What type of element is generally largest

Answer:

The concentration of HA is the same as concentration of H3O+ and A- produced.

Explanation:

The dissociation equation is given below:

HA(aq) + H2O (l) —> H3O+(aq) + A-(aq)

From the reaction above, we can see that the acid is monoprotic acid i.e it has only 1 ionisable hydrogen atom.

Now, from the balanced equation, we can see that the acid produced equal concentration of H3O+ and A-.

This account for the reason why the bars for H3O+ and A- have the same height as the bar for HA.

Answer:

C.

Explanation:

This is a reaction of elimination, because the water was removed and because of it double bond is formed.

Answer:

38g of Cr

Explanation:

Step 1:

The balanced equation for the reaction:

2K + CrBr2 —> 2KBr + Cr

Step 2:

Determination of the masses of K and CrBr2 that reacted and the mass of Cr produced from the balanced equation.

This is illustrated below:

Molar mass of K = 39g/mol

Mass of K from the balanced equation = 2 x 39 = 78g

Molar Mass of CrBr2 = 52 + (80x2) = 212g

Mass of CrBr2 from the balanced equation = 1 x 212 = 212g

Molar Mass of Cr = 52g/mol

Mass of Cr from the balanced equation = 1 x 52 = 52g

From the balanced equation above,

78g of K reacted with 212g of CrBr2 to produce 52g of Cr.

Step 3:

Determination of the limiting reactant.

This is illustrated below:

From the balanced equation above,

78g of K reacted with 212g of CrBr2.

Therefore, 57g of K will react with = (57 x 212)/78 = 154.92g of CrBr2.

From the above calculation, we can see that a lesser mass (i.e 154.92g) than what was given ( i.e 199g) of CrBr2 is needed to react completely with 57g of K. Therefore, K is the limiting reactant and CrBr2 is the excess reactant.

Step 4:

Determination of the mass of Cr produced by the reaction.

In this case, the limiting reactant will be use because it will give the maximum yield of Cr as all of it is used up in the reaction process. The limiting reactant is K and the mass of Cr produced is obtained as follow:

From the balanced equation above,

78g of K reacted to produce 52g of Cr.

Therefore, 57g of K will produce = (57 x 52)/78 = 38g of Cr.

Therefore, 38g of Cr is produced from the reaction.

Answer:

CuFeS2

Explanation:

Calculate the moles of each substance by doing moles= mass/relative atomic mass. you should get 0.25 moles of copper and iron and 0.5 moles of sulfur. Then divide all of those numbers by 0.25 (as its the lowest value) you should get 1 for copper and iron and 2 for sulfur. This represents the ratio that they are in within the mineral.

Answer:It allows us to see things so we know where we are going that’s why at night we had lamp posts

Explanation:

Answer:

18.0 g

Explanation:

M(H2) = 2.0 g/mol

32.0g * 1 mol/2 g= 16 mol H2

M(O2) = 32 g/mol

16.0 g * 1mol/32 g= 0.5 mol O2

                                      2H2 + O2 ---> 2H2O

from reaction              2 mol    1 mol

given                         16 mol     0.5 mol

We see that O2 is a limiting reactant.

                                    2H2 + O2 +-------> 2H2O

from reaction                         1 mol            2 mol

given                                      0.5 mol        x mol

x =(0.5*2)/1= 1 mol H2O

M(H2O)= 18 g/mol

18 g/mol* 1 mol = 18 g H2O

Answer:

1. carboxylic acid

2. ether

3. aldehyde

4. ketone

5. amine

6. alcohol

Explanation:

Know the functional groups. If you would like me to teach you them let me know.

- Hope that helps! Please let me know if you need further explanation.

Answer:

H+

Explanation:

Answer:

OH-

Explanation:

An Arrhenius base is any species that increases the concentration of

OH

Answer:t

Explanation:bc

Answer:

0.164541341 g H2

Explanation:

1) Convert grams to moles by dividing by RMM of Magnesium (24.31g).

  2g Mg * (1 mol Mg / 24.31 g Mg) = 0.082270671 mol of Mg

2) Use the balanced equation's ratio of 1 mol Mg: 1 mol H2.

  0.082270671 mol of Mg = 0.082270671 mol of H2

3) Convert the mol of H2 back into grams by multiplying by H2's RMM (2 g).

  0.082270671 mol of H2 * 2 g H2 = 0.164541341 g H2

* Answer can be rounded to your liking *

Answer:

the answer is A heterogeneous solutions

Explanation:

Mixtures in two or more phases are heterogeneous mixtures. Examples include ice cubes in a drink, sand and water, and salt and oil. The liquid that is immiscible form heterogeneous mixtures. A good example is a mixture of oil and water.Jun 26, 2019

Answer:

I would say that the mutation has no effect on the organism, as it doesn't help or harm it.

hope this helps :)

Explanation:

Answer:

its a neutral

Explanation:

i did the test

Answer:

It is widely believed that Buddhism entered China via the Silk Road under the Han Dynasty. After trade and travel was established with the Yuezhi, who by that time were forced southward toward India, Yuezhi monks began to travel with the merchant caravans; preaching their religion along the Silk Road.

Explanation:

i got this from google

Answer:

i believe it is strong acids, strong bases, and salts.

Explanation:

Hope this helps : )

Answer:

9.7 atm.

Explanation:

The following data were obtained from the question:

Initial pressure (P1) = 1 atm

Initial volume (V1) = 0.725 L

Final volume (V2) = 0.075 L

Final pressure (P2) =?

The final pressure can be obtained by using the Boyle's law equation since the temperature is constant. This is illustrated below:

P1V1 = P2V2

1 x 0.725 = P2 x 0.075

Divide both side by 0.075

P2 = 0.725 / 0.075

P2 = 9.7 atm.

Therefore, the new pressure is 9.7 atm.

Answer:

I believe the answer you're looking for is DNA, not sure though

Answer : A

0,15 moles of NaOH -------in-------1000ml

x moles of NaOH ---------in-------100ml

x= 0,015 moles of NaOH

final volume =150ml

0,015 moles of NaOH -------in------150ml

x moles of NaOH ------in--------1000ml

x= 0,1 moles of NaOH

Answer:

[tex]T1=166.66K[/tex]

Explanation:

According to Gay-Lussac’s law simply states that the ratio of the initial pressure and temperature is equal to the ratio of the final pressure and temperature for a gas of a fixed provided that the mass is kept at a constant volume.

Given:

Initial pressure, P1 = 1 atm

Final pressure, P2 = 1.5 atm

Final temperature, T2 = 250 K

The law can be applied using the below formula

P1T2 = P2T1

Then,

T1 = (P1T2)/P1 = (1*250)/(1.5) = 166.66 Kelvin.

[tex]T1=166.66K[/tex]

:

Answer:

[tex]T_1=166.7K[/tex]

Explanation:

Hello,

In this case, by applying the Gay-Lussac's law which help us to understand the pressure-temperature gas behavior via a directly proportional relationship:

[tex]\frac{P_1}{T_1} =\frac{P_2}{T_2}[/tex]

In such a way, as we are asked to compute the initial temperature knowing the initial pressure and final both temperature and pressure, so we solve for it:

[tex]T_1=\frac{T_2P_1}{P_2}=\frac{250K*1atm}{1.5atm} \\\\T_1=166.7K[/tex]

Best regards.

Answer

False

Explanation:

Answer: [tex]CO[/tex] is the limiting reagent and [tex]Fe_2O_3[/tex] is the excess reagent.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} Fe_2O_3=\frac{42.7g}{159.69g/mol}=0.267moles[/tex]

[tex]\text{Moles of} CO=\frac{13.2g}{28g/mol}=0.471moles[/tex]

The given balanced equation is :

[tex]Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)[/tex]

According to stoichiometry :

3 moles of [tex]CO[/tex] require = 1 mole of [tex]Fe_2O_3[/tex]

Thus 0.471 moles of [tex]CO[/tex] will require=[tex]\frac{1}{3}\times 0.471=0.157moles[/tex]  of [tex]Fe_2O_3[/tex]

As given amount of [tex]Fe_2O_3[/tex] is more than the required amount , it is the excess reagent.Thus [tex]CO[/tex] is the limiting reagent as it limits the formation of product.

Answer:

The limiting reactant is the propane gas, C₃H₈ while the percentage yield is 83.77%

Explanation:

Here we have

Propane gas with molecular formula C₃H₈, molar mass  = 44.1 g/mol combining with O₂ as follows

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Therefore, 1 mole of C₃H₈  combines with 5 moles of O₂ to produce 3 moles CO₂ and 4 moles of H₂O

Mass of propane = 0.1240 kg = 124.0 g

Number of moles of propane = mass of propane/(molar mass of propane)

The number of moles of propane = 124/44.1 = 2.812 moles

The molar mass of CO₂ = 44.01 g/mol

Mass of CO₂ = 0.3110 kg = 311.0 g

Therefore, number of moles of CO₂ = mass of CO₂/(molar mass of CO₂)

The number of moles of CO₂ = 311.0 kg/ 44.01 g/mol = 7.067 moles

Therefore, since 1 mole of propane produces 3 moles of CO₂, 2.812 moles of propane will produce 3 × 2.812 moles or 8.44 moles of CO₂

Therefore;

The limiting reactant is the propane gas, C₃H₈, since the oxygen is in excess

Hence

[tex]The \ percentage \ yield = \frac{Actual \, yield}{Theoretical \, yield} \times 100 = \frac{7.067}{8.44} \times 100 = 83.77 \%[/tex]

The percentage yield = 83.77%.

Answer:

c,density is the measure of compactness in a substance. Liquid particles are close together however they aren't as close as the particles in solids.

Answer:

8 kg mass

Explanation:

As we can see in the image the weight of mass 8 kgs has a large surface area as compared to the surface area of other masses. In general, it has been observed that a wide surface area has more surface particle for heat conduction. Hence, the rate of heat transfer is directly proportional to the surface area of heat conducting surface. Thus, the larger the surface area, the faster is the rate of heat conduction.

Hence, weight of mass 8Kg wil transfer heat a fast rate.

Answer:

A metal and a nonmetal

Explanation:

Picture NaCl, the most famous example of an ionic compound. Two ions, Na+ (sodium) and Cl- (chlorine) are joined by an ionic bond.

Sodium, the metal, gives up an electron to chlorine.

Chlorine, the nonmetal, accepts an electron from sodium.

That way both have 8 electrons in their outer shell! This is the way ionic bonds function.

Answer:

The ISS provides a location in the relative safety of low Earth orbit to test spacecraft systems that will be required for long-duration missions to the Moon and Mars.

Explanation:

Answer: PtF6

Explanation:  is one of seventeen known binary hexafluorides.