What name is given to a metal when it forms an ion, and what type of charge does it have?

Answers

Answer 1

Answer:

Cation metal. Positive charge.

Answer 2

Answer:

DHS has been working hard for years and it is still unclear whether this would happen if it is to end the market with the engine is a little less than the next 5years to be 8years in the first quarter and the same year in a quarter or less than a quarter or more than that


Related Questions

I need help with question 5

Answers

Answer:

B a spring being stretched

Exprese la concentración de una solución de H3PO4 al 30 % en masa y con una densidad de 1.39 g/mL en: M, y N.

Answers

Respuesta:

4.26 M; 12.8 N

Explicación:

Primer paso: Calcular la concentración volumétrica (Cv)

Usaremos la siguiente expression.

Cv = Cg × ρ

Cv = 30 g%g × 1.39 g/mL = 41.7 g%mL

Segundo paso: Calcular la molaridad

La concentración volumetrica es 41.7 g%mL, es decir, hay 41.7 gramos de soluto cada 100 mL de solución. Usaremos la siguiente fórmula para molaridad.

M = masa de soluto / masa molar de soluto × litros de solución

M = 41.7 g / 97.99 g/mol × 0.1 L = 4.26 M

Tercer paso: Calcular la normalidad

Usaremos la siguiente fórmula.

N = M × Z

donde Z para un ácido es igual al número de protones.

N = M × Z

N = 4.26 mol/L × 3 eq/mol = 12.8 N

How many moles are in 32g of O2?

Answers

Answer:

1 mol of O2

Explanation:

n = m/ M

n = 32/ ( 2× 15.999)

n= 1 mol of O2

hii pls help me to write the ionic equation ​

Answers

Answer:

net ionic equation

[tex]\boxed{ SO_4{}^{2-} {}_{(aq.)} + Ba^{2+} {}_{(aq.)} \rightarrow BaSO_4 {}_{(s)}} [/tex]

Draw the following structures and name them :
I. CH3CH2(OH)
II.CH3CH2CH(CH3)C(Cl)2C(l)2CH(F)OH
III.CH3CH(CH3)CHO
IV.CH2=CH(OH)
V.CH3OCH2CH3

Answers

Answer:

hope this helps.answer is in the picture

nguyên tử sắt có điện tích hạt nhân là 26+. trong nguyên tử, số hạt mang điện nhiều hơn số hạt không mang điện là 22. Hãy xác định số khối của nguyên tử sắt

Answers

Answer:

I don't know yr language

A pupil has drawn the electronic structure of fluorine and the diagram is shown below. However,
mistakes have been made. State three mistakes that have been made.

Fl atomic number: 9
Fl atomic mass: 10

(ps i have two of these but can’t figure out the last)

Answers

Answer:

The number of electrons in the orbit is wrong they have to be 9 and not 10since flourine is in group 7 the number of electrons in the outer most shell has to be 7 and not 2the first shell has 8 instead of 2 electrons

I hope this helps

Is this population more likely to grows slowly or quickly in the next 10 years

Answers

nobody can say it is uncertain but in my opinion it will grow quickly in the next 10 years

How many moles of KOH are there in 27.5 mL of 0.250 M KOH?

Question 2 options:

4.31 × 10−3 mol KOH


6.88 × 10−3 mol KOH


7.24 × 10−3 mol KOH


8.13 × 10−3 mol KOH


9.21 × 10−3 mol KOH

Answers

Answer:

6.88 × 10^-3mol

Explanation:

Molarity = number of moles (n) ÷ volume (V)

According to this question, there in 27.5 mL of 0.250 M KOH, the number of moles of KOH can, therefore, be calculated as follows:

number of moles = molarity × volume

Volume of KOH = 27.5mL = 27.5/1000

= 0.0275L

n = 0.0275 × 0.250

n = 0.006875 mol

n = 6.88 × 10^-3mol

if excess nitrogen gas reacts with 600 cm³ of hydrogen gas at room conditions , calculate the maximum volume of ammonia produced from the reaction? the chemical question is N2 + 3H2 = 2NH3​

Answers

Answer:

400 cm³ of ammonia, NH₃.

Explanation:

The balanced equation for the reaction is given below:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

3 cm³ of H₂ reacted to produce 2 cm³ of NH₃.

Finally, we shall determine the maximum volume of ammonia, NH₃ produced from the reaction. This can be obtained as illustrated below:

From the balanced equation above,

3 cm³ of H₂ reacted to produce 2 cm³ of NH₃.

Therefore, 600 cm³ of H₂ will react to produce = (600 × 2)/3 = 400 cm³ of NH₃.

Thus, 400 cm³ of ammonia, NH₃ were obtained from the reaction.

Analyse the temperature versus time graph of water, given below.

Which part of graph represent only liquid state and gaseous state and why?​

Answers

Answer:

Phase C - Liquid State

Phase E - Gaseous State

Explanation:

Usually, in phases of water, we have the following;

When temperature is less than zero, it is said to be in its solid phase as ice.

When temperature is between 0 to 100, we can say it is in the liquid phase as water.

When temperature is above 100°C, It is said to be in the gaseous phase as vapour.

From the diagram;

Phase C is the only liquid state because it falls between temperature of 0°C and 100°

Also, only phase E is in the gaseous phase because the temperature is above 100°C.

Please help me
will give the brainliest!​

Answers

Explanation:

a) The presence of sulfate ions in a solution can be confirmed by the reaction of barium chloride in an acidic medium.

The balanced chemical equation of the reaction is shown below:

[tex]BaCl_2(aq)+CuSO_4(aq)->CuCl_2(aq)+BaSO_4(s)[/tex]

Hence, the white precipitate is barium sulfate and its formation with the ionic equation is shown below:

[tex]Ba^2^+(aq)+SO_4^2^-(aq)->BaSO_4(aq)[/tex]

b) The presence of copper (II) ions can be confirmed by the following test:

Add potassium iodide solution to copper (II) solution.

Then a white ppt of cuprous iodide along with the liberation of iodine is observed and the entire solution attains brown color.

The chemical equation of the reaction is shown below:

[tex]2CuSO_4(aq)+4KI(aq)->Cu_2I_2(s)+I_2(s)+2K_2SO_4(aq)\\[/tex]

c)(i)Due to this reaction, the blue color of the solution becomes white.

Reddish-brown copper is deposited at the bottom of the container.

(ii)In this reaction, zinc is oxidized.

d) (i) Copper is produced at the cathode.

(ii)[tex]Cu^2^+(aq)+2e^-->Cu(s)[/tex]

(iii) The reaction that takes place at the cathode is reduction.

Reduction is gaining of electrons.

How much heat must be transferred to 55 g of ice to change the ice's
temperature from -13°C to -5.0°C? (The specific heat capacity of ice is 2.11
J/g.°C)


Answers

928.4 J/.C

Q= m x c x t
M= 55 g
C=2.11
T=8

Plants in forests take up carbon dioxide from the atmosphere during photosynthesis. They transform the carbon dioxide into plant material. When plants die, their organic matter is often worked into the soil by decomposers. Some of this organic matter remains within the soil and forest floor, and some of it is taken up by other living things.

Based on this information, what role do forests play in the carbon cycle?
A.
Forests are carbon sinks because they store carbon.
B.
Forests are carbon sinks because they do not absorb carbon dioxide when plants die.
C.
Forests are carbon sources because they emit carbon.
D.
Forests are carbon sources because they can be burned to emit carbon dioxide.

Answers

Answer is A

Because Trees store carbon and make it oxygen

Answer: B. forests are carbon sinks because they store carbon

Explanation:forests take up carbon from the atmosphere through photosynthesis and from organic matter through decomposition. so, forests are carbon sinks because they store carbon

The carbon atom forms a part of all the major molecules found in living things. Which of the following doesnot contain carbon?​

Answers

Hydrochloric acid or Hcl

what is the charge on ion X Li2X

Answers

In the compound Li2X, there are two lithium ions and one X^2- ion.

Ionic compounds are composed of an ion pair of opposite charge. Usually, the positive ion is a metal cation while the negative ion is a non metal anion. The two ions are held together by strong electrostatic interaction.

In the compound Li2X, there are two lithium ions and one X^2- ions. X^2 -is the  non metal anion present.

Learn more: https://brainly.com/question/2673886

b) The size of a star is a balance between
2 things. Explain this statement.

Answers

Answer:

Luminosity is the amount of light that a star radiates. The size of the star and its surface temperature determine its luminosity. Apparent magnitude of a star is its perceived brightness, factoring in size and distance, while absolute magnitude is its true brightness irrespective of its distance from earth

Explanation:

What is the pH of a 1.0 x 10-3 M KOH solution?
A. 10
B. 4.0
C. 11
D. 3.0

Answers

Answer:

Option C. 11

Explanation:

We'll begin by calculating the concentration of the hydroxide ion [OH¯] in the solution. This can be obtained as follow:

In solution, KOH will dissociate as follow:

KOH (aq) <=> K⁺(aq) + OH¯(aq)

From the balanced equation above,

1 mole of KOH reacted to produce 1 mole of OH¯.

Therefore, 1×10¯³ M KOH will also react to produce 1×10¯³ M OH¯.

Thus, the concentration of hydroxide ion [OH¯] in the solution is 1×10¯³ M

Next, we shall determine the pOH of the solution. This can be obtained as follow:

Concentration of hydroxide ion [OH¯] = 1×10¯³ M

pOH =?

pOH = –Log [OH¯]

pOH = –Log 1×10¯³

pOH = 3

Finally, we shall determine the pH of the solution. This can be obtained as follow:

pOH = 3

pH =?

pH + pOH = 14

pH + 3 = 14

Collect like terms

pH = 14 – 3

pH = 11

QUICK CHECK
Use the periodic table to select which type of bond is present and which of the listed properties is most
likely for each substance.
Substance
Type of bond
Likely property
A А
B
A
Cuzm
Ba
lonic
DO
covalent
02
С
D
metallic

Answers

Answer:

Coppell zinc,ironic bond

Explanation:

lt will give away two zinc atoms

Answer:

I will go with Sodium chlorine NaCl

Which is another word for 10 meters in the metric system?

Answers

Answer:

Dekameter

Explanation:

plz solve the question and send the answer
I will give u branist, follow u ,rate u 5 star and also give u like ,plz help me​

Answers

Answer:

64g of [tex]\bold{CH_{3}OH}\dashrightarrow[/tex]44.8L

vapour density of [tex]CH_{3}3OH=\frac{mass}{volume}[/tex] of [tex]\bold{CH_{3}OH}[/tex]

=64/44.8=10/7=1.43 g/l

Vapour density of [tex]\bold{CH_{3}OH}[/tex]=1.43g/l

64g of [tex]\bold{CH_{3}OH => 44.8L }[/tex]

vapour density of [tex]\small{\sf{CH_{3}3OH=\frac{mass}{volume} of } \bold{CH_{3}OH}}[/tex]

=64/44.8=10/7=1.43 g/l

Vapour density of [tex]\bold{CH_{3}OH = 1.43 g/L}[/tex]

hii pls help me!!
even if u know how to do one, it's okk
anything helps ​

Answers

Explanation:

a) HNO2(aq) = HNO3(aq) + H2O(l) +NO(g)

b) SoCl2 (l) + H2O (l) = So2(g) + 2HCl(aq)

c) CH4 (g) + 2O2(g) = Co2 (g) + 2H2O(g)

d) 3CuO(s) + 2NH3 (g) = 3Cu(s) + 3H2O (l) + N2(g)

Question 8 of 10
Which of the following is made of matter?

A. Light
B. Energy
C. The sun
D. Heat

Answers

The answer would have to be letter b. Energy

Answer: i Choose the sun

because it has mass

Explanation: matter is anything that has mass and occupies space / Volume

and the sun has mass though it is not a solid one, and is made up of matter

HOPE THIS HELPSS!!!!

Chromium forms a complex with diphenylcarbazide whose molar absorptivity is 4.17*10^4 at 540nm. Calculate the absorbance of a 7.68*10^-6 M solution of the complex at 540nm when measured in a 1.00cm cell and the transmittance of the solution.

Answers

Answer:

0.32 liters/mole cm.

Explanation:

According to Beer Lambert's law;

A= εcl

ε = molar absorptivity

c= concentration

l= path length

A= 4.17*10^4 × 7.68*10^-6 × 1

A= 0.32 liters/mole cm.

HELLO EVERYONE PLEASE I NEED HELP WITH

Please I REALLY NEED A HELP WITH THIS PLEASE HELP ME

THIS HARRY POTTER LITERARY ESSAY
OUTLINE


1. Love and Friendship is a central theme in Harry Potter and the Philosopher's Stone. Prove that this statement is true using 2(two) different characters from the novel as examples.


Introductory Statement/ Hook:



Statement of Intent: reason A and B :



thesis reason A and B:



BODY PARAGRAPH



#1 Point #1: Introduce REASON A here, but use general statement



#1: Provide quotations from the novel to support Reason A



Explanation #1:


Proof #2:


Explanation #2:



BODY PARAGRAPH


#2 Point #2: Introduce REASON B here, but use general statements


#1: Provide quotations from the novel to support ReasonB



Explanation #1:


Proof #2:


Explanation #2:



CONCLUSION


Restate/ Summarize Thesis:


Restate/ Summarize Points:

Answers

Answer:

Ron and Hermoine

Explanation:

They always fought over petty things, but at the end, they did end up together!

(Answer for your question about love and friendship being a central theme in Harry Potter and the Philosopher's stone)

*ALSO, MY ANSWER MIGHT BE WRONG* so be sure to use a pencil just in case!

PLEASE HELP QUICK!!! How many molecules are there in 4.00 L of
glucose, C6H1206? Please show your work!!

Answers

As 1 L is 1000 g
So mass= 4000g
Molar mass of Glucose= 180 g/mol
As Number of molecules= mass/molar mass x Avogadro’s no.
Number of molecules= 4000/180 x 6.022 x 10^23
Number of molecules = 1.3 x 10^25 molecules




Molar mass of NO2= 46
Number of molecules = 14/46 x 6.022 x 10^23
Number of molecules= 1.8 x 10^23 molecules

make a 450 gram solution with the mass by mass concentration of 7% how much salt and water do you need to mix​

Answers

you’d need to mix over have the mass of the 450 gram solution

Which diagram represents this molecule

Answers

Answer:

I think it is C

Explanation:

Hope this helps!! :)

If I'm wrong, then greatest apologies

If you hit the surface of Iron with a photon of energy and find that the ejected electron has a wavelength of .75 nm, what is the wavelength of the incoming photon in nanometers?

Answers

Answer:

The wavelength of the incoming photon is 172.8 nm

Explanation:

The wavelength of the incoming photon can be calculated with the photoelectric equation:

[tex] KE = h\frac{c}{\lambda_{p}} - \phi [/tex]   (1)

Where:

KE: is the kinetic energy of the electron

h: is Planck's constant = 6.62x10⁻³⁴ J.s  

c: is the speed of light = 3.00x10⁸ m/s

[tex]\lambda_{p}[/tex]: is the wavelength of the photon =?  

Φ: is the work function of the surface (Iron) = 4.5 eV        

The kinetic energy of the electron is given by:

[tex] KE = \frac{p^{2}}{2m} = \frac{(\frac{h}{\lambda_{e}})^{2}}{2m} [/tex]  (2)

Where:  

p: is the linear momentum = h/λ

m: is the electron's mass = 9.1x10⁻³¹ kg

[tex]\lambda_{e}[/tex]: is the wavelength of the electron = 0.75 nm = 0.75x10⁻⁹ m

Hence, the wavelength of the photon is:

[tex] \frac{(\frac{h}{\lambda_{e}})^{2}}{2m} = h\frac{c}{\lambda_{p}} - \phi [/tex]

[tex]\lambda_{p} = \frac{hc}{\frac{h^{2}}{2m\lambda_{e}^{2}} + \phi} = \frac{6.62 \cdot 10^{-34} J.s*3.00\cdot 10^{8} m/s}{\frac{(6.62 \cdot 10^{-34} J.s)^{2}}{2*9.1 \cdot 10^{-31} kg*(0.75 \cdot 10^{-9} m)^{2}} + 4.5 eV*\frac{1.602 \cdot 10^{-19} J}{1 eV}} = 1.728 \cdot 10^{-7} m = 172.8 nm[/tex]      

Therefore, the wavelength of the incoming photon is 172.8 nm.

I hope it helps you!        

PLEASE HELPP!!!
PLEASE HELP!!!
Write the sentences in your copybook and draw a line through one of the words in
bold to complete each of these sentences about alkali metals correctly.

 Alkali metals generally become more / less dense going down the group.

 The melting and boiling points of alkali metals increase / decrease down the group.

 The softness of alkali metals increases / decreases going down the group.

 The speed with which alkali metals react with oxygen increases / decreases going
down the group.

Answers

Answer:

vahshahhsjajaiaoakkakakaaosos

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