Answers
Answer: Tis 0
Step-by-step explanation:
Related Questions
The 100th term of 8, 8^4, 8^7, 8^10, …
Answers
Answer:
[tex]8^{298} \\8^{3(n-1)+1}[/tex]
Step-by-step explanation:
Answer:
8^298
Step-by-step explanation:
n = 1, 8^(1 + 0 * 3)
n = 2, 8^(1 + 1 * 3)
n = 3, 8^(1 + 2 * 3)
n = 4, 8^(1 + 3 * 3)
The exponent of 8 is 1 added to product of 1 less than the term number multiplied by 3.
n = n, 8^(1 + [n - 1] * 3) = 8^(1 + 3n - 3) = 8^(3n - 2)
For n = 100, the exponent is
3n - 2 = 3(100) - 2 = 300 - 2 = 298
Answer: 8^298
what percentage of undergraduates students in Calculus 1 are required to do computer assignments in their classes
Answers
Full question:
Every 5 years the Conference Board of the Mathematical Sciences surveys college math departments. In 2000 the board reported that 51% of all undergraduates taking Calculus I were in classes that used graphing calculators and 31% were in classes that used computer assignments. Suppose that 16% used both calculators and computers. a) What percent used neither kind of technology? b) What percent used calculators but not computers? c) What percent of the calculator users had computer assignments? d) Based on this survey, do calculator and computer use appear to be independent events? Explain.
Answer:
a. 34%
b. 35%
c. 31.4%
d. Independent events
Explanation:
a. To calculate percentage that used neither kind of technology, we already know those that use the technologies and total taking calculus so:
100%-51%-31%-16%= 34%
b. Percentage that used calculators but not computers.
= 51%-16%=35%
c. Percentage of the calculator users that had computer assignments?
= 16/51×100=31.4% (there are 16 people using both so that as a percentage of 51 people using calculators)
d. Independent events are events that do not affect the other, such that occurrence of one does not define occurrence of the other. Since percentage of calculator and computer assignment users is close to those who are not using any, we can say they are independent events.
The data on the box plot describes the weight of several students in sixth grade. Which of the following statements are true about the data set? Select all that apply.
One-fourth of the students weigh between 90 and 101 pounds.
One-half of the students weigh between 75 and 90 pounds.
The median weight of the sixth graders is 85 pounds.
One-fourth of the students weigh less than 75 pounds.
One-fourth of the students weigh more than 75 pounds.
The total range of weight is 40 pounds.
Answers
Answer:
Step-by-step explanation:
B
what are the coordinates of the point that is 1/6 of the way from a(14 -1) to b(-4 23)
Answers
9514 1404 393
Answer:
(11, 3)
Step-by-step explanation:
That point is ...
P = a + (1/6)(b -a) = (5a +b)/6
P = (5(14, -1) +(-4, 23))/6 = (70-4, -5+23)/6 = (11, 3)
The point of interest is (11, 3).
Answer:
The coordinates of the point that is 1/6 of the way from a to b is thus (11, 3)
Step-by-step explanation:
Let's look first at the x coordinates of the two given points: 14 and -4. From 14 to -4 is a decrease of 18. Similarly, from y = -1 to y = 23 is an increase of 24.
Starting at a(14, -1) and adding 1/6 of the change in x, which is -18, we get the new x-coordinate 14 + (1/6)(-18), or 14 - 3, or 11. Similarly, adding 1/6 of the increase in y of 24 yields -1 + 4, or 3.
The coordinates of the point that is 1/6 of the way from a to b is thus (11, 3)
What is the median of the following set of values? 7, 21, 19, 15, 19, 14, 15, 19
Answers
7, 14, 15, 15, 19, 19, 19, 21
The median is 15 and 19. OR 17, because 15+19=34/2 which equals 17.
The median of the following set of values is equals to 17.
What are median?Median represents the middle value of the given data when arranged in a particular order. The mean is the average value which can be calculated by dividing the sum of observations by the number of observations
We are given that the median of the following set of values
7, 21, 19, 15, 19, 14, 15, 19
Line them up in order first.
7, 14, 15, 15, 19, 19, 19, 21
Here the middle value are 15 and 19.
The median is 15 and 19. OR 17,
Therefore, 15 + 19 = 34/2 which equals to 17.
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What does it mean if a project has a Percent Spent of 90%, Percent Scheduled of 85%, and a Percent Complete of 95%
Answers
Answer:
It means that the project is in good shape, within budget an d it would finish early
Step-by-step explanation:
The answer to this question is pretty straight forward. If a project has the percent spent fine 90 percent, the scheduled has percentage of 85 percent and the complete is at the percentage of 95, what it means is that this project is in good shape, the project being carried out is still being done within the proposed budget and at 95% complete, it means that the project is going to finish early.
What is the solution set of the equation x2+3*-4=6
Answers
Answer:
x=9
Step-by-step explanation:
A coin is tossed times and comes up heads times. Use the Empirical Method to approximate the probability that the coin comes up heads. Round your answer to four decimal places as necessary.
Answers
Answer:
[tex]P(head) = 0.5600[/tex]
Step-by-step explanation:
Given
[tex]n = 500[/tex] -- number of toss
[tex]head = 280[/tex] --- outcomes of head
See comment
Required
Empirical probability of head
This is calculated as:
[tex]P(head) = \frac{n(head)}{n}[/tex]
[tex]P(head) = \frac{280}{500}[/tex]
[tex]P(head) = 0.5600[/tex]
Find the missing number?
Answers
Answer:
65 solve theprob
Step-by-step explanation:
sinolove ko po yan paki brainly
Carly is the principal at a middle school and wants to know the average IQ of all the female, seventh-grade students. She does not know anything about what the population distribution looks like. She took a simple random sample of 31 seventh-grade girls in her school and found the average IQ score in her sample was 105.8 and the standard deviation was 15. Assume that all conditions are met, construct the 96% Confidence interval for the average IQ score of all seventh-grade girls in the school.
Answers
Answer:
The 96% confidence interval for the average IQ score of all seventh-grade girls in the school is (105, 111.6).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 31 - 1 = 30
96% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 30 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.96}{2} = 0.98[/tex]. So we have T = 2.15
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.15\frac{15}{\sqrt{31}} = 5.8[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 105.8 - 5.8 = 105.
The upper end of the interval is the sample mean added to M. So it is 105.8 + 5.8 = 111.6
The 96% confidence interval for the average IQ score of all seventh-grade girls in the school is (105, 111.6).
Please Help NO LINKS
Answers
[tex]V = 864\pi[/tex]
Step-by-step explanation:
Since one of the boundaries is y = 0, we need to find the roots of the function [tex]f(x)=-2x^2+6x+36[/tex]. Using the quadratic equation, we get
[tex]x = \dfrac{-6 \pm \sqrt{36 - (4)(-2)(36)}}{-4}= -3,\:6[/tex]
But since the region is also bounded by [tex]x = 0[/tex], that means that our limits of integration are from [tex]x=0[/tex] (instead of -3) to [tex]x=6[/tex].
Now let's find the volume using the cylindrical shells method. The volume of rotation of the region is given by
[tex]\displaystyle V = \int f(x)2\pi xdx[/tex]
[tex]\:\:\:\:\:\:\:= \displaystyle \int_0^6 (-2x^2+6x+36)(2 \pi x)dx[/tex]
[tex]\:\:\:\:\:\:\:= \displaystyle 2\pi \int_0^6 (-2x^3+6x^2+36x)dx[/tex]
[tex]\:\:\:\:\:\:\:= \displaystyle 2\pi \left(-\frac{1}{2}x^4+2x^3+18x^2 \right)_0^6[/tex]
[tex]\:\:\:\:\:\:\:= 864\pi [/tex]
4
920
26°
?
74°
find the missing angle.
Answers
9514 1404 393
Answer:
44°
Step-by-step explanation:
The sum of the marked angles on the right is equal to the sum of the marked angles on the left:
? + 74 = 92 + 26
? = 92 +26 -74 = 44
The missing angle is 44°.
_____
Additional comment
The vertical angles in the center of the figure are v = 62°, the measure required to bring the total to 180° in each triangle. We have shortcut the equation(s) ...
? + 74 + v = 180 = 92 + 26 + v
by subtracting v from both sides, giving ...
? +74 = 92 +26
Each side of a square is increasing at a rate of 4 cm/s. At what rate (in cm2/s) is the area of the square increasing when the area of the square is 25 cm2
Answers
Answer:
The area of the square is increasing at a rate of 40 square centimeters per second.
Step-by-step explanation:
The area of the square ([tex]A[/tex]), in square centimeters, is represented by the following function:
[tex]A = l^{2}[/tex] (1)
Where [tex]l[/tex] is the side length, in centimeters.
Then, we derive (1) in time to calculate the rate of change of the area of the square ([tex]\frac{dA}{dt}[/tex]), in square centimeters per second:
[tex]\frac{dA}{dt} = 2\cdot l \cdot \frac{dl}{dt}[/tex]
[tex]\frac{dA}{dt} = 2\cdot \sqrt{A}\cdot \frac{dl}{dt}[/tex] (2)
Where [tex]\frac{dl}{dt}[/tex] is the rate of change of the side length, in centimeters per second.
If we know that [tex]A = 25\,cm^{2}[/tex] and [tex]\frac{dl}{dt} = 4\,\frac{cm}{s}[/tex], then the rate of change of the area of the square is:
[tex]\frac{dA}{dt} = 2\cdot \sqrt{25\,cm^{2}}\cdot \left(4\,\frac{cm}{s} \right)[/tex]
[tex]\frac{dA}{dt} = 40\,\frac{cm^{2}}{s}[/tex]
The area of the square is increasing at a rate of 40 square centimeters per second.
Find the maximum and the minimum value of the following objective function, and the value of x and y at which they occur. The function F=2x+16y subject to 5x+3y≤37, 3x+5y≤35, x≥0, y≥0
The maximum value of the objective function is ___ when x=___ and y=___
Answers
Answer:
The maximum value of the objective function is 112 when x = 0 and y = 7.
Step-by-step explanation:
Given the constraints:
5x+3y≤37, 3x+5y≤35, x≥0, y≥0
Plotting the above constraints using geogebra online graphing tool, we get the solution to the constraints as:
A(0, 7), B(7.4, 0), C(5, 4) and D(0, 0)
The objective function is given as E =2x+16y, therefore:
At point A(0, 7): E = 2(0) + 16(7) = 112
At point B(7.4, 0): E = 2(7.4) + 16(0) = 14.8
At point C(5, 4): E = 2(5) + 16(4) = 74
At point D(0, 0): E = 2(0) + 16(0) = 0
Therefore the maximum value of the objective function is at A(0, 7).
The maximum value of the objective function is 112 when x = 0 and y = 7.
Mrs Lee used 6 Meters of material to make 3 dresses. She used 4 ties as much material for a curtain as for a dress. How much material did she use for the curtain? (Dress)
Answers
Answer:
for each dress she used 6/3 of material
=2
then for a curtain =2x4=8 materials
Which of the following statements provides the correct freezing and boiling points of water on the Celsius and Fahrenheit temperature scales?
Answers
The freezing point of water is 0°C or 32°F while the boiling point of water is 100°C or 212°F.
TemperatureTemperature is the measure of the degree of hotness or coldness of a substance or place. It is usually expressed Fahrenheit and Celsius scale. Temperature indicates the direction of heat flow.
The freezing point of water is 0°C or 32°F while the boiling point of water is 100°C or 212°F.
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19.Find dy/dx
of the function y = f(x) definded by x²+xy-y2 = 4.
Answers
Answer:
2x + y
Step-by-step explanation:
x² + xy - y² = 4
→ Remember the rule, bring the power down then minus 1
2x + y
a/b=2/5 and b/c=3/8 find a/c
Answers
Answer:
[tex]\frac{a}{c}[/tex] = [tex]\frac{3}{20}[/tex]
Step-by-step explanation:
[tex]\frac{a}{c}[/tex] = [tex]\frac{a}{b}[/tex] × [tex]\frac{b}{c}[/tex] = [tex]\frac{2}{5}[/tex] × [tex]\frac{3}{8}[/tex] = [tex]\frac{6}{40}[/tex] = [tex]\frac{3}{20}[/tex]
What does p(B/A) represent?
Answers
Answer:
I believe you're asking about P(B|A).
Step-by-step explanation:
So,
P(B|A) represents the probability of event B occurring after it is assumed that event A has already occurred.
P(B|A) means "Event B given Event A" . In other words, event A has already happened, now what is the chance of event B? P(B|A) is also called the "Conditional Probability" of B given A.
Overige
1) IF A = {2,3, 5, 7, 11 OR Write four subdivisions of this set.
2) A set of sub-sets of any set from the figure below.
с
5
25
35
D
15
10
30
20
3) Find out which of the following sets is a subset of which set of figures.
1
с
B
A
1) X = A set of self-contained lines
U
Y- set of all the elements above line AB
Answers
Answer:
the answae is D THEN C THE. 1
For each of the following, assume that the two samples are obtained from populations with the same mean, and calculate how much difference should be expected, on average, between the two sample means. Each sample has n =4 scores with s^2 = 68 for the first sample and s^2 = 76 for the second. (Note: Because the two samples are the same size, the pooled variance is equal to the average of the two sample variances).
a) 4.24.
b) 0.24.
c) 8.48.
d) 6.00.
Next, each sample has n=16 scores with s^2 = 68 for the first sample and s^2 = 76 for the second.
a) 0.12.
b) 2.12.
c) 4.24.
d) 3.00.
Answers
Answer:
d)6.00
d)3.00
Step-by-step explanation:
We are given that
n=4 scores
[tex]S^2_1=68[/tex]
[tex]S^2_2=76[/tex]
We have to find the difference should be expected, on average, between the two sample means.
[tex]S_{M_1-M_2}=\sqrt{\frac{S^2_1}{n_1}+\frac{S^2_2}{n_2}}[/tex]
[tex]n_1=n_2=4[/tex]
Using the formula
[tex]S_{M_1-M_2}=\sqrt{\frac{68}{4}+\frac{76}{4}}[/tex]
[tex]S_{M_1-M_2}=\sqrt{\frac{68+76}{4}}[/tex]
[tex]S_{M_1-M_2}=\sqrt{36}=6[/tex]
Option d is correct.
Now, replace n by 16
[tex]n_1=n_2=16[/tex]
[tex]S_{M_1-M_2}=\sqrt{\frac{68}{16}+\frac{76}{16}}[/tex]
[tex]S_{M_1-M_2}=\sqrt{\frac{68+76}{16}}[/tex]
[tex]S_{M_1-M_2}=\sqrt{9}=3[/tex]
Option d is correct.
I need help with this, please.
Answers
Answer:
it can not cleared clear but it can not cleared
1. Using the factorisation method, simplify the following √32
Answers
Answer:
[tex]4 \sqrt{2} [/tex]
[tex] \sqrt{32} = \sqrt{16 \times 2} = 4 \sqrt{2} [/tex]
Help someone please
A car uses 3/4% of a tank of gasoline to go 600 kilometers. What must one know to be able to determine how many kilometers the car gets per liter?
(1) the number of liters the tank holds
(2) the cost of gasoline per liter
(3) the average daily mileage of the driver (4) the relative age of the car
(5) the ratio of the mass to volume of the car
Answers
Answer:
(1) the number of liters the tank holds
Step-by-step explanation:
The histogram below shows the distribution of the assets (in millions of dollars) of 71 companies. Does the distribution appear to be normal? Why or why not?
No, the assets do not appear to follow a normal distribution, the values are evenly concentrated.
Yes, the assets appear to follow a normal distribution, the values are evenly distributed. No, the assets do not appear to follow a normal distribution, the values are concentrated in the center and taper off towards the ends.
Yes, the assets appear to follow a normal distribution, the values are concentrated in the center and taper off towards the ends.
Answers
Answer:
Yes, the assets appear to follow a normal distribution, the values are concentrated in the center and taper off towards the ends
Step-by-step explanation:
The distribution shown above is normal as it exhibits symmetry. This means thatvtge values are concentrated in the middle with the peak so situated in the middle of the distribution which is exactly what is displayed above. As we move towards either side of the center, the values begin to decrease and we have the tail at either side of the midpoint and not on one side of the distribution.
The function in the table is quadratic:
True**
False
Answers
Answer:
false...
to be quadratic you need an "x^2" in the
function
(0,1) might be 0^2 + 1
but then 1^2 + 1 = 2 than would be (1,2) NOT (1,3)
Step-by-step explanation:
write the following sets in the set builder form C={1,4,9,16,25}
Answers
C={ check example in book}
A grinding stone completes 175 revolutions before coming to a stop. How many radians did the stone complete
Answers
Answer:
175 * 2 * [tex]\pi[/tex]
350[tex]\pi[/tex] radians
Step-by-step explanation:
The number of radians completed by the stone will be 350 radians.
What is an angle in radians?The angle subtended from a circle's centre that intercepts an arc with a length equal to the circle's radius is known as a radian.
Given that a grinding stone completes 175 revolutions before coming to a stop.
The number of the revolutions in radians will be calculated as:-
Multiply the number by 2π to convert it into the radians.
Number of revolutions = 175 x 2 x π
Number of revolutions = 350 radians
Therefore, the number of radians completed by the stone will be 350 radians.
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Identify the domain of the function shown in the graph.
A. -2 ≤ x ≤ 2
B. {-2,2}
C. x is all real numbers.
D. x > -2
Answers
Answer:
C. x is all real numbers
Step-by-step explanation:
Think of domain as how far the graph expands on the x-axis as asymptotes as the limits. So in this case, the graph extends infinitely on the x-axis; so it should be all real numbers.
When P(x) is divided by (x - 1) and (x + 3), the remainders are 4 and 104 respectively. When P(x) is divided by x² - x + 1 the quotient is x² + x + 3 and the remainder is of the form ax + b. Find the remainder.
Answers
Answer:
The remainder is 3x - 4
Step-by-step explanation:
[Remember] [tex]\frac{Dividend}{Divisor} = Quotient + \frac{Remainder}{Divisor}[/tex]
So, [tex]Dividend = (Quotient)(Divisor) + Remainder[/tex]
In this case our dividend is always P(x).
Part 1
When the divisor is [tex](x - 1)[/tex], the remainder is [tex]4[/tex], so we can say [tex]P(x) = (Quotient)(x - 1) + 4[/tex]
In order to get rid of "Quotient" from our equation, we must multiply it by 0, so [tex](x - 1) = 0[/tex]
When solving for [tex]x[/tex], we get
[tex]x - 1 = 0\\x - 1 + 1 = 0 + 1\\x = 1[/tex]
When [tex]x = 1[/tex],
[tex]P(x) = (Quotient)(x - 1) + 4\\P(1) = (Quotient)(1 - 1) + 4\\P(1) = (Quotient)(0) + 4\\P(1) = 0 + 4\\P(1) = 4[/tex]
--------------------------------------------------------------------------------------------------------------
Part 2
When the divisor is [tex](x + 3)[/tex], the remainder is [tex]104[/tex], so we can say [tex]P(x) = (Quotient)(x + 3) + 104[/tex]
In order to get rid of "Quotient" from our equation, we must multiply it by 0, so [tex](x + 3) = 0[/tex]
When solving for [tex]x[/tex], we get
[tex]x + 3 = 0\\x + 3 - 3 = 0 - 3\\x = -3[/tex]
When [tex]x = -3[/tex],
[tex]P(x) = (Quotient)(x + 3) + 104\\P(-3) = (Quotient)(-3 + 3) + 104\\P(-3) = (Quotient)(0) + 104\\P(-3) = 0 + 104\\P(-3) = 104[/tex]
--------------------------------------------------------------------------------------------------------------
Part 3
When the divisor is [tex](x^2 - x + 1)[/tex], the quotient is [tex](x^2 + x + 3)[/tex], and the remainder is [tex](ax + b)[/tex], so we can say [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]
From Part 1, we know that [tex]P(1) = 4[/tex] , so we can substitute [tex]x = 1[/tex] and [tex]P(x) = 4[/tex] into [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]
When we do, we get:
[tex]4 = (1^2 + 1 + 3)(1^2 - 1 + 1) + a(1) + b\\4 = (1 + 1 + 3)(1 - 1 + 1) + a + b\\4 = (5)(1) + a + b\\4 = 5 + a + b\\4 - 5 = 5 - 5 + a + b\\-1 = a + b\\a + b = -1[/tex]
We will call [tex]a + b = -1[/tex] equation 1
From Part 2, we know that [tex]P(-3) = 104[/tex], so we can substitute [tex]x = -3[/tex] and [tex]P(x) = 104[/tex] into [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]
When we do, we get:
[tex]104 = ((-3)^2 + (-3) + 3)((-3)^2 - (-3) + 1) + a(-3) + b\\104 = (9 - 3 + 3)(9 + 3 + 1) - 3a + b\\104 = (9)(13) - 3a + b\\104 = 117 - 3a + b\\104 - 117 = 117 - 117 - 3a + b\\-13 = -3a + b\\(-13)(-1) = (-3a + b)(-1)\\13 = 3a - b\\3a - b = 13[/tex]
We will call [tex]3a - b = 13[/tex] equation 2
Now we can create a system of equations using equation 1 and equation 2
[tex]\left \{ {{a + b = -1} \atop {3a - b = 13}} \right.[/tex]
By adding both equations' right-hand sides together and both equations' left-hand sides together, we can eliminate [tex]b[/tex] and solve for [tex]a[/tex]
So equation 1 + equation 2:
[tex](a + b) + (3a - b) = -1 + 13\\a + b + 3a - b = -1 + 13\\a + 3a + b - b = -1 + 13\\4a = 12\\a = 3[/tex]
Now we can substitute [tex]a = 3[/tex] into either one of the equations, however, since equation 1 has less operations to deal with, we will use equation 1.
So substituting [tex]a = 3[/tex] into equation 1:
[tex]3 + b = -1\\3 - 3 + b = -1 - 3\\b = -4[/tex]
Now that we have both of the values for [tex]a[/tex] and [tex]b[/tex], we can substitute them into the expression for the remainder.
So substituting [tex]a = 3[/tex] and [tex]b = -4[/tex] into [tex]ax + b[/tex]:
[tex]ax + b\\= (3)x + (-4)\\= 3x - 4[/tex]
Therefore, the remainder is [tex]3x - 4[/tex].
