Answer:
c
Step-by-step explanation:
Answer:
70,000 ccccccccccccccccccccc
Step-by-step explanation:
it's supposed to be 56,972,622 not
56,992622 so it's not A
I never asked for fifty million so it's not B
56,977,622 is incorrect so it's not D
So the one answer left is C and C is the correct answer :P
Find the area of the shaded regions.
QUICKLY PLEASE
Answer:
the answer is 270° on this
Answer:
84.78
Step-by-step explanation:
Area of a circle is pi(radius)^2
In this case it would be (pi(radius)^2)270/360 since it's 3/4 of a circle.
So we replace the values and solve:
3.14(36)(270/360)= 84.78 square centimeters.
HELP HELP HELP HELP PLEASE
Answer:
It is indeed 63
Step-by-step explanation:
The easy way to go about this is to recognize that if the triangles are similar, the ratio between the similar sides will be the same.
Notice:
4/5 = 36/45
So:
4/7 should = 36/x
If:
4/7 = 36/x
4x/7 = 36
4x = 36*7
x=36*7/4
x=63
In this problem, x = c1 cos t + c2 sin t is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the second-order IVP consisting of this differential equation and the given initial conditions. x(π/4) = 2 2 , x'(π/4) = 0
Differentiate the given solution:
[tex]x=C_1\cos(t)+C_2\sin(t) \implies x'=-C_1\sin(t)+C_2\cos(t)[/tex]
Now, given that x (π/4) = √2/2 … (I'm assuming there are symbols missing somewhere) … you have
[tex]\dfrac{\sqrt2}2=C_1\cos\left(\dfrac\pi4\right)+C_2\sin\left(\dfrac\pi4\right)[/tex]
[tex]\implies\dfrac1{\sqrt2} = \dfrac{C_1}{\sqrt2}+\dfrac{C_2}{\sqrt2}[/tex]
[tex]\implies C_1+C_2=1[/tex]
Similarly, given that x' (p/4) = 0, you have
[tex]0=-C_1\sin\left(\dfrac\pi4\right)+C_2\cos\left(\dfrac\pi4\right)[/tex]
[tex]\implies 0=-\dfrac{C_1}{\sqrt2}+\dfrac{C_2}{\sqrt2}[/tex]
[tex]\implies C_1=C_2[/tex]
From this result, it follows that
[tex]C_1+C_2=2C_1=1 \implies C_1=C_2=\dfrac12[/tex]
So the particular solution to the DE that satisfies the given conditions is
[tex]\boxed{x=\dfrac12\cos(t)+\dfrac12\sin(t)}[/tex]
PLEASE HELP ME IM HAVING TROUBLE WITH IT
Answer:
True
False
Step-by-step explanation:
BC are on the same line so, the new [tex]B^{1}[/tex][tex]C^{1}[/tex] will also be on the same. Just a different line than the original. The both move the same distance when dilated.
CD and the new [tex]C^{1}[/tex][tex]D^{1}[/tex] cannot be the same length. The dilation will increase their length by 1[tex]\frac{2}{3}[/tex]
Find Y. round to the nearest tenth.
9514 1404 393
Answer:
32.7°
Step-by-step explanation:
Solve the given equation for C, then fill in the given values and evaluate.
C = arccos((a² +b² -c²)/(2ab))
Y = arccos((50² +90² -55²)/(2·50·90)) = arccos(7575/9000) ≈ 32.7°
__
Y is angle A in the attached triangle solver.
Figure out the pattern, and write the next number.
2,6,21,88
A sales firm receives an average of three calls per hour on its toll-free number. For any given hour, find the probability that it will receive at least three calls. Use the Poisson distribution.
Answer:
At most 3 calls: 64.7%
At least 3 calls: 57.7%
5 or more calls: 18.5%
Step-by-step explanation:
!!!HELPPP PLEASE ASAP!!! I don’t know how to solve this problem nor where to start? Can some please help me out and explain how you got the answer please. Thank you for your time.
Step-by-step explanation:
a)
0.00000000007
b)
0.00000001
Solve the equation for x: 6-(4x-2)/5=x
What is the length of PO
These are similar triangles, therefore their sides are proportional.
36 / 24 = PO / 36
24PO = 1296
PO = 54
Hope this helps!
A. Given that K = {x: x ≤ -2}, Y = { x: 1 < x < 6} and z = {x: x < 3}
where x is an integer, find
i. K n (Y u Z)
ii. (K n Y) u (K n Z)
III. What property of operations on sets is shown by your answers in i and ii?
Since x is an integer, we have
K = {…, -6, -5, -4, -3, -2}
Y = {2, 3, 4, 5}
Z = {…, -1, 0, 1, 2, 3}
Then
(i)
Y U Z = {…, -1, 0, 1, 2, 3, 4, 5}
==> K ∩ (Y U Z) = {…, -6, -5, -4, -3, -2} = K
(ii)
K ∩ Y = { } (empty set)
K ∩ Z = {…, -6, -5, -4, -3, -2} = K
==> (K ∩ Y) U (K ∩ Z) = { } U K = K
(iii) This is a demonstration of the distributive property. That is, the intersection distributes over a union:
K ∩ (Y U Z) = (K ∩ Y) U (K ∩ Z)
MFP15017010 2021 Question 2 2.1 Calculate the following 2- and 3-digit numbers using strategic doubling: 34 2.1.2 340 2.13 277 214 00 (10) 2.15 500
Answer:
plz check ur school solution down.
Step-by-step explanation:
I am need help and an explanation on how to read these graphs.
Answer:
A is the answer
Step-by-step explanation:
A
plz mark it brainlist
y=5/3x + 3 in ordered pairs
Answer:
(3,8) ; (-3,-2) ; (6,13)
Step-by-step explanation:
A linear equation in Slope Intercept Form is given to us and we need to write the ordered pairs for x and y . The given equation is ,
[tex]\rm\implies y =\dfrac{5}{3}x + 3 [/tex]
For finding the ordered pairs , substitute different values of x to get different values of y.
Put x = 3 :-
[tex]\rm\implies y =\dfrac{5}{3}\times 3 + 3 [/tex]
[tex]\rm\implies y = 5+ 3 [/tex]
[tex]\rm\implies y =8[/tex]
Put x = -3 :-
[tex]\rm\implies y =\dfrac{5}{3}\times -3 + 3 [/tex]
[tex]\rm\implies y = -5+ 3 [/tex]
[tex]\rm\implies y =-2[/tex]
Put x =6 :-
[tex]\rm\implies y =\dfrac{5}{3}\times 6 + 3 [/tex]
[tex]\rm\implies y = 10+ 3 [/tex]
[tex]\rm\implies y =13[/tex]
Therefore ,
[tex]\small\implies\boxed{\rm\blue{ Odered \ Pairs \ = (3,8) ; (-3,-2) ; (6,13) }}[/tex]
A certain drug carn be used to reduce the acid produced by the body and heal damage to the esophagus due to acid reflux. The manufacturer of the drug claims that more than 94% of patients taking the drug are healed within B weeks. In clinical trials, 228 of 240 patients suffering from acid reflux disease were healed after 8 weeks. Test the manufacturer's claim at the a=0.05 level of significance. Click here to view the standard nomal distribution table (page 1). Cick here to view the standard nomal distribution table (page 2). Because rea (1-Po) =| satistied. (Pound to one decimal place as needed.) V 10, the sample size is 5% of the population size, and the sample the requirements for testing the hypothesis
According to the manufacturer's claim, we build an hypothesis test, find the test statistic and the p-value relative to this test statistic, reaching a conclusion that:
The p-value of the test is 0.2578 > 0.05, which means that there is not sufficient evidence to conclude that more than 94% of patients taking the drug are healed within B weeks.
The manufacturer of the drug claims that more than 94% of patients taking the drug are healed within 8 weeks.
At the null hypothesis, we test if the proportion is of at most 0.94, that is:
[tex]H_0: p \leq 0.94[/tex]
At the alternative hypothesis, we test if the proportion is of more than 0.94, so:
[tex]H_1: p > 0.94[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, is the value tested at the null hypothesis, is the standard deviation and n is the size of the sample.
0.94 is tested at the null hypothesis:
This means that [tex]\mu = 0.94, \sigma = \sqrt{0.94*0.06}[/tex]
In clinical trials, 228 of 240 patients suffering from acid reflux disease were healed after 8 weeks.
This means that [tex]n = 240, X = \frac{228}{240} = 0.95[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{0.95 - 0.94}{\frac{\sqrt{0.94*0.06}}{\sqrt{240}}}[/tex]
[tex]z = 0.65[/tex]
P-value of the test and decision:
The p-value of the test is the probability of finding a sample proportion above 0.95, which is 1 subtracted by the p-value of Z = 0.65.
Looking at the z-table, Z = 0.65 has a p-value of 0.7422.
1 - 0.7422 = 0.2578.
The p-value of the test is 0.2578 > 0.05, which means that there is not sufficient evidence to conclude that more than 94% of patients taking the drug are healed within B weeks.
A similar example can be found at https://brainly.com/question/24166849
Si una vara 2,15 mts de longitud da una sombra de 6,45 mts
Answer:
he casted 4.3. away
Step-by-step explanation:
Please help!
Solve for x
9514 1404 393
Answer:
x = 1
Step-by-step explanation:
The product of lengths to the two circle intercepts are the same for each secant.
7(7+9) = (8x)(8x+6x)
112 = 112x² . . . simplify
1 = x² . . . . . . divide by 112
x = 1 . . . . . . . take the square root (segment lengths are positive)
If Tevin has 2 times as many dimes as nickels and they have a combined value of 100 cents, how many of each coin does he have?
dimes____
nickels____
Answer:
dimes- 8
nickels- 4
Step-by-step explanation:
dime=10 cents
nickels=5 cents
5 x 4 = 20
10 x 8 = 80
80 + 20 = 100
... please give brainliest ...
An article in Fire Technology, 2014 (50.3) studied the effectiveness of sprinklers in fire control by the number of sprinklers that activate correctly. The researchers estimate the probability of a sprinkler to activate correctly to be 0.7. Suppose that you are an inspector hired to write a safety report for a large ballroom with 10 sprinklers. Assume the sprinklers activate correctly or not independently.
Required:
a. What is the probability that all of the sprinklers will operate correctly in a fire?
b. What is the probability that at least 7 of the sprinklers will operate correctly in a fire?
Answer:
a) 0.0282 = 2.82% probability that all of the sprinklers will operate correctly in a fire
b) 0.6496 = 64.96% probability that at least 7 of the sprinklers will operate correctly in a fire.
Step-by-step explanation:
For each sprinkler, there are only two possible outcomes. Either they will operate correctly, or they will not. The sprinklers activate correctly or not independently, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
The researchers estimate the probability of a sprinkler to activate correctly to be 0.7.
This means that [tex]p = 0.7[/tex]
10 sprinklers.
This means that [tex]n = 10[/tex]
a. What is the probability that all of the sprinklers will operate correctly in a fire?
This is [tex]P(X = 10)[/tex]. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 10) = C_{10,10}.(0.7)^{10}.(0.3)^{0} = 0.0282[/tex]
0.0282 = 2.82% probability that all of the sprinklers will operate correctly in a fire.
b. What is the probability that at least 7 of the sprinklers will operate correctly in a fire?
This is:
[tex]P(X \geq 7) = P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)[/tex]
So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 7) = C_{10,7}.(0.7)^{7}.(0.3)^{3} = 0.2668[/tex]
[tex]P(X = 8) = C_{10,8}.(0.7)^{8}.(0.3)^{2} = 0.2335[/tex]
[tex]P(X = 9) = C_{10,9}.(0.7)^{9}.(0.3)^{1}= 0.1211[/tex]
[tex]P(X = 10) = C_{10,10}.(0.7)^{10}.(0.3)^{0} = 0.0282[/tex]
Then
[tex]P(X \geq 7) = P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.2668 + 0.2335 + 0.1211 + 0.0282 = 0.6496[/tex]
0.6496 = 64.96% probability that at least 7 of the sprinklers will operate correctly in a fire.
Area: Change in Dimensions
A rectangle FGHJ has a width of 3 inches and a length of 7 inches.
Step-by-step explanation:
this is not complicated at all. first and second graders can do a-c (come on, you know how to calculate the area of a rectangle) and with some imagination also d and e.
this is meant for you to actually do it so that you get a feeling for these things.
I will therefore leave the pure calculation to you.
and I will give you some help for the conceptual/ theoretical part.
the area of a rectangle is, of course, length × width (or height some on the view you have on an object).
let's just call them l and w.
so the regular area is
Ar = l×w
now one dimension (or example and for the width, but it does not matter, it is the same for the length) is doubled.
it simply means the new width is twice the old width.
so the area with a double width is
A2w = l×(2×w) = 2×(l×w)
so, that means also the area is doubled compared to the regular area.
now, both dimensions are doubled.
A2w2l = (2×l)×(2×w) = 4×(l×w)
so, the area grew 4 times a large as the regular area.
what is the rule here ?
let's triple the dimensions.
A3w3l = (3×l)×(3×w) = 9×(l×w)
as you can easily see : the new area grows with the square of the scaling factor, when we change both dimensions equally.
the reason is simple - as our little equations show, we have to multiply in the scaling factor of every dimension in play.
therefore, the new area grows with the product of the scaling factors of the involved dimensions. if both scaling factors are the same, then the area grows therefore by the square of the common factor.
and this principle applies to every shape, where the area is constructed out of 2 dimensions. any other additional multiplication factors don't matter for this, because this is all one big multiplication of several factors, and if you multiply one of these factors by an additional factor, the whole result changes by that factor.
Suppose a + bi and c + di are complex numbers with b not equaling 0.
(a) Calculate (a + bi) + (c + di) and (a + bi)(c + di).
(b) Show that if both the sum and product are real numbers, then either the complex numbers are real numbers or conjugates.
9514 1404 393
Answer:
(a) sum: (a+c) +(b+d)i
product: (ac -bd) +(bc +ad)i
(b) (b+d)=0 and (bc+ad)=0 ⇒ a=c, d=-b or b=d=0
Step-by-step explanation:
(a) Combining like terms the sum is ...
(a +bi) +(c +di) = (a+c) +(b+d)i . . . . sum
And the product is ...
(a+bi)(c+di) = ac +(ad+bc)i +bd·i²
Since i = √-1, i² = -1 and the product can be written as ...
(a+bi)(c+di) = (ac-bd) +(ad+bc)i . . . . product
__
(b) If both the sum and product are real numbers, then we have ...
b +d = 0
ad +bc = 0
The first equation tells us d = -b. Substituting that into the second equation, we get ...
a(-b) +b(c) = 0
b(c -a) = 0
The zero product rule tells us this will be true if and only if b = 0 or c = a.
if b = 0, then d = 0 and both numbers are real.
if c = a, then c+di = a-bi and the numbers are conjugates.
Hence, if both the sum and product are real, both are real numbers or they are conjugates.
an experiment consists of tossing a coin five times and observing and the sequence of heads and tails. find pr
Answer:
[tex]P(TTTTT) = \frac{1}{32}[/tex]
Step-by-step explanation:
Given
[tex]n = 5[/tex] --- toss
See comment for complete question
Required
[tex]P(TTTTT)[/tex]
First, we calculate the number of possible outcomes
A coin has 2 faces; Since the coin is to be tossed 5 times;
[tex]Outcome = 2^5[/tex]
[tex]Outcome = 32[/tex]
There is only one outcome of TTTTT;
So:
[tex]P(TTTTT) = \frac{1}{32}[/tex]
Use all the six numerals 4, 5, 6, 7, 8 and 9 to form two 3-digit even numbers whose sum is smallest, and what is the sum?
Step-by-step explanation:
this Is hard to find.............
Answer:
The numbers should be even, it means the unit digits are 4, 6 or 8.
The numbers should be minimal, it means the hundred's digits are 4 and 5.
With this we have possible numbers:
4x6 and 5y8, here 6 and 8 could be exchanged.The options are:
496 and 578 or476 and 598 or498 and 576 or478 and 596The sum of the two numbers is:
1074Convert 0.181818 … to a fraction by writing the repeating decimal as an infinite geometric series. Show all of your work (please)
0.181818… = 18 (0.010101…)
… = 18 (0.01 + 0.0001 + 0.000001 + …)
… = 18 (1/100 + 1/100² + 1/100³ + …)
… = 18 (1 + 1/100 + 1/100² + 1/100³ + …) - 18
Then you have
[tex]0.181818\ldots = \displaystyle18\sum_{k=0}^\infty\frac1{100^k} - 18 = \frac{18}{1-\frac1{100}} - 18 = \boxed{\frac2{11}}[/tex]
find all the missing measurement
Answer:
find all the missing measurementI need help with this question please
Answer:
Average rate of change is - 1/6 or -0.166…
Step-by-step explanation:
[tex]{ \tt{f(x) = \frac{1}{x - 5} }}[/tex]
f(-1):
[tex]{ \tt{f( - 1) = \frac{1}{( - 1 - 5)} }} \\ = { \tt{ - \frac{1}{6} }}[/tex]
f(3):
[tex]{ \tt{f(3) = \frac{1}{3 - 5} }} \\ = { \tt{ - \frac{1}{2} }}[/tex]
Average rate of change:
[tex] = { \bf{ \frac{f(3) - f(-1)}{2} }}[/tex]
[tex]{ \tt{ = \frac{ - \frac{1}{2} - ( - \frac{1}{6} ) }{ 2 } }} \\ \\ = { \tt{ - \frac{1}{6} }}[/tex]
Answer:
- [tex]\frac{1}{12}[/tex]
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is
[tex]\frac{f(b)-f(a)}{b-a}[/tex]
Here [ a, b ] = [ - 1, 3 ] , then
f(3) = [tex]\frac{1}{3-5}[/tex] = - [tex]\frac{1}{2}[/tex]
f(- 1) = [tex]\frac{1}{-1-5}[/tex] = - [tex]\frac{1}{6}[/tex]
average rate of change
= [tex]\frac{-\frac{1}{2}-(-\frac{1}{6}) }{3-(-1)}[/tex]
= [tex]\frac{-\frac{1}{2}+\frac{1}{6} }{3+1}[/tex]
= [tex]\frac{-\frac{1}{3} }{4}[/tex]
= - [tex]\frac{1}{12}[/tex]
In a sample of 56 bags of fertilizer, the average weight was found to be 17.2lb with a standard deviation of 0.7. Give a point estimate for the population standard deviation of the weight of the bags of fertilizer.
Answer:
???????????????????????
The figure below consists of a rectangle and a
semicircle. Find the perimeter of the figure. Use π =
3.14.
Step 1: Find the perimeter of the rectangle
The rectangle has two lengths and one width that we need to add together. The width of the rectangle is equal to 2 times the radius (or the diameter) of the circle, which is 16.
25 + 25 + 16 = 66
Step 2: Find the perimeter of the semicircle
The perimeter of a semicircle is equal to half of the circumference.
C = pi x diameter
1/2 (3.14) x (16) = 25.12
Step 3: Find the perimeter of the figure
All that's left to do is add the two perimeters together.
66 + 25.12 = 91.12 m
Hope this helps!
If POR ~ ASTU, what is the scale factor of APQR to ASTU?
A. 1/5
B. 1/4
C. 5
D. 4
Answer:
[tex]k = \frac{1}{5}[/tex]
Step-by-step explanation:
Given
The attached triangles
Required
The scale factor
From the attachment, we have:
[tex]TU = 4[/tex]
[tex]QR = 20[/tex]
So, the scale factor from PQR to STU is:
[tex]k = \frac{TU}{QR}[/tex]
[tex]k = \frac{4}{20}[/tex]
[tex]k = \frac{1}{5}[/tex]
Which one correct answer??
What is the question of it ?