What is the missing number in the table?

Answer:

x = 19

Step-by-step explanation:

2x + 3 = 90 - 49

2x + 3 = 41

2x = 38

x = 19

Answer:

y=(x/2)+5

Step-by-step explanation:

Slope-intercept form is y=mx+b where m is the slope and b is the y-intercept form. To get that, we need y by itself so we have to add 3x to both sides: 6y=30+3x. Now we divide by 6 and rearrange the right side: y=(3x+30)/6.

y = (3x/6)+(30/6) => y = (x/2)+5. We also know that the slope is 1/2 and the y-intercept is 5 because of the slope-intercept equation.

Step-by-step explanation:

(7-11)+(-3+51)

(-4)+(48)

44 ans

Answer:

44

Step-by-step explanation:

7-11= -4

-3+51=48

-4+48=44

Step-by-step explanation:

jkkkkkkkkkkkkkkkkkkkkk

Answer:

[tex]2 \sqrt{35} [/tex]

Answer and Step-by-step explanation:

The 3D shape shown is a rectangle. This is the net-form of a rectangle.

#teamtrees #PAW (Plant And Water)

Answer:

rectangular prism

Step-by-step explanation:

a rectangle is not 3d. a rectangle is 2d. the correct answer is a rectangular prism.

Answer:

domain of function refers to the various values that can be passed through to the function.

Step-by-step explanation:

Answer:

cscθ = 5/4, secθ = 5/3

Step-by-step explanation:

First, let's view the drawing that I have attached, with the dot in the bottom left representing the origin. We know that cosecant and secant are the reciprocals of sin and cos respectively, and in order to find sin and cos, we must find the opposite, adjacent, and hypotenuse sides. The hypotenuse is opposite the right angle, equal to √(8²+6²) = 10

Next, we can find sin and cos of θ . sinθ = 8/10=4/5, making cscθ the reciprocal of 4/5, or 5/4

Similarly, cosθ = 6/10=3/5, and secθ = 5/3

Answer:

Step-by-step explanation:

Answer:

a. i. (i + tj + 2tk)/√(1 + 5t²)

ii.  (-5ti + j + 2k)/√[25t² + 5]

b. √5/[√(1 + 5t²)]³

Step-by-step explanation:

a. The unit tangent

The unit tangent T(t) = r'(t)/|r'(t)| where |r'(t)| = magnitude of r'(t)

r(t) = (t, t²/2, t²)

r'(t) = dr(t)/dt = d(t, t²/2, t²)/dt = (1, t, 2t)

|r'(t)| = √[1² + t² + (2t)²] = √[1² + t² + 4t²] = √(1 + 5t²)

So, T(t) = r'(t)/|r'(t)| = (1, t, 2t)/√(1 + 5t²)  = (i + tj + 2tk)/√(1 + 5t²)

ii. The unit normal

The unit normal N(t) = T'(t)/|T'(t)|

T'(t) = dT(t)/dt = d[ (i + tj + 2tk)/√(1 + 5t²)]/dt

= -5ti/√(1 + 5t²)⁻³ + [-5t²j/√(1 + 5t²)⁻³] + [-10tk/√(1 + 5t²)⁻³]

= -5ti/√(1 + 5t²)⁻³ + [-5t²j/√(1 + 5t²)⁻³] + j/√(1 + 5t²)+ [-10t²k/√(1 + 5t²)⁻³] + 2k/√(1 + 5t²)

= -5ti/√(1 + 5t²)⁻³ - 5t²j/[√(1 + 5t²)]⁻³ + j/√(1 + 5t²) - 10t²k/[√(1 + 5t²)]⁻³ + 2k/√(1 + 5t²)

= -5ti/√(1 + 5t²)⁻³ - 5t²j/[√(1 + 5t²)]⁻³ - 10t²k/[√(1 + 5t²)]⁻³ + j/√(1 + 5t²) + 2k/√(1 + 5t²)

= -(i + tj + 2tk)5t/[√(1 + 5t²)]⁻³ + (j + 2k)/√(1 + 5t²)

We multiply by the L.C.M [√(1 + 5t²)]³  to simplify it further

= [√(1 + 5t²)]³ × -(i + tj + 2tk)5t/[√(1 + 5t²)]⁻³ + [√(1 + 5t²)]³ × (j + 2k)/√(1 + 5t²)

= -(i + tj + 2tk)5t + (j + 2k)(1 + 5t²)

= -5ti - 5²tj - 10t²k + j + 5t²j + 2k + 10t²k

= -5ti + j + 2k

So, the magnitude of T'(t) = |T'(t)| = √[(-5t)² + 1² + 2²] = √[25t² + 1 + 4] = √[25t² + 5]

So, the normal vector N(t) = T'(t)/|T'(t)| = (-5ti + j + 2k)/√[25t² + 5]

(b) Use Formula 9 to find the curvature.

The curvature κ = |r'(t) × r"(t)|/|r'(t)|³

since r'(t) = (1, t, 2t), r"(t) = dr'/dt = d(1, t, 2t)/dt  = (0, 1, 2)

r'(t) = i + tj + 2tk and r"(t) = j + 2k

r'(t) × r"(t) =  (i + tj + 2tk) × (j + 2k)

= i × j + i × 2k + tj × j + tj × 2k + 2tk × j + 2tk × k

= k - 2j + 0 + 2ti - 2ti + 0

= -2j + k

So magnitude r'(t) × r"(t) = |r'(t) × r"(t)| = √[(-2)² + 1²] = √(4 + 1) = √5

magnitude of r'(t) = |r'(t)| = √(1 + 5t²)

|r'(t)|³ = [√(1 + 5t²)]³

κ = |r'(t) × r"(t)|/|r'(t)|³ = √5/[√(1 + 5t²)]³

Answer:

here is your answer

Step-by-step explanation:

here is your answer

Answer:

whats the question

Step-by-step explanation:

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Pick a point (such as K, L, or M). Count one grid square to the left and 7 up. That is its new location.

Answer:

B

Step-by-step explanation:

I'm not really shure tho

Answer:

D. -0.5

Step-by-step explanation:

AB dilated by scale factor -0.5 to produce AB'.

the length of AB = 4 units and the length of AB' = 2 units, the direction is backward, so the scale factor is - 2/4 = -0.5

Answer:

C

Step-by-step explanation:

For C the y axis changes, add 5 to -3 and you get 2. Therefore 5 units away!

Hope this helps, good luck! :)

9514 1404 393

Answer:

  x ≈ 9.3

Step-by-step explanation:

The relevant trig relation is ...

  Cos = Adjacent/Hypotenuse

  cos(50°) = 6/x

Solving for x gives ...

  x = 6/cos(50°) ≈ 9.3343

  x ≈ 9.3

__

There is no 'c' to find the value of.

Answer:

x ≈ 9.3

Step-by-step explanation:

Since , this is right triangle, we can use trigonometry functions;

cos θ = Adjacent side / Hypotenuse

Where, θ = 50°

Solve for x

cos 50° = 6 / x

Multiply both side by x

cos 50° × x = 6 / x × x

cos 50° × x = 6

divide cos50° by both sides

cos 50° / cos 50° × x = 6 / cos 50°

x = 6 / cos 50°

x ≈ 9.33434296

Nearest tenth :- x ≈ 9.3

-11/5 = -11 ÷ 5 = -2.2

Answer:

-2.2

Answer:

x=6

Step-by-step explanation:

Answer:

Interval Notation:

(6,∞)

Inequality Form:

x>6

there ya go

Answer:

[tex]=280[/tex] [tex]in^2[/tex]

Step-by-step explanation:

----------------------------------------

Let's find the surface area of the pink rectangular prism first.

[tex]2*10=20+20=40[/tex]

[tex]4*10=40+40=80[/tex]

[tex]4*2=8+8=16[/tex]

[tex]40+80+16=136[/tex]

The surface area for the pink rectangular prism is [tex]136[/tex] [tex]in^2[/tex].

-------------------->>>>>

Now, let's find the surface area of the green rectangular prism.

[tex]4*7=28+28=56[/tex]

[tex]4*7=28+28=56[/tex]

[tex]4*4=16+16=32[/tex]

[tex]56+56+32=144[/tex]

The surface area for the green rectangular prism is 144 [tex]in^2[/tex].

-------------------->>>>>

Now let's add the surface area of both rectangular prisms to find the surface area of the composite figure.

[tex]136+144=[/tex]

[tex]=280[/tex] [tex]in^2[/tex]

----------------------------------------

Hope this is helpful.

9514 1404 393

Answer:

  224 in²

Step-by-step explanation:

There are a couple of ways to go at this. Here, we choose to figure the areas of each of the prisms individually, then subtract the "hidden" area where they are joined together.

The area of a prism is ...

  A = 2(LW +H(L+W))

Pink area:

  A = 2(10·4 +2(10+4)) = 2(40 +28) = 136 . . . square inches

Green area:

  A = 2(7·4 +4(7+4)) = 2(28 +44) = 144 . . . square inches

One 4 in × 7 in face of the green prism meets with a similar area of the pink prism, so the area hidden at that interface is 2(4·7) = 56 square inches. Then the total surface area of the composite figure is ...

  SA = 136 in² +144 in² -56 in² = 224 in²

Answer:

You answered it

Answer:

The answer in each numeral is:

Step-by-step explanation:

To obtain the result in each case, you must replace the variable (n) by the value that appears in the second case, I'll explain it with the first exercise:

As you can see, in the second doesn't appear f(n), but f(4), that means you must replace the "n" in the equation by 4, if we do this, we obtain:

The first answer is 28, now we'll continue with the next exercises:

In this form, you can prove the answers are: 28, -19, -33, and -9 respectively.

Answer:

(a)=50%(b)=2.1and(c)=16.1

Step-by-step explanation:

Hope this helps

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The graph that includes the point (1, 3) will be the one that is a graph of ...

  y = 3^x

Answer:

68 degrees

Step-by-step explanation:

Since the angle is a right angle, it is 90 degrees, to figure out the measurement of a section if it, simply subtract the known angle 22, from 90 to get an answer of 68.

Answer:

[tex]CV=0.2[/tex] ---- dataset 1

[tex]CV = 7.2[/tex] --- dataset 2

Step-by-step explanation:

Given

[tex]A: 30500, 27500, 31200, 24000, 27100,28600, 39100, 36900, 35000, 21400, 37900, 27900, 18700,[/tex][tex]33100[/tex]

[tex]B: 4.29, 4.88, 4.34, 4.17, 4.52, 4.80, 3.28, 3.79, 4.84, 4.77, 3.11[/tex]

Required

The coefficient of variation of each

Dataset A

Calculate the mean

[tex]\mu = \frac{\sum x}{n}[/tex]

[tex]\mu = \frac{30500+ 27500+31200+24000+ 27100+28600+ 39100+ 36900+ 35000+ 21400+ 37900+ 27900+ 18700+33100}{14}[/tex][tex]\mu = \frac{418900}{14}[/tex]

[tex]\mu = 29921.43[/tex]

Next, calculate the standard deviation using:

[tex]\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}[/tex]

So, we have:

[tex]\sigma= \sqrt{\frac{(30500 - 29921.43)^2 +.................+ (18700- 29921.43)^2 + (33100- 29921.43)^2}{13}}[/tex]

[tex]\sigma= \sqrt{\frac{487723571.42857}{14}}[/tex]

[tex]\sigma= \sqrt{34837397.959184}[/tex]

[tex]\sigma= 5902.32[/tex]

So, the coefficient of variation is:

[tex]CV=\frac{\sigma}{\mu}[/tex]

[tex]CV=\frac{5902.32}{29921.43}[/tex]

[tex]CV=0.2[/tex] --- approximated

Dataset B

Calculate the mean

[tex]\mu = \frac{\sum x}{n}[/tex]

[tex]\mu = \frac{4.29+ 4.88+ 4.34+ 4.17+ 4.52+ 4.80+ 3.28+ 3.79+ 4.84+ 4.77+ 3.11}{11}[/tex]

[tex]\mu = \frac{46.79}{11}[/tex]

[tex]\mu = 4.25[/tex]

Next, calculate the standard deviation using:

[tex]\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}[/tex]

[tex]\sigma = \sqrt{\frac{(4.29 - 4.25)^2 + (4.88- 4.25)^2 +.........+ (3.11- 4.25)^2}{11}}[/tex]

[tex]\sigma = \sqrt{\frac{3.859}{11}}[/tex]

[tex]\sigma = \sqrt{0.35081818181}[/tex]

[tex]\sigma = 0.593[/tex]

So, the coefficient of variation is:

[tex]CV=\frac{\sigma}{\mu}[/tex]

[tex]CV = \frac{4.25}{0.5903}[/tex]

[tex]CV = 7.2[/tex] -- approximated

Answer:

When using this technique, the AOQ:

improves (AOQ becomes a smaller fraction).

Step-by-step explanation:

AOQ simply means Average Outgoing Quality, which improves with inspection.  It is a part of an organization's Acceptance Sampling Plan, usually designed to meet product quality and risk level targets.  The plan draws samples from a population of items.  Then it tests the samples.  It only accepts the entire population if the sample is considered good enough.  It also rejects the population when the sample is poor enough.  In the plan, information about sample size and critical acceptance or rejection numbers are clearly indicated.  Acceptance sampling is common in most business environments because it has been found to be more economical than doing 100% inspection of incoming production input and output.

Answer:

x = 5q - 15

Step-by-step explanation:

[tex]\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15[/tex]

Answer:

1979

91%

Step-by-step explanation:

Given the relation :

P = (318t + 6792) / (1.19t + 107.36)

P = % of household with PC

t = years since 2000

1.) We need to find t, when P = 85%

P = 0.85

0.85 = (318t + 6792) / (1.19t + 107.36)

0.85(1.19t + 107.36) = (318t + 6792)

1.0115t + 91.256 = 318t + 6792

Collect like terms :

1.0115t - 318t = 6792 - 91.256

−316.9885t = 6700.744

t = 6700.744 / - 316.9885

t = - 21.138760

t = - 21 years

2000 - 21 years = 1979

Percentage who had computer in 2014

t = 2014 - 2000 = 14

P = (318(14) + 6792) / (1.19(14)+ 107.36)

P = (4452 + 6792) / (16.66 + 107.36)

P = 11244 / 124.02

P = 90.6627

P = approximately 91%

Answer:

19.01%

Step-by- step explanation:

[tex]Percentage = \frac{1.35 billion }{ 7.1 billion } \times 100[/tex]

                [tex]= \frac{ 1.35 \ times 1, 000, 000, 000} {7.1 \times 1,000,000,000} \times 100\\\\\\=\frac{1.35}{7.1} \times 100 = 19.01 \%[/tex]

9514 1404 393

Answer:

  (c)  g(x) = -f(x) +1

Step-by-step explanation:

We really only need to consider one point on f(x) and/or g(x). We can look at the y-intercepts.

  f(0) = 4  and  g(0) = -3

Looking at the answer choices, we see ...

  A. -f(0) -1 = -4 -1 = -5 ≠ g(0)

  B. f(0 -1) = f(-1) = 1 ≠ g(0)

  C. -f(0) +1 = -4 +1 = -3 = g(0) . . . . . matches requirements

  D. -f(0) = -4 ≠ g(0)

The relation between f(x) and g(x) is g(x) = -f(x) +1.