What must be the same for two resistors that are connected in parallel?

Answers

Answer 1

Answer:

the voltage will be the same across all resistors

Explanation:

the total voltage supplied to the circuit will remain the same across all resistors


Related Questions

On page 14 of the call of the wild jack London, writes,in vague ways he remembered back to the youth of the breed ,this statement is example of

Answers

Answer:

On page 14 of the call of the wild jack London, writes,in vague ways he remembered back to the youth of the breed ,this statement is example of the racial unconscious. As a general rule, really great novels contain universal truths. 

Explanation:

Hey mate dont worry! My answer is correct!!

Answer:

racial unconscious

Explanation:

took the test and it was correct

explain why this is important for life on earth​

Answers

Answer:

THIS is very important.

Explanation:

If the word "this" was never invented, people wouldn't have a way to tell another person what is directly in front of them.

BTW this is a joke.

Using only astronomical data from the Appendix E in the textbook, calculate the speed of the planet Venus in its essentially circular orbit around the sun.
Venus = 4.87x10^24

Answers

Answer:

[tex]v=3.49\times 10^4\ m/s[/tex]

Explanation:

Given that,

Mass of Venus, [tex]M_V=4.87\times 10^{24}\ kg[/tex]

We know that,

Mass of Sun, [tex]M_s=1.98\times 10^{30}\ kg[/tex]

The distance between the center of Sun and the center of Venus is [tex]1.08\times 10^{11}\ m[/tex]

We need to find the peed of the planet Venus in its essentially circular orbit around the sun. using the formula,

[tex]v=\sqrt{\dfrac{GM_s}{r}}[/tex]

Put all the values,

[tex]v=\sqrt{\dfrac{6.67\times 10^{-11}\times 1.98\times 10^{30}}{1.08\times 10^{11}}}\\\\v=3.49\times 10^4\ m/s[/tex]

So, the speed of the planet venus is [tex]3.49\times 10^4\ m/s[/tex].

how to reduce fluid friction

Answers

Answer:

By making the object sharp pointed

you are given a set of facts regarding a lens : object heigh, and dostance to objects. Given this jnformation, how can you tell if you're dealing with a concave or convex lens

Answers

Answer:

concave curves inward like an hourglass and convex is an outward curve like a football

Explanation:

hope this helps

The image shows the right-hand rule being used for a current-carrying wire.

An illustration with a right hand with fingers curled and thumb pointed up.

Which statement describes what the hand shows?

When the current flows down the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
When the current flows down the wire, the magnetic field flows in on the left side of the wire and out on the right side of the wire.
When the current flows up the wire, the magnetic field flows in on the left side of the wire and out on the right side of the wire.

Answers

D PLS MARK ME AS BRAINLY

Answer:

The answer is (D): When the current flows up the wire, the magnetic field flows in on the left side of the wire and out on the right side of the wire.

Explanation:

Mixed powders may be categorized as​

Answers

Answer:

on  flow properties and free-flowing and cohesive.

Explanation:

the power Free flowing powders do not cling together, as cohesive powders stick to each other and form that do not disperse well during mixing

A spring scale hung from the ceiling stretches by 6.1cm when a 2.0kg mass is hung from it. The 2.0kg mass is removed and replaced with a 2.8kg mass.What is the stretch of the spring?

Answers

2.0kg and the mass of sometimes makes it hard 2.8kg

A constant force moves an object along the line segment from to . Find the work done if the distance is measured in meters and the force in newtons.

Answers

This question is incomplete, the complete question is;

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A constant force F = 6i+8j-6k moves an object along a straight line from point (6, 0, -10) to point (-6, 7, 2).

Find the work done if the distance is measured in meters and the magnitude of the force is measured in newtons.

Answer:

the work done is -88 J

Explanation:

Given the data in the question;

we know that;

Work done = F × S

where constant force F = ( 6i + 8j - 6k )

S = ( -6i + 7j + 2k ) - ( 6i + 0j - 10k )

S = ( (-6i - 6i) + (7j - 0j) + ( 2k - ( -10k) ) )

S = ( -12I + 7j + 12k )

so

Work force = ( 6i + 8j - 6k ) × ( -12I + 7j + 12k )

Work force = ( 6 × -12 ) + ( 8 × 7 ) + ( -6 × 12 )

Work force = -72 + 56 - 72

Work force = -88 J

Therefore, the work done is -88 J

A boy throws a ball straight up with a speed of 21.5 m/s. The ball has a mass of 0.19 kg. How much gravitational potential energy will the ball have at the top of its flight? (Assume there is no air resistance.) A. 43.9 J B. 37.5 J C. 48.5 J D. 41.2 J​

Answers

Answer:

Explanation:

The equation fo potential energy is PE = mgh, where m is the mass of the ball, g is the pull of gravity (constant at 9.8), and h is the max height of the ball. What we do not have here is that height. We need to first solve for it using one-dimensional equations. What we have to know above all else, is that the final velocity of an object at its max height is always 0. That allows us to use the equation

[tex]v_f=v_0+at[/tex] where vf is the final velocity and v0 is the initial velocity. We will find out how long it takes for the object to reach that max height first and then use that time to find out what that max height is. Baby steps here...

0 = 21.5 + (-9.8)t and

-21.5 = -9.8t so

t = 2.19 seconds (Keep in mind that if I used the rules correctly for sig fig's, the answer you SHOULD get is not one shown, so I had to adjust the sig fig's and break the rules. But you know what they say about rules...)

Now we will use that time to find out the max height of the object in the equation

Δx = [tex]v_0t+\frac{1}{2}at^2[/tex] and filling in:

Δx = [tex]21.5(2.19)+\frac{1}{2}(-9.8)(2.19)^2[/tex] which simplifies down a bit to

Δx = 47.1 - 23.5 so

Δx = 23.6 meters.

Now we can plug that in to the PE equation to find the PE of the object:

PE = (.19)(9.8)(23.6) so

PE = 43.9 J

Two thin conducting plates, each 56.0 cm on a side, are situated parallel to one another and 7.0 mm apart. If 10^-10 electrons are moved from one plate to the other, what is the electric field between the plates?

Answers

Answer:

[tex]E=576.5V/m[/tex]

Explanation:

From the question we are told that:

Length [tex]l=56.0cm=0.56m[/tex]

Distance apart [tex]d=7.0mm=0.007m[/tex]

Electron Transferred [tex]n=10^{-10}[/tex]

Therefore

Total Charge

Since Charge on each electron is

[tex]e=1.602*10^{-19}[/tex]

Therefore

[tex]T=1.602*10^{-19} *10^{10}[/tex]

[tex]T=1.602*10^{-9}[/tex]

Generally the equation for Charge density is mathematically given by

[tex]\rho=T/A[/tex]

Where

Area

[tex]A=0.56*0.56[/tex]

[tex]A=0.3136[/tex]

Therefore

[tex]\rho=1.602*10^{-9}/0.3136[/tex]

[tex]\rho=5.10*10^{-9}[/tex]

Generally the equation for Electric Field in the capacitor is mathematically given by

[tex]E=\frac{\rho}{e_0}[/tex]

[tex]E=\frac{5.10*10^{-9}}{8.85x10{-12}}[/tex]

[tex]E=576.5V/m[/tex]

A 8.37*10^-5 F capacitor has 2.15*10^-4 C of charge on its plates. How much energy is stored on the capacitor

Answers

Answer:

2.76*10^-4

Explanation:

Trust me :)

What are the messing forces that would make the object be in equilibrium?

Answers

Answer:

A) 20 N, B) 20 N, & C) 8 N

Explanation:

For the object to be in equilibrium, the upward forces must be equal to the downward forces and the forward forces must be equal to the backward forces.

1. Determination of A and B.

Forward forces = Backward forces

A + 10 + B = 25 + 25

A + 10 + B = 50

Collect like terms

A + B = 50 – 10

A + B = 40

Assume A and B to be equal. Thus, A is 20 N and B is 20 N.

2. Determination of C

Upward forces = Downward forces

C + 112 = 20 + 100

C + 112 = 120

Collect like terms

C = 120 – 112

C = 8 N

Thus, for the object to be in equilibrium, A must be 20 N, B must be 20 N and C must be 8N.

What is the equivalent resistance of a circuit that contains two 50.0 0
resistors connected in series to a 12.0V battery?

Answers

Answer:

the correct answer is A :)

What is the friction force on a box that has a mass of 15kg as it slides across the floor. The coefficient of friction of the not very clean floor is 0.25
please explain everything including formula used ​

Answers

Answer:

36.75 N

Explanation:

Applying

F = mgμ................. Equation 1

Where F = Friction force on the box, m = mass of the box, g = acceleration due to gravity of the box, μ = coefficient of static friction

From the question,

Given: m = 15 kg, μ = 0.25

Constant: g = 9.8 m/s²

Substitute these values into equation 1

F = 15(9.8)(0.25)

F = 36.75 N

Hence the friction force on the box is 36.75 N

A hoop rolls with constant velocity and without sliding along level ground. Its rotational kinetic energy is:______a- half its translational kinetic energyb- the same as its translational kinetic energyc- twice its translational kinetic energyd- four times its translational kinetic energy

Answers

Answer:

The same as its translational KE.

The easy way to do this is to make up numbers and use them.

So, I'll say m=2 and r=3. I will also say v=3 .

Rot. Inertia of a hoop is mr^2. So the rot KE is: 1/2 (mr^2)(w^2)

note: (1/2*I*w^2)

Translational kinetic energy is basically normal KE, so 1/2(m)(v^2)

Now, lets plug our made up values in:

Rot Ke : 1/2 (9*2)(3/3) *note w = v/r

Tran Ke: 1/2(2)(9)

Rot Ke: 9

Tran Ke: 9

9=9, same.

Find the ratio of the diameter of copper to iron wire, if they have the same resistance per unit length (as they might in household wiring). dCu dFe =

Answers

Answer:

The ratio of diameter of copper wire to the iron wire is 0.42.

Explanation:

length of both the wires is same as L and resistance is R.

resistivity of copper = 1.7 x 10^-8 ohm m

resistivity of iron = 9.7 x 10^-8 ohm m

Let the diameter of copper is d and for iron is d'.

The formula of the resistance is

[tex]R = \rho\times\frac{L}{A}\\\\R = \rho\times\frac{4L}{\pi d^2}.... (1)\\And\\ R = \rho'\times\frac{4L}{\pi d'^2}.... (2)\\\\comparing (1) by (2)\\\\1.7\times10^{-8}\times\frac{4L}{\pi d^2}=9.7\times10^{-8}\times\frac{4L}{\pi d'^2}\\\\d : d' = 0.42[/tex]

instrument used in measurement Amount of substance

Answers

Answer:

For liquids: A measuring cylinder is used.

For solid: Over flow can is used

Answer:

i think a measuring cylinder

Sunsets are a deep red because A) tiny particles in the air are more efficient at scattering short wavelength light than they are at scattering long wavelength light. Hence, long wavelength light ends up coming directly towards you. B) most polluting gases and dust particles in the air are reddish in color and lend their color to that of the sky. C) air molecules absorb red light more efficiently than they do blue light because of their electron orbitals. D) air molecules absorb blue light more efficiently than they do red light because of their electron orbitals.

Answers

Answer:

i think its A

Answer:tiny particles in the air are more efficient at scattering short wavelength light than they are at scattering long

Explanation:

An empty 12,954 kg railroad car, traveling at a speed of 28 m/s strikes a partially filled 17,616 kg railroad car moving in the same direction at a speed of 5 m/s. What is the total momentum of the two railroad cars AFTER the collision?

Answers

Answer:

450792 kgm/s

Explanation:

by conservation of momentum,

total momentum AFTER collision = total momentum BEFORE collision

                                                       =mv+m'v'

                                                       =12954×28+17616×5

                                                       =450792 kgm/s

A block of mass m is moved over a distance d. An applied force F is directed perpendicularly to the block’s displacement. How much work is done on the block by the force F?​

Answers

zero

Explanation:

Work W is defined as

W = Fd = Fdcos(theta)

and it is a dot product of the force and displacement and theta is angle between F and d Since the force is perpendicular to d, angle is 90° thus cos90 = 0. Hence work is zero.

A train moves with a uniform velocity of 36km/hr 10sec. calculate the distance travelled​

Answers

Given:-

Speed = 36 km/hr

converting speed into m/s

Speed = 36*5/18

Speed = 10 m/s

t = 10 sec  

By using the Formula

Distance = Speed * time

D = 10*10

D = 100 m

Hope it helps....

1. Convert the following length into meters
a. 123.50mm
b. 560cm
c. 100dm
d. 125.89km​

Answers

I don’t really know this either

if p=2i+4j+3k and q=I+5j-2k,find P×q.

Answers

Answer:

[tex]p\times q=-23i+7j+6k[/tex]

Explanation:

We are given that

p=2i+4j+3k

q=i+5j-2k

We have to find pxq

We know that

[tex]p\times q=\begin{vmatrix}  i&j  &k\\  2&4  & 3\\  1& 5 & -2\end{vmatrix}[/tex]

[tex]p\times q=i(-8-15)-j(-4-3)+k(10-4)[/tex]

[tex]p\times q=-23i+7j+6k[/tex]

Hence,[tex]p\times q=-23i+7j+6k[/tex]

a. A horse pulls a cart along a flat road. Consider the following four forces that arise in this situation.

1. the force of the horse pulling on the cart
2. the force of the cart pulling on the horse
3. the force of the horse pushing on the road
4. the force of the road pushing on the horse

b. Suppose that the horse and cart have started from rest; and as time goes on, their speed increases in the same direction. Which one of the following conclusions is correct concerning the magnitudes of the forces mentioned above?

1. Force 1 exceeds Force 2.
2. Force 2 is less than Force 3.
3. Force 2 exceeds Force 4.
4. Force 3 exceeds Force 4.
5. Forces 1 and 2 cannot have equal magnitudes.

Answers

Answer:

a) F₁ = F₂,  F₃ = F₄,  b)  the correct answer is 3

Explanation:

a) In this exercise we have several action and reaction forces, which are characterized by having the same magnitude, but different direction and being applied to different bodies

Forces 1 and 2 are action and reaction forces F₁ = F₂

Forces 3 and 4 are action and reaction forces F₃ = F₄

as it indicates that the

b) how the car increases if speed implies that force 1> force3

      F₁ > F₃

therefore the correct answer is 3

Which of the following elements has the largest atomic radius?
Silicon
Aluminum
Sulfur
Phosphorous

Answers

aluminum has the largest atomic radius

Answer:

francium

Atomic radii vary in a predictable way across the periodic table. As can be seen in the figures below, the atomic radius increases from top to bottom in a group, and decreases from left to right across a period. Thus, helium is the smallest element, and francium is the largest.

The cycle is a process that returns to its beginning, but it does not repeat
itself.
True
False

Answers

False. It does repeat itself


During the fission reaction shown, how did the target nucleus change ?

Answers

Answer:

A. The target nucleus split into two nuclei, each with fewer nucleons than the original.

Explanation:

Answer: A. The target nucleus split into two nuclei, each with fewer nucleons than the original.

Explanation:

What is energy?
Select one:

A force that must be exerted in order to accelerate an object.

A property that must be transferred to perform work.

A particle that can be absorbed to change momentum.

A system that can be rearranged in order to change its state.

Answers

Answer:

Energy is:

A property that must be transferred to perform work.

Answer:

Energy

Explanation:

A property that must be transferred to perform work .

Hope it is helpful to you Stay safe healthy and happy ☺️

A surfactant with a Hydrophile-
Lipophile Balance (HLB) value of 18 is expected to function as a solubilizing agent
O False
O True​

Answers

Answer:

Explanation:

True

The Best answer from the options is TRUE

A surfactant with a Hydrophile-lipophile Balance value of 18 is a solubilizing agent because a hydrophilic-lipophilic balance is used to measure the degree /level of hydrophilicness or liphophilicness of a Surfactant is at . and the

method used by the Hydrophile-lipophile balance to achieve this is by calculating the values for the different regions of the surfactant.

Hence a Surfactant with a hydrophile-lipophile Balance value of 18 is expected to function as a solubilizing agent.

Attached below is the HLB

Learn more : https://brainly.com/question/11338364

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