What is the value of this expression?

What Is The Value Of This Expression?

Answers

Answer 1

Answer:

-3

Step-by-step explanation:

Step 1: Solve (-2+(-1))^2/3 3

           1. -2+(-1) = -3

           2. (-3)^2 = 9

           3. 9/3 = 3

Step 2: Solve (-4)^2-17 -1

           1. 3/-1

Step 3: Simplify 3/-1 = -3. I hope this helped and please don't hesitate to reach out with more questions!


Related Questions

Write the expression as an exponent:

5^8 x 25
6^15 x 36

Answers

Answer:

a.) 5¹⁰

b.) 6¹⁷

Step-by-step explanation:

a.) 5⁸ × 25

Write 25 in the exponential form with the base of 5.

5⁸ × 5²

To calculate product use exponent rule

5⁸+²5¹⁰

b.) 6¹⁵ × 36

Similarly, 6¹⁵ × 36

Write 25 in the exponential form with the base of 6.

6¹⁵ × 6²

To calculate product use exponent rule.

6¹⁵ + ²6¹⁷

Answer:

[tex] \displaystyle {5}^{10} [/tex]

[tex] \displaystyle {6}^{17} [/tex]

Step-by-step explanation:

Question-1:

we want to rewrite the following expression as an exponent

[tex] \displaystyle {5}^{8} \times {25}[/tex]

remember that 25 is the square of 5 therefore

[tex] \displaystyle {5}^{8} \times {5}^{2} [/tex]

recall that,

[tex] \displaystyle {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]

with that law we obtain:

[tex] \displaystyle {5}^{8 + 2} [/tex]

simplify addition:

[tex] \displaystyle {5}^{10} [/tex]

Question-2:

likewise Question-1 36 is the square of 6 Thus,

[tex] \displaystyle {6}^{15} \times {6}^{2} [/tex]

similarly apply law of exponent:

[tex] \displaystyle {6}^{15 + 2} [/tex]

simplify addition:

[tex] \displaystyle {6}^{17} [/tex]

hence,

we have written the expression as an exponent

what is the product of the prime factors of 24​

Answers

Answer:

So the prime factorization of 24 is 24 = 2 · 2 · 2 · 3 = 23 · 3. A good way to check the result is to multiply it out and make sure the product is 24.

Step-by-step explanation:

Situation:
Find the age of
A student in Greece discovers a pottery
bowl that contains 28% of its original
amount of C-14.
Ent
N= Noekt
No
= inital amount of C-14 (at time
t = 0)
N = amount of C-14 at time t
k = 0.0001
t = time, in years

Answers

Answer:

Step-by-step explanation:

I'm assuming you need the age of the bowl. Start with the fact that you have remaining 28% of the original amount before any of it decayed. You always start with 100% of something unless you're told differently. That means that the equation looks like this:

[tex]28=100e^{-.0001t}[/tex] and begin by dividing both sides by 100 to get

[tex].28=e^{-.0001t}[/tex] . To solve for t we have to be able to bring it down from its current position of exponential. To do this we would either take the log or the natural log since the rules for both are the same. However, the natural log is the inverse of e, so they undo each other. We take the natural log of both sides which allows us to pull down the -.0001t. At the same time remember that the natural log and e are inverses of each other so they are both eliminated when we do this.

ln(.28) = -.0001t Now it's easy to solve for t.

[tex]\frac{ln(.28)}{-.0001}=t[/tex] and

[tex]\frac{-1.272965676}{-.0001}=t[/tex] so

t = 12729.65676 years or rounded, 12730 years.

Solve The inequality

Answers

Answer:

D is the correct answer.

Please thank me

Step-by-step explanation:

given that O is the center of the circle, find the measure of angle BAC of arc DC = 120

Answers

Answer:

30 degrees.

Step-by-step explanation:

DC is given as 120, so start off by finding arc BC.

180-120= Semicircle-DC=60.

BC=60.

Inscribed angles are half of their arcs.

60/2=30.

1) Find the measure of 0. (imagine that is an x) 2) Then, find the measure of AB. (the length from A to B) ​

Answers

Answer:

θ ≈ 50°, AB ≈ 15.6

Step-by-step explanation:

Using the tangent ratio in the right triangle

tanθ = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{11.9}{10}[/tex] = 1.19 , then

θ = [tex]tan^{-1}[/tex] (1.19 ) ≈ 50° ( to the nearest degree

-----------------------------------------------------------------

Using the cosine ratio in the right triangle

cos50° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{10}{AB}[/tex] ( multiply both sides by AB )

AB × cos50° = 10 ( divide both sides by cos50° )

AB = [tex]\frac{10}{cos50}[/tex] ≈ 15.6 ( to 1 dec. place )

Joseph is creating a dilation through point B with a scale factor of 2. Which statements about the dilation are correct? Check all that apply.
Triangle A B C. Angle B is a right angle.
A’ will be located on ray Ray B A.
B and B’ are the same point.
Line segment B prime C prime will be One-half as long as Line segment B C.
Line segment A B and Line segment B C will be part of the image’s sides.
The image will be inside the pre-image.

Answers

Answer:

A’ will be located on ray Ray B A.

B and B’ are the same point.

Line segment A B and Line segment BC will be part of the image’s sides.

Step-by-step explanation:

Given that the dilation is made through point B, B and B’ are the same point, A’ will be located on Ray BA, C’ will be located on Ray BC, line segment B'C' will be double than line segment BC, line segment B'A' will be double than line segment BA, and the pre-image (triangle ABC) will be inside the image (triangle A'B'C').

Answer:

A B D is your answer

Step-by-step explanation:

The number of strokes in which a hole is designed to be played. [ Choose ] The person who is farthest away from the hole is said to have _____.

Answers

Answer:

the answer is more strokes since the farther away you are the more strokes it takes

Hope This Helps!!!

1. Students were surveyed and asked if they play lacrosse and/or football. The results are shown below.




What percent of football players also play lacrosse?

Answers

36%

Step-by-step explanation:

28 + 16 = 44 Football players

Of those, 16 are on the lacrosse team.

16 / 44 × 100 = 36.36% (We round to 36%)

To verify:

44 × 36.36% = 15.84 (Which we can round to 16)

Pardon me if it's wrong

A particle is projected with a velocity of [tex]40ms^-^1[/tex] at an elevation of 60°. Calculate the vertical component of its velocity at a height of 50m. (Take g = [tex]9.8ms^-^2[/tex])
A. [tex]25\sqrt{3} ms^-^1\\\\B.20\sqrt{3} ms^-^1\\\\c. 2\sqrt{545} ms^-^1[/tex]

Answers

Answer:

[tex]2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}[/tex]

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be [tex]y[/tex]. The magnitude of [tex]40\text{ m/s}[/tex] will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is [tex]60^{\circ}[/tex], we have:

[tex]\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}[/tex](Recall that [tex]\sin 60^{\circ}=\frac{\sqrt{3}}{2}[/tex])

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation [tex]v_f^2=v_i^2+2a\Delta y[/tex] to solve this problem, where [tex]v_f/v_i[/tex] is final and initial velocity, respectively, [tex]a[/tex] is acceleration, and [tex]\Delta y[/tex] is distance travelled. The only acceleration is acceleration due to gravity, which is approximately [tex]9.8\:\mathrm{m/s^2}[/tex]. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

[tex]v_i=20\sqrt{3}\text{ m/s}[/tex] [tex]a=-9.8\:\mathrm{m/s^2}[/tex] [tex]\Delta y =50\text{ m}[/tex]

Solving for [tex]v_f[/tex]:

[tex]v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}[/tex]

Solve the inequality. q/3 < 11

Answers

Answer:

[tex]q < 33[/tex]

Step-by-step explanation:

[tex] \frac{q}{3} < 11[/tex]

[tex]q < 11 \times 3[/tex]

[tex]q < 33[/tex]

Hope it is helpful....

Answer:

33

Step-by-step explanation:

q/3<11

q=11×3

q=33

:. The answer is 33.

if the measure of angle def is 65° what is the measure of arc de?

Answers

EF is tangent to the circle we'll assume; otherwise there's no progress.

Call the center C. ECD is isosceles, formed from two radii and the chord.

Angle CED is complementary to DEF

CED = 90 - 65 = 25 degrees

CDE is congruent, isosceles triangle and all that: CDE=25

That leaves DCE=180-25-25=130 degrees

That's the measure of arc DE as well:

Answer: 130 degrees, choice A

Answer:

130

Step-by-step explanation:

Help, I have a time limit for this

Answers

Answer:

I believe that it is the first one.

Step-by-step explanation:

Someone pls help me ill give out brainliest pls don’t answer if you don’t know

Answers

Answer:

i dont know

Step-by-step explanation:

figure it out yourself

What is dummy variable? Explain interaction effects using dummy variables? Explain Autoregressive Conditional Heteroskedasticity (ARCH) and Generalized Autoregressive Conditional Heteroskedasticity (GARH) models. What to do when find problem of Autocorrelation?

Answers

Answer:

u here then today the thats yjvfh dfnrugevc5hdb

Class 3 question ,pls help

Answers

Answer:

bigger number minus larger number plus 1

430-421 = 9 + 1 = 10

573 - 567 = 6+1 = 7

898 - 890 = 8+ 1 = 9

Step-by-step explanation:

If < A and < B are vertical angles, and < A is 43 ° , then what is the measure of < B?

Select one:
a. 47 °
b. 137 °
c. 21 °
d. 43 °

Answers

Answer:

d

Step-by-step explanation:

vertical angles are congruent , so

∠ B = ∠ A  = 43°

I need help figuring out what the answer is.

Answers

Answer:

A

Step-by-step explanation:

Plss Answer!!!!!!!!!​

Answers

Answer:

Ecosystem: Trees

Ways to protect are as follows:-

Control over Forest FireDon't waste paper. Plant a tree

Simplify. 6x-2
A.6/x^2
B.x²/6
C.1/6x^2
D.1/36x^2

Answers

Answer:

Step-by-step explanation:

[tex]a^{-m}=\frac{1}{a^{m}}\\\\6x^{-2}=6*\frac{1}{x^{2}}=\frac{6}{x^{2}}[/tex]

Evidencia de aprendizaje Se desea obtener 80 kilogramos de café molido mezclando café arábico de S/18 el kilogramo y café torrado de S/10 el kilogramo. Si se quiere que el precio del kilogramo de mezcla sea de S/13, ¿Qué cantidad de café de S/18 debe usar? Responde las siguientes preguntas:  ¿Qué estrategias utilicé para validar la solución al sistema de ecuaciones?  ¿Para qué me servirá lo que aprendí?,  ¿Qué dificultades encontraron en este aprendizaje?  A partir de la situación planteada ¿A qué conclusión puedo llegar?

Answers

Answer:

50kg de café torrado

30kg de café arábico

Step-by-step explanation:

Queremos obtener un total de 80kg de café molido.

Se utilizarán:

Café arábico, que cuesta $18 el kg

Café torrado, que cuesta $10 el kg

Queremos que el precio, por kilo, de la mezcla de 80kg sea $13.

Ok, primero debemos definir las variables:

Definamos:

x = cantidad de café arábico usado

y = cantidad de café torrado usado.

Entonces, como la mezcla deberá tener 80kg en total, tenemos:

x + y = 80kg

Y el costo total de esta mezcla será:

x*$18 + y*$10

Si lo dividimos por el peso total, tendremos el costo por kilo, que es:

(x*$18 + y*$10)/80kg

Y queremos que esto sea igual a $13, entonces tenemos la ecuación

(x*$18 + y*$10)/80kg = $13

Ok, ahora tenemos dos ecuaciones, es decir, tenemos un sistema de ecuaciones:

x + y = 80kg

(x*$18 + y*$10) = $13*80kg

(donde reescribimos levemente la segunda ecuación)

Ok, para resolver este sistema trataremos de reemplazar variables, para ello, el primer paso es aislar una de las variables en una de las ecuaciones.

Aislemos x en la primera:

x = 80kg - y

Ahora reemplazamos esto en la otra ecuación:

(x*$18 + y*$10) = $13*80kg

(( 80kg - y)*$18 + y*$10) = $13*80kg

Ahora podemos resolver esto para la variable y:

$18*80kg - $18*y + $10*y = $13*80kg

$18*80kg - $13*80kg = $18*y - $10*y

($18 - $13)*80kg = ($18 - $10)*y

$5*80kg = $8*y

($5*80kg)/$8 = y

50kg = y

Se usan 50kg de café torrado.

y como:

x + y = 80kg

x = 80kg - y

x = 80kg - 50kg = 30kg

Entonces los 30kg restantes serán de café arábico.

y la estrategia utilizada fue el remplazo de variables.

find the distance between the points (-3,-2) and (1,-5)

Answers

the slope or distance is 4/-3

Find the constant of proportionality if y is
proportional to x.

A. 25
B. 21
C. 26
D. 28

HELPPP!!!!!!

Answers

B. 21 because 21+21=42 42+21=63 etc

What is the vertex of the graph of the function f(x) = (x + 2)^2 − 3?

Answers

25 it should be the answer

What is the area of the obtuse triangle given below? ​

Answers

Answer:

D. 38.5 sq. units

Step-by-step explanation:

The formula for the area of a triangle is A=bh(1/2)

So to solve, first multiply the base, by the height: 11*7=77

Then, multiply by 1/2 or divide by 2.

You get 38.5

That's your answer!

Hope this helps!

Johnny asks you to guess the specific coins he has in his pocket if he has $3.70 in change. You say you need a little
more information, to guess. So he tells you all he has is quarters and dimes and that he has 22 colns in all.

Answers

Answer:

10 quarters and 12 dimes :)

Step-by-step explanation:

what is the percentage of 690 out of 800

Answers

Answer:

the percentage of 690 out of 800 is 86.25%

Step-by-step explanation:

690/800 = 0.8625

0.8625*100 = 86.25

hope it helped :)

mark me brainliest

Answer:

86.25%

Step-by-step explanation:

(A) Given that the expression​​ x^3-ax^2+bx+c leaves the same ​remainder when divided by x+1 or x-2, find a in term of b.
(B) (2x-1)^3+6(3+4x^2) is divided by 2x+​​​​​​​​​​​​​​​1.

Answer those two question please. I need it quickly. No silly answers would not be allowded. ​​​​​

Answers

Hello,

A:

[tex]\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=-1&&-1&a+1&-a-b-1\\---&---&---&---&---\\&1&-a-1&a+b+1&-a-b+c-1\\\end{array}\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=2&&2&-2a+4&-4a+2b+8\\---&---&---&---&---\\&1&-a+2&-2a+b+4&-4a+2b+c+8\\\end{array}\\\\\\\\-a-b+c-1=-4a+2b+c+8\\\\\boxed{b=a-3}\\[/tex]

B:

[tex](2x-1)^3+6(3+4x^2)\\\\=8x^3-12x^2+6x-1+18+24x^2\\\\=8x^3+12x^2+6x+17\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&8&12&6&17\\x=-\dfrac{1}{2} &&-4&-4&-1\\---&---&---&---&---\\&8&8&2&16\\\end{array}\\\\\\(2x-1)^3+6(3+4x^2)=(2x+1)(4x^2+4x+1)+16[/tex]

what is the measure of 2?

Answers

Answer:

Value of x:

[tex]{ \tt{(7x + 1) \degree + (18x + 4) \degree = 180 \degree}} \\ { \tt{25x + 5 = 180}} \\ { \tt{25x = 175}} \\ x = 7[/tex]

Finding m‹2 :

[tex]{ \tt{m \angle2 = (7x + 1) \degree}} \\ { \tt{m \angle2 = (7 \times 7) + 1}} \\ { \bf{m \angle2 = 50 \degree}}[/tex]

Answer:

m∠2 = 50

Step-by-step explanation:

7x + 1 and 18x + 4 are angles in a linear pair.

Sum of linear pair angles is supplementary.

7x + 1 + 18x + 4 = 180

7x + 18x + 1 + 4 = 180

25x + 5 = 180

25x = 180 - 5

25x = 175

x = 175 / 25

x = 7

Substitute x = 7 in 7x + 1,

7x + 1

= 7 ( 7 ) + 1

= 49 + 1

= 50

7x + 1 and ∠2 are vertically opposite angles and vertically opposite angles are equal.

∠2 = 7x + 1

∠2 = 50

Point A (6,2) is translated using the vector <-5,2>. Where is the new point located?

Answers

Answer:  (1,4)

======================================================

Explanation:

The notation <-5,2> is the same as writing the translation rule [tex](x,y) \to (x-5,y+2)[/tex]

It says: move 5 units to the left and 2 units up

The point (6,2) moves to (1,2) when moving five units to the left. Then it ultimately arrives at (1, 4) after moving 2 units up. You could move 2 units up first and then 5 units to the left later on, and you'd still arrive at (1, 4). In this case, the order doesn't matter (some combinations of transformations this won't be the case and order will matter).

---------

Or you could write out the steps like so

[tex](x,y) \to (x-5, y+2)\\\\(6,2) \to (6-5, 2+2)\\\\(6,2) \to (1, 4)\\\\[/tex]

We see that (6,2) moves to (1, 4)

Other Questions
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