What is the measure of angle x?

Answer:

78

Correct term:60

Step-by-step explanation:

We are given that

[tex]\frac{4x^4-6x^3+6x+3}{x-3}[/tex]

The quotient of this expression is given by

[tex]4x^3+6x^2+18x+78+\frac{183}{x-3}[/tex]

We have to find the term in this expression  which contains an error.

[tex]\frac{4x^4-6x^3+6x+3}{x-3}[/tex]

The quotient of this expression is given by

[tex]=4x^3+6x^2+18x+60[/tex]

[tex]Dividend=Divisor\times quotient+ remainder[/tex]

Using the formula

[tex]4x^4-6x^3+6x+3=(x-3)(4x^3+6x^2+18x+60)+\frac{183}{x-3}[/tex]

We can see that in the given expression there is 60 in place of 78.

The error in the expression of quotient is 78.

Correct term is 60.

Answer:

4 > [tex]-\frac{n}{4}[/tex]

-16 > n

Step-by-step explanation:

Greater than would mean that the "arrow" is not facing the number. It would mean it is larger than the other number. Also, you have to construct the other part of the inequality which would be [tex]-\frac{n}{4}[/tex].

4×4 > [tex]-\frac{n}{4}[/tex]×4

16 > -n

-16 > n

Solution :

Trigonometric angles :

The trigonometric angles are defined as the angles that are obtained by the ratios of trigonometric functions. It shows the relationship between the sides of the triangle and the angles between them. These values of the trigonometric angles ranges from 0 to 36 degrees.

Below attached shown are the angles on a unit circle which shows the angles for each value of sin, cos and tan, and also the radian measure for each of the angles.

Answer:

H0 : The mean difference in strikes between pre and post strike is equal to 0

H1 : The mean difference in strikes between pre and post strike is not equal to 0

Step-by-step explanation:

The scenario described abibe meets the condition for a paired (dependent) sample t test as the same subject is involved in both the pre and post strike data. Therefore measurement from the strike(pre) must be paired with measurement from the strike(post) data.

For a paired test involving a single subject ; The mean difference in the two sample is 0 ; that is both are the same while the alternative negates the null by claiming that the mean difference is not equal to zero.

Answer:

100%_$40.80

? × _$38.76

Step-by-step explanation:

100%×$38.76÷$40.80=95%

Answer:

40.80

Step-by-step explanation:

Answer:

C. 2x

Step-by-step explanation:

Let

B's age = x years

A's age = 2 times older than B

= 2 * x

= 2x years

A's age = 2x years

For instance, if B's age is 17 years

Then,

A's age = 2x

= 2(17)

= 34 years old

Answer:

12

Step-by-step explanation:

because line FB divides triangle f v w into two equal halves therefore line WP is equal to line PV which is equal to 12

The required value of the PV is 12 in triangle DEF where p is the incenter.

Point P is the incenter of ΔDEF. Point P is the point of concurrency of the angle bisector. PV to be determined.

The incenter of a triangle is the intersection point of the internal angle bisectors of the triangle. In additional expressions, it can be clarified as the point where the internal angle bisectors of the triangle and perpendicular distance from this point to any of the sides of triangle is the same.

Since in triangle FGH, P is the incenter and PW, PV,PX is perpendicular distance to the sides HF, GF and GH respectively.
From image,
PW = 12
So by the property of incenter, perpendicular distance from this point to any of the sides of triangle is the same.

PW = PV
PV = 12

Thus, the required value of the PV is 12 in triangle DEF where p is the incenter.

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Answer:

6

Step-by-step explanation:

Answer:

$51.38

Step-by-step explanation:

7.43% of 47.83=(rounded to the nearest hundredth) 3.55

7.43/100*x/47.83

x=3.55

because we are solving for x

we can also cross check by taking out the percentage

x/100*3.55/47.83

47.83x=355

x=7.42212000836

which is about 7.43%

47.83+3.55= 51.38

Answer:

A) 6 square inches.

Step-by-step explanation:

A(Triangle) = 1/2bh

b = base length

h = height length

A(Triangle) = 1/2(4)(3) = 6

Therefore, the area of the triangle is 6 in².

Answer:

Step-by-step explanation:

So, yearly $2100 is paid, plus the 1.73% interest, so 1.73% interest is $2136.33every year interest stacks on itself so youll take 1.73% of the year 1 total with interest.  

Year 1 total: $2136.33

Year 2 total:$2173.29

Year 3 total:$2210.89

Year 4 total:$2249.14

Year 5 total:$2288.05

Total Paid After 5 years:$11057.70

Year 1 total interest:$36.33

Year 2 total interest:$36.96Year 3 total interest:$37.60Year 4 total interest:$38.25Year 5 total interest:$38.91

Total Interest paid after 5 years:$188.05

Answer:

in neighbourhood q the total number of people in the nine families I higher than that in neighbourhood s because of we add up the number of people in the families in neighbourhood q we get a total of 35 yet we have a total of only 27 people in the nine families in neighbourhood s

hope that helps ❤

Answer:

Step-by-step explanation:

here's the answer to your question

Answer:

it must be yes!

Step-by-step explanation:

Answer:

your closest number should be A

Answer:

A.√99

Step-by-step explanation:

10^2 = 100

Or vise versa √100 = 10

The closest number to 100 is 99

So √99 is closest to 10

Given:

The expression is:

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}[/tex]

To find:

The correct form of the partial fraction decomposition for the given expression.

Solution:

We have,

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}[/tex]

By partial fraction decomposition, it can be written as:

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}=\dfrac{A}{x+1}+\dfrac{B}{(x+1)^2}+\dfrac{Cx+D}{x^2+7}[/tex]           ...(i)

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}=\dfrac{(x+1)^2(Cx+D)+(x+1)(x^2+7)A+(x^2+7)B}{(x+1)^2(x^2+7)}[/tex]

[tex]4x^3+3x^2=(x+1)^2(Cx+D)+(x+1)(x^2+7)A+(x^2+7)B[/tex]

[tex]4x^3+3x^2=x^3A+x^3C+x^2A+x^2B+2x^2C+x^2D+7xA+xC+2xD+7A+7B+D[/tex]

[tex]4x^3+3x^2=x^3(A+C)+x^2(A+B+2C+D)+x(7A+C+2D)+7A+7B+D[/tex]

On comparing both sides, we get

[tex]A+C=4[/tex]

[tex]A+B+2C+D=3[/tex]

[tex]7A+C+2D=0[/tex]

[tex]7A+7B+D=0[/tex]

On solving these equations, we get

[tex]A=\dfrac{23}{32},B=-\dfrac{1}{8},C=\dfrac{105}{32},D=-\dfrac{133}{32}[/tex]

Substituting these values in (i), we get

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}=\dfrac{\dfrac{23}{32}}{x+1}+\dfrac{-\dfrac{1}{8}}{(x+1)^2}+\dfrac{\dfrac{105}{32}x-\dfrac{133}{32}}{x^2+7}[/tex]

Therefore, the required partial fraction decomposition is:

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}=\dfrac{\dfrac{23}{32}}{x+1}+\dfrac{-\dfrac{1}{8}}{(x+1)^2}+\dfrac{\dfrac{105}{32}x-\dfrac{133}{32}}{x^2+7}[/tex]

Answer:

A on Edg

Step-by-step explanation:

got it right

Answer:

A

Step-by-step explanation:

Answer:

I have no clue sorry bro.

Last year He was 7 years old.

His father is 4 times the age 7 x 4 = 28

Last year his dad was 28, so this year he is 29.

Combined age this year = 29 + 8 = 37

51 - 37 = 14 years

14/ 2 people = 7 years

8 + 7 = 15

29 + 7 = 36

15 + 36 = 51

It will take 7 years.

Answer:

Step-by-step explanation:

7) PQ // RS,  RQ is transversal

x = 38 {Alternate interior angles are congruent}

In ΔPQR ,

x + y + ∠P  = 180   {Angle sum property of triangle}

38 + 90 + y = 180

  128 + y =  180

           y = 180 - 128

y = 52

9) Construct XY // AB

XY // AB  & AC is transversal

∠1 = ∠4     ---------(I)      {alternate interior angles are equal}

XY // AB  & BC is transversal

∠3 = ∠5     ---------(II)      {alternate interior angles are equal}

∠1 + ∠2 + ∠3 = 180   {straight line angles}

∠4 + ∠2 + ∠5 = 180    {From (I) & (II) }

Sum of three angles of triangle is 180.Hence proved.

Answer:

usual number of yellow eggs = 12

Usual maximum = 21

Usual minimum = 3

Step-by-step explanation:

To solve this, we will use the expected value of a binomial probability.

The formula is;

E(X) = np

Where;

n is sample size

p is probability of success.

We are given;

n = 58

p = 21%

Thus;

usual number of yellow eggs in samples = np = 58 × 21% = 12.18 ≈ 12

From USL(Upper specification limit) and LSL(Lower specification limit) formula, we can find the maximum usual number and minimum usual number of eggs respectively.

Thus;

USL = n(p + 3√(p(1 - p)/n)

USL = 58(0.21 + 3√(0.21(1 - 0.21)/58)

USL = 21.48 ≈ 21

LSL = n(p - 3√(p(1 - p)/n)

LSL = 58(0.21 - 3√(0.21(1 - 0.21)/58)

LSL = 2.87 ≈ 3

Answer:

x = 0, π/3, 2π/3,  π,  4π/3,  5π/3

Step-by-step explanation:

4cos^4(x) – 5cos^2(x) + 1 = 0

(4cos^2(x) - 1)(cos^2(x) - 1) = 0

When 4cos^2(x) - 1 = 0

cos^2(x) = 1/4

cos x = +/-1/2

so x = π/3, 2π/3, 4π/3, 5π/3.

When cos^2x - 1 = 0

cos x = +/- 1

x =  0, π.

x

The solution is : x = 0, π/3, 2π/3,  π,  4π/3,  5π/3

Simplify simply means to make it simple. In mathematics, simply or simplification is reducing the expression/fraction/problem in a simpler form. It makes the problem easy with calculations and solving.

here, we have,

given that,

4cos^4(x) – 5cos^2(x) + 1 = 0 from [0, 2π)

so, we get,

4cos^4(x) – 5cos^2(x) + 1 = 0

(4cos^2(x) - 1)(cos^2(x) - 1) = 0

When 4cos^2(x) - 1 = 0

cos^2(x) = 1/4

cos x = +/-1/2

so x = π/3, 2π/3, 4π/3, 5π/3.

When cos^2x - 1 = 0

cos x = +/- 1

x =  0, π.

Hence, The solution is : x = 0, π/3, 2π/3,  π,  4π/3,  5π/3.

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Given:

The expression is:

[tex]\dfrac{25x^2}{2x+6}\cdot \dfrac{2}{5x}[/tex]

To find:

The simple product.

Solution:

We have,

[tex]\dfrac{25x^2}{2x+6}\cdot \dfrac{2}{5x}[/tex]

It can be written as:

[tex]=\dfrac{5\times 5\times x\times x}{2(x+3)}\cdot \dfrac{2}{5x}[/tex]

Cancel out the common factors.

[tex]=\dfrac{5\times x}{x+3}[/tex]

[tex]=\dfrac{5x}{x+3}[/tex]

Therefore, the correct option is C.

Answer:

Options (1) and (4)

Step-by-step explanation:

Given equation for the deposit in the saving account is,

y = 20x + 50

Here, y = Amount of money in the account

20 = money added in the account every month

50 = Initial deposit

By comparing this equation with the slope-intercept form of the equation of a line,

y = mx + b

Here, slope m = money added in the account every month

And b = y-intercept

Therefore, Options (1) and (4) will be the answer.

Answer:

y = 1/(x+1)   -5

X cannot be -1 because the denominator would go to zero

Step-by-step explanation:

f(x) = 1/(x+5) -1

y =  1/(x+5) -1

Exchange x and y and solve for y

x =  1/(y+5) -1

x+1 = 1/(y+5)

Multiply by (y+5)

(x+1) (y+5) = 1

Divide by (x+1)

y+5 = 1/(x+1)

Subtract 5

y = 1/(x+1)   -5

X cannot be -1 because the denominator would go to zero