What is your hypothesis (or hypotheses) for this experiment? (Lab was on Newton’s first two laws of motion)

Vertical:

(20 m/s) sin(25º) ≈ 8.45 m/s

Horizontal:

(20 m/s) cos(25º) ≈ 18.1 m/s

The balanced equation for S(g) + O₂ → SO₂ is as follows: S₈ + 8O₂ → 8SO₂ (option C).

A balanced equation is a chemical equation in which the number of atoms of each element on both sides of the equation are the same.

This means that the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.

Balancing chemical equations involves the addition of stoichiometric coefficients to the reactants and products.

According to this question, sulfur reacts with oxygen gas to produce sulfur dioxide as follows:

S₈ + O₂ → SO₂

The balanced chemical equation is as follows:

S₈ + 8O₂ → 8SO₂

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Answer:

53.53 km/h

Explanation:

Given that the person drives for 30.0 min at 80.0 km/h, 12.0 min at 105 km/h, and 45.0 min at 40.0 km/h, and he spends 15.0 min eating lunch and buying gas.

So, the total time to complete the journey is

t=30+12+45+15=102 min

[tex]=\frac{102}{60}=1.7[/tex] hours

As distance=(speed)x(time), so

the distance covered in 30 minutes with a speed of 80 km/h

[tex]d_1=80 \times \frac{30}{60}=40[/tex] km.

The distance covered in 12 minutes with a speed of 105 km/h

[tex]d_2=105 \times \frac{12}{60}=21 km[/tex].

The distance covered in 45 minutes with a speed of 40 km/h

[tex]d_3=40 \times \frac{45}{60}=30 km[/tex].

So, to the total distance covered is

[tex]d=d_1+d_2+d_3[/tex]

[tex]=40+21+30=91 km[/tex]

As the average speed = (Total distance covered)/(Total time taken)

So, the average speed for the whole journey

[tex]=\frac{d}{t}[/tex]

[tex]=\frac{91}{1.7}= 53.53 km/h[/tex].

Hence, the average speed for the trip is 53.53 km/h.

Answer:

t = 0.55 s

Explanation:

Given that,

Height of the marble, h = 1.5 m

We need to find the time for which the marble is in air. Let the time is t. Using second equation of motion to find it as follows :

[tex]h=ut+\dfrac{1}{2}at^2[/tex]

Here, u = 0 and a = g

[tex]h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\cdot1.5}{9.8}}\\\\t=0.55\ s[/tex]

So, the marble is in air for 0.55 s. Hence, the correct option is (c).

Answer:

yes

Explanation:

cuz 15x2=30 30x2=60 60=1 hour, and the limited is 80 km per hour

15=25

15x4=60 25x4=100

so yes

he was going 100km per hour

Answer:Whenever an object experiences uniform circular motion there will always be a net force acting on the object pointing towards the center of the circular path. This net force has the special form  , and because it points in to the center of the circle, at right angles to the velocity, the force will change the direction of the velocity but not the magnitude.

It's useful to look at some examples to see how we deal with situations involving uniform circular motion.

Example 1 - Twirling an object tied to a rope in a horizontal circle. (Note that the object travels in a horizontal circle, but the rope itself is not horizontal). If the tension in the rope is 100 N, the object's mass is 3.7 kg, and the rope is 1.4 m long, what is the angle of the rope with respect to the horizontal, and what is the speed of the object?

As always, the place to start is with a free-body diagram, which just has two forces, the tension and the weight. It's simplest to choose a coordinate system that is horizontal and vertical, because the centripetal acceleration will be horizontal, and there is no vertical acceleration.

The tension, T, gets split into horizontal and vertical components. We don't know the angle, but that's OK because we can solve for it. Adding forces in the y direction gives:

This can be solved to get the angle:

In the x direction there's just the one force, the horizontal component of the tension, which we'll set equal to the mass times the centripetal acceleration:

We know mass and tension and the angle, but we have to be careful with r, because it is not simply the length of the rope. It is the horizontal component of the 1.4 m (let's call this L, for length), so there's a factor of the cosine coming in to the r as well.

Rearranging this to solve for the speed gives:

which gives a speed of v = 5.73 m/s.

Example 2 - Identical objects on a turntable, different distances from the center. Let's not worry about doing a full analysis with numbers; instead, let's draw the free-body diagram, and then see if we can understand why the outer objects get thrown off the turntable at a lower rotational speed than objects closer to the center.

In this case, the free-body diagram has three forces, the force of gravity, the normal force, and a frictional force. The friction here is static friction, because even though the objects are moving, they are not moving relative to the turntable. If there is no relative motion, you have static friction. The frictional force also points towards the center; the frictional force acts to oppose any relative motion, and the object has a tendency to go in a straight line which, relative to the turntable, would carry it away from the center. So, a static frictional force points in towards the center.

Summing forces in the y-direction tells us that the normal force is equal in magnitude to the weight. In the x-direction, the only force there is is the frictional force.

The maximum possible value of the static force of friction is

As the velocity increases, the frictional force has to increase to provide the necessary force required to keep the object spinning in a circle. If we continue to increase the rotation rate of the turntable, thereby increasing the speed of an object sitting on it, at some point the frictional force won't be large enough to keep the object traveling in a circle, and the object will move towards the outside of the turntable and fall off.

Why does this happen to the outer objects first? Because the speed they're going is proportional to the radius (v = circumference / period), so the frictional force necessary to keep an object spinning on the turntable ends up also being proportional to the radius. More force is needed for the outer objects at a given rotation rate, and they'll reach the maximum frictional force limit before the inner objects will.

Explanation:

Answer : 16 m/s east

Explanation: Trust the process!!

From the frame of reference of runner 1, the velocity of runner 2 will be D) 16 m/s east

The relative velocity is defined as the velocity of an object with respect to another observer

When two bodies are moving in opposite directions , relative velocity get added and if bodies are moving in same direction , relative velocity will get subtracted .

From the frame of reference of runner 1, the velocity of runner 2 will be

v (relative) = v1 + v1

v1 = velocity of runner 1  = 11m/s west

v2 = velocity of runner 2 = 5m/s

v = 11 + 5 = 16 m/s

correct answer will be O D. 16 m/s east as runner 2 is running in east direction

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Answer:

A. Cue, White Ball, Blue Ball

Explanation:

Visualize in which order things are being hit

Answer:

A toaster because you plug it up for electric energy and heat to toast it

[tex]\sf{m_1}[/tex] = 8kg

[tex]\sf{m_2}[/tex] = 4kg

g = 10m/s²

→Acceleration of block

→Tension in strings

Let, the two equation will be ,

[tex]\leadsto[/tex] 8g - T = 8a ..... Equation no (1)

[tex]\leadsto[/tex] T - 4g = 4a ..... Equation no (2)

Putting the value of equation no (1) and (2) we get,

[tex]\implies[/tex] 4g = 12a

[tex]\implies[/tex] 4 × 10 = 12a

[tex]\implies[/tex] 40 = 12a

[tex]\implies[/tex] a = [tex]\sf\dfrac{\cancel{40}}{\cancel{12}}[/tex]

[tex]\dashrightarrow[/tex] a = [tex]\dfrac{10}{3}[/tex]

Again, we have to putting the value of a in the equation no (2) we get,

[tex]\implies[/tex] T - 4g = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 4 × 10 = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 40 = [tex]\dfrac{40}{3}[/tex]

[tex]\implies[/tex] T = [tex]\dfrac{40}{3}[/tex] + 40

[tex]\implies[/tex] T = [tex]\dfrac{40 + 120}{3}[/tex]

[tex]\dashrightarrow[/tex] T = [tex]\dfrac{160}{3}[/tex] N

[tex]\therefore[/tex] Acceleration of block = [tex]\dfrac{10}{3}[/tex] m/s².

And, Tension in strings = [tex]\dfrac{160}{3}[/tex] N

Answer:law of interia(1st law)

Explanation:

Answer:

speed of rocket=615.38m/s

Explanation:

Answer:

(a) 5.62 m/s²

(b) 5.46 m/s²

Explanation:

The given values are:

mass,

m = 50 kg

angle

= 35°

(a)

If friction neglected,

⇒ [tex]F_x=mgSin \theta=ma[/tex]

⇒ [tex]a_x=gSin \theta[/tex]

       [tex]=9.8 \ Sin35^{\circ}[/tex]

       [tex]=5.62 \ m/s^2[/tex]

(b)

If friction present,

⇒ [tex]F_x=mgCos \theta[/tex]

⇒ [tex]F_x=mgSin \theta-\mu_r mgCos \theta[/tex]

⇒ [tex]a=gSin \theta-\mu_rgCos \theta[/tex]

      [tex]=9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}[/tex]

      [tex]=5.46 \ m/s^2[/tex]

Answer:

Explanation:

The speed of the car can be found by using the formula

where

a is the acceleration

v is the speed

t is the time

From the question we have

v = 10 × 25

We have the final answer as

Hope this helps you

Answer:

A E and F are the correct answers

Explanation:

Answer:

A E F are correct

Explanation:

Answer:

1000 N

Explanation:

Answer:

B

Magnified images will not be created.

Explanation:

I did it and this was the correct answer

Answer:

B is correct the person above me is also correct. Hope this helps

Explanation:

The combination of a wire coil and a core would make the weakest electromagnet 20 coils of insulated wire around a hollow cardboard core. Thus, option B is correct.

Electromagnet is a type of magnet that produces its magnetic field when an electric field is applied across the material. The electromagnet is the temporary magnet as it acquires the magnetic properties when the electric current passes through it. When there is no electric current, its magnetic properties disappear.

Electromagnet consists of a wire wound on the coil and the current passes through the wire. The wire wound on the coil is mostly a ferromagnetic material like iron and the coil is a soft iron core. In an electromagnet, the magnetic field depends on the number of turns of the coil and the current flows through it.

From the given, steel core is wounded with wire it makes a strong electromagnet depending on the number of turns of the coil. The cardboard core is not a ferromagnetic material and hence, a small number of turns over the cardboard forms the weakest electromagnet.

Hence, the ideal solution is option B)20 coils of insulated wire around a hollow cardboard core.

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Answer:

Stupid

Explanation:

Because there is never a answer when we are trying to find one

Answer:

c) 6 m/s²

Explanation:

Answer:

(a) La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]

(b) Un satélite de 1,200 kg pesará allí 264 N.

Explanation:

(a) Cada punto del espacio tiene un  valor del campo proporcional a la función, siguiendo el modelo de gravitación de Newton:

[tex]g=G*\frac{m}{r^{2} }[/tex]

donde m será masa, r  la distancia entre los objetos y G la constante de gravitación universal, cuyo valor es [tex]G=6.672*10^{-11}\frac{N*m^{2} }{kg }[/tex]

En este caso:

Reemplazando:

[tex]g=6.672*10^{-11}\frac{N*m^{2} }{kg }*\frac{6*10^{24}kg }{(42,370,000 m)^{2} }[/tex]

Resolviendo, obtenes:

g= 0.22 [tex]\frac{m}{s^{2} }[/tex]

La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]

(b) La ley fundamental de la dinámica o segunda ley de Newton expresa que la fuerza neta que es aplicada sobre un cuerpo es proporcional a la aceleración que adquiere en su trayectoria.  Esto se expresa matemáticamente como:

F= m*a

en donde  F es fuerza neta , m la masa y a la aceleración.

El peso es la fuerza que ejerce la gravedad sobre una masa, por lo que se obtiene de manera análoga a la fuerza:

P=m*g

En este caso la masa m tiene un valor de 1,200 kg y la gravedad g un valor de 0.22 [tex]\frac{m}{s^{2} }[/tex].

Reemplazando:

P=1,200 kg*0.22 [tex]\frac{m}{s^{2} }[/tex]

Resolviendo:

P= 264 N

Un satélite de 1,200 kg pesará allí 264 N.

Answer:

B) t = 1.83 [s]

A) y = 16.51 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} =v_{o} -g*t[/tex]

where:

Vf = final velocity = 0

Vo = initial velocity = 18 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time [s]

Note: the negative sign in the above equation means that the acceleration of gravity is acting in the opposite direction to the motion.

A) The maximum height is reached when the final velocity of the ball is zero.

0 = 18 - (9.81*t)

9.81*t = 18

t = 18/9.81

t = 1.83 [s], we found the answer for B.

Now using the following equation.

[tex]y = y_{o} + v_{o}*t - 0.5*g*t^{2}\\[/tex]

where:

y = elevation [m]

Yo = initial elevation = 0

y = 18*(1.83) - 0.5*9.81*(1.83)²

y = 16.51 [m]

The acceleration of the truck is obtained from the calculation done as  0.055 m/s^2.

We know that the acceleration is defined as the rate of the change of the velocity of the object with time and we can be able to obtain the acceleration by the use of the equations of kinematics as usual.

Initial velocity =  1.8 km/h  or 0.5 m/s

Final velocity = 24.0 km/h or 6.67 m/s

Distance covered = 4.0 * 10^2 m

Then;

v^2 = u^2 + 2as

v = final velocity

u = initial velocity

a = acceleration

s = distance covered

a = v^2 - u^2/2s

a = (6.67)^2 - (0.5)^2/2 *  4.0 * 10^2

a = 44.4 - 0.25/800

a = 0.055 m/s^2

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Answer:

Your answer is: D) Tinea Pedis

Explanation:

Hope this helped : )

Answer:

D = 1.8677 miles , θ = 24.28º at South of West

Explanation:

This is an exercise in adding vectors, the easiest way to solve them is to decompose the vectors and add each component algebraically. Let's use trigonometry

first displacement. d = 1.2 miles to 30º south of East

     cos ( 360-30) = cos (-30) = x₁ / d

     sin (-30) = y₁ / d

     x₁ = d cos (-30)

     y₁ = d sin (-30)

     x₁ = 1.2 cos (-30) = 1,039 miles

     y₁ = 1.2 sin (-30) = -0.6 miles

second shift. d = 2.0 miles to 20º West of South

       cos (270-20) = x₂ / d

       cos (250) = y₂ / d

       x₂ = 2.0 cos 250 = -0.684 miles

       y₂ = 2.0 sin250 = -1.879 miles

Third displacement. d = 1.6 miles to 30º South of West

       cos (180 + 30) = x₃ / d

       sin (210) = y₃ / d

       x₃ = 1.6 cos 210 = -1.3856 miles

       y₃ = 1.6 sin 210 = -0.8 miles

Fourth displacement. d = 2.6 miles to 15º West of North

       cos (90 + 15) = x₄ / d

       sin (105) = y₄ / d

       x₄ = 2.6 cos 105 = -0.6729 miles

       y₄ = 2.6 sin 105 = 2,511 miles

having all the components we add

x-axis  (West-East direction)

       X = x₁ + x₂ + x₃ + x₄

       X = 1.039 -0.684 - 1.3846 - 0.6729

       X = -1.7025 miles

       Y = y₁ + y₂ + y₃ + y₄

       Y = -0.6 -1.879 -0.8 +2.511

       Y = -0.768

The modulus of this displacement is we use the Pythagorean theorem

      D = √ (X² + Y²)

      D = √ (1.7025² + 0.768²)

      D = 1.8677 miles

let's use trigonometry to find the direction

       tan θ = Y / X

       θ = tan⁻¹ Y / x

       θ = tan⁻¹ (0.768 / 1.7025)

       θ = 24.28º

as the two components are negative this angle is in the third quadrant

therefore in cardinal direction form is

         θ = 24.28º at South of West

1.53 secs :)))))))))))))))

Answer:

The answer is B.

Explanation:

They are in control of the experiment, they can change it the variables to better help the experiment.

Answer:

b

Explanation: its b

Answer:

All i got to say is that he is dead dead

Explanation: