We know
[tex]\boxed{\Large{\sf M_1V_1=M_2V_2}}[/tex]
[tex]\\ \Large\sf\longmapsto M_2=\dfrac{M_1V_1}{V_2}[/tex]
[tex]\\ \Large\sf\longmapsto M_2=\dfrac{3(75)}{250}[/tex]
[tex]\\ \Large\sf\longmapsto M_2=\dfrac{225}{250}[/tex]
[tex]\\ \Large\sf\longmapsto M_2=0.9M[/tex]
Answer:
Mass 1=3M
Mass 2=?
Volume1=75mL
Volume2=250mL
By using molarity formula:
mass1*volume 1=mass2*volume 2
3M*75=mass2*250
mass2=225/250
mass2:0.9M
the molarity of a solution is 0.9M.Question 47
4 pts
Dimensional analysis & conversions. If you need scientific notation in you answer, copy this for the
exponential part: "x10^". An example would be 6.022x10^23 for Avogadro's number.
Your answers need to have the correct number of significant figures.
How many grams of hydrogen are in 10.45 moles of C&Hg? (The molar mass is not
needed for this problem.)
Answer:
84.27 g
Explanation:
How many grams of hydrogen are in 10.45 moles of C₃H₈?
Step 1: Calculate the moles of atoms of hydrogen
The molar ratio of C₃H₈ to H is 1:8.
10.45 mol C₃H₈ × 8 mol H/ 1mol C₃H₈ = 83.60 mol H
Step 2: Calculate the mass corresponding to 83.60 moles of hydrogen
The molar mass of hydrogen is 1.008 g/mol.
83.60 mol × 1.008 g/mol = 84.27 g
A dehydration reaction starting with 3.0 g cyclohexanol produces 1.9 g cyclohexene. Calculate the theoretical yield for this reaction. Report your answer with two significant figures.
Answer:
77%
Explanation:
First we convert 3.0 g of cyclohexanol (C₆H₁₂O) to moles, using its molar mass:
Molar mass of C₆H₁₂O = 100.158 g/mol3.0 g ÷ 100.158 g/mol = 0.030 molThen we convert 1.9 g of cyclohexene (C₆H₁₀) to moles, using its molar mass:
Molar mass of C₆H₁₀ = 82.143 g/mol1.9 g ÷ 82.143 g/mol = 0.023 molFinally we calculate the theoretical yield:
0.023 mol / 0.030 mol * 100% = 77%What type of energy does a skier stopped at the top of a hill have because of
his or her position?
A. Kinetic energy
B. Gravitational potential energy
C. Heat energy
D. Chemical energy
Answer:
B
Explanation:
0.45 mole of krypton gas occupies a volume of 1.6 L. What volume will 1.8 moles of krypton occupy assuming the temperature and pressure remain the same
Answer:
6.4 L
Explanation:
As the temperature and pressure are assumed to remain the same, we can solve this problem by using Avogadro's law, which states:
V₁n₂ = V₂n₁Where in this case:
V₁ = 1.6 Ln₂ = 1.8 molV₂ = ?n₁ = 0.45 molWe input the data given by the problem:
1.6 L * 1.8 mol = V₂ * 0.45 molAnd solve for V₂:
V₂ = 6.4 LWhat is the mass of a piece of iron if its density is 1.98 g/mL and its volume is 2.45 mL?
0.80 g
4.858
1.248
5.998
2.71 g
Answer:
4.858 g
Explanation:
Start with the formula
density = [tex]\frac{mass}{volume}[/tex]
density = 1.98 g/mL
volume = 2.45 mL
mass = ??
rearrange the formula to solve for mass
(density) x (volume) = mass
Add in the substitutes and solve for mass
1.98 g/mL x 2.45 mL = 4.858 g
If 13.50 mL of an aluminum chloride solution is needed to reach the equivalence point with 10.00 mL of 0.109 M silver nitrate solution, determine the molarity of the aluminum chloride solution.
Answer:
If 13.50 mL of an aluminum chloride solution is needed to reach the equivalence point with 10.00 mL of 0.109 M silver nitrate solution, determine the molarity of the aluminum chloride solution.
Explanation:
The balanced chemical equation of the reaction is:
[tex]AlCl_3(aq)+3AgNO_3(aq)->3AgCl(s)+Al(NO_3)_3(aq)[/tex]
So, one mole of aluminum chloride reacts with three moles of silver nitrate.
At the equivalence point,
the number of moles of each reactant must be equal.
The number of moles = molarity x volume in L.
Number of moles of AlCl3 = volume x molarity
=0.0135Lx Molarity
The number of moles of AgNO3 = 3 x 0.010Lx 0.109M
Thus,
0.0135Lx Molarity = 3 x 0.010Lx 0.109M
Molarity of AlCl3 :
[tex]Molarity of Alcl_3=3 x 0.010Lx 0.109M/0.0135\\=0.242M[/tex]
Answer is : 0.242M.
The following pairs of soluble solutions can be mixed. In some cases, this leads to the formation of an insoluble precipitate. Decide, in each case, whether or not an insoluble precipitate is formed.
a. K2S and NH4Cl
b. CaCl2 and NH4CO3
c. Li2S and MnBr2
d. Ba(NO3)2 and Ag2SO4
e. RbCO3 and NaCl
Answer:
a) [tex]K_{2} S[/tex] and [tex]NH_{4} Cl[/tex] :
There are no insoluble precipitate forms.
b) [tex]Ca Cl_{2}[/tex] and [tex](NH_{4} )_{2} Co_{3}[/tex] :
There are the insoluble precipitates of [tex]CaCo_{3}[/tex] forms.
c) [tex]Li_{2}S[/tex] and [tex]MnBr_{2}[/tex] :
There are the insoluble precipitates of [tex]MnS[/tex] forms.
d) [tex]Ba(No_{3} )_{2}[/tex] and [tex]Ag_{2} So_{4}[/tex] :
As [tex]Ag_{2} So_{4}[/tex] is insoluble, therefore no precipitate forms.
e) [tex]Rb_{2}Co_{3}[/tex] and [tex]NaCl[/tex]:
There are no insoluble precipitates forms.
Explanation:
a)
Solubility rule suggests:- [tex]K_{2} S[/tex] ⇒ soluble, [tex]NH_{4} Cl[/tex] ⇒ soluble.
KCl ⇒ soluble, [tex](NH_{4})_{2} S[/tex] ⇒ soluble.
There are no insoluble precipitate forms.
b)
Solubility rule suggests:- [tex]Ca Cl_{2}[/tex] ⇒ soluble, [tex](NH_{4} )_{2} Co_{3}[/tex] ⇒ soluble.
[tex]CaCo_{3}[/tex] ⇒ insoluble, [tex]NH_{4} Cl[/tex] ⇒ soluble.
There are the insoluble precipitates of [tex]CaCo_{3}[/tex] forms.
c)
Solubility rule suggests:- [tex]Li_{2}S[/tex] ⇒ soluble, [tex]MnBr_{2}[/tex] ⇒ soluble.
[tex]LiBr[/tex] ⇒ soluble, [tex]MnS[/tex] ⇒ insoluble.
There are the insoluble precipitates of [tex]MnS[/tex] forms.
d)
Solubility rule suggests:- [tex]Ba(No_{3} )_{2}[/tex] ⇒ soluble, [tex]Ag_{2} So_{4}[/tex] ⇒insoluble.
As [tex]Ag_{2} So_{4}[/tex] is insoluble, therefore no precipitate forms.
e)
Solubility rule suggests:- [tex]Rb_{2}Co_{3}[/tex] ⇒ soluble, [tex]NaCl[/tex] ⇒ soluble.
[tex]RbCl[/tex] ⇒ soluble, [tex]Na_{2} Co_{3}[/tex] ⇒ soluble.
There are no insoluble precipitates forms.
Jane performed the following trials in an experiment.
Trial 1: Heat 80.0 grams of water at 15.0 °C to a final temperature of 65.0 °C.
Trial 2: Heat 80.0 grams of water at 10.0 °C to a final temperature of 65.0 °C.
Which statement is true about the experiments?
The same amount of heat is absorbed in both the experiments because the mass is same.
The same amount of heat is absorbed in both the experiments because the final temperature is same.
The heat absorbed in Trial 2 is about 1,240 J greater than the heat absorbed in Trial 1.
The heat absorbed in Trial 2 is about 1,674 J greater than the heat absorbed in Trial 1.
Answer:
The heat absorbed in Trial 2 is about 1,240 J greater than the heat absorbed in Trial 1.
The heat absorbed in Trial 2 is about 1,674 J greater than the heat absorbed in Trial 1.
The amount of heat absorbed or released by a substance can be calculated using the formula Q = mcΔT, where Q represents heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
In this case, the mass (m) is the same in both trials, but the initial and final temperatures (ΔT) differ. By comparing the values of ΔT in both trials, we can determine the difference in the amount of heat absorbed.
In Trial 1, the initial temperature is 15.0 °C and the final temperature is 65.0 °C, resulting in a ΔT of 65.0 - 15.0 = 50.0 °C.
In Trial 2, the initial temperature is 10.0 °C and the final temperature is 65.0 °C, resulting in a ΔT of 65.0 - 10.0 = 55.0 °C.
Since the specific heat capacity of water is approximately 4.18 J/g°C, we can calculate the difference in heat absorbed:
ΔQ = mcΔT = (80.0 g)(4.18 J/g°C)(55.0 °C - 50.0 °C) = 1,674 J
Therefore, the heat absorbed in Trial 2 is approximately 1,674 J greater than the heat absorbed in Trial 1.
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How do I balance this equation? ?KClO3 → ?KCl + ?O2(g) and what type of reaction is it?
Explanation:
the reaction is a decomposition reaction since potassium hypochlorite is decomposed into potassium chloride and oxygen
Please help
Explain why a molecule that has polar bonds can be a polar molecule.
Answer:
Explanation:
Well, obviously a molecule with polar bonds can be polar in itself. It's like saying I am an atheltic person who can just reach the basketball rim with my head and also I can dunk.
But if the question is how can a molecule that in non-polar have polar bonds, well, its because the polar bonds' dipole cancels each other out. It's like a tight rope. If a person pulls in one direction, it intuitively, the rope would go in that direction. However, if a person pulls in the other direction with the same amount of force, the rope stays still. This is the same case. Although molecules can have different electronegativities, the pull of electrons in one direction is cancelled out by a pull in the opposite direction, making the net dipole 0.
This is common for main VSERP shaped molecules like linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral.
Which statement bets describes the liquid state of matter
Answer:
It has no fixed shape and therefore takes the shape of the part of the container in which it is placed
Write the net ionic equation for the reaction that occurs when equal volumes of 0.546 M aqueous acetylsalicylic acid (aspirin) and sodium acetate are mixed. It is not necessary to include states such as (aq) or (s).
Answer:
[tex]C_9H_8O_4+C_2H_3O_2^-\rightarrow C_2H_4O_2+C_9H_7O_4^-[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to figure out the required net ionic equation by firstly writing out the complete molecular equation between aspirin and sodium acetate:
[tex]C_9H_8O_4+NaC_2H_3O_2\rightarrow C_2H_4O_2+NaC_9H_7O_4[/tex]
Whereas acetic acid and sodium acetylsalicylate are formed. Now, we write the complete ionic equation whereby sodium acetate and sodium acetylsalicylate are ionized because they are salts yet neither aspirin nor acetic acid are ionized as they are weak acids:
[tex]C_9H_8O_4+Na^++C_2H_3O_2^-\rightarrow C_2H_4O_2+Na^++C_9H_7O_4^-[/tex]
Finally, for the net ionic equation we cancel out the sodium spectator ions to obtain:
[tex]C_9H_8O_4+C_2H_3O_2^-\rightarrow C_2H_4O_2+C_9H_7O_4^-[/tex]
Regards!
Acetylene gas is often used in welding torches because of the very high heat produced when it reacts with oxygen gas, producing carbon dioxide gas and water vapor. Calculate the moles of water produced by the reaction of of acetylene. Be sure your answer has a unit symbol, if necessary, and round it to significant digits.
Answer:
0.60 mol
Explanation:
The equation is as stated below;
2 C2H2 + 5 O2----> 4 CO2 +2 H2O
5 mole amount of Oxygen produces 2 mole of water. Then upon reaction of 1.5mol of O2.
thus, number of mole = (1.5*2)/5 =0.60mol
Propane is a major component of natural gas used as fuel in homes. Write a balanced equation for the complete oxidation reaction that occurs when propane () burns in air.
Answer:
C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)
Explanation:
The chemical formula of propane is C₃H₈. When it burns in air, it reacts with gaseous oxygen (O₂), so carbon dioxide (CO₂) and water (H₂O) are formed. The combustion reaction is the following:
C₃H₈(g) + O₂(g) → CO₂(g) + H₂O(g)
Finally, we have to balance the equation. For this, we write a coefficient 3 in CO₂, then a coefficient 4 in H₂O, and a coefficient 5 in O₂. We obtain the balanced equation:
C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)
The second law of thermodynamics requires that spontaneous processes generate entropy, either in the system or in the surroundings. What is the thermodynamic driving force for dissolving a solid in a liquid if it is an endothermic process (which reduces the entropy of the surroundings)
Answer:
See explanation
Explanation:
Truly, the second law of thermodynamics requires that spontaneous processes generate entropy, either in the system or in the surroundings.
When a solid is dissolved in a liquid, the solid dissociates into ions. These ions increases the number of particles and hence the entropy of the system thereby making the process spontaneous.
Hence, the dissolution of a substance via an endothermic process is spontaneous because of increase in the number of particles which in turn increases the entropy of the system.
How much energy is released when 31.0 g of water freezes? The heat of fusion for water is 6.02 kJ/mol.
Express your answer in kilojoules to three significant figures.
Answer:
The molar heat of fusion for a given substance basically tells you how much heat is required to melt one mole of that substance at its melting point from two angles.
Explanation:
:)
Complete the table by assigning variable or fixed to the shape and volume of solids, liquids, and gases.
You are currently in a labeling module. Turn off browse mode or quick nav, Tab to items, Space or Enter to pick up, Tab to move, Space or Enter to drop.
Shape Volume
solids
liquids
gases
Answer Bank
Fixed or variable
The properties of solids, liquids and gases regarding their shapes and volumes are:
Shape Volume
Solids Fixed Fixed
Liquids Variable Fixed
Gases Variable Variable
Solids have strong attraction forces between their molecules. Thus, the molecules are closely packed with little movement. As a consequence, both shape and volume are fixed.
In liquids, attraction and repulsion forces are similar. They have a little more movement than the solid state. Then, they do have a fixed volume but they adopt the shape of the container.
Gases have very weak attraction forces between their molecules. They move very freely and expand trying to occupy as much volume as possible. So, they have a variable volume and shape (adopt the shape of the container).
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What is the molality of a glucose solution prepared by dissolving 16.7 g of glucose, C6H12O6, in 133.6 g of water
Answer:
0.696 m
Explanation:
We'll begin by calculating the number of mole in 16.7 g of C₆H₁₂O₆. This can be obtained as follow:
Mass of C₆H₁₂O₆ = 16.7 g
Molar mass of C₆H₁₂O₆ = (6×12) + (12×1) + (6×16)
= 72 + 12 + 96
= 180 g/mol
Mole of C₆H₁₂O₆ =?
Mole = mass / molar mass
Mole of C₆H₁₂O₆ = 16.7 / 180
Mole of C₆H₁₂O₆ = 0.093 mole
Next, we shall convert 133.6 g of water to Kg. This can be obtained as follow:
1000 g = 1 Kg
Therefore,
133.6 g = 133.6 g × 1 Kg / 1000 g
133.6 g = 0.1336 Kg
Thus, 133.6 g is equivalent to 0.1336 Kg.
Finally, we shall determine the molality of the solution. This can be obtained as illustrated below:
Mole of C₆H₁₂O₆ = 0.093 mole
Mass of water = 0.1336 Kg
Molality =?
Molality = mole / mass of water (in Kg)
Molality = 0.093 / 0.1336
Molality = 0.696 m
Therefore, the molality of the solution is 0.696 m
The numerical value of 0.001 is written with the prefix:
Answer:
Milli, m.
Explanation:
Hey there!
In this case, according to the given information, it turns out possible for us to answer to this question by bearing to mind the attached file whereas the most common prefixes and their factors are shown both in standard and scientific notation.
In such a way, we will be able to infer that the prefix related to the numerical value of 0.001 is milli, m, for example 1 mm which is 0.001 m.
Regards!
Please help me order these bonds
Answer:
From least polar covalent to most polar covalent;
S-I< Br-Cl < N-H< Te-O
From most ionic to least ionic
Cs-F> Sr-Cl> Li- N> Al-O
Explanation:
Electro negativity is the ability of an atom in a bonding situation to attract the electron pair of a bond towards itself.
Electro negativity difference between two atoms determines the nature of bond existing between any two atoms. When this difference is large, an ionic bond exists in the compound. However, an intermediate difference in electro negativity implies the existence of a polar covalent bond.
Hence, going by electro negativity differences as mentioned in the question, the bonds in the answer were arranged in order of increasing polar covalent nature or decreasing ionic nature as shown.
A gas at 273K temperature has a pressure of 590 MM Hg. What will be the pressure if you change the temperature to 273K? 
Explanation:
here's the answer to your question
The standard enthalpies of combustion of fumaric acid and maleic acid (to form carbon dioxide and water) are - 1336.0 kJ moJ-1 and - 1359.2 kJ moJ-1, respectively. Calculate the enthalpy of the following isomerization process:
maleic acid ----> fumaric acid
Answer:
Explanation:
maleic acid ⇒ fumaric acid
ΔHreaction = ΔHproduct - ΔHreactant
ΔHproduct = -1336.0 kJ mol⁻¹
ΔHreactant = - 1359.2 kJ mol⁻¹.
ΔHreaction = -1336.0 kJ mol⁻¹ - ( - 1359.2 kJ mol⁻¹.)
= 1359.2 kJ mol⁻¹ -1336.0 kJ mol⁻¹
= 23.2 kJ mol⁻¹ .
Enthalpy of isomerization from maleic to fumaric acid is 23.2 kJ per mol.
What is the volume of 1.5 moles of gas at STP ?
0 9.02 L
0 20.0 L
0 33.6 L
0 22.4L
The volume of 1.5 moles of gas at STP is 33.6 L.
Volume of the gas at STPThe volume of the gas at STP is calculated as follows;
I mole of gas at STP = 22.4 L
1.5 moles of the gas at STP = ?
= 1.5 moles x 22.4 L/mole
= 33.6 L
Thus, the volume of 1.5 moles of gas at STP is 33.6 L.
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Please help answering 46)
Answer:
CO2 is a trigonal planar.
Identify each of the following properties as more typical of organic or inorganic compound
a. contains Li and F
b. is a gas at room temperature
c. contains covalent bonds
d. produces ion in water
this is the difference between organic and inorganic if this doesn't help you can research more on it
What is the pH of a 0.85 M solution of N(CH3)3?
Note: Kb = 6.4 x 10^-5 for N(CH3)3
Include a reaction and a Ka or Kb expression
A sample of a compound is analyzed and found to contain 0.420 g nitrogen, 0.480g oxygen, 0.540 g carbon and 0.135 g hydrogen. What is the empirical formula of the compound? a. C2H5NO b. CH3NO c. C3H9N2O2 d. C4HN3O4 e. C4H13N3O3
Answer:
c. C3H9N2O2
Explanation:
The empirical formula of a compound is defined as the simplest whole number ratio of atoms present in a molecule. To solve this question we need to convert the mass of each atom to moles. With the moles we can find the ratio as follows:
Moles N -Molar mass: 14.01g/mol-
0.420g N * (1mol/14.01g) = 0.0300 moles N
Moles O -Molar mass: 16g/mol-
0.480g O * (1mol/16g) = 0.0300 moles O
Moles C -Molar mass: 12.01g/mol-
0.540g C * (1mol/12.01g) = 0.0450 moles C
Moles H -Molar mass: 1.0g/mol-
0.135g H * (1mol/1g) = 0.135moles H
Dividing in the moles of N (Lower number of moles) the ratio of atoms is:
N = 0.0300 moles N / 0.0300 moles N = 1
O = 0.0300 moles O / 0.0300 moles N = 1
C = 0.0450 moles C / 0.0300 moles N = 1.5
H = 0.135 moles H / 0.0300 moles N = 4.5
As the empirical formula requires whole numbers, multiplying each ratio twice:
N = 2, O = 2, C = 3 and H = 9
And the empirical formula is:
c. C3H9N2O2
Please help thank you
Answer:
[tex]K=1.7x10^{-3}[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to solve this problem by firstly setting up the equilibrium expression for the given reaction, in agreement to the law of mass action:
[tex]K=\frac{[NO]^2}{[N_2][O_2]}[/tex]
Next, we plug in the given concentrations on the data table to obtain:
[tex]K=\frac{(0.034)^2}{(0.69)(0.98)}\\\\K=1.7x10^{-3}[/tex]
Regards!
What is the relationship (formula) and proportionality
between frequency, and wavelength?
Answer:
Frequency and wavelength are inversely proportional. c=f⋅λ (The speed of light is directly proportional to f and λ)
For each of the scenarios, determine if the ionic strength of the solution would increase, decrease, or not change.
a. If a solution of HNO3 were added to a solution of KOH , the ionic strength of the KOH solution would:_________
1. Increase
2. Decrease
3. Not change
b. If a dilute solution of KOH were added to a solution of CaCl2 (Ca(OH)2 (s) is formed), the ionic strength would:
1. Increase
2. Decrease
3. Not change
Answer:
Increase
Decrease
Explanation:While in solution, ionic substances produce ions. The ions in solution determine the conductivity of the solution.
The ionic strength of a solution shows the concentration of ions in a given solution. The more the number of ions in the solution, the greater the ionic strength of the solution and vice versa.
When HNO3 is added to a solution of KOH, the number of ions in the solution increases and so does the ionic strength of the solution.
When KOH is added to a solution of CaCl2 then Ca(OH)2 is formed. The formation of a solid precipitate decreases the concentration of ions in solution as well as the ionic strength of the solution.
