what type of forces either interatomic or intermolecular forces prevents ice cubes from adopting the shape of their container​

Answer:

320 L

Explanation:

We'll begin by calculating the number of mole in 80.7 g of C₂SO₄. This can be obtained as follow:

Mass of C₂SO₄ = 80.7 g

Molar mass of C₂SO₄ = (12×2) + 32 + (16×4)

= 24 + 32 + 64

= 120 g/mol

Mole of C₂SO₄ =?

Mole = mass /molar mass

Mole of C₂SO₄ = 80.7 / 120

Mole of C₂SO₄ = 0.6725 mole

Finally, we shall determine the volume. This can be obtained as follow:

Mole of C₂SO₄ = 0.6725 mole

Molarity = 0.0021 M

Volume =?

Molarity = mole / Volume

0.0021 = 0.6725 / Volume

Cross multiply

0.0021 × Volume = 0.6725

Divide both side by 0.0021

Volume = 0.6725 / 0.0021

Volume ≈ 320 L

Thus, the volume that can be prepared is approximately 320 L.

Answer:

Pressure, P = 67.57 atm

Explanation:

Given the following data;

Conversion:

We would convert the value of the temperature in Celsius to Kelvin.

T = 273 + °C

T = 273 + 159

T = 432 Kelvin

To find the pressure of the gas, we would use the ideal gas law;

PV = nRT

Where;

Making P the subject of formula, we have;

[tex] P = \frac {nRT}{V} [/tex]

Substituting into the formula, we have;

[tex] P = \frac {0.467*0.08206*432}{0.245} [/tex]

[tex] P = \frac {16.5551}{0.245} [/tex]

Pressure, P = 67.57 atm

Answer:

uh 2

Explanation:

Its 2 cause uh 2 sounds about right

To solve this we must know the concept behind partition coefficient. The partitioning coefficient for this compound in the system used is 0.67. Therefore, the correct option is option F.

The ratio of a solute's concentrations in two solids, immiscible liquids, or barely miscible liquids when they are in equilibrium throughout the interface connecting them is called partition coefficient.

In fundamental chemistry, partitioning is utilized to separate components in procedures like chromatography. Partitioning is a crucial factor in the distribution of chemicals and medications between the blood and bodily tissues in the field of pharmacology.

Mathematically,

partition coefficient= concentration of the solute in  stationary phase/concentration of the solute in mobile phase

partition coefficient={(0.25 /M)÷50}÷{(1.0/M)÷100 }

                                =0.005÷0.01

                                =0.67

Therefore, the correct option is option F.

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Answer:

the weakest base will have a higher Kb value since it will be closer to an acid than a base

7 kb values represents the weakest base.

Kb is the base dissociation constant which is a measure of how completely a base dissociates into its component ions in water. pKb is define as the negative base-10 logarithm of the base dissociation constant (Kb) of a solution.

Ka is define as the acid dissociation constant while pKa is the -log of this constant. Kb is define as the base dissociation constant, while pKb is the -log of the constant.

The acid and base dissociation constants are usually expressed in terms of moles per liter (mol/L).

Thus, 7 kb values represents the weakest base.

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Answer:

a. +0.40 V

Explanation:

Reduction of O2 in acid medium is +1.23 V. The reduction of O2 in basic medium will be calculated by subtracting equation of acidic medium from equation in base medium.

Kw^4 = [10^-14 ] ^ 4

solving we get -0.8274

Subtracting the value from oxygen reduction in acidic medium;

+ 1.23 - 0.8274 = +0.4026

Answer:

2.25 M

Explanation:

The reaction that takes place is:

First we calculate how many potassium iodide moles reacted, using the given volume and concentration:

Then we convert 45 mmoles of KI into mmoles of Pb(NO₂)₃, using the stoichiometric coefficients of the balanced reaction:

Finally we calculate the molarity of the Pb(NO₂)₃ solution, using the calculated number of moles and given volume:

Answer:

R=k[D]^2

Explanation:

Given that it is a decomposition reaction;

D--->product

Hence;

The rate law is;

R= k[D]^x ----(1)

When we triple the concentration of D we have;

[D]' = [3D]^x

Therefore;

R'= 3R

R'= k[D]'----(2)

Hence dividing (1) by (2);

R/R' = k[D]^x/k[D]'

R/9R = k[D]^x/k[3D]^x

1/9 = 1/3^x (take inverse of both sides)

9 = 3^x

3^2 = 3^x

x= 2

Hence the rate law;

R=k[D]^2

Answer:

The pH is greater than 7 at the equivalence point.

Explanation:

Equivalence point is the point where the acid reacts with the base as stipulated in the equation of the reaction.

When a weak acid and a strong base are titrated, the pH of the solution at equivalence point is actually found to be around about pH ~ 9.

Hence, for a weak acid and strong base titration, The pH is greater than 7 at the equivalence point.

A titration between a weak acid and a strong base yields a solution whose pH is greater than 7 at the equivalence point.

Weak acids are acids which only ionize partially in aqueous solutions.

When weak acids are dissolved in water, they produce only few hydrogen ions.

A strong base on the other hand ionizes completely to produce hydroxide ions in aqueous solutions.

The titration of a weak acid and a strong base gives a solution whose pH is greater than 7 at equivalence point.

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Answer:

Physical and psychological dependence is high, and withdrawal symptoms include watery eyes, runny nose, loss of appetite, irritability, tremors, panic, abdominal cramps and diarrhea, nausea, chills, and sweating. Use of contaminated syringes/needles to inject drugs may result in serious blood borne infections such as HIV-AIDS and hepatitis.

Answer:

1. 26.30 g C.

2. 4.42 g H.

3. 35.04 g O.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required as follows:

1. Here, the only source of carbon is in CO2, and thus, we calculate the grams of carbon from the produced grams of this substance:

[tex]m_C=96.38gCO_2*\frac{1molCO_2}{44.01gCO_2} *\frac{1molC}{1molO_2} *\frac{12.01gC}{1molC} =26.30g[/tex]

2. Here, the only source of hydrogen is in H2O, and thus, we calculate the grams of hydrogen from the produced grams of this substance:

[tex]m_H=39.46gH_2O*\frac{1molH_2O}{18.02gH_2O} *\frac{2molH}{1molH_2O} *\frac{1.01gH}{1molH} =4.42gH[/tex]

3. Here, we subtract the mass of H and C from the mass of the sample, to obtain the mass of oxygen:

[tex]m_O=65.76g-26.30g-4.42g\\\\m_O=35.04g[/tex]

Regards!

Answer:

the first one is a decomposition reaction

the second one is also a synthesis reaction

Solution:-1

[tex]\boxed{\sf {MgCO_3\atop Magnesium\:Carbonate}\overset{\Delta H}{\longrightarrow}{MgO\atop Magnesium \:Oxide}+{CO_2\atop Carbon\:Dioxide}}[/tex]

It is a thermal decomposition reaction

Solution:-2:-

[tex]\boxed{\sf {4Al\atop Aluminium}+{3O_2\atop Oxygen}\longrightarrow{2Al_2O_3\atop Aluminium\:oxide}}[/tex]

It is a combination reaction.

Answer:

1 kpa = 7.5 torr

1.75*10^7 pa = 1.75*10^4 Kpa = (1.75/7.5)*10^4 torr = 2333 torr

Explanation:

Answer:

Cu+(aq)--->Cu2+(aq) + e- : oxidation

reason: there is loss of electrons.

I2(s) + 2e--->2I-(aq) : reduction

reason: There is reduction of electrons.

Answer:

The correct answer is - acid-base reaction or chemical weathering.

Explanation:

Vinegar is an acid that dissolves a material that is commonly found and known as calcium carbonate present in the limestone. When these two, vinegar mix with calcium carbonate of the limestone, the atoms in the acetic acid and the calcium carbonate come apart and rearrange in different ways to make new chemicals.

This rearrangement results in the release of carbon dioxide as a stream of bubbles. It is a form of weathering called chemical weathering and many monuments are based on rocks that have limestones in their composition and acid rain work similar to vinegar.

Answer:

[tex]d=4.24x10^{-4}\frac{lb}{in^3}[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set the equation for the calculation of density and mass divided by volume:

[tex]d=\frac{m}{V}[/tex]

Thus, we can find the mass of the unknown by subtracting the total mass of the liquid to the mass of the flask and the liquid:

[tex]m=552.4g-464.7g=87.7g[/tex]

So that we are now able to calculate the density in g/mL first:

[tex]d=\frac{87.7g}{27.8mL}=3.15g/mL[/tex]

Now, we proceed to the conversion to lb/in³ by using the following setup:

[tex]d=3.15\frac{g}{mL}*\frac{1lb}{453.6g}*\frac{1in^3}{16.3871mL}\\\\d=4.24x10^{-4}\frac{lb}{in^3}[/tex]

Regards!

Answer:

Measure liquid by aligning the meniscus with the volume line.

Explanation:

A pipette is an instrument specially made for measuring a small volume of liquid.

The pipette comes in various sizes to be used in measuring various volumes of liquid. Generally, the pipette has a volume line which helps us to measure a liquid.

A liquid is measured by aligning the meniscus with the volume line.

Answer:

Following are the solution to the given question:

Explanation:

Answer:

False

Explanation:

Because Elaidic acid is an isomer of oleic acid. I really hope this helps you.

Answer: The mass of 45.0 L of [tex]F_{2}[/tex] at 87.0° C and 750 mm Hg is 56.605 g.

Explanation:

Given: Volume = 45.0 L

Temperature = [tex]87.0^{o}C[/tex] = (87.0 + 273) K = 360 K

Pressure = 750 mm Hg (1 mm Hg = 0.00131579 atm) = 0.98 atm

Formula used to calculate moles is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

[tex]PV = nRT\\0.98 atm \times 45.0 L = n \times 0.0821 L atm/mol K \times 360 K\\n = \frac{0.98 atm \times 45.0 L}{0.0821 L atm/mol K \times 360 K}\\= \frac{44.1}{29.556} mol\\= 1.49 mol[/tex]

Moles is the mass of a substance divided by its molar mass. So, mass of [tex]F_{2}[/tex] (molar mass = 37.99 g/mol) is calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\1.49 mol = \frac{mass}{37.99 g/mol}\\mass = 56.605 g[/tex]

Thus, we can conclude that the mass of 45.0 L of [tex]F_{2}[/tex] at 87.0° C and 750 mm Hg is 56.605 g.

Answer:

[tex]CuF_2[/tex] the empirical formula of the metal fluoride.

Explanation:

Mass of copper heated = 8.249 g

Mass of copper fluoride formed = 13.18 g

Mass of fluorine gas in copper fluoride = x

[tex]13.18 g = 8.249 g + x\\x= 13.18 - 8.249 g = 4.931 g[/tex]

Moles of copper :

[tex]= \frac{8.249 g}{63.546 g/mol}=0.1298 mol[/tex]

Moles of fluorine:

[tex]= \frac{4.931 g}{18.998 g/mol}=0.2596 mol[/tex]

For the empirical formula divide the smallest mole of an element with all the moles of elements present in the compound.

[tex]Copper= \frac{0.1298 mol}{0.1298 mol}=1\\Fluorine = \frac{0.2596 mol}{0.1298 mol}=2[/tex]

The empirical formula of the copper fluoride = [tex]CuF_2[/tex]

[tex]CuF_2[/tex] the empirical formula of the metal fluoride.

Answer:

Four common types of reactions involving carbonyl reactions: 1) nucleophilic addition; 2) nucleophilic acyl substitution; 3) alpha substitution; 4) carbonyl condensations. The first two were previously discussed and the second two involve the properties of the carbon directly adjacent to the carbonyls, α carbons.

Alpha-substitution reactions results in the replacement of an H attached to the alpha carbon with an electrophile.  

The nucleophile in these reactions are new and called enols and enolates.

Explanation:

The carbon in the carbonyl is the reference point and the alpha carbon is adjacent to the carbonyl carbon.  

Hydrogen atoms attached the these carbons denoted with Greek letters will have the same designation, so an alpha hydrogen is attached to an alpha carbon.  

Aldehyde hydrogens not given Greek leters.  

α hydrogens display unusual acidity, due to the resonance stabilization of the carbanion conjugate base, called an enolate.  

Tautomers are readily interconverted constitutional isomers, usually distinguished by a different location for an atom or a group, which is different than resonance.  

The tautomerization in this chapter focuses on the carbonyl group with alpha hydrogen, which undergo keto-enol tautomerism.  

Keto refers to the tautomer containing the carbonyl while enol implies a double bond and a hydroxyl group present in the tautomer.  

The keto-enol tautomerization equilibrium is dependent on stabilization factors of both the keto tautomer and the enol tautomer, though the keto form is typically favored for simple carbonyl compounds.  

The 1,3 arrangement of two carbonyl groups can work synergistically to stabilize the enol tautomer, increasing the amount present at equilibrium.

The positioning of the carbonyl groups in the 1,3 arrangement allows for the formation of a stabilizing intramolecular hydrogen bond between the hydroxyl group of the enol and the carbonyl oxygen as well as the alkene group of the enol tautomer is also conjugated with the carbonyl double bond which provides additional stabilization.

Aromaticity can also stabilize the enol tautomer over the keto tautomer.

Under neutral conditions, the tautomerization is slow, but both acid and base catalysts can be utilized to speed the reaction up.  

Biological enol forming reactions use isomerase enzymes to catalyze the shifting of a carbonyl group in sugar molecules, often converting between a ketose and an aldose in a process called carbonyl isomerization.

Answer:

Following are the solution to the given question:

Explanation:

In the aqueous solution of [tex]Hg^{2+}[/tex] ion is used to represent a [tex][Hg(H_2O)_4]^{2+}[/tex].

It is used to form a complex with iodide ions as [tex][Hgl_4]^{2-}[/tex].  

Conversion reaction:

[tex][Hg(H_2O)_4]^{2+} +4I^{-} \to [HgI_4]^{2-}+4H_20[/tex]

Following are the formation constants:

[tex]k_f=\frac{[HgI_4]^{2-}}{[Hg(H_2O)_4]^{2+} [I^{-}]^4}[/tex]

Following are the first step to the conversion:  

[tex][Hg(H_2O)_4]^{2+} +I^{-} \to [HgI(H_2O)_3]^{+}+H_20[/tex]

The process of watering the crops is called irrigation.

Any two methods of irrigation are:

This system is used on the uneven land where less water is available. The perpendicular pipes, having rotating nozzles on top, are joined to the main pipeline at regular intervals. Water is allowed to flow through main pipe under pressure, which escapes from the rotating nozzles. In this way water gets sprinkled on the crop.

This system is used to save water as it allows the water to flow drop by drop at the roots of the plants. It is the best technique for watering fruit plants, gardens and trees. Water is not wasted at all.

Answer:

10.4%

Explanation:

Recall that the formula for percent solution = mass of solute/mass of solution * 100

Mass of solute = 2.07 g

Mass of solution = 19.9 g

Hence mass percent of solute = 2.07/19.9 * 100

= 10.4%

Answer:

The correct answer is - 83. torr

Explanation:

We know that:

p = X solvent * P pure solvent,

where, X solvent = number of moles of solvent / total number of moles.

in this solution, solute is 10.9 g of C12 H10 and the solvent is 25.3 g C6H6.  

molar mass of C6H6 = 6 * 12 g/mol + 6 * 1g/mol = 78 g/mol ( =>  moles of solvent = mass in grams / molar mass)

moles of solvent = 25.3 g / 78 g/mol = 0.3243 mol

molar mass of C12H10 = 12 * 12g/mol + 10*1g/mol = 154 g/mol

moles of solute = 10.9 g / 154 g/mol = 0.07077 mol

=> X solvent = 0.3243 / (0.3243 + 0.07077) = 0.8208

=> p = 0.8208 * 100.84 torr = 82.77 torr ≈ 83.0 torr

Answer: 83.0 torr

Answer:

kinetically stable.

Explanation:

When we say that a system is thermodynamically unstable, it means that there is still a state in which the system is expected to have lower energy than it currently has. A thermodynamically unstable system is yet to attain equilibrium hence it can still undergo further chemical processes in order to attain thermodynamic stability.

When we say that a system is kinetically stable, it means that the activation energy or energy barrier for the reaction system is high. Thus reactants are not easily converted into products. The reaction system remains the same for a long while without change.

Finally, when a reaction is thermodynamically unstable (spontaneous) but no change is observed, the reaction is kinetically stable.

Answer:

Following are the response to the given question:

Explanation:

The number of shells

n = 4

Calculating the spectral line:

[tex]= \frac{n(n-1)}{2}\\\\ = \frac{4(4-1)}{2} \\\\= \frac{4\times 3}{2}\\\\ = \frac{12}{2}\\\\ = 6[/tex]

Answer:

The coins are gold

Explanation:

To solve this question we need to find the density of the sample knowing that density is the ratio between the mass of a sample (385.000g) and the volume that is occupying (20.0mL).

Density is:

385.000g / 20.0mL = 19.3g/mL

As the density of the sample is equal to the density of gold:

Answer:

1.38 × 10²⁰ zinc ions

Explanation:

Step 1: Given data

Moles of Zn²⁺: 2.29 × 10⁻⁴ mol

Step 2: Convert 2.29 × 10⁻⁴ moles to ions

To convert moles to ions, we need a conversion factor: Avogadro's number. There are 6.02 × 10²³ Zn²⁺ ions in 1 mole of Zn²⁺ ions.

2.29 × 10⁻⁴ mol × 6.02 × 10²³ ions/1 mol = 1.38 × 10²⁰ ions

Answer:

[tex]{ \sf{B. \: AgCl _{(s)} + NaNO _{3(aq)}}}[/tex]

Explanation:

Silver chloride precipitates out because it has a low value of Ksp.