What number should be added to 2/8 to -1/12 get ?​

Answer:

8/3 or 2.6667

Step-by-step explanation:

when you divide fractions you use a technique called KCF

K = keep

C = change

F = flip

You write the equation [tex]\frac{2}{3}[/tex] ÷ [tex]\frac{1}{4}[/tex]

you keep [tex]\frac{2}{3}[/tex]

you change the symbol, so from ÷ you change it to x

and flip the last fraction, so you would have  [tex]\frac{4}{1}[/tex]

then you solve it

[tex]\frac{2}{3}[/tex] x  [tex]\frac{4}{1}[/tex] = [tex]\frac{8}{3}[/tex]

The result of 2/3 divided by 1/4 in simplest form is 8/3 .

Division: It is one of the four basic mathematical operation, the other three being addition, subtraction, multiplication.

Given, division of [tex]\frac{2}{3}[/tex] by [tex]\frac{1}{4}[/tex].

Division of fractional terms:

[tex]=\dfrac{\frac{a}{b}}{\frac{c}{d}}\\= (a)\times(d)/(b)\times(c)[/tex]

Apply, division process of fractional terms.

[tex]=\dfrac{\frac{2}{4}}{\frac{1}{3}}\\ = (2)\times(4)/(1)\times(3)[/tex]

[tex]= \frac{8}{3}[/tex]

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Answer:

18.63

Step-by-step explanation:

[tex] \frac{6}{10} = 0.6 \\ \frac{3}{100} = 0.03[/tex]

[tex]10 + 8 + 0.6 + 0.03 = 18.63[/tex]

Answer:

-18 is the right answer..

[tex]6\cdot\square=9\\\\\square=9:6\\\\\square=\frac{9}{6}\rightarrow\square=\frac{3}{2} \ (\text{devide 9 and 6 by 3})[/tex]

Answer:

you either need to score a perfect on one exam and get a 80 on the second or get two 90s on both exams.

Step-by-step explanation:

Answer:

x = 5

Step-by-step explanation:

x^2/(x + 5) = 25/(x+5)      Subtract the right side from both sides.

x^2/(x + 5) - 25/(x + 5) = 0

x^2 - 25

=======   = 0

x + 5

(x + 5)(x - 5)

============= = 0

(x + 5)

Cancel x + 5 in the numerator and denominator.

x - 5 = 0

x = + 5

Does it check?

x^2/(x + 5) = 25/(x + 5)

x = 5

5^2/(10) = 25/10

25/10 = 25/10 Yes it checks.

Given Data : Length = (7p - 10q) and Breadth = (2p - 9q)

Calculation :

⟹ Perimeter = 2(Length + Breadth)

⟹ Perimeter = 2(7p - 10q + 2p - 9q)

⟹ Perimeter = 2(9p - 19q)

⟹ Perimeter = 18p - 38q centimetres

The required perimeter of the rectangle is 18p - 38q centimeters.

It is required to find the required perimeter of the rectangle.

A rectangle is a type of quadrilateral, whose opposite sides are equal and parallel. It is a four-sided polygon that has four angles, equal to 90 degrees. A rectangle is a two-dimensional shape.

Given:

width of a rectangle = (2p - 9q) centimeters,

length measures= (7p - 10q) centimeters.

We know that

⟹ Perimeter = 2(Length + Breadth)

By put the value width and length in perimeter we get,

⟹ Perimeter = 2(7p - 10q + 2p - 9q)

⟹ Perimeter = 2(9p - 19q)

⟹ Perimeter = 18p - 38q centimeters

Therefore, the required perimeter of the rectangle is 18p - 38q centimeters.

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Answer:

1 hour 12 minutes

Step-by-step explanation:

1.2 × 60 = 72 minutes

72-60 = 12 minutes

Answer:

-29

Step-by-step explanation:

(-14) + (-15) =

-14 - 15 =

-29

Answer:

I believe the answer is B. a^2 = c^2 - 2cx + x^2 + h^2

Step-by-step explanation:

The law of cosines states: c^2 = a^2 + b^2 - 2bc * cos(C). If we plug in the values from the diagram, we'll have (c-x)^2 = a^2 + h^2 -2ah * cos(90)

cos(90) = 0, so now we have just (c-x)^2 = a^2 + h^2

Let's expand this to c^2 -2cx + x^2 = a^2 + h^2

Isolate a^2 and we now have a^2 = c^2 -2cx + x^2 + h^2

pls vote me brainliest if i was able to help you!! <3

[tex]2 {m}^{8} - 6 {m}^{2} [/tex]

Step-by-step explanation:

[tex](12 {m}^{7} - 36m) \div 6m[/tex]

➡️ [tex] \frac{1 {2m}^{7} - 36m }{6} \times m[/tex]

➡️ [tex] \frac{6(2 {m}^{7} - 6m)}{6} \times m[/tex]

➡️ [tex](2 {m}^{7} - 6m)m[/tex]

➡️ [tex]2 {m}^{8} - 6 {m}^{2} [/tex]

Answer:

2x + 3 + 3x +12 + 90 = 180 (degree )

5x +105=180 (degree )

5x= 180-105 (degree )

5x = 75 (degree )

x = 75/5 (degree )

x = 15 #

therefore, 2x + 3= 2*15 + 3

=30+3

= 33#

3x + 12 = 3*15+12

= 45 +12

= 57#

Answer:

The product of any rational number and any irrational number will always be an irrational number.

Step-by-step explanation:

5 students offers all the two subjects.

Student that offers Physic only = 15 students

Student that offers chemistry only  = 13 students

Students that offers only one subject = 28 students

Total student in the class = 35

20 offer physics.

18 offer chemistry

2 offer neither physics nor chemistry.

Therefore,

x = student that offer both subject

35 = 20 + 18 - x + 2

35 - 2 - 20 - 18 = -x

-5 = -x

x = 5

Therefore, 5 students offers all the two subjects.

Student that offers Physic only = 20 - 5 = 15

Student that offers chemistry only = 18 - 5 = 13

Students that offers only one subject = 13 + 15 = 28

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Answer:

Answer = he made 7,000 in July and sold 10 cars in august.

Step-by-step explanation:

Answer: Circumference = 7.85 inches

Concept:

Here, we need to know the idea of circumference.

The circumference is the perimeter of a circle. The perimeter is the curve length around any closed figure.

Circumference = 2πr

r = radius

π = constant

Solve:

Given information

r = (1/2) d = (1/2) (2.5) = 1.25 inches

π = 3.14

Given formula

Circumference = 2πr

Substitute values into the formula

Circumference = 2 · (3.14) · (1.25)

Simplify by multiplication

Circumference = (2.5) · (2.14)

Circumference = [tex]\boxed {7.85 inches}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Step-by-step explanation:

Using the formulas

C=2πr

d=2r

Solving forC

C=πd=π·2.5≈7.85398in

The scaled factor is 3 for all of them.

Answer: g(x) = (x+1)-3

Step-by-step explanation: Assuming you are moving from expression f to expression g, the plus one in the equation moves the vertex to the right one. subtracting three outside of the parenthesis moves the vertex down three, giving you a vertex of (1,-3). hope this helps!

Answer:

Step-by-step explanation:

x - first

x + 12 - second

x + (x + 12) = 44

2x=44-12

x=16

first number is 16

second number is 16+12=28

two numbers are 16 and 28

16 and 28 are the required two numbers when one number exceeds another by 12 and their sum is 44

One number exceeds another by 12 and their sum is 44

We need to find the two numbers

Two expressions with equal sign is called equation.

Let x be the first number

x + 12 be the  second number

x + (x + 12) = 44

2x=44-12

x=16

Therefore first number is 16

second number is 16+12=28

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Answer:

Step-by-step explanation:

My answer is in the picture

Answer:

-1

Step-by-step explanation:

f(-1) = 2|-1| + 3(-1)

|-1| = 1

=> f(-1) = 2(1) - 3

=> f(-1) = 2 - 3

=> f(-1) = -1

Answer:

45000rupees

Step-by-step explanation:

cost of 1 litre of petrol=60rupees

cost of 750 litres of petrol=750×60rupees

=45000rupees

Line 1-Line 2-Associative property .

Line 2-Line 3- Distributive property

Solution:-

[tex]\\ \rm\longmapsto (9+x)x[/tex]

[tex]\\ \rm\longmapsto x(x+9)[/tex]

[tex]\\ \rm\longmapsto x(9+x)[/tex]

[tex]\\ \rm\longmapsto x^2+9[/tex]

Answer:

B. [tex] {a}^{ - 7 - 10} [/tex] (second option)

Step-by-step explanation:

[tex] \frac{ {a}^{ - 7} }{ {a}^{10} } [/tex]

[tex] {a}^{ - 7 - 10} [/tex]

[tex] - 7 - 10 = - (7 + 10) = - 17[/tex]

Step-by-step explanation:

A 45° angle is complementary to angle

45°+x°=90°

I hope it helped U

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We need to find the equation which is equidistant to the given points.

[tex]A(-2,6,3)[/tex] and [tex]B(5,3,-3)[/tex]

This can be done using the distance formula.

Let us take a point [tex]P(x,y,z)[/tex] which is equidistant from both points so

[tex]\sqrt{(x+2)^2+(y-6)^2+(z-3)^2}=\sqrt{(x-5)^2+(y-3)^2+(z+3)^2}\\\Rightarrow y^2-12y+x^2+4x+z^2+49-6z=y^2-6y+x^2+z^2+6z+43-10x\\\Rightarrow 7x-3y-2z+1=0[/tex]

The required equation is [tex]7x-3y-2z+1=0[/tex]

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