what is the pH of a 8.27*10^-2 M solution of HClO_4

The correct equation that has been balanced is option (c): ZnS + 02 -> 2ZnO + SO2. This equation is balanced because the number of sulfur atoms (1 on each side) and the number of oxygen atoms (2 on each side) are equal.

The correct equation that has been balanced is option (c): ZnS + 02 -> 2ZnO + SO2. To determine whether an equation is balanced, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's analyze each option:

(a) 2ZnS + 302 -> 2ZnO + 2SO2: This equation is unbalanced because there are an unbalanced number of oxygen atoms (7 on the left side and 4 on the right side) compared to the amount of sulphur atoms (2 on each side).

(b) ZnS + 02 --> ZnO + SO2: This equation is unbalanced because there are an unbalanced number of oxygen atoms (2 on the left side and 3 on the right side) compared to the sulphur atoms (1 on each side).

(c) ZnS + 02 -> 2ZnO + SO2: This equation is balanced because the number of sulfur atoms (1 on each side) and the number of oxygen atoms (2 on each side) are equal. Therefore, option (c) is the only equation that has been balanced correctly.

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The given chemical equation, 2N₂ + 3H₂ <==>2NH3, is an example of a reversible reaction.option A.

The double arrows between the reactants and products indicate that the reaction can proceed in both directions, forming both products and reactants.The reversible reaction, also known as a chemical equilibrium reaction, refers to a chemical reaction that can occur in both forward and reverse directions. It occurs when reactants are converted into products, and the products are also converted back into the original reactants.A reversible reaction can be identified by the symbol “<==>” or “⇌” that appears between the reactants and products in the chemical equation. It denotes that the reaction is in a state of chemical equilibrium. When the reactants and products have achieved equilibrium, the rate of the forward and reverse reactions is equal, and there is no further net change in the amounts of the reactants and products.A combustion reaction is a type of exothermic reaction in which a substance reacts with an oxidizing agent to produce heat and light. A one-way reaction is a type of reaction that occurs in only one direction and cannot be reversed without significant changes to the reaction conditions, such as changing the temperature or pressure.A reversible reaction, unlike a one-way reaction, can occur in both directions and reach equilibrium when the forward and reverse reaction rates are equal.option A.

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The IUPAC name of the given substance, CH3CH2CH2C=CCH2CH2CH3 is 5-octene.

Here is a step by step explanation for naming the compound following IUPAC nomenclature system:Step 1: Count the number of carbon atoms in the longest continuous chain of carbon atoms (parent chain).The parent chain here contains 8 carbon atoms, so it is an octane derivative.Step 2: Number the carbon atoms in the parent chain in such a way that the double bond gets the lowest number. In this case, there are two possible ways to number the carbon atoms of the parent chain. In one way, we start from the left side of the molecule and in the other way, we start from the right side of the molecule.Both are correct, as long as the double bond is assigned the lowest number.The numbers are assigned as shown below:Step 3: Identify and name the substituents attached to the parent chain. In this case, there is one methyl (-CH3) group attached to the third carbon atom of the parent chain.Step 4: Assign a locant (number) to each substituent based on its position in the parent chain.Here, the locant for the methyl group is 3.Step 5: Combine the names of the substituents and the parent chain.

Here, the name of the parent chain is octene and the name of the substituent is methyl. Therefore, the IUPAC name of the compound is 3-methyloctene.

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A.) The solubility of nitrogen at a pressure of 2.00 atm is [tex]1.36 \times 10^{(-3)} M.[/tex]

B.) The solubility of nitrogen at a pressure of 688 mmHg is [tex]6.17 \times 10^{(-4)} M.[/tex]

To calculate the solubility of nitrogen (N2) in M (molarity) at different pressures, we need to use Henry's Law, which states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. The equation for Henry's Law is:

C = k * P

Where:

C is the solubility of the gas in M (molarity)

k is the Henry's Law constant

P is the partial pressure of the gas

For nitrogen, the Henry's Law constant (k) is approximately 6.8 x 10^(-4) M/atm.

a) To calculate the solubility of nitrogen at a pressure of 2.00 atm:

C = (6.8 x 10^(-4) M/atm) * (2.00 atm)

C = 1.36 x 10^(-3) M

Therefore, the solubility of nitrogen at a pressure of 2.00 atm is 1.36 x 10^(-3) M.

b) To calculate the solubility of nitrogen at a pressure of 688 mmHg:

First, we need to convert mmHg to atm by dividing by 760 (since 1 atm = 760 mmHg).

P = 688 mmHg / 760 mmHg/atm

P = 0.905 atm

C = (6.8 x 10^(-4) M/atm) * (0.905 atm)

C = 6.17 x 10^(-4) M

Therefore, the solubility of nitrogen at a pressure of 688 mmHg is 6.17 x 10^(-4) M.

It's important to note that the solubility of a gas can also depend on temperature, so these calculations assume a constant temperature. Additionally, Henry's Law is an approximation and may not hold true for all gas-liquid systems, especially at high pressures or when there are significant intermolecular interactions between the gas and liquid.

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