Answer:
To find the mean absolute deviation of the data, start by finding the mean of the data set. Find the sum of the data values, and divide the sum by the number of data values. Find the absolute value of the difference between each data value and the mean: |data value – mean|
Step-by-step explanation:
Circle the equation of a straight line that does not intersect the curve y = x2
(1 m
y = 5
X=-3
y = 2x - 5
y= -3x + 1
Answer:
[tex] \boxed{y = 2x\: – \: 5} [/tex]
Which of these numbers had exactly tow factors?
Select your answer. 7 8 9 10
A B C D
Answer:
prime numbers only have two factors...
7 is the only prime in the list
Step-by-step explanation:
Find the missing angle measures.
Answer:
<ABD = 42 degrees
<ABC = 84 degrees
Step-by-step explanation:
<ABC = 42 + 42 = 84
I want to know the Answers
Step-by-step explanation:
this is the correct answer you wanted to know
please mark brainliest
jerry has been staying up late at night to get in some extra study time. He hopes to get accepted into his favorite college and needs to pass the entrance exam. The test is a stressor and which of the following is symptom of how he is reacting to stress?
normal heart rate
upset stomach
extra sleep
increased energy
Jerry has been stressing a lot for getting into his favorite college. The symptom by which he is reacting to stress is 'upset stomach'.
How do people react to stress?Stress can lead to a lot of emotional and physical negative responses in the body. This includes difficulty breathing, panic attacks, blurred eyesight or sore eyes, sleep problems, fatigue, muscle aches and headaches, chest pains and high blood pressure, Indigestion or heartburn, constipation, feeling sick, dizzy or fainting.
When Jerry stayed up late at night to get in some extra study time, had a mental burden of passing an entrance exam, a lot of stress was built. He reacted to it with an upset stomach just like others.
Learn more about reacting to stress here
https://brainly.com/question/14973731
#SPJ2
the base of a right prism is an equilateral triangle each of whose sides measures 4cm.the altitude of the prism measures 5cm.Find the volume of the prism
Answer:
[tex]V=34.64\ cm^3[/tex]
Step-by-step explanation:
Given that,
The side of an equilateral prism = 4 cm
The altitude of the prism = 5 cm
We need to find the volume of the prism. The formula for the volume of a prism is as follows :
[tex]V=A\times h[/tex]
Where
A is the area of equilateral triangle, [tex]A=\dfrac{\sqrt3}{4}a^2[/tex]
So,
[tex]V=\dfrac{\sqrt3}{4}a^2\times h\\\\V=\dfrac{\sqrt3}{4}\times 4^2\times 5\\\\V=34.64\ cm^3[/tex]
So, the volume of the prism is equal to [tex]34.64\ cm^3[/tex].
Can someone help me with this math homework please!
Answer:
2nd option
{(-8, -2), (-4, 1), (0, -2), (2, 3), (4, -4)}
Step-by-step explanation:
For a function to exist, every value of input must have exactly one value of output.
The rest of the relations(1, 3, and 4) have 2 outputs for 1 input so they dont make a function.
Answer:
(B)
Step-by-step explanation:
If you noticed, all the other input values have one input value that has two output values. This doesn't represent a function. Only (B) has one output for each input.
Hope that helps (●'◡'●)
The sum of two numbers is -4 and their difference is zero. Find the numbers.
Answer:
- 2 and - 2
Step-by-step explanation:
let the 2 numbers be x and y , then
x + y = - 4 → (1)
x - y = 0 → (2)
Add the 2 equations term by term to eliminate y
2x + 0 = - 4
2x = - 4 ( divide both sides by 2 )
x = - 2
Substitute x = - 2 into either of the 2 equations and solve for y
Substituting into (1)
- 2 + y = - 4 ( add 2 to both sides )
y = - 2
The 2 numbers are - 2 and - 2
The given equation has been solved in the table. Step Statement 1 1 –7n + 11 = -10 2. -7n + 11 – 11 = -10 – 11 3 -7n = -21 4 = = =21 .In -7 -21 __7 5 n = 3 Use the table to complete each statement. In step 2, the In step 4, the property of equality was applied. property of equality was applied.
Answer:
In step 2, the subtraction property of equality was applied
In step 4, the division property of equality was applied
Step-by-step explanation:
The Cooking Club made some pies to sell during lunch to raise money for a field trip. The cafeteria helped by donating three pies to the club. Each pie was then cut into six pieces and sold. There were a total of 72 pieces to sell. How many pies did the club make?
Which equation can be used to solve this problem? Select all that apply.
Vicki and Tamra are working on their math homework together. Vicki has worked p problems, and Tamra has worked 4 times as many problems as Vicki. The expression shows how many problems they have worked altogether.
Answer:
p + 4p
5p
Step-by-step explanation:
Problems Vicki solved = p
Tamra worked 4 times as many problems as Vicki = 4 x p = 4p
total problems solved by both of them =4p + p
= 5p
If and are the zeroes of the polynomial 2x^2+3x+5 then the value of 1/alpha + 1/beta
Pls answer fast..I’ll mark the brainlest
Answer:
-4/15
Step-by-step explanation:
Mathematically, we know that;
alpha= -b/a and beta = c/a
a refers to the coefficient of the x^2 which is 2
b is the coefficient of x which is 3
c is the last number which is 5
alpha = -b/a = -3/2
beta = c/a = 5/2
1/alpha = -2/3
1/beta = 2/5
so we have the sum as;
-2/3 + 2/5
= -5(2) + 3(2)/15 = (-10 + 6)/15 = -4/15
A and B are two similar 2D shapes
A 12cm
B 15cm
The area of the shape A is 200cm^2.
Calculate the area of shape B
Answer: [tex]312.5\ cm^2[/tex]
Step-by-step explanation:
Given
A and B are two similar shape with lengths of 12 cm and 15 cm
A has an area of [tex]200\ cm^2[/tex]
For similar figures, ratio of the square of corresponding length is equal to the ratio of the area
[tex]\Rightarrow \dfrac{200}{A_b}=\dfrac{12^2}{15^2}\\\\\Rightarrow A_b=\dfrac{15^2}{12^2}\times 200\\\\\Rightarrow A_b=312.5\ cm^2[/tex]
solve g(x)=(the square root of x+1)+3
Step-by-step explanation:
solve for what ?? do you mean graph the function??
Activity 2. pls just give me the formula or answer this, it really help me
Answer:
X= sin (56) . 17) hope this helps
Select the two values of x that are roots of this equation.
x² + 3x-6=0
A. X=
-3+ /33
2
B. x=-3-83
c. x. -3-15
D. x. -3*4/15
please help
Answer:
[tex]x1 = \frac{ - 3 - \sqrt{33} }{2} \\ x2 = \frac{ - 3 + \sqrt{33} }{2} [/tex]
Step-by-step explanation:
[tex]x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} \\ = \frac{ - 3 + - \sqrt{9 + 24} }{2} \\ x1 = \frac{ - 3 - \sqrt{33} }{2} \\ x2 = \frac{ - 3 + \sqrt{33} }{2} [/tex]
eeeeeeee please help!
Answer:
1) Less than
2) greater than
Step-by-step explanation:
Equation of the first line:
(y+7)/(-13+7) = x/-1
(y+7))/-6 = -x
y+7 = 6x
y= 6x - 7
Equation of the second line:
A (4/3,0) ; B (0,8)
y/8 = (x-4/3)/-4/3
y/8 = (x-4/3) * -3/4
y/8 = -3/4x + 1
y = -6x + 8
The HCF and LCM of two numbers x and 126 are 24 and 840 respectively. Find the value of x.
Answer:
x=160
Step-by-step explanation:
x×126=24×840
[tex]x=\frac{24 \times840}{126} =160[/tex]
A. -1/4 + 2/3=
B. 1/2-3/5-1/2=
C. 3/4 of 2/9=
D. 2/5 of 7/12=
please help me
with explanation as well
Answer:
[tex]A) - \frac{1}{4} + \frac{2}{3} \\ \frac{ - 3 + 8}{12} \\ = \frac{5}{12} [/tex]
[tex]B) \frac{1}{2} - \frac{3}{5} - \frac{1}{2} \\ \frac{5 - 6 - 5}{10} \\ = \frac{ - 6}{10} [/tex]
[tex]C) \frac{3}{4} of \frac{2}{9} \\ \frac{3}{4} \times \frac{2}{9} \\ \frac{6}{36} = \frac{1}{6} [/tex]
[tex]D) \frac{2}{5} \times \frac{7}{12} \\ = \frac{14}{60} = \frac{7}{30} [/tex]
Find the area of a rectangle with a length of 10 cm and a width of 7 cm.
70 cm
17 cm2
70 cm2
17 cm
Plz help. How to convert this standard notation to scientific notation 549,755,813,888.
Answer:
To change a number from scientific notation to standard form, move the decimal point to the left (if the exponent of ten is a negative number), or to the right (if the exponent is positive). You should move the point as many times as the exponent indicates. Do not write the power of ten anymore
What is the range of the function f(x) = 4x + 9, given the domain D = {-4, -2, 0, 2}?
Answer:
Range D = {-7, 1, 9, 17}
Step-by-step explanation:
f(x) = 4x + 9
4(-4) + 9 = -7
4(-2) + 9 = 1
4(0) + 9 = 9
4(2) + 9 = 17
f(x)=2^x by a factor of five
Which property does each equation demonstrate?
x2 + 2x = 2x + x2
Solve the equation and enter the value of x below. 3(x+11) + 5= 68
[tex]\boxed{ \sf{Answer}} [/tex]
[tex]3(x + 11) + 5 = 68 \\ 3x + 33 + 5 = 68 \\ 3x + 38 = 68 \\ 3x = 68 - 38 \\ 3x = 30 \\ x = \frac{30}{3} \\ x = 10[/tex]
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐
[tex] \huge\boxed{\mathfrak{Answer}}[/tex]
[tex]3(x + 11) + 5 = 68 \\ 3 \times x + 3 \times 11 + 5 = 68 \\ 3x + 33 + 5 = 68 \\ 3x + 33= 68 - 5 \\ 3x + 33= 63 \\ 3x = 63 - 33 \\ 3x = 30 \\ x = \frac{30}{3} \\ x = 10[/tex]
Two sides of a triangle have the following measures, Vind the range of possible measures for
the third side,
13) 8,7
14) 12,6
A) 1
B) 2 < x < 14
C) 1
D) 1
A) 8
B) 9
C) 8 < X < 18
D) 6 < X < 18
Answer:
[tex](13)\ 1 <x < 15[/tex]
[tex](14)\ 6 <x < 18[/tex]
Step-by-step explanation:
Question 13:
[tex]a,b = 8,7[/tex] -- the two sides
Using triangle inequality theorem, we have:
[tex]a + b > x[/tex]
[tex]a + x > b[/tex]
[tex]x + b > a[/tex]
So, we have:
[tex]a + b > x[/tex]
[tex]8 + 7 > x[/tex]
This gives:
[tex]15 > x[/tex]
[tex]a + x > b[/tex]
[tex]8 + x > 7[/tex]
Collect and evaluate like terms
[tex]x > -1[/tex]
[tex]x + b > a[/tex]
[tex]x + 7 > 8[/tex]
Collect and evaluate like terms
[tex]x > 1[/tex]
Ignore the inequality with a negative value.
So, we have:
[tex]x > 1[/tex] and [tex]15 > x[/tex]
Rewrite as:
[tex]1< x[/tex] and [tex]x < 15[/tex]
Merge
[tex]1 <x < 15[/tex]
Question 14:
[tex]a,b = 12,6[/tex] -- the two sides
Using triangle inequality theorem, we have:
[tex]a + b > x[/tex]
[tex]a + x > b[/tex]
[tex]x + b > a[/tex]
So, we have:
[tex]a + b > x[/tex]
[tex]12 + 6 > x[/tex]
This gives:
[tex]18 > x[/tex]
[tex]a + x > b[/tex]
[tex]12 + x > 6[/tex]
Collect and evaluate like terms
[tex]x > -6[/tex]
[tex]x + b > a[/tex]
[tex]x + 6 > 12[/tex]
Collect and evaluate like terms
[tex]x > 6[/tex]
Ignore the inequality with a negative value.
So, we have:
[tex]x > 6[/tex] and [tex]18 > x[/tex]
Rewrite as:
[tex]6< x[/tex] and [tex]x < 18[/tex]
Merge
[tex]6 <x < 18[/tex]
help or i will fail my acellus
Answer:
I think it's 155 cm
Step-by-step explanation:
=(5×5×3)+(5×2×4)
= 75+40
= 155 cm2
Find the sum of integers -72, 237, 84, 72, -184, -37
Answer:
100
Step-by-step explanation:
add positive numbers. then subtract the negative numbers.
Which of the statements proves that the lines a and b are parallel?
Answer:
C
Step-by-step explanation:
1,2 are both supplementary
For a project in his Geometry class, Tyler uses a mirror on the ground to measure the height of his school building. He walks a distance of 14.65 meters from his school, then places a mirror on flat on the ground, marked with an X at the center. He then steps 0.8 meters to the other side of the mirror, until he can see the top of the school clearly marked in the X. His partner measures the distance from his eyes to the ground to be 1.15 meters. How tall is the school? Round your answer to the nearest hundredth of a meter.
Answer:
The height of the school building is approximately 21.06 meters
Step-by-step explanation:
The method of Geometry Tyler is using to determine the height of his school building is through the property that similar triangles have a common ratio of corresponding their sides
The given parameters for the triangle formed by Tyler and the mirror are;
The distance from Tyler's eyes to the ground = 1.15 meters
The horizontal distance between Tyler and the mirror at X = 0.8 m
The parameters of the triangle formed by the height, h, of the school building and the mirror at X are;
The horizontal distance between the school building and the mirror = 14.65 m
The height of the school building = h
Therefore, we have;
[tex]\dfrac{The \ distance \ from \ Tyler's \ eyes \ to \ the \ ground}{The \ height \ of the \ school \ building} =\dfrac{Tyler's \ horizontal \ distance \ from \ mirror }{The \ building \ to \ mirror \ horizontal \ distance }[/tex]Therefore;
[tex]\dfrac{1.15 \, m}{h} = \dfrac{0.8 \ m}{14.65 \ m}[/tex]
[tex]h = \dfrac{1.15 \, m \times 14.65 \, m }{0.8 \, m} = 21.059375 \ m[/tex]
The height of the school building h to the nearest hundredth meter ≈ 21.06 m.