What kind of magma produce the most violent eruptions

Answers

Answer 1

Answer:

Explosive eruptions from Composite or strato volcano

Explanation:

since they have multiple holes of exit, they can get pretty explosive.


Related Questions

Which of the following colors has the highest energy? O A. Red O B. Green O C. Blue O D. Yellow​

Answers

Answer:

C. Blue

Explanation:

This is because, Blue color highest frequency of energy after Violet and Indigo.

A recipe calls for 1/4 cup of butter. One ounce (oz) of butter is equivalent to 2 tablespoons (T), and there are 8 oz of butter in 1 cup. Which of the following statements correctly interpret the information provided?

a. The information provided gives the conversion factor 8oz/2T.
b. The information provided gives the conversion factor 8oz/1 cup.
c. The recipe requires 64 T of butter.
d. The recipe requires 4T of butter.

Answers

Answer:

D

Explanation:

8oz=1cup

Xoz=1/4cup

cross multiply

Xoz=8×1/4=2

2oz=1/4cup

1oz=2T

2oz=x

cross multiply

×=2×2=4T

The cup of butter, number of tablespoons and ounces of butter are all in direct proportion with one another. The interpretation of the information provided is:

(b). The information provided gives the conversion factor 8oz/1 cup.

Given that:

[tex]1\ recipe = \frac{1}{4}\ cup[/tex]

[tex]1\ oz = 2T[/tex]

[tex]8\ oz = 1\ cup[/tex]

Multiply both sides of [tex]1\ oz = 2T[/tex] by 8

[tex]8 \times 1oz = 8 \times 2T[/tex]

[tex]8 oz = 16T[/tex]

Substitute 8oz for 1 cup in: [tex]1\ recipe = \frac{1}{4}\ cup[/tex]

[tex]1\ recipe = \frac{1}{4} \times 8oz[/tex]

Substitute [tex]8 oz = 16T[/tex]

[tex]1\ recipe = \frac{1}{4} \times 16T[/tex]

[tex]1\ recipe = 4T[/tex]

The interpretations are as follows:

[tex]1\ recipe = 4T[/tex] means that 1 recipe requires 4T of butter [tex]8\ oz = 1\ cup[/tex] means that the information provided gives a conversion of 8oz/1 cup

Hence, (b) is correct

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Write briefly on carbohydrates

Answers

Answer:

carbohydrates are simple sugars which can be broken down to form 3 sugars.

which are , (maltose) (fructose) & (glucose)

When H2S(g) reacts with O2(g) to form H2O(g) and SO2(g), 124 kcal of energy are evolved for each mole of H2S(g) that reacts. Write a balanced equation for the reaction with an energy term in kcal as part of the equation.

Answers

Answer:

2H2S(g) + 3O2(g) → 2H2O(g) + 2SO2(g) + 248kcal

Explanation:

The reaction of the problem occurs as follows:

H2S(g) + O2(g) → H2O(g) + SO2(g)

To balance the reaction we must balance oxygens:

H2S(g) + 3O2(g) → 2H2O(g) + 2SO2(g)

To balance the complete reaction:

2H2S(g) + 3O2(g) → 2H2O(g) + 2SO2(g)

As the energy is evolved, 124kcal are as product in the reactio per mole of H2S. As the balanced reaction contains 2 moles of H2S, the heat evolved is:

124kcal*2 = 248kcal:

2H2S(g) + 3O2(g) → 2H2O(g) + 2SO2(g) + 248kcal

And this is the balanced equation

I am holding a balloon containing 439 mL of gas over my fireplace. The temperature and pressure of the gas inside the balloon is 317.15 K and 0.959 atm, respectively. Suppose I don't want the pressure to change, but I want to the volume to go down to 0.378 L. What is the temperature that I need to reach when I cool down the balloon?


To what temperature (in Celsius) must the balloon be cooled to reduce its volume to 0.378 L if the pressure doesn't change (remained constant)?

Answers

Answer:

-0.08 °C

Explanation:

We can solve this problem by using Charles' law, which states that at constant pressure:

V₁T₂ = V₂T₁

Where in this case:

V₁ = 439 mLT₂ = ?V₂ = 0.378 L ⇒ 0.378 * 1000 = 378 mLT₁ = 317.15 K

We input the data:

439 mL * T₂ = 378 mL * 317.15 K

And solve for T₂:

T₂ = 273.08 K

Finally we convert 273.08 K to Celsius:

273.08 K - 273.16 = -0.08 °C

Which of these increases the friction of someone walking on the floor?

Answers

Answer:

.This is because gravity pulls down harder on the heavier one, which increases its friction with the floor

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After mixing the solutions in a separatory funnel, the stopper should be ______ and the liquid should be _______ and the layers allowed to separate. When you get close to the interface between the layers, ______ the funnel and turn over _______ heat up until the first layer is collected get eye level with to collect the second layer. _______

Answers

Answer:

Hence,  

1) removed  

2) drained through the stopcock  

3) get eye level with  

4) slow the draining  

5) switch to a new flask

Explanation:

After mixing the solutions in a separatory funnel, the stopper should be removed and the liquid should be drained through the stopcock, and the layers allowed to separate. When you get close to the interface between the layers, get eye level with the funnel and turn over to slow the draining heat up until the first layer is collected. Switch to a new flask get eye level with it to collect the second layer.

A student is adding DI water to a volumetric flask to make a 50% solution. Unfortunately, he was not paying attention and filled the flask past the calibration mark. Instead of starting over, the student decides to continue with the experiment. How will the student's results be affected by his mistakes

Answers

Answer:

His results will be skewed because there was more water than stock solution. Which would cause the percentage solution to be less than 50% therefore the density would be less than the actual value.

Explanation:

The solution will have percentage less than that of 50%. Therefore the density would be less than the actual value.

Suppose there should be 50 mL of the solution, and he added 60 mL. So 10 mL of the solution is added more.

Suppose the mass of the solute is m.

Originally, the density is = [tex]$\frac{m}{50}$[/tex]     [tex]\left(\frac{\text{mass}}{\text{volume}}\right)[/tex]

Now after adding extra 10 mL , the density becomes [tex]$\frac{m}{60}$[/tex].

Therefore, [tex]$\frac{m}{50}>\frac{m}{60}$[/tex]

So the density decreases when we add more solution.

Name the following ketone:
여 o
A. cyclohexyne
B. cyclohexanal
C. cyclohexanol
D. cyclohexanone

Answers

a. cyclohexyne is the answer

Answer:

It is D).cyclohexanone ( in acellus)

Explanation:

4. After reaching the final titration endpoint the solution will be cloudy white. As time goes on the solution will turn back to a cloudy dark purple color. Why does this occur if you have already reached the endpoint

Answers

Answer: hello some part of your question is missing below is the missing part

In an experiment to determine the % of ascorbic acid in Vitamin C Tablets by Titration with Potassium Bromate,

answer:

Oxidation half reaction of Vitamin C

Explanation:

The solution will turn cloudy dark purple even after reaching endpoint when allowed to settle with time. because of the Oxidation half reaction of Vitamin C. also during the Titration process few drops of starch solution will be added to help determine the endpoint of the experiment .

Give the balanced equation for the neutralisation of the excess NaOH with HCI.​

Answers

1 NaCl + 1 HCl ➡️ 1 NaCl + Water (H2O) .

CAN SOMEONE PLEASE HELP ME I WILL MARK YOU AS BRAINLIEST

Answers

Explanation:

[tex]2H_2O_2 \rightarrow 2H_2O + O_2[/tex]

First convert the amount of water into moles:

360 g H2O × [tex]\left(\dfrac{1\:\text{mol}H_2O}{18.015\:\text{g}H_2O}\right)[/tex]

[tex] = 20. \:\text{mol}H_2O[/tex]

Now let's calculate the number of moles of O2 gas produced.

20 mol H2O × [tex]\left(\dfrac{1\:\text{mol}O_2}{2\:\text{mol}H_2O}\right)=10\:\text{mol}O_2[/tex]

The volume of gas at 10°C and 5 atm can be found using the ideal gas law:

[tex]PV=nRT[/tex]

[tex]V= \dfrac{nRT}{P}[/tex]

[tex]= \dfrac{(10)(0.082)(283)}{(5)}=46.4\:L[/tex]

Anew fictitious element was discovered. It is a metal named jolmium, J,and it has three valence electrons. If it combineswith iodine it forms jolmium iodide. Answer the following questions.a.Is this compound ionic or covalent

a. Is this compound ionic or covalent?
b. What is the formula of Jolmium iodide?
c. What is the charge on the metal J in this compound?
d. Explain how you know that is the charge?

Answers

Answer:

A new fictitious element was discovered.

It is a metal named jolmium, J, and it has three valence electrons.

If it combines with iodine it forms jolmium iodide. Answer the following questions.

a.Is this compound ionic or covalent

b. What is the formula of Jolmium iodide?

c. What is the charge on the metal J in this compound?

d. Explain how you know that is the charge?

Explanation:

It is given the element jolmium J is a metal with three valence electrons.

Since metals are highly electropositive, they lose electrons easily and form cations (Ions with a positive charge).

[tex]J^{3+}[/tex] ion will be formed.

b) The formula of jolmium iodide is shown below:

[tex]J^{+3} I^{-1}\\The formula becomes:\\JI_{3}[/tex]

a) The compound is ionic in nature.

Since the compound formed between a metal atom and a nonmetal atom will take place by transfer of electrons.

Hence, it is ionic in nature.

c) The charge on the metal J in this compound is +3.

d) Given J has three valence electrons.

That means it can lose three electrons to form a bond.

So, its valency is three.

According to the equation 2K(s) + CI2(g) 2kCI(s), potassium reacts with chlorine to form potassium chlorine. If 100 atoms of potassium react with chlorine gas, how many chlorine molecules will be needed to completely react?

Answers

Answer:

50 CI₂ molecules

Explanation:

2K(s) + CI₂(g) → 2KCI(s)

By looking at the stoichiometric coefficients, we can tell that if 2 atoms of potassium (K) react with chlorine gas (CI₂), 1 chlorine molecule would react.

With that in mind we can calculate how many CI₂ molecules would react with 100 K atoms:

100 atoms K *[tex]\frac{1Cl_2Molecule}{2KAtom}[/tex] = 50 CI₂ molecules

convert 12nanometer to centimeter

Answers

Answer:

1x10^-6

Explanation:

Ch3-ch2-o-ch2-ch2-och3

Answers

Explanation:

ethoxypropane

Ch3-ch2-o-ch2-ch2-och3

What mass of hydrochloric acid that reacted with zinc will produced 0.15dm3 of hydrogen at st.p? Equation for this reaction:
Zn + 2HCl ------> ZnCl2 + H2​

Answers

Answer:

[tex]{ \tt{22.4 \: dm {}^{3} \: contains \: 1 \: mole \: of \: hydrogen }} \\ { \tt{0.15 \: {dm}^{3} \: will \: contain \: ( \frac{0.15}{22.4} \times 1) \: moles }} \\ = 0.0067 \: moles \\ { \bf{mole \: ratio = 1 :1 }} \\ { \tt{1 \: mole \: weighs \: 65.38 \: g}} \\ { \tt{0.0067 \: moles \: weighs \: (0.0067 \times 65.38) \: g}} \\ = 0.44 \: g[/tex]

What is the pH of a solution with a 7.8 × 10−13 M hydronium ion concentration?

A) 1.9
B) 2.8
C) 11
D) 12

Answers

Answer:

12

Explanation:

The pH of a solution can be found by using the formula

[tex]pH = - log [ { H_3O}^{+}][/tex]

From the question we have

[tex]ph = - log(7.8 \times {10}^{ - 13} ) \\ = 12.1079...[/tex]

We have the final answer as

12

Hope this helps you

The pH of this solution with a 7.8 × 10⁻¹³ M concentration of hydronium ion is equal to: D. 12.

Given the following data:

Concentration of hydronium ion = 7.8 × 10⁻¹³ M.

What is pH?

pH is literally the power of hydrogen ions and it can be defined as a measure of the molar concentration of hydrogen ions in a given solution.

How to calculate the pH of a solution?

We would determine the pH of this solution by using this formula;

pH = -log[H⁺]

pH = -log(7.8 × 10⁻¹³).

pH = -(-12.1)

pH = 12.1 12.

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An ideal gas is made up of gas particles that...
(A) ...have volume.
(B) ... attract each other.
(C)...can be liquified.
(D) ... are in random motion.

Answers

Answer:

Its D Are in random motion

i hope it will help you if not soo sorry :)

Stomach acid is approximately 0.10 M HCl. How many mL of stomach acid can be neutralized by one regular antacid tablet that contains 500 mg of solid CaCO3 (100.09 g/mol)?

Answers

Answer:

100 mL

Explanation:

The reaction that takes place is:

CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

First we convert 500 mg of CaCO₃ into mmoles, using its molar mass:

500 mg ÷ 100 mg/mmol = 5 mmol CaCO₃

Then we convert 5 mmoles of CaCO₃ into HCl mmoles, using the stoichiometric coefficients of the balanced reaction:

5 mmol CaCO₃ * [tex]\frac{2mmolHCl}{1mmolCaCO_3}[/tex] = 10 mmol HCl

Finally we calculate the volume of a 0.10 M HCl solution (such as stomach acid) that would contain 10 mmoles:

10 mmol / 0.10 M = 100 mL

the total pressure in a mixture of gases is equal to the partial pressures of

Answers

Answer:

"The total pressure in a mixture of gases is equal to the sum of partial pressures of each gas"

Explanation:

Dalton's law of partial pressures state that, in a mixture of gases, the total pressure is equal to the sum of the partial pressure exerted by each gas of the mixture. The equation is:

Total pressure = Partial pressure Gas 1 + Partial pressure Gas 2 + .... + Partial pressure Gas n

To complete the sentence we can say:

"The total pressure in a mixture of gases is equal to the sum of partial pressures of each gas"

Considering the Dalton's partial pressure, the total pressure in a mixture of gases is equal to the sum of partial pressures of each gas.

The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

[tex]P_{T} =P_{A} +P_{B}[/tex]

This relationship is due to the assumption that there are no attractive forces between the gases.

Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture. The mole fraction is a dimensionless quantity that expresses the ratio of the number of moles of a component to the number of moles of all the components present.

So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:

[tex]P_{A} =x_{A} P_{T}[/tex]

In summary, the total pressure in a mixture of gases is equal to the sum of partial pressures of each gas.

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Toothpastes containing sodium hydrogen carbonate (sodium bicarbonate) and hydrogen peroxide are widely used. Write Lewis structures for the hydrogen carbonate ion and hydrogen peroxide molecule, with resonance forms where appropriate.

Answers

Answer:

See explanation and images attached

Explanation:

The first image shows the structure of hydrogen peroxide. It does not exist as resonance structures. The structure and properties of the molecule can wholly be explained on the basis of a single Lewis structure.

However, the structure of the bicarbonate ion in sodium bicarbonate can not be completely described by a single Lewis structure. Hence, two resonance structures are shown for the bicarbonate ion. In each case, Na^+ is the counter ion.

Write a balanced equation for the combination reaction described, using the smallest possible integer coefficients. When methane (CH4) combines with carbon tetrachloride , dichloromethane (CH2Cl2) is formed.

Answers

Answer:

C H₄ + C Cl₄ = 2 (C H₂ Cl₂)

‎‎‎‎‎‎‎‎‎

What is the IUPAC name for this organic molecule?

Answers

Answer:

2–methylbutane

Explanation:

To name the compound given above, the following must be obtained:

1. Determine the longest continuous carbon chain. This gives the parent name of the compound.

2. Determine the substituent group attached.

3. Determine the position of the substituent group by giving it the lowest possible count..

4. Combine the above to obtain the name of the compound.

With the above information, we can name the compound as follow:

1. The longest continuous carbon chain of the compound is 4. Thus, the parent name is butane.

2. The substituent group attached to the compound is methyl (–CH₃).

3. The methyl (–CH₃) group is located at carbon 2 (i.e counting from the left side).

4. The name of the compound is:

2–methylbutane

complete and balanced the following equations by predicting the products of each reaction pair.
NA + LiCI -> _ + _

Answers

Explanation:

this is a single Replacement Reaction, so Na and Cl will form a bond.

Consider these two cases.
Case 1: An electron jumps from energy level 1 to energy level 2 in an atom.
Case 2: An electron jumps from energy level 1 to energy level 3 in an atom.
For case 1, what happens when an electron jumps from energy level 1 to energy level 3 in an atom?
A. A photon is absorbed by the atom.
B. A photon is emitted by the atom.
C. A proton is absorbed by the atom.
D. A proton is emitted by the atom.
Assuming that both cases describe Hydrogen-like atoms with one electron, for which case is more energy emitted or absorbed?
A. The energy is the same for both cases.
B. More energy is emitted or absorbed for case 2
C. It is impossible to tell.
D. More energy is emitted or absorbed for case 1

Answers

Answer:

A photon is absorbed by the atom.

More energy is emitted or absorbed for case 2

Explanation:

According to the Bohr model of the atom, electrons occur in energy levels. The energy of each level is fixed. However, electrons can absorb photons and move from a lower to higher energy level or emit photons and move from a higher to a lower energy level.

In each case, the energy absorbed or emitted is equal to the difference in energy between the two energy levels.

Since energy level 3 is much higher than energy level 2, the electron absorbs more energy in moving from energy level 1 to energy level 3 than it absorbs when moving from energy level 1 to energy level 2.

5-Analysis of a 12.04-g sample of a liquid compound composed of carbon, hydrogen, and nitrogen showed it to contain 7.34 g C, 1.85 g H, and 2.85 g N. What is the percent composition of this compound

Answers

Answer:

%C = 60.9%; %H = 15.4%; %N = 23.7%

Explanation:

Step 1: Given data

Mass of the sample (m): 12.04 gMass of Carbon (mC): 7.34 gMass of Hydrogen (mH): 1.85 gMass of Nitrogen (mN): 2.85 g

Step 2: Calculate the percent composition of this compound

To calculate the percent by mass of any element (E), we will use the following expression.

%E = mE/m × 100%

%C = 7.34 g/12.04 g × 100% = 60.9%

%H = 1.85 g/12.04 g × 100% = 15.4%

%N = 2.85 g/12.04 g × 100% = 23.7%

Give reason: The maximum covalence of boron is 4.​

Answers

Answer:

true

Explanation:

Answer:

true

Explanation:

Use the Conductivity interactive to identify each aqueous solution as a strong electrolyte, weak electrolyte, or nonelectrolyte. You are currently in a sorting module. Turn off browse mode or quick nav, Tab to items, Space or Enter to pick up, Tab to move, Space or Enter to drop.
Strong electrolyte Weak electrolyte Nonelectrolyte
NH3 NaCl HCI NaOH C12H22O

Answers

Explanation:

strong electrolyte- Nacl HCL NAOH

weak electrolyte- c12H22O, NH3

NaCl,HCl and NaOH  are strong electrolytes while ammonia is a weak electrolyte and sucrose is a non-electrolyte.

What are electrolytes?

It is a solution which consists of ions which are electrically conducting as a result of movement of ions.Class of electrolytes include most soluble salts,acids and bases which are dissolved in a polar solvent.On dissolution, they separate into the constituent ions.

There are 3 classes according to the nature of substance which results upon dissolution:

1) Strong electrolytes- Substances which on dissolution in a medium dissociate completely are strong electrolytes. eg: NaCl,HCl

2) Weak electrolytes-  Substances which on dissolution in a medium dissociate partially are weak electrolytes. eg: NH₃

3)Non-electrolytes- Substances which do not dissociate on dissolution are non-electrolytes. eg: sucrose

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A TLC plate showed 2 spots with Rf values of 0.25 and 0.26. The plate was removed from the developing chamber, the residual solvent was allowed to evaporate from the plate, and then the plate was returned to the developing chamber. What would you expect to see after the second development was complete

Answers

Answer:

See explanation

Explanation:

TLC is a chromatographic method in which the solute is spotted on a plate and the plate is placed in an air tight chamber containing a solvent. The solvent is maintained below the level of the spot. The capillary movement of the solvent through the plate achieves the required separation.

If two spots have Rf values of 0.25 and 0.26 respectively and then the plate was removed from the developing chamber, subsequently, the residual solvent was allowed to evaporate from the plate, and then the plate was returned to the developing chamber.

It will be observed after the second development is complete that the new Rf values will be 0.50 and 0.52 respectively. It will just be as though the second chromatogram picked up from where the first chromatogram stopped.

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