a.    [tex]\mathbf{36 \sqrt{5}}[/tex]

b.   [tex]\mathbf{ \dfrac{1}{108} [ 145 \sqrt{145} - 1]}}[/tex]

Step-by-step explanation:

Evaluate integral _C x ds  where C is

a. the straight line segment x = t, y = t/2, from (0, 0) to (12, 6)

i . e

[tex]\int \limits _c \ x \ ds[/tex]

where;

x = t   , y = t/2

the derivative of x with respect to t is:

[tex]\dfrac{dx}{dt}= 1[/tex]

the derivative of y with respect to t is:

[tex]\dfrac{dy}{dt}= \dfrac{1}{2}[/tex]

and t varies from 0 to 12.

we all know that:

[tex]ds=\sqrt{ (\dfrac{dx}{dt})^2 + ( \dfrac{dy}{dt} )^2}} \ \ dt[/tex]

∴

[tex]\int \limits _c \ x \ ds = \int \limits ^{12}_{t=0} \ t \ \sqrt{1+(\dfrac{1}{2})^2} \ dt[/tex]

[tex]= \int \limits ^{12}_{0} \ \dfrac{\sqrt{5}}{2}(\dfrac{t^2}{2}) \ dt[/tex]

[tex]= \dfrac{\sqrt{5}}{2} \ \ [\dfrac{t^2}{2}]^{12}_0[/tex]

[tex]= \dfrac{\sqrt{5}}{4}\times 144[/tex]

= [tex]\mathbf{36 \sqrt{5}}[/tex]

b. the parabolic curve x = t, y = 3t^2, from (0, 0) to (2, 12)

Given that:

x = t  ; y = 3t²

the derivative of  x with respect to t is:

[tex]\dfrac{dx}{dt}= 1[/tex]

the derivative of y with respect to t is:

[tex]\dfrac{dy}{dt} = 6t[/tex]

[tex]ds = \sqrt{1+36 \ t^2} \ dt[/tex]

Hence; the  integral _C x ds is:

[tex]\int \limits _c \ x \ ds = \int \limits _0 \ t \ \sqrt{1+36 \ t^2} \ dt[/tex]

Let consider u to be equal to  1 + 36t²

1 + 36t² = u

Then, the differential of t with respect to u is :

76 tdt = du

[tex]tdt = \dfrac{du}{76}[/tex]

The upper limit of the integral is = 1 + 36× 2² = 1 + 36×4= 145

Thus;

[tex]\int \limits _c \ x \ ds = \int \limits _0 \ t \ \sqrt{1+36 \ t^2} \ dt[/tex]

[tex]\mathtt{= \int \limits ^{145}_{0} \sqrt{u} \ \dfrac{1}{72} \ du}[/tex]

[tex]= \dfrac{1}{72} \times \dfrac{2}{3} \begin {pmatrix} u^{3/2} \end {pmatrix} ^{145}_{1}[/tex]

[tex]\mathtt{= \dfrac{2}{216} [ 145 \sqrt{145} - 1]}[/tex]

[tex]\mathbf{= \dfrac{1}{108} [ 145 \sqrt{145} - 1]}}[/tex]

Answer:

  1/8, 3/8

Step-by-step explanation:

Let x and y represent the two fractions. Then we are given ...

  x + y = 1/2

  x + 5y = 2

Subtracting the first equation from the second, we get ...

  (x +5y) -(x +y) = (2) -(1/2)

  4y = 3/2 . . . . . simplify

  y = 3/8 . . . . . . divide by 4

  x = 1/2 -3/8 = 1/8

The two numbers are 1/8 and 3/8.

Answer:

4/6 or 66.666...%

Step-by-step explanation:

If you want to find the probability of obtaining neither a 5 nor a 2 you find how many times they occur and add them together in this case 5 occurs once and 2 also occurs once out of 6 numbers so 1/6 + 1/6 equals 2/6, you now know that 4/6 of them won't be a 5 nor a 2 and because it is a fair die the likelihood of it falling on a number is the same for all sides so the answer is 4/6 or 66.67%.

Answer:

10

Step-by-step explanation:

Let the no. of sodas be x

Price of each soda = $2

Therefore, no . of sodas you can buy = $2x

2x=20

=>x=[tex]\frac{20}{2}[/tex]

=>x=10

you can buy 10 sodas

Answer: 10 sodas

Step-by-step explanation:

2x = 20       Divide both sides by 2  

x = 10

If I brought 20 dollars and I  want to by only sodas and each sodas cost 2 dollars, then I will divide the total amount of money that I brought  by 2 to find out how many sodas I could by.

Answer:

7+sqrt(37)

Step-by-step explanation:

7+sqrt(6*(3+4)-2+9-3*2^2)=7+sqrt(6*7+7-3*4)=7+sqrt(42+7-12)=7+sqrt(37)

Answer:

6(x-3)

Step-by-step explanation:

the common number for 6 and 18 is 6 so if you extract that from the expression then it turns to 6(x-3) which cannot be factored further

Answer:

Option B:  6(x - 3)

Step-by-step explanation:

Answer:

Step-by-step explanation:

The sequence above is an arithmetic sequence

For an nth term in an arithmetic sequence

A(n) = a + ( n - 1)d

where a is the first term

n is the number of terms

d is the common difference

From the question

a = 38

d = 32 - 38 = - 6 or 20 - 26 = - 6

Substitute the values into the above formula

A(n) = 38 + (n - 1)-6

= 38 - 6n + 6

We have the final answer as

Hope this helps you

Answer:

a

Step-by-step explanation:

you're welcome!

Answer:

132 kilo meters

Step-by-step explanation:

Pro por tions:

9 lite rs ⇒ 99 km

12 lite rs  ⇒  P km

P = 99*12/9

P = 132 km

Answer:

132

Step-by-step explanation:

give person above brainliest :))

Answer:

A) ( -8, -32 )

Step-by-step explanation:

Given function : f (x,y) = 21 - 4x^2 - 16y^2

point p( 1,1,1 ) on surface

Gradient of F

attached below is the detailed solution

Answer:

0.5

1 divide by 2 = 0.5

Answer:

Explained below.

Step-by-step explanation:

Enter the data in an Excel sheet.

(a)

Go to Insert → Chart → Scatter.

Select the first type of Scatter chart.

The scatter plot is attached below.

(b)

The scatter plot with the line of best fit is attached below.

The line of best fit is:

[tex]y=-0.8046x+103.56[/tex]

(c)

Compute the value of x for y = 30 as follows:

[tex]y=-0.8046x+103.56[/tex]

[tex]30=-0.8046x+103.56\\\\0.8046x=103.56-30\\\\x=\frac{73.56}{0.8046}\\\\x\approx 91.42[/tex]

Thus, the Advance Mathematics mark of a student who scores 30 out of 100 in English is 91.42.

(d)

The Pearson's Correlation Coefficient is:

[tex]r=\frac{n\cdot \sum XY-\sum X\cdot \sum Y}{\sqrt{[n\cdot \sum X^{2}-(\sum X)^{2}][n\cdot \sum Y^{2}-(\sum Y)^{2}]}}[/tex]

  [tex]=\frac{14\cdot 44010-835\cdot 778}{\sqrt{[14\cdot52775-(825)^{2}][14\cdot 47094-(778)^{2}]}}\\\\= -0.7062\\\\\approx -0.71[/tex]

Thus, the Pearson's Correlation Coefficient is -0.71.

(e)

A correlation coefficient between ± 0.50 and ±1.00 is considered as a strong correlation.

The correlation between Advanced Mathematics and English results is -0.71.

This implies that there is a strong negative correlation.

Answer:

Option C. x + 12 ≤ 2(x – 3)

Step-by-step explanation:

From the question, we obtained the following information:

x + 12 ≤ 5 – y .......(1)

5 – y ≤ 2(x – 3) ....... (2)

To know which option is correct, do the following:

From equation 2,

5 – y ≤ 2(x – 3)

Thus, we can say

5 – y = 2(x – 3)

Now, we shall substitute the value of 5 – y into equation 1 as shown below:

x + 12 ≤ 5 – y

5 – y = 2(x – 3)

x + 12 ≤ 2(x – 3)

From the above illustration, we can see that if x + 12 ≤ 5 – y and 5 – y ≤ 2(x – 3), then x + 12 ≤ 2(x – 3) must be true.

Option C gives the correct answer.

Answer:

77

Step-by-step explanation:

4x^2-6x+7

Let x = 5

4* 5^2-6*5+7

4 * 25 -30 +7

100-30+7

7-+7

77

Answer:

4

Step-by-step explanation:

Original coordinates:

A (0, 2)

B (2, 3)

The scale is what number the original coordinates was multiplied by to reach the new coordinates

1. Divide

(0, 8) ÷ (0, 2) = 4

(8, 12) ÷ (2, 3) = 4

AB was dilated by a scale factor of 4.

Answer:

25(4 + 3)

Step-by-step explanation:

100 = 2^2 + 5^2

75 = 3 * 5^2

GCF = 5^2 = 25

100 + 75 =

= 25 * 4 + 25 * 3

= 25(4 + 3)