Answer:
Bone Marrow, or Cartilage
Predict the molecular structure (including bond angles) for each of the following.
a. PCl3
b. SCl2
c. SiF4
Answer:
PCl3 - trigonal pyramidal <109 degrees
SCl2 - bent<109 degrees
SiF4 - tetrahedral 109 degrees
Explanation:
The shape of all three molecules derive from a tetrahedral arrangement of electron pairs.
However, in PCl3 there is a lone pair of electrons on P and three bond pairs. This leads to the observance of a trigonal pyramidal geometry with bond angle <109 degrees.
In SCl2, there are four regions of electron density around S, two lone pairs and two bond pairs leading to a bent molecular geometry with bond angle <109 degrees.
In SiF4, there are four bond pairs and no lone pair. The molecular geometry is tetrahedral with a bond angle of 109 degrees.
What happens after condensation to cause precipitation?
A
The sun heats water on the Earth's surface.
B
Water is absorbed into the ground.
C
Clouds fill with moisture and get too heavy.
D
Excess water runs downhill.
Answer:
The answer is c, Clouds fill with moisture and get too hravy
Write the formula for diphosphorous pentoxide
Answer:
P4O10
Explanation:
Protons and neutrons are similar because they both:
cause objects to become charged
are attracted to electrons
are found in the nucleus of an atom
have positive charges
Answer:
C. are found in the nucleus of an atom
Explanation:
Protons and Neutrons are always located at the center of the atom also called as the nuclei of the atom and constitute nearly all the mass of the atom, while the electrons revolve around them in orbits called shells. Only protons have a positive charge and electrons have negative charges, due to which only protons and electrons attract each other, while neutrons lack charges or have 'Neutral Charges'.
What term is used when heat is transferred from one piece of matter to another until they are of equal temperature?
thermal contact
When heat flows from one object or substance to another it is in contact with, the objects or substances are said to be in thermal contact. The state where objects in thermal contact with each other reach the same temperature, no heat flows between them.
#1...TRUE/FALSE, the best way to write a conclusion is to use the RERUN method.?
#2...TRUE/FALSE, an example of an inference is “I saw it rain today.”?
#3...TRUE/FALSE, an example of a quantitative observation is “That is a red doll.”?
#4...TRUE/FALSE, a scientific hypothesis is written as “If [independent variable] Then [dependent variable.]”?
please answer all of them
9. If purple flowers are dominant to white flowers and
two white flowered plants are crossed, what
percentage of their offspring will be white
flowered?
What is question?
A gas sample occupies 4.39 L at 44 ºC. What will be the new volume, using Charles’ Law, if the temperature decreases to 25 ºC?
Hi there! :)
[tex]\large\boxed{x = 2.49 L}[/tex]
Use the proportion for Charles' Law where:
[tex]\frac{v_{1}}{t_{1}}= \frac{v_{2}}{t_{2}}[/tex]
v1 = initial volume
t1 = initial temperature
v2 = final volume
v2 = final temperature
Substitute in the given values into the proportion:
v1 = 4.39 L
t1 = 44° C
t2 = 25°C
v2 = x L
Set up the proportion:
[tex]\frac{4.39}{44} = \frac{x}{25}[/tex]
Cross multiply:
[tex]25 * 4.39 = 44x\\\\109.75 = 44x\\\\x = 2.49 L[/tex]
Answer:
The new volume will be approximately 2.49 L.
Explanation:
We are given that a gas sample occupies 4.39 L at 44° C.
We are also given that we are going decrease the temperature to 25° C.
Charles' Law has a formula which shows the relationship between the volumes of a samples and the temperatures of the samples.
The proportion is shown as:
[tex]\displaystyle \bullet \ \ \ \frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex],
where V₁ and V₂ are the initial and final volume respectively and T₁ and T₂ are the initial and final temperature respectively.
This proportion can be used to determine what our unknown is. We need to know the final volume.
[tex]\displaystyle \frac{4.39 \ \text{L}}{44 \ \text{C}} = \frac{\text{x}}{25 \ \text{C}}\\\\\\\frac{4.39}{44} = \frac{x}{25}\\\\\\4.39 \times 25 = 44 \times x\\\\\\44x = 109.75\\\\\\\frac{44x}{44}=\frac{109.75}{44}\\\\\\x = 2.49432 \approx \boxed{2.49 \ \text{L}}[/tex]
Therefore, if we reduce the temperature to 25 °C, we will be reducing the volume of the substance to 2.49 L.
A solution has a pH of 11.75. Calculate the [H:0*] of the solution
The [H₃0⁺] of the solution : 1.778 x 10⁻¹² M
Further explanationpH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.
pH = - log [H⁺]
So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.
A solution whose value is different by n has a difference in the concentration of H⁺ ion of 10ⁿ.
pH of solution = 11.75
the [H₃0⁺] of the solution :
[tex]\tt pH=-log[H_3O^+]\\\\11.75=-log[H_3O^+]\\\\(H_3O^+]=10^{-11.75}=1.778\times 10^{-12}[/tex]
The volume of a sample of gas measured at 35 C and 1.00 atm pressure is 2.00 L. What must the final temperature be in order for the gas to have a final volume of 3.00 L at 1.00 atm pressure?
Answer:
the final temperature is 465.2k
At what velocity (m/s) must a 19.9 g object be moving in order to possess a kinetic energy of 1.0 J
Answer:
Explanation:
T
Answer:
for this one you would have to divide 19.9g by the kinetic energy 1.0 and you would get your answer.
Explanation:if you would give me brainiest that would help a lot :)
THE OH BOND IN WATER IS POLAR BECAUSE
Answer: In the case of water, we know that the O-H covalent bond is polar, due to the different electronegativities of hydrogen and oxygen. Since there are two O-H bonds in water, their bond dipoles will interact and may result in a molecular dipole which can be measured.
Explanation:
Part A: You are given a beaker containing a solution of an enzyme that hydrolyzes adenosine triphosphate (ATP) while it generates a lot of heat. You add a substantial amount of the sodium salt of ATP, and you measure the temperature of the beaker, and determine that nothing is happening. The enzyme is not performing the reaction. What is a reasonable chemical to add to the solution to get the enzyme to proceed with the hydrolysis of adenosine triphosphate?
Sulfur oxide,
Iron chloride,
magnesium chloride,
or add more sodium ATP.
Part B: You are investigating the reduction of oxygen that is performed by cytochrome c oxidase. As you start the reaction in a slightly acidic aqueous buffer with 2 mM Cu2SO4 and bubbling oxygen into the buffer. As the reaction proceeds, the solution slowly turns blue, what is happening?
a) Ozone is formed. This causes the solution to turn blue.
b) The copper is getting oxidized from Cu+ to Cu2+ and turns blue.
c) The cytochrome c oxidase protein is decomposing down to a blue product.
d) The pH of the solution is changing. Cu2SO4 is a pH indicator that turns blue when a solution becomes basic.
Part C: In the previous reaction, if you add a small amount of cyanide before adding the
Cu2SO4, the solution does not turn blue. What is a reasonable explanation?
a) The cyanide ion displaces the copper ions in the cytochrome c oxidase and stops the redox reaction.
b) The cyanide ion keeps the pH of the solution high. So the Cu2SO4 pH indicator does not show the decrease in pH.
c) The cyanide ion prevents the formation of ozone.
Answer:
1) magnesium chloride
2) b) The copper is getting oxidized from Cu+ to Cu2+ and turns blue.
Explanation:
The work published by David N. Frick, Sukalyani Banik, and Ryan S. Rypma in J Mol Biol. 2007 Jan 26; 365(4): 1017–1032 clearly shows that divalent metal ions of group 2 such as Mg^2+ play an important role in ATP hydrolysis. Addition of EDTA decreased the rate of hydrolysis of ATP (due to sequestration of the divalent ion of group 2) indicating an active participation of divalent ions in the process.
2) The copper I ion is colourless because it is a d^10 specie. However, when it is oxidized to Cu^2+, a blue colour appears in the solution.
What is the total charge of an iron nucleus
A sample of radioactive material starts with 80 grams. After 3 half-lives have passed, how much radioactive sample remains?
Answer:
After 3 half lives 10 g of radio active material left.
Explanation:
Given data:
Total amount of radio active material = 80 g
Amount left after 3 half lives = ?
Solution:
At time zero = 80 g
At first half life = 80 g/2 = 40 g
At 2nd half life = 40 g/2 = 20 g
At 3rd half life = 20 g/2 = 10 g
Thus, after 3 half lives 10 g of radio active material left.
What is the name of the tides when the moon
is in 1st and 3rd quarter?
1 carbon atom mixed with 1 oxygen atom what is the formula
Answer:
carbon mono oxide CO
Explanation:
as both are in 1:1 ratio so CO is formed
What is the average Mw for a fatty acid mixture whose fats (1 gram) required 0.0034 equivalents of NaOH to titrate. Remember: 1 Fatty acid has 1 equivalent.
1. Ew = Mw (#H+)
2. Ew = mass/eq
a.) 294.12 g/mol
b.) 145.04 g/mol
c.) 345.56 g/mol
d.) 132.04 g/mol
Answer:
a.) 294.12 g/mol
Explanation:
1 equivalent of fatty acid reacts with 1 equivalent of NaOH.
As in the titration are required 0.0034 equivalents of NaOH, the equivalents of fatty acids = moles of fatty acids are:
0.0034 moles of fatty acids
Molar mass is defined as the ratio between mass of substance in a determined amount of moles. The mass of the fats was 1 gram, that means the molar mass is:
1g / 0.0034moles =
294.12g/mol
Right option is:
a.) 294.12 g/molHow many joules are required to melt 250 grams of water
Answer:
i not sure but i searched it up and it said Q=104525J
Explanation:
What mass (in grams) of silver contains the same number of atoms as 5.59 grams of sulfur?
Answer:
18.84 g of silver.
Explanation:
We'll begin by calculating the number atoms present in 5.59 g of sulphur. This can be obtained as follow:
From Avogadro's hypothesis,
1 mole of sulphur contains 6.02×10²³ atoms.
1 mole of sulphur = 32 g
Thus,
32 g of sulphur contains 6.02×10²³ atoms.
Therefore, 5.59 g of sulphur will contain = (5.59 × 6.02×10²³) / 32 = 1.05×10²³ atoms.
From the calculations made above, 5.59 g of sulphur contains 1.05×10²³ atoms.
Finally, we shall determine the mass of silver that contains 1.05×10²³ atoms.
This is illustrated below:
1 mole of silver = 6.02×10²³ atoms.
1 mole of silver = 108 g
108 g of silver contains 6.02×10²³ atoms.
Therefore, Xg of silver will contain 1.05×10²³ atoms i.e
Xg of silver = (108 × 1.05×10²³)/6.02×10²³
Xg of silver = 18.84 g
Thus, 18.84 g of silver contains the same number of atoms (i.e 1.05×10²³ atoms) as 5.59 g of sulfur
someone please help me answer this i’m struggling and i will give branliest
Answer:
bottom right corner with arrows going up
The Earth and the spaceship both have mass. The astronaut is attracted to Earth by gravity, but he is not attracted to the spaceship. Explain.
As explained by kinetic theory, what causes gas pressure? *
A:The gain of energy from the collisions of gas particles with one another
B:The loss of energy from the collisions of gas particles with one another
C:The collisions between an object and rapidly moving gas particles
D:The weight of stationary gas particles upon a unit area of an object
Answer:
i think the answer is c
Explanation:
collission
10 mL of a 0.65 M KMnO4 solution is diluted to a concentration of 0.055 M. What is the final volume of the diluted solution?
a. 20.0 mL
b. 0.846 mL
c. 108 ml
d. 118 ml
Answer:
118 mL
Explanation:
We can easily calculate the final volume of the solution (V₂) by applying the following mathematical expression:
V₁ x C₁ = V₂ x C₂
⇒ V₂ = V₁ x C₁/C₂
Given:
V₁ = 10 mL
C₁ = 0.65 M
C₂ = 0.055 M
We replace the data in the mathematical expression to calculate V₂:
V₂ = V₁ x C₁/C₂ = 10 ml x (0.65 M)/ (0.055 M) = 118.18 mL ≅ 118 mL
A sample of an unknown compound is vaporized at 150.°C . The gas produced has a volume of 960.mL at a pressure of 1.00atm , and it weighs 0.941g . Assuming the gas behaves as an ideal gas under these conditions, calculate the molar mass of the compound. Round your answer to 3 significant digits.
Answer:
the molar mass of the compound is 34.0 g /mol
Explanation:
The computation of the molar mass of the compound is as follows:
As we know that
PV = nRT
n = mass ÷ MW
PV = mRT ÷ MW
It can be rearrange as
MW = mRT ÷ (PV)
MW = (0.941)(0.082)(150 + 273) ÷ (1 × 0.96)
= 33.99g/mol
= 34.0 g /mol
Hence, the molar mass of the compound is 34.0 g /mol
How many mL of 0.125 M Ba(OH)2 would be required to completely neutralize 75.0 mL of 0.845 M HCl? What is the pH of the solution at the equivalence point?
Answer:
253.5mL of Ba(OH)₂ are required to neutralize the HCl solution
The pH at equivalence point is = 7
Explanation:
The reaction of Ba(OH)₂ with HCl is:
Ba(OH)₂ + 2HCl → BaCl₂ + 2H₂O
First, we need to find moles of HCl. With these moles and the chemical equation we can find the moles of Ba(OH)₂ and the volume required:
Moles HCl:
75.0mL = 0.075L * (0.845mol / 1L) = 0.063375moles HCl
Moles Ba(OH)₂:
0.06338moles HCl * (1mol Ba(OH)₂ / 2mol HCl) = 0.03169 moles Ba(OH)₂
Volume of the 0.125M Ba(OH)₂:
0.03169 moles Ba(OH)₂ * (1L / 0.125mol) = 0.2535L are required =
253.5mL of Ba(OH)₂ are required to neutralize the HCl solution
As the titration was of a strong acid, HCl, with a strong base, Ba(OH)₂, the pH at equivalence point is = 7
what is the molarity of a solution made by adding 0.720 mole of NaOH to 2.40 liters of water
Answer:
Molarity = 0.3 M
Explanation:
Given data:
Moles of NaOH = 0.720 mol
Volume of water = 2.40 L
Molarity = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Molarity = 0.720 mol / 2.40 L
Molarity = 0.3 mol/L
Molarity = 0.3 M
Pls help plssssssdsss
Answer:
i do k12 too!
Explanation:
lol
. If you have 4.65 moles of H2 gas from: 2H2 + O2 → 2H2O
a. How much Oxygen is needed to completely react with hydrogen?
O2? =
b. How many moles of water will be produced?
H2O? =
Work shown would be appreciated ❤️
20 points!!!!
Answer:
35.453 amu.
Explanation:
From the question given above, the following data were obtained:
Isotope A (Cl–35):
Abundance (A%) = 75.77%
Mass of A = 34.969 amu
Isotope B (Cl–37):
Abundance (B%) = 24.23%
Mass of B = 36.966 amu
AVERAGE atomic mass of Cl =?
The average atomic mass of Cl can be obtained as follow:
Average = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
Average = [(34.969 × 75.77)/100] + [(36.966 × 24.23)/100]
Average = 26.496 + 8.957
Average atomic mass of Cl = 35.453 amu.