What is the kinetic energy of a bicylcle with a mass of 15 kg traveling at a velocity of 3 m/s?​

KE = 0.5 x mv^2

Kinetic energy equals 1/2 times mass times velocity squared.

Mass = 15kg

Velocity = 3m/s

Plug it into the formula.

KE = 0.5 x 15(3^2)

KE = 0.5 x 15(9)

Multiply the mass and velocity squared.

KE = 0.5 x 135

Then, multiply the result by 1/2 or 0.5

KE = 67.5

The kinetic energy of a bicycle that has a mass of 15kg and travels at 3m/s is 67.5J.

Answer:

67.5 J

Explanation:

Kinetic energy can be found using the following formula.

[tex]KE=\frac{1}{2}mv^2[/tex]

where m is the mass in kilograms and v is the velocity in m/s.

We know the bike has a mass of 15 kilograms. We also know the velocity is 3 m/s. Therefore, we can substitute 15 for m and 3 for v

[tex]KE=\frac{1}{2}*15*3^2[/tex]

Evaluate the exponent first. 3^2 is the same as 3*3, which is equal to 9.

[tex]KE=\frac{1}{2} *15*9[/tex]

Multiply 15 and 9.

[tex]KE=\frac{1}{2} *135[/tex]

Multiply 1/2 and 135

[tex]KE=67.5[/tex]

Add appropriate units. Kinetic energy uses Joules or J as the units.

[tex]KE= 67.5 Joules[/tex]

The kinetic energy of the bike is 67.5 Joules

what is mass times acceleration?

The diagram shows the field lines near the poles, X and Y, of two magnets.

At left a rectangular box with the long horizontal side labeled X. At right a rectangular box with the long horizontal side labeled Y. There is a gap between the boxes. Curved lines with arrowheads emerge from the right end of X and the left end of Y and point up and down.
Based on the field lines, what are the poles of the magnets?

X: north
Y: south

X: south
Y: north

X: north
Y: north

X: south
Y: south