When optically active (R)-2-methylcyclohexanone is treated with either aqueous base or acid, racemization occurs. Explain.

Answers

Answer 1

Answer:

See explanation

Explanation:

Racemization is said to occur when a 1:1 ratio of (+) and (-) enantiomers of a compound are produced in a reaction.

The reaction of optically active (R)-2-methylcyclohexanone with either aqueous base or acid leads to the formation of a planar enol species for reaction with acid and a planar enolate species for reaction with base.

Both reactions involves the formation of achiral species which reverts back to the chiral product with equal chances of the formation of both enantiomers of the product during the process. This leads to racemization of the product in both cases.

Answer 2

Racemization of the optically active (R)-2-methylcyclohexanone results from the production and subsequent interconversion of intermediates during the reaction with an aqueous base or acid. This is due to the inversion of stereochemistry at the chiral centre.

Racemization can happen when an optically active molecule is exposed to an aqueous base or acid because the compound's enantiomers are interconverted. The carbon-carbon bond next to the carbonyl group in (R)-2-methylcyclohexanone breaks as a result of the chemical reaction with the aqueous base or acid. The creation of the negatively charged intermediate known as the enolate ion occurs when a base, such as hydroxide ions, is present and attacking the carbonyl carbon. The carbonyl group can then be reformated by this enolate ion after it has undergone a nucleophilic attack on a proton.

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Related Questions

How did the development of the earliest idea about atoms differ from the later work of scientists?
It was based on sound evidence.
There were explanations for the idea.
It was based on the thoughts of an early philosopher.
There were experiments conducted to support the idea.

Answers

Answer:

C. It was based on the thoughts of an early philosopher.

Almost 99% of Earth's atmosphere is made up of two gases. What are the two gases and the percents of each?
A)
21% oxygen and 78% nitrogen
B)
21% water vapor and 78% oxygen
09
21% nitrogen and 78% oxygen
D)
21% carbon dioxide and 78% oxygen

Answers

D 21% carbon dioxide and 78% oxygen

P4 + NaOH + H2O——> PH3 + Na2HPO3
Balance given equation by oxidation no. Method

Answers

Answer:

P4 + 4NaOH + 2H2O → 2PH3 + 2Na2HPO3

Explanation:

A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. In a balanced chemical equation, the mass and the charge are both equal.

A chemical equation must balance according to the rule of conservation of mass. According to the rule, mass cannot be generated or removed during a chemical process.

Chemical equations must be balanced, which means that the atom types and numbers on both sides of the reaction arrow must match. Coefficients are the values added in front of formulas to balance equations; they multiply each atom in a formula.

Here the given equation is balanced as:

P₄ + 4NaOH + 2H₂O——> 2PH₃ + 2Na₂HPO₃

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The mass percent of element X
in X(NO3)2 is 52.55%.
Chemical analysis of a pure
sample of X(NO3)2 shows that
it contains 67.50 g of element
X. What is the total mass of
the pure sample?

Answers

Answer:

128.4 g

Explanation:

Step 1: Given data

Mass percent of element X in X(NO₃)₂: 52.55%Mass of the element X in the sample: 67.50 g

Step 2: Determine the total mass of the sample

The mass percent of element X in X(NO₃)₂ is 52.55%, that is, there are 52.55 g of X every 100 g of X(NO₃)₂. Then, the mass of X(NO₃)₂ that contains 67.50 g of X is:

67.50 g X × 100 g X(NO₃)₂/52.55 g X = 128.4 g X(NO₃)₂

given two equations representing reactions: which type of reaction is represented by each of these equations?

Answers

Answer:

Equation 1 - nuclear fission

Equation 2 - nuclear fusion

Explanation:

Nuclear fission is a reaction in which a large nucleus is split into smaller nuclei when it is bombarded by neutrons. The process produces more neutrons to continue the chain reaction. This is clearly depicted in equation 1 as shown in the question.

Nuclear fusion is a reaction in which two light nuclei combine in order to form a larger nuclei. This is clearly depicted in equation 2 as shown in the question.

In the first reaction, a neutron is released, and in the second a helium atom is released. The given two equations represent nuclear fission and fusion.

What are nuclear reactions?

A nuclear reaction is a reaction that involves the nuclei of the atom and the absorption and release of energy. In the first reaction, a big nucleus is split by the neutron bombardment into smaller nuclei.

In the second reaction the process of nuclear fusion, two nuclei combine into a single larger nucleus that is shown as:

₁¹H+ ²₁H → ³₂He

Therefore, nuclear fission and fusion are represented by each of these equations.

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Write the equation showing the formation of a monosubstituted product when butane reacts with chlorine. Use molecular formulas for the organic compounds (C before H, halogen last) and the smallest possible integer coefficients.

Answers

Answer:

CH3CH2CH2CH3 + Cl2 --------> CH3CH2CH2CH2Cl + HCl

Explanation:

Alkanes react with halogens in the presence of light to yield alkyl halides. The degree of substitution increases as the reaction progresses. The reaction occurs by free radical mechanism.

The reaction between butane and chlorine molecule to yields a monosubstitution product occurs as follows;

CH3CH2CH2CH3 + Cl2 --------> CH3CH2CH2CH2Cl + HCl

Verdadero o falso si un átomo presenta de 5 a 7 electrones en su nivel más extremo tenderá a perderlos?

Answers

Esta es falso no me deja responder

How many grams of hydrogen gas, H, are necessary to produce 119.0 g of ammonia, NH3?

Answers

Answer:

What's the equation?

Answer:

14.5 g

Explanation:

its true

Chromium (VI) forms two different oxyanions, the orange dichromate ion, Cr2o72-, And the yellow chromate ion, CrO4 2-. The equilibrium reaction between the ions is:
Cr2O7 2- (aq) + H2O(l)→ 2CrO4 2-(aq) + 2H(aq)
Explain
a) Why does the orange dichromate solution turn yellow when sodium hydroxide is added. Write the net ionic equation for this shift.
b) How will this system shift at equilibrium if the temperature is increased

Answers

Answer:

See explanation

Explanation:

Let us look at the reaction again;

Cr2O7 2- (aq) + H2O(l)⇄ 2CrO4 2-(aq) + 2H^+(aq)

When we add sodium hydroxide to the system as shown, the hydroxide ion removes the hydrogen ion thereby leaving a large concentration CrO4^2-(aq) in the system this causes the solution to turn green(equilibrium position shifts to the right).

The net ionic equation is;

OH^-(aq) + H^+(aq) ----> H2O(l)

The reaction;

OH^-(aq) + H^+(aq) ----> H2O(l) is exothermic hence, if the temperature of the system is increased, the equilibrium position will shift towards the left hand side and the solution turns orange.

Which term describes matter that can vary in composition?

Answers

Answer:

A mixture is matter that can vary in composition. ... A heterogeneous mixture is a type of mixture in which the individual substances are not evenly mixed. Because the substances in a heterogeneous mixture are not evenly mixed, two samples of the same mixture can have different amounts of the substance.

Explanation:

A. Direction: Identify the word or phrase being described in the sentence. Write your
answers in your notebook.
1. It is an electronic measuring instrument that combines several
measurement functions in one unit.
2. In diodes, what do the silver stripe represents?
3. This is an Electronic/Electrical component that stores energy in
the form of Electric Charge.
4. This allows you to change the function between volts, ohms, and
amps, and to change the scale of the meter.
5. In testing capacitor, if the multimeter shows very low resistance,
it means that the capacitor is .
6. These are components used to resist the flow of electric current.
7. It is a system used to determine the value of a resistor without
using a multimeter.
8. What defective capacitor that shows very low Resistance?
9. A type of transformer that is used to increase the output voltage.
10. A type of transformer that is used to decrease the output voltage.

Answers

Answer:

1. Multimeter

2. Cathode

3. Capacitor

4.  Selector switch

5. Short or Shorted

6. Resistors

7. Resistor color coding

8. Open Capacitor

9. Step-up transformer

10. Step-down transformer

Explanation:

The above-described elements are electronic components. Resistors for instance are designed to resist the flow of electric current. They are also standardized such that a deviation from the set resistance level will indicate a problem. The capacitor is another electrical component that stores energy as an electrical charge. Knowledge of these electrical components and the ways they are tested will make a person proficient in electrical electronics.

The chemical formula for an emerald is Be3Al2(SiO3)6. An emerald can be described as

Answers

Answer:

Emerald is a compound made of Beryllium, Aluminium, Silicon and Oxygen with the formula, Be3Al2(SiO3)6

Explanation:

Answer:

A pure substance because its a compound

Explanation:

Classify each of the following as a Strong acid (sa) or a Weak acid (wa) and indicate how each should be written in aqueous solution.
1. hydrobromic acid
2. hydrochloric acid
3. carbonic acid
Write a net ionic equation for the reaction that occurs when aqueous solutions of hydrochloric acid and barium hydroxide are combined.

Answers

Answer:

A. 1. Strong acid (sa): Hydrobromic acid: HBr (aq)

2. Strong acid (sa); Hydrochloric acid: HCl (aq)

3. Weak acid (wa); Carbonic acid: H₂CO₃ (aq)

B. H+ (aq) + OH- (aq) ----> H₂O (l)

Explanation:

Strong acids are which ionize completely in aqueous solution into hydrogen ions and the corresponding anion. Examples of strong acids include hydrobromic acid, hydrochloric acid, tetraoxosulfate (vi) acid.

The ionization of hdyrobromic and hydrochloric acids in aqueous solution is given below:

1. Hydrobromic acid: HBr (aq) ----> H+ (aq) + Br- (aq)

Hydrobromic acid in aqueous solution ionizes completely into hydrogen ions and bromide ions

2. Hydrochloric acid: HCl (aq) ----> H+ (aq) + Cl- (aq)

Hydrochloric acid in aqueous solution ionizes completely into hydrogen ions and chloride ions

Weak acids are acids which ionizes only partially in aqueous solutions to hydrogen ions and the corresponding anions. Examples of weak acids are carbonic acid and ethanoic acid. The ionization of carbonic acid in aqueous solution is shown below:

3. Carbonic acid: H₂CO₃ (aq) ⇄ 2 H+ (aq) + CO₃²- (aq)

Carbonic acid ionizes partially only to give hydrogen ions and trioxocarbonate (iv) ions. The unionized acid exists in equilibrium with the ions produced by the partial ionization of the acid.

Part B:

The reaction between hydrochloric acid and barium hydroxide is a neutralization reaction producing barium chloride salt and water.

The net ionic equation of the neutralization reaction is given below :

H+ (aq) + OH- (aq) ----> H₂O (l)

In the electrolysis of water, how long will it take to produce 75.00 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 205.0 mA

Answers

answer is 2546 h

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how many s electrons are there in potassium?​

Answers

Answer: 19

Explanation:

In order to write the Potassium electron configuration we first need to know the number of electrons for the K atom (there are 19 electrons). When we write the configuration we'll put all 19 electrons in orbitals around the nucleus of the Potassium atom.

You are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A and 2% B. What is the ee of this solution

Answers

Answer:

ee = 96%

Explanation:

Enantiomeric excess, ee, is a way to express a mixture that is not enantiomerically pure. It is defined as 100 times the ratio between the  differences of amounts of enantiomers and the total amunt. that is:

ee = |A-B|/ A+B * 100

ee = |98%-2%| / 98+2 * 100

ee = 96%

Before the lab student needs to make necessary chemical reagent solutions, the teacher asked them to make 50.0mL of 1.0 M H2SO4 from a 6.0 M sock

V1=
M1=
V2=
M2=

Answers

Answer:

V1 = 8.3 mL

Explanation:

Step 1: Given data

Initial volume (V1): ?

Initial concentration (M1): 6.0 M

Final volume (V2): 50.0 mL

Final concentration (M2): 1.0 M

Step 2: Calculate the volume of the initial solution

We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the initial solution using the dilution rule.

M1 × V1 = M2 × V2

V1 = M2 × V2 / M1

V1 = 1.0 M × 50.0 mL / 6.0 M = 8.3 mL

We will take 8.3 mL of the 6.0 M solution and add water until we have 50.0 mL.

20)
Which substance is an acid?


A)
Ba(OH)2

B)
CH3COOCH3

C)
H3PO4

D)
NaCl

help

Answers

Answer:

C.

Explanation:

Also, please help me in my questions tab if you can! Thank you so much

Which of the following is formed last in daughter cells when plant cells divide?
The nucleus
The nuclear envelope
The cell membrane
The cell wall

Answers

Answer:

The Cell Wall

Explanation:

Completa las siguientes reacciones, nombrando todos los compuestos que intervienen:

a) CH2=CH2 + energía 

b) CH2=CH2 + H2O 

c) CH2=CH2 + HCl 

d) CH2=CH2 + Cl2 

e) CH2=CH2 + H2 

2 Completa las siguientes reacciones, nombrando todos los compuestos que intervienen:

a) CH4 + Cl2 

b) CH2=CH2 + H2O 

c) CH≡CH + H2 

d) CH3-COOH + KOH 

e) CH3OH + CH3-COOH 

3 Completa y ajusta la siguientes reacciones nombrando todos los compuestos que intervienen en cada una de ellas:

a) CH3-COOH + NaOH

b) CH3-CH2I + NH3 

c) CH2=CH2 + H2O 

d) CH3-CH=CH2 + Br2 ​

Answers

Answer:

1

Explanation:

hhihh2

What is one way in which a field investigation can differ from a classroom or laboratory experiment?

Answers

Answer:

□In field investigations, you are usually working with much larger animals than in the lab. In field investigations, it is much more difficult to separate your control and experimental groups.

There are many ways in which a field  experiment can differ form of a classroom or a laboratory experiment,  one of which can be the environmental condition.

What is a field experiment?

 A field experiment Is an experiment  which is performed in practically Outside the classroom or a laboratory in live situtations .

Environmental factors may deter the results  of a field experiment or  may alter the physical conditions of the object, For example  an anhydrous substance may become  hygroscopic, Which may  Alter the result of the field experiment.

  Hence,  field experiment can differ from  a classroom or a laboratory experiment  due to environmental conditions .

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What three parts of your eye work together to create a clear image?

Answers

Answer:

cornea,Jens and pupil

tma Po yan

What is the mass of 8.12 ×10^23

Answers

Answer:

59.3g

Explanation:

Mole = no. Molecules/6.02×10^23

Mole = (8.12×10^23)/(6.02×10^23)

Mole = 1.35mole

Molar mass of CO2 = 12+ 2(16)

Molar mass= 12 + 32= 44g/mol

Mole = mass/molar mass

Mass = Mole × molar mass

Mass = 1.35× 44

Mass= 59.35g

What word means the same as Chordata?

A. non-vertebrate

B. vertebrate

Answers

What is another name for Chordata?
n. urochordate, cephalochordate, tunicate, craniate, urochord, vertebrate.

How many molecules are there in 4.27 mol of tungsten(VI) oxide, WO3

Answers

Answer:

Molar mass of WO3 = 231.8382 g/mol Convert grams Tungsten(VI) Oxide to moles  or  moles Tungsten(VI) Oxide to grams Molecular weight calculation: 183.84 + 15.9994*3

Explanation:

#hopeithelpsbrainliest me later.

25.71 × 10²³ molecules are there in 4.27 mol of tungsten (VI) oxide, [tex]WO_3[/tex].

How to find the number of molecules ?

To find the Number of molecules of substance multiply the number of moles of given substance by Avogadro number

Number of molecules = Number of moles × Avogadro's Number

Avogadro's Number

Avogadro's number [tex](N_{A})[/tex] is the number of particles in one mole of substance. 6.023 × 10²³ is known as Avogadro's constant / Avogadro's number.

Avogadro's number = 6.023 × 10²³ [tex]mol^{-}[/tex]

Now,

Number of molecules in 4.27 moles of [tex]WO_{3}[/tex]

= Number of moles of [tex]WO_{3}[/tex] × Avogadro's Number

= 4.27 × 6.023 × 10²³

= 25.71 × 10²³ molecules

Thus, we can say that 25.71 × 10²³ molecules are there in 4.27 moles of tungsten (VI) oxide, [tex]WO_3[/tex].

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What is the pH of a solution whose hydronium ion [H20+] (or proton [H+1)
concentration is 7.6' 10-5 M?

Answers

Answer:

[tex]pH = - log(7.6 \times {10}^{ - 5} ) \\ pH = 4.12[/tex]

Using the periodic table,
choose the more reactive nonmetal. Br or as

Answers

Answer:

Br

Explanation:

because bromine is more reactive as reactivity increases on moving from left to right in p-block. hope this make sense :)

How many moles of fluorine are in 100.0 g

Answers

From what I got the answer for this question would be 0.01 moles

Given the Vapour Density of a hydrocarbon is 150, what is it's molecular formula.​

Answers

Molecular formula = C4H10.

or

Simplest ratio
Empirical formula mass = 12 1 + 1 1+ 16 1 = 29.

Molecular mass = 2 vapour density. = 2 58. = 116.

Molecular formula mass = n Empirical formula mass.

Molecular formula = n Empirical formula.

= 4 (CHO)

Ammonia burns in the presence of a copper catalyst to form nitrogen gas. 4 NH3(g) + 3 O2(g) → 2 N2(g) + 6 H2O(g) ΔΗ = -1267 kJ What is the enthalpy change to burn 38.4 g of ammonia?​

Answers

Answer:

-713 kJ

Explanation:

Step 1: Write the balaned thermochemical equation

4 NH₃(g) + 3 O₂(g) → 2 N₂(g) + 6 H₂O(g)  ΔΗ = -1267 kJ

Step 2: Calculate the moles corresponding to 38.4 g of NH₃

The molar mass of NH₃ is 17.03 g/mol.

38.4 g × 1 mol/17.03 g = 2.25 mol

Step 3: Calculate the  enthalpy change to burn 2.25 mol of ammonia

According to the thermochemical equation, 1267 kJ are released per 4 moles of ammonia that react.

2.25 mol × (-1267 kJ/4 mol) = -713 kJ

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