What is the surface area of the cube, in square inches?

Answer:

max: -4

Step-by-step explanation:

(x+3)^2 》0 mọi x

<=> -(x+3)^2 《0

<=> -(x+3)^2 -4 《 -4

Answer:

D

Step-by-step explanation:

The opposite faces of the prism are congruent , then

SA = areas of (top/bottom + front/ back + 2 sides )

     = 2(19 × 16) + 2(19 × 10) + 2(16 × 10)

     = 2(304) + 2(190) + 2(160)

     = 608 + 380 + 320

     = 1308 m² → D

The total Surface Area is 1308 m²

The total area occupied by the surfaces of an object is called its surface area. In geometry, different 3D shapes have different surface areas which can be easily calculated using the formulas that we will be learning in this article. The surface area is classified into two categories:

The total surface area of a prism = Lateral surface area of prism + area of the two bases = (2 × Base Area) + Lateral surface area = (2 × Base Area) + (Base perimeter × height).

SA = areas of (top/bottom + front/ back + 2 sides )

= 2(19 × 16) + 2(19 × 10) + 2(16 × 10)

= 2(304) + 2(190) + 2(160)

= 608 + 380 + 320

= 1308 m²

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Answer:

A. Angle Y is a right angle.

B. The measure of angle Z is 45°.

E. The perpendicular bisector of creates two smaller isosceles triangles.

Step-by-step explanation:

Let x represent the measures of base angles X and Z. 2x is the measure of vertex angle Y.

x + x + 2x = 180°

x = 45°

2x = m∠Y = 90°

The triangle is an isosceles right triangle which has base angles of 45°.

The perpendicular bisector of line XZ creates two smaller isosceles triangles with acute angles of 45°

Answer:

The answers are A B E

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Answer:

I don't understand the question, but I think its 18°

Step-by-step explanation:

Cot A=1/tan A=12/5

cos A= 12/13

sin A=5/13

Draw a right angled triangle

the hypotenuse is the longest side which is 13 using Pythagoras theorem

the side opposite the angle A is 5

the side closest to the angle A which is called the adjacent is 12

sinA =opp/hyp

cos A= adj/hyp

cotA =1/tanA=cos A/sinA

Note: Pythagoras theorem is

hyp²=opp²+adj²

Answer:

Step-by-step explanation:

[tex]tan \ A = \frac{5}{12}=\frac{opposite \ site}{adjacent \ side}[/tex]

hypotenuse² = (opposite side)² + (adjacent side)²

                      =  5² + 12²

                      = 25 + 144

                      = 169

hypotenuse = √169 = √13*13 = 13

[tex]Cot \ A = \frac{adjacent \ side}{opposite \ side}=\frac{12}{5}\\\\Cos \ A = \frac{adjacent \ side}{hypotenuse}=\frac{12}{13}\\\\Sin \ A = \frac{opposite \ side}{hypotenuse}=\frac{5}{13}[/tex]

Answer:

x = 10

Step-by-step explanation:

smaller triangle / bigger triangle = 20 / 28

hence,

3x / (4x+2) = 20/28

28(3x) = 20(4x+2)

84x = 80x + 40

4x = 40

x = 10

Step-by-step explanation:

what to find then??.........

Answer:

5

Step-by-step explanation:

m + p - p^2 ÷ 6

Let m = 5 and p=6

5 + 6 - 6^2 ÷ 6

Exponents first

5 + 6 - 36 ÷ 6

Then divide

5 + 6 - 6

Then add and subtract from left to right

11-6

5

Answer:

59.04°

58.31 inches

Step-by-step explanation:

The solution triangle is attached below :

Since we have a right angled triangle, we can apply trigonometry to obtain the angle ladder makes with the ground;

Let the angle = θ

Tanθ = opposite / Adjacent

Tanθ = 50/30

θ = tan^-1(50/30)

θ = 59.036°

θ = 59.04°

The length of ladder can be obtained using Pythagoras :

Length of ladder is the hypotenus :

Hence,

Hypotenus = √(adjacent² + opposite²)

Hypotenus = √(50² + 30²)

Hypotenus = √(2500 + 900)

Hypotenus = 58.309

Length of ladder = 58.31 inches

Answer:

59°

58.3 inches

Step-by-step explanation:

Here is the full question :

A ladder is placed 30 inches from a wall. It touches the wall at a height of 50 inches from the ground. The angle made by the ladder with the ground is degrees, and the length of the ladder is inches.

Please check the attached image for a diagram explaining this question

The angle the ladder makes with the ground is labelled x in the diagram

To find the value of x given the opposite and adjacent lengths, use tan

tan⁻¹ (opposite / adjacent)

tan⁻¹  (50 / 30)

tan⁻¹ 1.667

= 59°

the length of the ladder can be determined using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c =  hypotenuse

√(50² + 30²)

√(2500 + 900)

√3400

= 58.3 inches

Answer:

4x+y=-32

Step-by-step explanation:

given,

slope (m) = -4

point: (-8,0)

as we know the slope intercept form of the line is, y=mx+b, b=y-mx, now we put x=-8, y=0 to find b [because the point is given (-8,0) so it must satisfy the equation]

so,

b = 0-(-4)×(-8) = -32

y=mx+b

or, y=-4x-32

or, 4x+y=-32

(this is the standard form of the line)

Using the equation y - y1 = m(x - x1)

y - 0 = -4(x - (-8))

y = -4(x + 8)

y = -4x - 32

Answer:

[tex]1.6^{4}[/tex]

Step-by-step explanation:

1.6 is multiplied by itself 4 times. This is represented in exponential form as

[tex]1.6^{4}[/tex]

Hey there!

We know that Danielle earns $10 per hour, so muliply that by 3 and get 30.

Because Danielle works an extra half an hour, divide 10 by 2 and get 5.

Danielle earns $35 in 3 hours and a half.

Hope this helps! Please mark me as brainliest!

Have a wonderful day :)

Answer:

To find the leading coefficient, first expand the function:

[tex]y= -(x+3)^{2} -5\\\\y=-(x^{2} +6x+9)-5\\\\y=-x^{2} -6x-9-5\\\\y=-x^{2} -6x-14[/tex]

The leading coefficient is the coefficient of the highest-order term, which, in this case, would be the -1 from -x².

To find the vertex: see image below

Vertex = (-3, -5)

Answer:

45 / 27 = 30 / 18 = x / 24

x = 40

Step-by-step explanation:

Hi there!

The question here states that the two polygons are similar

Polygons that are similar have similar side length ratios.

If we want to find a side length we must create a proportional relationship

We are already given a partial proportional relationship.

Which is...

45 / __ = __ / 18 = x / __

First let's fill in the blanks

The side that is corresponding to the side with a length of 45 has a length of 27. So it would be 45/27

The side that is corresponding to the side with a length of 18 has a length of 30. So it would be 30/18

The side corresponding to side labeled "x" has a length of 24. so it would be x/24

So we would have

45 / 27 = 30 / 18 = x / 24

Now let's find x

We only need 2 ratios ( the one including x of course, and the other one can either be 30/18 or 45/27)

30 / 18 = x / 24

Now let's solve for x

Cross multiply

30*24=720

18*x=18x

We now have 18x = 720

Divide both sides by 18

18x / 18 = x

720 / 18 = 40

x = 40

To check our answers we can see if the ratios are similar

If they are then we are correct

45/27 = 1.66

30/18 =1.66

40/24 = 1.66

They are all equivalent meaning that our answers are correct

Answer:

geometric

x=number of terms

∑ 2(-5)^(k-1)

k=1

Step-by-step explanation:

the sequence has a ratio of -5 (2*-5=-10, -10*-5=50)

x=number of terms

∑ 2(-5)^(k-1)

k=1

for this i don't know what the last term is since it doesn't show in the question but just find 2(-5)^x and x will be the top term

The new coordinates are ( -3 , -6) , Option B is the answer.

Reflection means to create a mirror image of an object along any axis .

The shape and size of the object remains constant while reflection.

An object of coordinate ( -3 ,6) is given

This is reflected in the x axis .

When an object is reflected along any axis , the coordinate of that axis remains the same while the coordinate of the other changes to its additive inverse .

object  ( -3 ,6) is reflected along x axis ,

( x, y) ----> ( x , -y)

The new coordinates are ( -3 , -6)

Therefore Option B is the answer.

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Answer:

B

Step-by-step explanation:

27%=0.27 and sqrt(2)<2.75

Answer:

0.0125x or x/80

Step-by-step explanation:

Salary: x dollars per year

To find the pay per month, we divide the annual pay by 12.

The monthly pay is x/12

15% of the first month's salary is

15% of x/12 = 0.15 * x/12 = 0.0125x = x/80

Answer: 0.0125x

Answer:

I start to say from my name,age,family,qualifications and etc.

Answer:

In your response, do the following:

Begin by rereading the job description. Take note of the required skills that you have, and identify recent stories that demonstrate them . Ideally, you should draw primarily from recent professional experience; however, volunteer work can also support your narrative while demonstrating a commitment to your community.

Is it a more senior role? If so, explain how you are taking on more responsibilities in your current position. If you are making a lateral transition to a role with different skills, describe how your current skills translate into the new position.

When you start building the script of each example, focus on details and outcomes that you can quantify if possible. For example, stating that you “improved customer service” is less impactful than “increased customer service response rates each quarter by 10–15%.” If you don’t have the exact information, estimate a realistic value.

Since the “Tell me about yourself” interview question is about getting to know you, it’s a good idea to share your personality with your interviewer—but not personal details. You may want to briefly mention hobbies that demonstrate intellectual development and/or community engagement (e.g., reading, music, sports league, volunteering) or those that showcase personal discipline and achievement (e.g., learning a new skill, training for a half marathon). Discussing personal interests is a good way to wrap up your response while maintaining a professional tone.

For your response to be clear and concise, you’ll want to make sure you organize your answer following a format or formula. There are two common formulas you may consider:

Both of these formulas work for your response, but you may choose one over the other based on the roles from your experience that are most relevant to the position you're interviewing for. For example, if your most recent role highlights many of the skills and qualifications that are required for the role you’re interviewing with, you may want to lead with the present. However, if you're making a career transition and your past experience is more closely related to the role than your current position, you may want to lead with your past.

Answer:

The average value of the Function f(x) by squeeze theorem states that no extreme or greater value will exist within the designated area for f(x)

Answer:

x < 4

Step-by-step explanation:

|x+3| >2x-1 [|a| is the absolute value of a]

x+3 > 2x-1

4 > x

Therefore,

x < 4

The negative case doesn't have equal RHS and LHS so, it isn't valid.

Answer:

Slope-intercept form: [tex]y=-\frac{7}{4}x-\frac{19}{2}[/tex]

Point-slope-form: [tex]y-1=-\frac{7}{4}(x+6)[/tex]

Step-by-step explanation:

Hi there!

We want to find the equation of the line perpendicular to the line 4x-7y=2 that goes through (-6, 1) in slope-intercept form, as well as the point-slope form

Slope-intercept form is defined as y=mx+b, where m is the slope and b is the y intercept

Point-slope form is defined as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point

Meanwhile, perpendicular lines have slopes that are negative and reciprocal. When they are multiplied together, the result is -1

So let's find the slope of the line 4x-7y=2

The equation of the line is in standard form, which is ax+by=c, where a, b, and c are integer coefficients a is non-negative, and a and b aren't 0

So let's find the slope of the line 4x-7y=2

One way to do that is to convert the equation of the line from standard form to slope-intercept form

Our goal is to isolate y onto one side

Subtract 4x from both sides

-7y=-4x+2

Divide both sides by -7

y=[tex]\frac{4}{7}x-\frac{2}{7}[/tex]

So the slope of the line 4x-7y=2 is [tex]\frac{4}{7}[/tex]

Now, we need to find the slope of the line perpendicular to it

Use this formula: [tex]m_1*m_2=-1[/tex]

[tex]m_1[/tex] in this case is [tex]\frac{4}{7}[/tex]

[tex]\frac{4}{7}m_2=-1[/tex]

Multiply both sides by [tex]\frac{7}{4}[/tex]

m=[tex]-\frac{7}{4}[/tex]

Let's see the equation of the perpendicular line so far in slope-intercept form:

y=[tex]\frac{-7}{4}x[/tex]+b

We need to find b now

The equation of the line passes through (-6,1), so we can use it to solve for b.

Substitute -6 as x and 1 as y

[tex]1=-\frac{7}{4}*-6+b[/tex]

Now multiply

1=[tex]\frac{42}{4}+b[/tex]

Subtract 42/4 from both sides to isolate b

-19/2=b

Substitute -19/2 as b into the equation

The equation in slope-intercept form y=[tex]\frac{-7}{4}x-\frac{19}{2}[/tex]

Now, here's the equation in point-slope form

Recall that the slope is [tex]\frac{-7}{4}[/tex] , our point is (-6, 1), and point-slope form is [tex]y-y_1=m(x-x_1)[/tex]

Let's label the value of everything to avoid any confusion

[tex]m=-\frac{7}{4} \\x_1=-6\\y_1=1[/tex]

Now substitute those values into the equation

[tex]y-1=-\frac{7}{4}(x--6)[/tex]

We can simplify the x--6 to x+6

[tex]y-1=-\frac{7}{4}(x+6)[/tex]

Hope this helps!

Answer:

[tex]{ \tt{1 \: mg = 1 \times {10}^{ - 3} \: g}} \\ { \tt{75 \: mg = (75 \times 1 \times {10}^{ - 3} ) \: g}} \\ { \bf{ = 75 \times 10 {}^{ - 3} \: grams}} \\ { \bf{ = 0.075 \: grams}}[/tex]

When the Center of dilation is inside the figure

When the Center of dilation is outside the figure

    3. The original figure is closer to the the center of dilation

    4. The dilated figure is closer to the center of dilation

The center of dilation is the fixed point from which the distances in a dilation are measured

The scale factor is ratio of the side lengths of an original figure or preimage to  the side lengths of the newly formed image

Center of dilation is inside the figure

The distance of a point on the dilated figure, including the distances from the center of dilation is 3 times the distances of points on the original image from the center of dilation

Therefore, the original figure has a shorter distance to and is therefore closer to the the center of dilation than the dilated figure

     2. Where the center of dilation is inside the figure, and the scale factor is a fraction between 0 and 1 k = 1/2, we have;

The distance of a point on the dilated figure, including the distances from the center of dilation is 1/2 times the distances of points on the original image from the center of dilation

Therefore, the dilated figure has a shorter distance to and is therefore closer to the the center of dilation than the original figure

Center of dilation outside the figure

     3. Given that the center of dilation is outside the figure and the scale factor is larger than 1, k = 120% = 120/100 = 1.2 > 1, we have;

The distance of the dilated figure from the center of dilation is 120% of the distance of the original figure from the center of dilation, therefore, the original figure is closer to the the center of dilation than the dilated figure

     4. Where the center of dilation is outside the figure and the scale factor is a fraction between 0 and 1, k = 0.1 < 1

The distance of the dilated figure from the center of dilation is only 0.1 times the distance of the original figure from the center of dilation, and therefore, the dilated figure is closer to the center of dilation

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Answer:

4

Step-by-step explanation:

Func 2 is -2

Func 3 is 1

Func 4 is 8

Func 1 is unknown

Answer:

[tex]y = - \frac{3}{2} x + 1[/tex]

Step-by-step explanation:

Slope -intercept form: y= mx +c, where m is the slope and c is the y-intercept.

Parallel lines have the same slope. Let's find the slope of the given line.

Given points: (-2, 0) and (0, -3)

[tex]\boxed{slope = \frac{y1 - y2}{x1 - x2} }[/tex]

slope of given line

[tex] = \frac{0 - ( - 3)}{ - 2 - 0} [/tex]

[tex] = \frac{0 + 3}{ - 2} [/tex]

[tex] = - \frac{3}{2} [/tex]

[tex]y = - \frac{3}{2} x + c[/tex]

Given that the y- intercept is 1, c= 1.

[tex]y = - \frac{3}{2} x + 1[/tex]

Answer:

(0, -13/2) or (0, -6.5)

Step-by-step explanation:

a point on the y-axis means x=0.

so, the solution is a point (0, y).

and I assume (5, 6) is not R but is B.

for the angle at B being 90 degrees, we are looking at a right-angled triangle, and basic Pythagoras has to be true :

c² = a² + b²

with c being the Hypotenuse (the line opposite of the angle with the 90 degrees).

in our case, this c is the connection from A to C.

and a and b are the connections AB and BC.

so,

AC² = AB² + BC²

the distance between two points is again calculated via Pythagoras, where the differences in x and y directions are the sides, and the distance itself is the Hypotenuse.

so, we get

(0-0)² + (8-y)² = (0-5)² + (8-6)² + (5-0)² + (6-y)²

(8-y)² = -5² + 2² + 5² + (6-y)²

64 - 16y + y² = 25 + 4 + 25 + 36 - 12y + y²

64 - 16y + y² = 90 - 12y + y²

64 - 16y = 90 - 12y

-26 = 4y

y = -26/4 = -13/2 = -6.5

Answer:

1. a. 2

b. -½

c. y - 3 = -½(x - 8) => point-slope form

y = -½x + 7 => slope-intercept form

2. a. -1

b. 1

c. y - 5 = 1(x - 3) => point-slope form

y = x + 2 => slope-intercept form

Step-by-step explanation:

1. (8, 3) and (10, 7):

a. The gradient for the line joining the points:

Gradient = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Let,

[tex] (8, 3) = (x_1, y_1) [/tex]

[tex] (10, 7) = (x_2, y_2) [/tex]

Plug in the values

Gradient = [tex] \frac{7 - 3}{10 - 8} [/tex]

Gradient = [tex] \frac{4}{2} [/tex]

Gradient = 2

b. The gradient of the line perpendicular to this line = the negative reciprocal of 2

Negative reciprocal of 2 = -½

c. The equation of perpendicular line if it passes through the first point, (8, 3):

Equation of the perpendicular line in point-slope form can be expressed as y - b = m(x - a).

Where,

(a, b) = (8, 3)

Slope (m) = -½

Substitute (a, b) = (8, 3), and m = -½ into the point-slope equation, y - b = m(x - a).

Thus:

y - 3 = -½(x - 8) => point-slope form

We cam also express the equation of the perpendicular line in slope-intercept form by rewriting y - 3 = -½(x - 8) in the form of y = mx + b:

Thus:

y - 3 = -½(x - 8)

y - 3 = -½x + 4

y - 3 + 3 = -½x + 4 + 3

y = -½x + 7

2. (3, 5) and (4, 4):

a. The gradient for the line joining the points:

Gradient = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Let,

[tex] (3, 5) = (x_1, y_1) [/tex]

[tex] (4, 4) = (x_2, y_2) [/tex]

Plug in the values

Gradient = [tex] \frac{4 - 5}{4 - 3} [/tex]

Gradient = [tex] \frac{-1}{1} [/tex]

Gradient = -1

b. The gradient of the line perpendicular to this line = the negative reciprocal of -1

Negative reciprocal of -1 = 1

c. The equation of perpendicular line if it passes through the first point, (3, 5):

Equation of the perpendicular line in point-slope form can be expressed as y - b = m(x - a).

Where,

(a, b) = (3, 5)

Slope (m) = 1

Substitute (a, b) = (3, 5), and m = 1 into the point-slope equation, y - b = m(x - a).

Thus:

y - 5 = 1(x - 3) => point-slope form

We can also express the equation of the perpendicular line in slope-intercept form by rewriting y - 5 = 1(x - 3) in the form of y = mx + b:

Thus:

y - 5 = 1(x - 3)

y - 5 = x - 3

y - 5 + 5 = x - 3 + 5

y = x + 2