What is the solution to the inequality 21x - 12x _< 54

Answer:

x = 28.4°

Step-by-step explanation:

The cos(x) = 15/17 ≈ 0.88

The acos(0.88) = 28.4°

Answer:

[tex]c=-2[/tex]

Step-by-step explanation:

We are given the function:

[tex]f(x) = -2c + cx - x^2[/tex]

And that:

[tex]\displaystyle f^{-1} (5) = -1[/tex]

And we want to determine the value of c.

Recall that by definition of inverse functions:

[tex]\displaystyle \text{If } f(a) = b, \text{ then } f^{-1}(b) = a[/tex]

So, since f⁻¹(5) = -1, then f(-1) = 5.

Substitute:

[tex]f(-1) = 5 = -2c + c(-1) - (-1)^2[/tex]

Simplify:

[tex]5 = -2c - c - (1)[/tex]

Combine like terms:

[tex]6 = -3c[/tex]

And divide. Hence:

[tex]c = -2[/tex]

In conclusion, the value of c is -2.

Answer:

M ≤ μ (=78)

Here μ denotes the means of the population

And, M denotes the sample mean

Step-by-step explanation:

The computation of the  null hypothesis, in both words and symbols is given below:

Null Hypothesis(H0) is

M ≤ μ (=78)

This means that the study application does not improve the grades

Also

Alternative hypothesis (H1): M> μ

Here μ denotes the means of the population

And, M denotes the sample mean

Answer:

Multiply 800 by 1.022^7 because 1.022^(n-1)

Step-by-step explanation:

Series and sequences.

Answer:2 and 6

Step-by-step explanation:

Given

In 4 years Craston's age will be the same as Terrins age is now

Suppose the present of Craston's and Terrins are [tex]x[/tex] and [tex]y[/tex] respectively

According to the question

[tex]\Rightarrow x+4=y\\\Rightarrow y-x=4\quad \ldots(i)[/tex]

In 2 years Terrin will be twice as old  as craston

[tex]\Rightarrow (y+2)=2(x+2)\\\Rightarrow y-2x=4-2\\\Rightarrow y-2x=2\quad \ldots(ii)\\[/tex]

Solving (i) and (ii) we get

[tex]x=2,y=6[/tex]

Thus, the present age of Craston and Terrins are [tex]2[/tex] and [tex]6[/tex]

Answer:

1980

Step-by-step explanation:

13 sides

Number of sides n=13

The sum of interior angles of polygon =(2n−4)×90o

=(2×13−4)×90o

=(26−4)×90o

=22×90o

We get,

=1980

Answer:

(x+2)^2 + (y-15)^-1 = 64

Step-by-step explanation:

plz mark brainlist

Answer:

70.875

Step-by-step explanation:

Area of park=Area of rectangle+Area of triangle

Area of park=13.5*4.8+(0.5)*(13.5)*0.9=70.875

Answer:

[tex] {6}^{3} = 216[/tex]

The equation in point slope form is y - 6 = 2(x + 3)

This is from the general point slope template of [tex]y - y_1 = m(x - x_1)[/tex]

The m is the slope, which in this case is m = 2. The [tex](x_1,y_1)[/tex] is the point the line goes through. In this case, [tex]x_1 = -3 \text{ and } y_1 = 6[/tex]

If you were to solve that equation in bold for y, then you should get y = 2x+12 which is now in y = mx+b form, aka slope intercept form.

Answer:

its 80 meters longs

Step-by-step explanation:

if it is wrong just go look it up

there are two solutions:

a) y = [tex]\frac{-6+2\sqrt{6} }{5}[/tex]

b) [tex]y = \frac{-6-2\sqrt{6} }{5}[/tex]

Answer:

it's A

Step-by-step explanation:

Trust me I got the question right on the quiz

Answer:

Since all the three sides of the triangle are of equal length, we can find the perimeter by multiplying the length of each side by 3. 20 + 20 + 20 = 3 × 20 = 60 cm.

Answer:

4

Step-by-step explanation:

ln(e)=1 since ln= log_e

log(x^y)=y*log(x) so ln(e^4)=4*ln(4)=4*1=4

Answer:

D

Step-by-step explanation:

ln(e^4)

The 4 comes down in front of the natural log (ln). You get 4 ln(e)

The natural log of e (ln e )  is 1.

So the answer is 4 * 1 = 4

That may not be clear to you. We could try it another way.

e = 2.718281828

ln (2.718281828) = 1

ln(2.718281828)^4 = 4.  The calculator gags until you get it right.  You need the y^x key (or the x^y key of ^) It does come back with 4.

You have to monkey around with the calculator to get this to happen.  

Answer:

=k=0.25h-7/12

Step-by-step explanation:

4(h-3k)=h+7

=4h-12k=h+7

collecting like terms and leaving characters with k on 1 side, we get;

12k=3h-7

=k=0.25h-7/12

y = x^2 - 8x + 3

y - 3 = x^2 - 8x + 3 - 3

y - 3 = x^2 - 8x + ___

c = (8/2)^2 = 16

y - 3 + 16 = x^2 - 8x + 16

y + 13 = (x - 4)^2

y + 13 - 13 = (x - 4)^2 - 13

y = (x - 4)^2 - 13

Vertex: (4, -13)

Hope this helps!

Answer:

4π inches

Step-by-step explanation:

Formula for finding length of arc AB = θ/360*2πr

Where,

Central angle (θ) = 120°

Radius (r) = 6 inches

Length of arc AB = 120/360*2*π*6

Length for arc AB = ⅓*12π

= 4π inches

Answer:

see below

Step-by-step explanation:

2^30

-------

8^9

Rewriting

8^9

2^3 ^ 9

We know a^b^c = a^(b*c)

2^(3*9) = 2^27

2^30

-------

2^27

We know a^b / a^c = a^(b-c)

2^(30-27) = 2^3

Assuming you mean 2^x

2^3 = 2^x

x=3

If you mean 2x

2^3 = 8

8 = 2x

Divide by 2

4 =x

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{\dfrac{2^{30}}{8^9}=2x}[/tex]

[tex]\mathsf{2^{30}}\\\mathsf{= \bf 1,073,741,824}\\\\\mathsf{8^9}\\\mathsf{= \bf 134,217,728}[/tex]

[tex]\mathsf{\rightarrow \dfrac{1,073,741,824}{134,217,728}= 2x}\\\\\\\mathsf{\dfrac{1,073,741,824}{134,217,728}= \bf 8}\\\\\\\mathsf{\rightarrow \ 8 = 2x}\\\\\\\\\large\textsf{TURN\ the\ EQUATION\ around}\\\\\\\mathsf{\rightarrow\ 2x = 8}\\\\\\\large\textsf{DIVIDE 2 to BOTH SIDES}\\\\\\\mathsf{\dfrac{2x}{2}=\dfrac{8}{2}}\\\\\\\large\textsf{CANCEL out: }\mathsf{\dfrac{2}{2}}\large\textsf{ because it gives you 1}\\\\\\\large\textsf{KEEP: }\mathsf{\dfrac{8}{2}}\large\textsf{ because it gives you the answer of x}[/tex]

[tex]\mathsf{x = \dfrac{8}{2}}\\\\\\\mathsf{x = 8\div 2}\\\\\\\mathsf{x = \bf 4}\\\\\\\\\\\boxed{\boxed{\huge\text{Therefore, your answer is: \textsf{x = 4}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

Step-by-step explanation:

I'm assuming that strange looking thing is a 9, so begin by multiplying both sides by that denominator to get:

[tex]x-9=\sqrt{x}+3[/tex] then subtract 3 from both sides to get

[tex]x-12=\sqrt{x}[/tex] and then square both sides to get

[tex]x^2-24x+144=x[/tex] and get everything on one side to solve for x by factoring:

[tex]x^2-25x+144=0[/tex] and factor that however it is you have learned to factor second-degree polynomials to get that

x = 16 and x = 9. We have to check for extraneous solutions because anytime you manipulate an equation, as we did by squaring both sides, you run the risk of these solutions that actually don't work when you plug them back into the original equation. Let's try 16 first:

[tex]\frac{16-9}{\sqrt{16}+3 }=1[/tex]  If 16 is a solution, then this statement will be mathematically true.

[tex]\frac{7}{4+3}=1[/tex]  and   [tex]\frac{7}{7}=1[/tex] so 16 works. Let's try 9:

[tex]\frac{9-9}{\sqrt{9}+3 }=1[/tex]  We know that one doesn't work, because 9-9 = 0 and 0 over anything = 0, not 1.

x = 16 is the only solution.

Answer:

x =  16

Step-by-step explanation:

[tex]\frac{x-9}{\sqrt{x}+3}=1[/tex]

Cross multiply,

x - 9 = √x + 3

Subtract 3 from both sides

x - 9 - 3 = √x

x - 12 = √x

Square both sides

(x -12)² = (√x)²

x² - 2 * x*12 + 12² = x

x² - 24x + 144 = x

x² - 24x + 144 - x = 0

x² - 25x + 144 = 0

Sum = -25

Product = 144

Factors = -9 , -16            {(-9)+(-16) = -25  & (-)*(-16) = 144}

x² - 25x + 144 = 0

x² - 16x - 9x + (-9)*(-16) = 0

x(x - 16) - 9(x - 16) = 0

(x - 16) (x - 9) = 0

x - 16 = 0     ; x - 9 = 0

x = 16          ; x = 9

x = 9 is  an extraneous solution.

When we plug in 9 in the LHS of the equation,

LHS = [tex]\frac{9-9}{\sqrt{9}+3}[/tex]

       [tex]= \frac{0}{3+3}[/tex]

        = 0 ≠ RHS

So, x = 16 is the only  solution

Answer:

The length is 12metres, the width is 6metres

Step-by-step explanation:

Suppose the width is x, the length is x+6

The square is 72. The square of rectangular field is equal to product of length and width.

so x(x+6)=72

x^2+6x-72=0

a=1 b=6 c=-72

D= b^2-4ac= 6*6+288= 36+288= 324

sqrtD= 18

x1= (-b-sqrtD)/2a=(-6-18)/2= -12 (it is negative, but width is only positive. So this root doesn't match)

x2=(-b+sqrtD)/2a= (-6+18)/2= 12/2=6 - the width

The length is 6+6=12

Answer:

Step-by-step explanation:

Given,

Radius of a circle = 17m

Therefore,

Area in terms of pi

[tex] = \pi {r}^{2} [/tex]

[tex] = \pi \times 17m \times 17m[/tex]

[tex] = 289\pi {m}^{2} (ans)[/tex]

Answer:

A = 289π m²

Step-by-step explanation:

The area (A) of a circle is calculated as

A = πr² ( r is the radius ) , then

A = π × 17² = 289π m²

Answer:

8.44 m

Step-by-step explanation:

SohCahToa is a good way to remember that Sin = opposite/hypotenuse, Cosine = adjacent/hypotenuse and Tangent = opposite/adjacent. In this case, we have to use tangent. So tan 37° = x/11.2. Multiply both sides by 11.2 and you get tan 37° × 11.2 = x; The height of the school is x so the height of the school is 8.44 m

Answer: 1/32

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

We know that a^b / a^c = a^(b-c)

9^8 / 9^7

9^(8-7)

9^1

9

Answer:

x=1

Step-by-step explanation:

3x+9 = 12

Subtract 9 from each side

3x+9-9=12-9

3x = 3

Divide by 3

3x/3 = 3/3

x=1

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]x = 1[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Calculating the answer...}}\\\\3x + 9 = 12\\-------------\\\rightarrow 3x + 9 - 9 = 12 - 9\\\\\rightarrow 3x = 3\\\\\rightarrow \frac{3x=3}{3}\\\\\rightarrow \boxed{x=1}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

A is false

Step-by-step explanation:

notice how in both diagrams, there are 4 triangles with lengths a, b, c, but in each diagram the triangles are just rotated and positioned differently. if there are the same amount of triangles in both diagrams, and the have equal lengths then the area of the remaining figure, should both match up.

basically the area of the big square in Step 2, is equal to both of the shaded squares, combined area, in Step 1.

to solve for y, we must multiply by t on both side to get ride of the t in the denominator. By doing this, we will get:

[tex] {t}^{3} [/tex]

on the right side.

Subtracting 3, and we have successfully isolated y.

It would be impossible to get a quantitative value for y if we don't know the value of t.

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