What is the value of the expression 4x^3 – 3x when x = 6?

Answer:

18.63

Step-by-step explanation:

[tex] \frac{6}{10} = 0.6 \\ \frac{3}{100} = 0.03[/tex]

[tex]10 + 8 + 0.6 + 0.03 = 18.63[/tex]

The scaled factor is 3 for all of them.

Answer:

B

Step-by-step explanation:

It just is

Answer:

-11,9.42,10,11.8

-11<9.42<10<11.8

Answer:

I think the answer is

-11, 9.24 ,10, 11.8

Answer:

11

Step-by-step explanation:

The answer will be 11

as she is thinking of prime number so

111 is not a prime number

aswell as 77 is not a prime number

11 is a prime number and is also a multiple of 11

Answer:

11

Step-by-step explanation:

Answer:

25/100

Step-by-step explanation:

0.25=25/100

Hope this helps! Thanks.

Answer:

-1/4

Step-by-step explanation:

-0.25

Answer:

they travel 115 km/h long

Answer:

The value of 6 in 675,002 is 1,000 times greater than the value of 6 in 385,621.

Answer:

D ig?

Step-by-step explanation:

Because opposite angles are equal in parallelogram

Answer:

Step-by-step explanation:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

Answer:

B=Product

C=polynominal

D=distirbutive property

Step-by-step explanation:

Answer:

78,000

Step-by-step explanation:

Answer:

1st expression= rational 2nd expression= rational 3rd expression = irrational

Step-by-step explanation:

The first and second expressions are rational because they both equal whole numbers (4 and 3) while the last expression equals a decimal that goes on forever with no end, thus making it irrational.

Differentiate both sides with respect to x and solve for the derivative dy/dx :

[tex]\dfrac{\mathrm d}{\mathrm dx}\left[x^2y^2+xy\right] = \dfrac{\mathrm d}{\mathrm dx}[2] \\\\ \dfrac{\mathrm d}{\mathrm dx}\left[x^2\right]y^2 + x^2\dfrac{\mathrm d}{\mathrm dx}\left[y^2\right] + \dfrac{\mathrm d}{\mathrm dx}\left[x\right]y + x\dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ 2xy^2 + x^2(2y)\dfrac{\mathrm dy}{\mathrm dx} + y + x\dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ (2x^2y+x)\dfrac{\mathrm dy}{\mathrm dx} = -2xy^2-y \\\\ \dfrac{\mathrm dy}{\mathrm dx} = -\dfrac{2xy^2+y}{2x^2y+x}[/tex]

This gives the slope of the tangent to the curve at the point (x, y).

If the slope of some tangent line is -1, then

[tex]-\dfrac{2xy^2+y}{2x^2y+x} = -1 \\\\ \dfrac{2xy^2+y}{2x^2y+x} = 1 \\\\ 2xy^2+y = 2x^2y+x \\\\ 2xy^2-2x^2y + y - x = 0 \\\\ 2xy(y-x)+y-x = 0 \\\\ (2xy+1)(y-x) = 0[/tex]

Then either

[tex]2xy+1 = 0\text{ or }y-x=0 \\\\ \implies y=-\dfrac1{2x} \text{ or }y=x[/tex]

In the first case, we'd have

[tex]x^2\left(-\dfrac1{2x}\right)^2+x\left(-\dfrac1{2x}\right) = \dfrac14-\dfrac12 = -\dfrac14\neq2[/tex]

so this case is junk.

In the second case,

[tex]x^2\times x^2+x\times x=x^4+x^2=2 \\\\ x^4+x^2-2 = (x^2-1)(x^2+2)=0[/tex]

which means either

[tex]x^2-1 = 0 \text{ or }x^2+2 = 0 \\\\ x^2 = 1 \text{ or }x^2 = - 2[/tex]

The second case here leads to non-real solutions, so we ignore it. The other case leads to [tex]x=\pm1[/tex].

Find the y-coordinates of the points with x = ±1 :

[tex]x=1 \implies y^2+y=2 \implies y=-2 \text{ or }y=1 \\\\ x=-1\implies y^2-y=2\implies y=-1\text{ or }y=2[/tex]

so the points of interest are (1, -2), (1, 1), (-1, -1), and (-1, 2).

Answer:

Answer = he made 7,000 in July and sold 10 cars in august.

Step-by-step explanation:

Answer:

Question unclear

Step-by-step explanation:Your probally asking what times 8 gives us 80. If you are than 10!

Answer:

Yes. It is a rational number.

Hi there!

The numbers you have written there are correct.

[tex]-5<x<0[/tex] is true for any value of x that is greater than -5 or less than 0.

When a number is less than 0, we know that it has to be negative.

However, it cannot be more negative than -5. It cannot be -5 either.

So, x could be -1, -2, -3, -4, -1/2, -2.3, -4.9, the list goes on.

I hope this helps!

Answer:

Step-by-step explanation:

x - first

x + 12 - second

x + (x + 12) = 44

2x=44-12

x=16

first number is 16

second number is 16+12=28

two numbers are 16 and 28

16 and 28 are the required two numbers when one number exceeds another by 12 and their sum is 44

One number exceeds another by 12 and their sum is 44

We need to find the two numbers

Two expressions with equal sign is called equation.

Let x be the first number

x + 12 be the  second number

x + (x + 12) = 44

2x=44-12

x=16

Therefore first number is 16

second number is 16+12=28

To learn more about solving equation click here: https://brainly.com/question/24638714

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Answer:

Step-by-step explanation:

Answer:

D = 8y-15

Step-by-step explanation:

-y-9y-15 than combine -y and -9y

so = 8y-15

[tex]\\ \sf\longmapsto 0.49=\dfrac{49}{100}[/tex]

[tex]\\ \sf\longmapsto 0.093=\dfrac{93}{1000}[/tex]

[tex]\\ \sf\longmapsto 0.021=\dfrac{21}{1000}[/tex]

[tex]\\ \sf\longmapsto 0.103=\dfrac{103}{1000}[/tex]

Answer:

you could have a 6 and then a -6

or a 3 and a -3

or 0 and 0

have 2 cards with the same number but one is negative

Step-by-step explanation:

9514 1404 393

Answer:

Step-by-step explanation:

1. The ratio is ...

  (6 in)/(8 in) = 6/8 = 3/4

__

2. The scaled dimensions are ...

  6 in × 3 = 18 in (vertical side)

  8 in × 3 = 24 in (horizontal side)

__

3. You know from your process of reducing the fraction in part 1 that multiplying numerator and denominator by the same value does not change the reduced ratio.

Step-by-step explanation:

Let [tex]P_1(-1, -8)\:\text{and}\:P_2(-4, -9)[/tex]

The slope of the line through these two points is

[tex]m = \dfrac{y_2 - y_1}{x_2 - x_1} = \dfrac{(-9 + 8)}{(-4 + 1)} = \dfrac{1}{3}[/tex]

So the slope-intercept form of the line passing through the two points is

[tex]y = mx + b = \frac{1}{3}x + b[/tex]

To find b, we use either point into our equation. Let's use (-1, -8):

[tex]-8 = \frac{1}{3}(-1) + b \Rightarrow b = -\dfrac{23}{3}[/tex]

Therefore, the slope-intercept form of the equation for the line is

[tex]y = \dfrac{1}{3}x - \dfrac{23}{3}[/tex]

The standard form of the equation can be written as

[tex]x + 3y + 23 = 0[/tex]

Answer:

B

Step-by-step explanation:

Let the two numbers be a and b.

The product of the two is 120 and their sum of their squares is 289. In other words:

[tex]\displaystyle ab = 120 \text{ and } a^2 + b^2 = 289[/tex]

And we want to find the sum of the two numbers.

We can use the perfect square trinomial. Recall that:

[tex]a^2 + 2ab + b^2 = (a+b)^2[/tex]

From the first equation, multiply by two:

[tex]2ab = 240[/tex]

Add the two equations together:

[tex](a^2+b^2)+(2ab) = (289)+(240)[/tex]

Simplify and rewrite:

[tex]a^2+2ab+b^2 = 529[/tex]

Factor using the perfect square trinomial pattern:

[tex](a+b)^2 = 529[/tex]

And take the square root of both sides:

[tex]\displaystyle a + b = \pm\sqrt{529} = \pm23[/tex]

Hence, the sum of the two numbers is 23 or -23.

In conclusion, our answer is B.

Answer:

107 full and .103 of another

Step-by-step explanation:

6212/58 =