What is the range of the function represented by the graph?

Answer:

Option D (There is no solution) is the correct answer.

Step-by-step explanation:

According to the question, the matrix is:

⇒ [tex]\left[\begin{array}{ccc}1&-5&-4\\0&0&7\end{array}\right][/tex]

The linear equation will be:

⇒ [tex]x-5y=-4[/tex]

and

⇒ [tex]0.x+0.y=7[/tex]

i.e,

                [tex]0=7[/tex] (Not possible)

Thus the above given matrix has no solution. So the above is the correct option.

Answer:

10

Step-by-step explanation:

5

C

3

5!/(3!(5-3)!)

5!/(3!x2!)

120/12

10

In 10 ways can a supermarket manager display 5 brands of cereals

in 3 spaces on a shelf.

Combinations are mathematical operations that count the number of potential configurations for a set of elements when the order of the selection is irrelevant. You can choose the components of combos in any order. Permutations and combinations can be mixed up.

Given:

Total brands of cereals= 5

Using Combination, C(n, r)

= n!/ r! (n- r)!

So, the number of ways

= C(5, 3)

= 5!/(3!(5-3)!) 5

= 5 x 4 x 3! / 3! x 2!

= 5 x 4 /2

= 10

Thus, the total number of ways is 10.

Learn more about Combination here:

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Answer:

to put the equation into standard for we must multiply the terms on the right side of the equation. To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

Step-by-step explanation:

y

=

(

x

−

13

)

(

x

−

12

)

becomes:

y

=

(

x

×

x

)

−

(

x

×

12

)

−

(

13

×

x

)

+

(

13

×

12

)

y

=

x

2

−

12

x

−

13

x

+

156

We can now combine like terms:

y

=

x

2

+

(

−

12

−

13

)

x

+

156

y

=

x

2

+

(

−

25

)

x

+

156

y

=

x

2

−

25

x

+

156

Answer:

(a) The mean is 0

(b) The median is -30

(c) The mode is unimodal

Step-by-step explanation:

Given

[tex]Data: 15,-4,-10,8,14,-10,-2,-11[/tex]

Solving (a): The mean.

This is calculated using:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x =\frac{15-4-10+8+14-10-2-11}{8}[/tex]

[tex]\bar x =\frac{0}{8}[/tex]

[tex]\bar x =0[/tex]

Solving (b): The median

First, arrange the data

[tex]Sorted: -11,-10, -10, -4, -2,8,14,15[/tex]

There are 4 elements in the dataset. So, the median is the mean of the 4th and 5th item.

[tex]Median = \frac{-4-2}{2}[/tex]

[tex]Median = \frac{-6}{2}[/tex]

[tex]Median = -3[/tex]

Solving (c): The mode

The item that has occurs most is -10.

Hence, the mode is -10. The dataset is unimodal because it has only 1 mode (-10).

Answer:

The probability that the mean number of holding penalties per game is of X or less is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean number of penalties per game, [tex]\sigma[/tex] is the standard deviation and n is the number of games that will be sampled.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have that:

The mean number of penalties per game is [tex]\mu[/tex] and the standard deviation is [tex]\sigma[/tex].

Sample of n games:

This means that [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

What is the probability that, for a sample of college games to be played next week, the mean number of holding penalties will be X penalties per game or less?

The probability that the mean number of holding penalties per game is of X or less is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean number of penalties per game, [tex]\sigma[/tex] is the standard deviation and n is the number of games that will be sampled.

Answer:

(a)

[tex]Pr(x = 0) = \frac{^7C_2}{45}[/tex]            [tex]Pr(x = 1) = \frac{^7C_1 * ^3C_1}{45}[/tex]            [tex]Pr(x = 2) = \frac{^3C_2}{45}[/tex]

(b)

[tex]E(x) = \frac{3}{5}[/tex]

Step-by-step explanation:

Given

[tex]n = 10[/tex] --- flashbulbs

[tex]k = 3[/tex] --- defective bulbs

[tex]r = 2[/tex] --- selected

Solving (a): The distribution of x

The total outcome is: [tex]^nC_r[/tex]

This gives:

[tex]^{10}C_2 = 45[/tex]

Having 3 defective bulbs means 7 are not.

When there is no defective bulb among the selected, the probability is:

[tex]Pr(x = 0) = \frac{^7C_2}{45}[/tex]

When 1 is defective:

[tex]Pr(x = 1) = \frac{^7C_1 * ^3C_2}{45}[/tex]

When both are defective

[tex]Pr(x = 2) = \frac{^3C_2}{45}[/tex]

So, the distribution is:

[tex]Pr(x = 0) = \frac{^7C_2}{45}[/tex]

[tex]Pr(x = 1) = \frac{^7C_1 * ^3C_1}{45}[/tex]

[tex]Pr(x = 2) = \frac{^3C_2}{45}[/tex]

Solving (b): The expected value

This is calculated as:

[tex]E(x) = \sum x * Pr(x)[/tex]

So, we have:

[tex]E(x) = x_1 * Pr(x_1) +x_2 * Pr(x_2) + ............... + x_n * Pr(x_n)[/tex]

The equation becomes:

[tex]E(x) = 0* Pr(x=0) +1* Pr(x=1) + 2 * Pr(x=2)[/tex]

[tex]E(x) = 1* Pr(x=1) + 2 * Pr(x=2)[/tex]

[tex]E(x) = Pr(x=1) + 2 * Pr(x=2)[/tex]

From the distribution in (a), we have:

[tex]E(x) = \frac{^7C_1 * ^3C_1}{45} + 2 * \frac{^3C_2}{45}[/tex]

[tex]E(x) = \frac{7 * 3}{45} + 2 * \frac{3}{45}[/tex]

[tex]E(x) = \frac{21}{45} + \frac{6}{45}[/tex]

[tex]E(x) = \frac{21+6}{45}[/tex]

[tex]E(x) = \frac{27}{45}[/tex]

Simplify

[tex]E(x) = \frac{3}{5}[/tex]

Answer:

x=3

Step-by-step explanation:

Answer:

The time-mean speed of the minivans is of 105.8 seconds.

Step-by-step explanation:

Mean of a data-set:

The mean of a data-set is the sum of all values in the data-set divided by the number of values.

Five minivans, times of: 98.0, 108.0, 113.0, 108.0, 102.0, in seconds.

Thus, the mean is:

[tex]M = \frac{98 + 108 + 113 + 108 + 102}{5} = 105.8[/tex]

The time-mean speed of the minivans is of 105.8 seconds.

Answer:

B. 4/3pi (7^3)

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

We know the radius is 7

V = 4/3 pi 7^3

Answer:

Thirty rounded to the nearest whole number percent is 30% (%=percent)

Step-by-step explanation:

Well, you see that if you have 30 out of one hundred then that's when all you have to do is go with the same number and just add percent or % to the end.

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Hope this Helps

This is just evidence

Answer:

y = -x + 8

Step-by-step explanation:

First, plug in the slope.

y = mx + b

y = -1x + b

y = -x + b

Then, plug in the point.

7 = -(1) + b

7 = -1 + b

8 = b

Answer:

21%

Step-by-step explanation:

Area of one sprinkler

a = πr²

a = π10²

a = 314.159 ft²

8 sprinklers

a = 8 * 314.159

a = 2,513.272

---------------------

area of field

a = lw

a = 80 * 40

a = 3200

------------------------

area not watered

a = 3200 - 2,513.272

a = 686.728

------------------

percentage not watered

p = 686.728 / 3200 * 100%

p = 21.46025%

Rounded

21%

Answer:19.82

Step-by-step explanation:

Got it right i did it on a test

Answer:

-46

Step-by-step explanation:

To find your score, take Bill's score which is -17 and if it is 29 less than, you subtract 29

So, - 17 - 29 is -46

The new age of the teacher is 25

Answer:

The age of the new teacher is 35

Answer:

c is equal to e

Step-by-step explanation: a

Answer:

Hence when the radius is halved the area is divided by 4

2.5 inches^2

Step-by-step explanation:

Given data

Area= 10inches^2

We know that the expression for the area of  a circle is given as

Area= πr^2

10= 3.142*r^2

10/3.142= r^2

r^2= 3.18

Square both sides

r= √3.18

r= 1.78 inches

Now let us half the radius and find the area of the new circle

r/2= 1.78/2

r= 0.89

Area of the new circle is

Area= 3.142*0.89^2

Area= 3.142*0.7921

Area= 2.5 inches^2

Answer:

(A) 89 (B) 91 (C) 92 (D) 95 4.If |x−2| = p, where x < 2, then x+1 equals (A) −2 (B) 3− p (C) |2p−2| (D) 2p−2 5.A

Step-by-step explanation:

Following are the calculation to the find the value of x:

Given:

Please find the question.

To find:

x=?

Solution:

[tex]\frac{71}{7} <\frac{x}{9} < \frac{113}{11}\\\\10 <\frac{71}{7} < 11 \\\\10< \frac{113}{11}<11\\\\\frac{x}{9} >10\\\\x>90\\\\\text{When}\ x=91 \\\\\frac{71}{7} > \frac{91}{9}\\\\x=92\\\\ \frac{71}{7}< \frac{92}{9} <\frac{113}{11}\\\\[/tex]

so, x= 92 \\\\

by compare score value x= 92

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Answer: wheres the photo ?

Step-by-step explanation:

Answer:

-3-4=-7

-3+(-4)

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

x =35

Step-by-step explanation:

The sum of the angles of a triangle add to 180

x+10 +x + 3x-5 = 180

Combine like terms

5x+5 = 180

Subtract 5 from each side

5x+5-5 =180-5

5x = 175

Divide by 5

5x/5 =175/5

x =35

Answer:

Given:

Cost = £ 800

Tax = 20%

To find:

The total cost

Solution:

Total cost = Cost + Tax

Tax = 20 % of cost

20 / 100 * 800

Tax = £ 160

Hence,

Total cost =  £ 800 + £ 160

Total cost = £ 960

Answer:

[tex]x\approx 5.48[/tex]

Step-by-step explanation:

Draw a line from the center of the circle O to the end of either side of the line marked as 4. This line represents two things:

In this case, both are important. Since [tex]x[/tex] is also a radius of the circle, the line must be equal to [tex]x[/tex], since all radii of a circle are equal. To find the length of this line, use the Pythagorean Theorem:

[tex]a^2+b^2=c^2[/tex], where [tex]c[/tex] is the hypotenuse of the triangle and [tex]a[/tex] and [tex]b[/tex] are the two legs of the triangle.

Since we're solving for the hypotenuse and the two legs are 5.1 and 2, we have:

[tex]5.1^2+2^2=c^2,\\26.01+4=c^2,\\c^2=30.01,\\c=5.47813836992\approx \boxed{5.48}[/tex] (round as necessary).

Answer:

C) f(x) = 1500(2.15)x

Step-by-step explanation:

Got it right on Edge :)

Answer:

1/2( 110+42)

Step-by-step explanation:

Angle Formed by Two Chords= 1/2(sum of Intercepted Arcs)

<<XYZ = 1/2( 42+110)

Answer:

1/13

Step-by-step explanation:

there are total no of 52 cards

out of that there are 4 queen

propability = tatal no of favorable outcomes / total no of possible outcomes

=4 / 52

=1/13

Answer:

1/13

Step-by-step explanation:

Total cards = 52

Number of Queen = 4

Probability of the chosen card to be queen

                                                                   [tex]=\frac{Number \ of \ queen}{total \ number \ of \ cards}\\\\=\frac{4}{52} \\\\= \frac{1}{13}[/tex]

Answer:

[tex]P(x< 240) = 0.0521[/tex]

Step-by-step explanation:

Given

[tex]\bar x = 266[/tex]

[tex]\sigma = 16[/tex]

Required

[tex]P(x < 240)[/tex] --- pregnancy will last less than 240 days

First, calculate the z score

[tex]z = \frac{x - \bar x}{\sigma}[/tex]

Where:

[tex]x = 240[/tex]

So, we have:

[tex]z = \frac{240 - 266}{16}[/tex]

[tex]z = \frac{-26}{16}[/tex]

[tex]z = -1.625[/tex]

So:

[tex]P(x< 240) = P(z < -1.625)[/tex]

From z probability:

[tex]P(z < -1.625) = 0.052081[/tex]

[tex]P(z < -1.625) = 0.0521[/tex] --- approximated

So:

[tex]P(x< 240) = 0.0521[/tex]

Answer:

This identity holds as long as [tex]\displaystyle \theta \ne k\, \pi + \frac{\pi}{2}[/tex] for all integer [tex]k[/tex].

For the proof, make use of the fact that:

[tex]\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}[/tex] (definition of tangents,) and

[tex]\cos(\theta) = \sqrt{1 - \sin^{2}(\theta)}[/tex] (Pythagorean identity,) which is equivalent to [tex]1 - \cos^{2}(\theta) = \sin^{2}(\theta)[/tex].

Step-by-step explanation:

Assume that [tex]\displaystyle \theta \ne k\, \pi + \frac{\pi}{2}[/tex] for all integer [tex]k[/tex]. This requirement ensures that the [tex]\tan(\theta)[/tex] on the left-hand side takes a finite value. Doing so also ensures that the denominator [tex]\sqrt{1 - \sin^2(\theta)}[/tex] on the right-hand side is non-zero.

Make use of the fact that [tex]\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}[/tex] to rewrite the left-hand side:

[tex]\begin{aligned} & \tan(\theta) \cdot \sin(\theta) \\ =&\; \frac{\sin({\theta})}{\cos({\theta})} \cdot \sin(\theta) \\ =&\; \frac{\sin^{2}(\theta)}{\cos(\theta)}\end{aligned}[/tex].

Apply the Pythagorean identity [tex]\sin^{2}(\theta) = 1 - \cos^{2}(\theta)[/tex] and [tex]\cos(\theta) = \sqrt{1 - \sin^{2}(\theta)}[/tex] to rewrite this fraction:

[tex]\begin{aligned} & \frac{\sin^{2}(\theta)}{\cos(\theta)}\\ =\; &\frac{1 - \cos^{2}(\theta)}{\cos(\theta)}\\ =\; & \frac{1 - \cos^{2}(\theta)}{\sqrt{1 - \sin^{2}(\theta)}}\end{aligned}[/tex].

Hence, [tex]\displaystyle \tan(\theta) \cdot \sin(\theta) = \frac{1 - \cos^{2}(\theta)}{\sqrt{1 - \sin^{2}(\theta)}}[/tex].