what line will most likely have a slope of 10

Step-by-step explanation:

There was originally 8 pieces of pie.

Answer:

if you have 3/8 of one pie, the denominator tells you that the pie was divided into 8 piece.

Answer:

What function?

Step-by-step explanation:

Answer:

Here's your answer .

hope it helps you

Answer:

the car travels 10km then 15km 60* north of east

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

x + 2 < -5

x < - 5 - 2

x < - 7

Answer:

{x| x R, x<-7}

Step-by-step explanation:

=> x+2<-5

=> x<-5-2

=> x<-7

9514 1404 393

Answer:

  $180

Step-by-step explanation:

The relationship between the prices is said to be ...

  (amount you pay) = 2/3 × (original price)

To find the original price, multiply the equation by the reciprocal of the coefficient of the (original price).

  (3/2)×(amount you pay) = (3/2)(2/3)(original price) = (original price)

  (3/2)×$120 = original price = $180

Answer:

95°Fahrenheit

hipe this helps you

Answer:

( x - 3.5)² - 29/4

Step-by-step explanation:

Given :-

Writing in ( x - a)² - b form ,

Answer:

8^2+12x

Step-by-step explanation:

4x(2x+3)

=4x times 2x+4x times 3

=4 times 2xx+4 times 3x

Answer:

8x^2 +12x

Step-by-step explanation:

Step 1) Multiply each term in the parentheses by 4x

4xx2x+4xx3

Step 2) Calcuate the product

8x^2 +12x

Answer:

sorting;

greatest = 2,700

least = 2,250

HAVE A NİCE DAY

Step-by-step explanation:

GREETINGS FROM TURKEY ツ

Step-by-step explanation:

2x+60°= 110°

2x= 110-60

2x= 50

x= 25°

Answer:

Step-by-step explanation:

The equation in slope-intercept form:  y = mx + b

y + 2 = -2(x - 5)

y + 2 = -2x + 10              {subtract 2 from both sides

y = -2x + 8

9514 1404 393

Answer:

  517 minutes

Step-by-step explanation:

There are 60 minutes in an hour, so 8×60 = 480 minutes in 8 hours.

In 8 hours 37 minutes, there are ...

  480 min + 37 min = 517 minutes

Answer:

13

Step-by-step explanation:

1. Round 19.625 up to 20.

2. Round 6.77 up to 7.

3. Calculate the equation. Ans is 13.

Answer:

A. (4,4.5)

Step-by-step explanation:

Midpoint={x1+x2/2,y1+y2/2}

M={4+4/2,1+8/2}

M={8/2,9/2}

M={4,4.5}

Answer: 0.108

Step-by-step explanation:

Since the probability of the uninsured is 21.6% of the population, then the probability of insured will be:

= 1 - 21.6%

= 78.4%

The probability of high cost patients is 5%. Therefore, the probability that a patient in a Texas healthcare facility will be a high cost patient who is uninsured will be:

= 5% × 21.6%

= 0.05 × 0.216

= 0.108

Recall that variation of parameters is used to solve second-order ODEs of the form

y''(t) + p(t) y'(t) + q(t) y(t) = f(t)

so the first thing you need to do is divide both sides of your equation by t :

y'' + (2t - 1)/t y' - 2/t y = 7t

You're looking for a solution of the form

[tex]y=y_1u_1+y_2u_2[/tex]

where

[tex]u_1(t)=\displaystyle-\int\frac{y_2(t)f(t)}{W(y_1,y_2)}\,\mathrm dt[/tex]

[tex]u_2(t)=\displaystyle\int\frac{y_1(t)f(t)}{W(y_1,y_2)}\,\mathrm dt[/tex]

and W denotes the Wronskian determinant.

Compute the Wronskian:

[tex]W(y_1,y_2) = W\left(2t-1,e^{-2t}\right) = \begin{vmatrix}2t-1&e^{-2t}\\2&-2e^{-2t}\end{vmatrix} = -4te^{-2t}[/tex]

Then

[tex]u_1=\displaystyle-\int\frac{7te^{-2t}}{-4te^{-2t}}\,\mathrm dt=\frac74\int\mathrm dt = \frac74t[/tex]

[tex]u_2=\displaystyle\int\frac{7t(2t-1)}{-4te^{-2t}}\,\mathrm dt=-\frac74\int(2t-1)e^{2t}\,\mathrm dt=-\frac74(t-1)e^{2t}[/tex]

The general solution to the ODE is

[tex]y = C_1(2t-1) + C_2e^{-2t} + \dfrac74t(2t-1) - \dfrac74(t-1)e^{2t}e^{-2t}[/tex]

which simplifies somewhat to

[tex]\boxed{y = C_1(2t-1) + C_2e^{-2t} + \dfrac74(2t^2-2t+1)}[/tex]

Answer:

56600 cars

Step-by-step explanation:

Below is the calculation of number of cars produced.

The percentage of cars that is defected = 3%

Number of cars that are defective = 1698 cars

The number of cars produced in a year = 1698 / 3%  

The number of cars produced in a year = 56600 cars

Answer:

none of these

Step-by-step explanation:

The null hypothesis is [tex]\mu = 39.09[/tex]  

The symbol [tex]\mu[/tex] is the Greek letter mu

The alternate hypothesis is [tex]\mu \ne 39.09[/tex] telling us we have a two-tailed test here. The "not equal" is directly tied to the keyword "different" given in the instructions. In other words, mu being different from 39.09 directly leads to [tex]\mu \ne 39.09[/tex]

So either mu is 39.09 or it's not 39.09

You can use H0 and H1 to represent the null and alternate hypotheses respectively.  

----------------------

Summary:

The two hypotheses are

H0: [tex]\mu = 39.09[/tex]

H1: [tex]\mu \ne 39.09[/tex]

This is a two tailed test.

Answer:

6x + y

Step-by-step explanation:

6x + 3y/3​

6x + y

Answer:

6x + y

Step-by-step explanation:

6x + 3y / 3

cancel 3y by 3

6x + y

Answers:

=============================================

Explanation:

The angle theta is between pi and 3pi/2, excluding both endpoints.

This places theta in the third quadrant (Q3) between 180 degrees and 270 degrees. The third quadrant is in the southwest.

Plot point A at the origin. 12 units to the left of this point, will be point B. So B is at (-12,0). Then five units lower is point C at (-12,-5). Refer to the diagram below. Notice how triangle ABC is a right triangle.

The angle theta will be the angle BAC, or simply angle A.

Since cos(theta) = -12/13, this indicates that

AB = -12 = adjacent

AC = 13 = hypotenuse

Technically, AB is should be positive, but I'm making it negative so that we can then say

cos(angle) = adjacent/hypotenuse

cos(theta) = AB/AC

cos(theta) = -12/13

------------------

If you apply the pythagorean theorem, you should find that BC = 5, which I'll  make negative since we're below the x axis. Then we can say

sin(theta) = opposite/hypotenuse

sin(theta) = BC/AC

sin(theta) = -5/13

------------------

If you divide sine over cosine, then you'll get 5/12. The 13's cancel out. This is the value of tangent.

Or you could say

tan(theta) = opposite/adjacent

tan(theta) = BC/AB

tan(theta) = (-5)/(-12)

tan(theta) = 5/12

------------------

To find csc, aka cosecant, you apply the reciprocal to sine

sin = -5/13 which means csc = -13/5

sec, or secant, is the reciprocal of cosine

cos = -12/13 leads to sec = -13/12

and finally cotangent (cot) is the reciprocal of tangent

tan = 5/12 leads to cot = 12/5

------------------

Note: everything but tan and cot is negative in Q3.

Answer:

a. A linear pattern exists in the data.

b. The parameters for the line that minimizes MSE for this time series are as folows:

ß1 = Estimated slope = 1.4567

ß0 = Estimated intercept = 4.7165

Also, we have:

MSE = Mean squared error = 0.4896

c. Forecast for year 10 is 19,280.

Step-by-step explanation:

a. What type of pattern exists in the data?

Note: See Sheet1 of the attached excel file for the line graph.

From the line graph, it can be observed that a linear pattern exists in the data.

b. Use simple linear regression analysis to find the parameters for the line that minimizes MSE for this time series.

Note: See Sheet2 of the attached excel file for all the calculations to obtain the following:

Sample size = 9

Total of X = 45

Total of Y = 108

Mean of X = Total of X / Sample size = 45 / 9 = 5

Mean of Y = Total of X / Sample size = 108 / 9 = 12

SSxx = Total of (X - Mean of X)^2 = 60

SSyy = Total of (Y - Mean of Y)^2 = 130.74

SSxy = Total of (X - Mean of X) * (Y - Mean of Y) = 87.40

Therefore, we have:                

ß1 = Estimated slope = SSxy/SSxx = 87.4 / 60  = 1.4567

ß0 = Estimated intercept = Mean of Y – (ß1 * Mean of X) = 12 - (5 * 1.4567) = 4.7165

Therefore, the parameters for the line that minimizes MSE for this time series are as folows:

ß1 = Estimated slope = 1.4567

ß0 = Estimated intercept = 4.7165

Regression equation which also used in the attached excel is as follows:

Y = ß0 + ß1X =

Y = 4.7165 + 1.4567X …………………. (1)

SSE = Sum of squared error = Total of (Y - Y*)^2 = 3.4273

Therefore, we have:

MSE = Mean squared error = (SSE/(n-2)) = (3.4273 / (9 - 2)) = 0.4896

c. What is the forecast for year 10?

This implies that X = 10

Substitute X = 10 into equation (1), we have:

Y = 4.7165 + (1.4567 * 10) = 19.28

Since it is 1,000s, we have:

Y = 19.28 * 1,000 = 19,280

Therefore, forecast for year 10 is 19,280.

Answer:

Class interval ____, Frequency _ C/frequency

1 - 10 ____________ 1 _________ 1

11 - 20 ___________ 4 _________ 5

20 - 30 __________ 6 _________ 11

31 - 40 ___________3 _________ 14

41 - 50 ___________ 1 _________ 15

51 - 60 ___________ 1 _________ 16

Step-by-step explanation:

Given the data :

35, 26, 31, 17, 46, 30, 28, 21, 26, 34, 15, 27, 7, 18, 16, 57

Class interval ____, Frequency _ C/frequency

1 - 10 ____________ 1 _________ 1

11 - 20 ___________ 4 _________ 5

20 - 30 __________ 6 _________ 11

31 - 40 ___________3 _________ 14

41 - 50 ___________ 1 _________ 15

51 - 60 ___________ 1 _________ 16

The next to highest frequency group has a frequency of 4 and the highest frequency of 6

Total frequency, n = (1 + 4 + 6 + 3 + 1 + 1) = 16

Answer:

The original graph was shifted 2 units to the left and 5 units down.

Step-by-step explanation:

y = |x|

From this, we go to: y = |x - 2|.

When we want to shift a function f(x) a units to the left, we find f(x - a). So first, the graph was shifted 2 units to the left.

y = |x - 2|.

From this, we go to: y = |x - 2| - 5.

Shifting a function f(x) down b units is the same as finding f(x) - b, so the second transformation was shifting the graph 5 units down.

Answer:

The rate at which the distance between the cars increasing two hours later=52mi/h

Step-by-step explanation:

Let

Speed of one car, x'=48 mi/h

Speed of other car, y'=20 mi/h

We have to find the rate at which the distance between the cars increasing two hours later.

After 2 hours,

Distance traveled by one car

[tex]x=48\times 2=96 mi[/tex]

Using the formula

[tex]Distance=Time\times speed[/tex]

Distance traveled by other car

[tex]y=20\times 2=40 mi[/tex]

Let z be the distance between two cars after 2 hours later

[tex]z=\sqrt{x^2+y^2}[/tex]

Substitute the values

[tex]z=\sqrt{(96)^2+(40)^2}[/tex]

z=104 mi

Now,

[tex]z^2=x^2+y^2[/tex]

Differentiate w.r.t t

[tex]2z\frac{dz}{dt}=2x\frac{dx}{dt}+2y\frac{dy}{dt}[/tex]

[tex]z\frac{dz}{dt}=x\frac{dx}{dt}+y\frac{dy}{dt}[/tex]

Substitute the values

[tex]104\frac{dz}{dt}=96\times 48+40\times 20[/tex]

[tex]\frac{dz}{dt}=\frac{96\times 48+40\times 20}{104}[/tex]

[tex]\frac{dz}{dt}=52mi/h[/tex]

Hence, the rate at which the distance between the cars increasing two hours later=52mi/h

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Answer:

  b. No; the domain values are not at regular intervals although the range values have a common factor.

Step-by-step explanation:

The differences between x-values are ...

  -1, -1, -1, -2 . . . . not a constant difference

The ratios of y-values are ...

  2/8 = 0.5/2 = 0.125/0.5 = 0.25 . . . . a constant difference

The fact that the domain values do not have a common difference renders the common factor of the range values irrelevant. The relation is not exponential.