What is the frequency of visible light which has a wavelength of 625nm?

Answer:

35.453 amu.

Explanation:

From the question given above, the following data were obtained:

Isotope A (Cl–35):

Abundance (A%) = 75.77%

Mass of A = 34.969 amu

Isotope B (Cl–37):

Abundance (B%) = 24.23%

Mass of B = 36.966 amu

AVERAGE atomic mass of Cl =?

The average atomic mass of Cl can be obtained as follow:

Average = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

Average = [(34.969 × 75.77)/100] + [(36.966 × 24.23)/100]

Average = 26.496 + 8.957

Average atomic mass of Cl = 35.453 amu.

Answer:

the final temperature is 465.2k

Answer: In the case of water, we know that the O-H covalent bond is polar, due to the different electronegativities of hydrogen and oxygen. Since there are two O-H bonds in water, their bond dipoles will interact and may result in a molecular dipole which can be measured.

Explanation:

Answer:

carbon mono oxide CO

Explanation:

as both are in 1:1 ratio so CO is formed

Answer:

PCl3 - trigonal pyramidal <109 degrees

SCl2 - bent<109 degrees

SiF4 - tetrahedral 109 degrees

Explanation:

The shape of all three molecules derive from a tetrahedral arrangement of electron pairs.

However, in PCl3 there is a lone pair of electrons on P and three bond pairs. This leads to the observance of a trigonal pyramidal geometry with bond angle <109 degrees.

In SCl2, there are four regions of electron density around S, two lone pairs and two bond pairs leading to a bent molecular geometry with bond angle <109 degrees.

In SiF4, there are four bond pairs and no lone pair. The molecular geometry is tetrahedral with a bond angle of 109 degrees.

Answer:

After 3 half lives 10 g of radio active material left.

Explanation:

Given data:

Total amount of radio active material = 80 g

Amount left after 3 half lives = ?

Solution:

At time zero = 80 g

At first half life = 80 g/2 = 40 g

At 2nd half life = 40 g/2 = 20 g

At 3rd half life = 20 g/2 = 10 g

Thus, after 3 half lives 10 g of radio active material left.

The characteristic that could distinguish a crystalline solid from an amorphous solid is option b. The way it breaks.

Crystalline solids contained edges and faces, that should be diffracted x-rays, and have sharp melting points.

While on the other hand, amorphous solids should contain irregular does not provide well-resolved x-ray diffraction patterns.

hence, the option b is correct.

And, the rest of the options are wrong.

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Answer:

18.84 g of silver.

Explanation:

We'll begin by calculating the number atoms present in 5.59 g of sulphur. This can be obtained as follow:

From Avogadro's hypothesis,

1 mole of sulphur contains 6.02×10²³ atoms.

1 mole of sulphur = 32 g

Thus,

32 g of sulphur contains 6.02×10²³ atoms.

Therefore, 5.59 g of sulphur will contain = (5.59 × 6.02×10²³) / 32 = 1.05×10²³ atoms.

From the calculations made above, 5.59 g of sulphur contains 1.05×10²³ atoms.

Finally, we shall determine the mass of silver that contains 1.05×10²³ atoms.

This is illustrated below:

1 mole of silver = 6.02×10²³ atoms.

1 mole of silver = 108 g

108 g of silver contains 6.02×10²³ atoms.

Therefore, Xg of silver will contain 1.05×10²³ atoms i.e

Xg of silver = (108 × 1.05×10²³)/6.02×10²³

Xg of silver = 18.84 g

Thus, 18.84 g of silver contains the same number of atoms (i.e 1.05×10²³ atoms) as 5.59 g of sulfur

Hi there! :)

[tex]\large\boxed{x = 2.49 L}[/tex]

Use the proportion for Charles' Law where:

[tex]\frac{v_{1}}{t_{1}}= \frac{v_{2}}{t_{2}}[/tex]

v1 = initial volume

t1 = initial temperature

v2 = final volume

v2 = final temperature

Substitute in the given values into the proportion:

v1 = 4.39 L

t1 = 44° C

t2 = 25°C

v2 = x L

Set up the proportion:

[tex]\frac{4.39}{44} = \frac{x}{25}[/tex]

Cross multiply:

[tex]25 * 4.39 = 44x\\\\109.75 = 44x\\\\x = 2.49 L[/tex]

Answer:

The new volume will be approximately 2.49 L.

Explanation:

We are given that a gas sample occupies 4.39 L at 44° C.

We are also given that we are going decrease the temperature to 25° C.

Charles' Law has a formula which shows the relationship between the volumes of a samples and the temperatures of the samples.

The proportion is shown as:

[tex]\displaystyle \bullet \ \ \ \frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex],

where V₁ and V₂ are the initial and final volume respectively and T₁ and T₂ are the initial and final temperature respectively.

This proportion can be used to determine what our unknown is. We need to know the final volume.

[tex]\displaystyle \frac{4.39 \ \text{L}}{44 \ \text{C}} = \frac{\text{x}}{25 \ \text{C}}\\\\\\\frac{4.39}{44} = \frac{x}{25}\\\\\\4.39 \times 25 = 44 \times x\\\\\\44x = 109.75\\\\\\\frac{44x}{44}=\frac{109.75}{44}\\\\\\x = 2.49432 \approx \boxed{2.49 \ \text{L}}[/tex]

Therefore, if we reduce the temperature to 25 °C, we will be reducing the volume of the substance to 2.49 L.

The [H₃0⁺] of the solution : 1.778  x 10⁻¹² M

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.  

pH = - log [H⁺]  

So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.  

A solution whose value is different by n has a difference in the concentration of H⁺ ion of 10ⁿ.  

pH of solution = 11.75

the [H₃0⁺] of the solution :

[tex]\tt pH=-log[H_3O^+]\\\\11.75=-log[H_3O^+]\\\\(H_3O^+]=10^{-11.75}=1.778\times 10^{-12}[/tex]

Answer:

i not sure but i searched it up and it said Q=104525J

Explanation:

Answer:

C. are found in the nucleus of an atom

Explanation:

Protons and Neutrons are always located at the center of the atom also called as the nuclei of the atom and constitute nearly all the mass of the atom, while the electrons revolve around them in orbits called shells. Only protons have a positive charge and electrons have negative charges, due to which only protons and electrons attract each other, while neutrons lack charges or have 'Neutral Charges'.

Answer:

Molarity = 0.3 M

Explanation:

Given data:

Moles of NaOH = 0.720 mol

Volume of water = 2.40 L

Molarity = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Molarity = 0.720 mol / 2.40 L

Molarity = 0.3 mol/L

Molarity = 0.3 M

Protons,neutrons,electrons

Answer:

3.68 g/cm3

Explanation:

D = M / V

350 / 95

Answer:

253.5mL of Ba(OH)₂ are required to neutralize the HCl solution

The pH at equivalence point is = 7

Explanation:

The reaction of Ba(OH)₂ with HCl is:

Ba(OH)₂ + 2HCl → BaCl₂ + 2H₂O

First, we need to find moles of HCl. With these moles and the chemical equation we can find the moles of Ba(OH)₂ and the volume required:

Moles HCl:

75.0mL = 0.075L * (0.845mol / 1L) = 0.063375moles HCl

Moles Ba(OH)₂:

0.06338moles HCl * (1mol Ba(OH)₂ / 2mol HCl) = 0.03169 moles Ba(OH)₂

Volume of the 0.125M Ba(OH)₂:

0.03169 moles Ba(OH)₂ * (1L / 0.125mol) = 0.2535L are required =

253.5mL of Ba(OH)₂ are required to neutralize the HCl solution

As the titration was of a strong acid, HCl, with a strong base, Ba(OH)₂, the pH at equivalence point is = 7

Answer:

P4O10

Explanation:

thermal contact

When heat flows from one object or substance to another it is in contact with, the objects or substances are said to be in thermal contact. The state where objects in thermal contact with each other reach the same temperature, no heat flows between them.

Answer:

bottom right corner with arrows going up

Answer:

i think the answer is c

Explanation:

collission

Answer: The empirical formula is [tex]NaBO_2[/tex]

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given:

Mass of Na= 34.5 g

Mass of B= 16.4 g

Mass of O = 48.6 g

Step 1 : convert given masses into moles.

Moles of Na =[tex]\frac{\text{ given mass of Na}}{\text{ molar mass of Na}}= \frac{34.5g}{23g/mole}=1.5moles[/tex]

Moles of B =[tex]\frac{\text{ given mass of B}}{\text{ molar mass of B}}= \frac{16.4g}{11g/mole}=1.5moles[/tex]

Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{48.6g}{16g/mole}=3moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Na = [tex]\frac{1.5}{1.5}=1[/tex]

For B = [tex]\frac{1.5}{1.5}=1[/tex]

For O =[tex]\frac{3}{1.5}=2[/tex]

The ratio of Na: B: O= 1: 1: 2

Hence the empirical formula is [tex]NaBO_2[/tex]

Answer:

The answer is c, Clouds fill with moisture and get too hravy

Answer:

1. They will react.

2. 2HCI + Zn —> ZnCl2 + H2

Explanation:

1. From the question given above,

We can see that Zn is higher than H in the activity series.

NOTE: Elements higher (i.e at the top) in the activity series will displace those lower (i.e at the bottom) in the series. Thus, Zn is higher in the series than H. Therefore, Zn will displace H from solution. Hence, they will react.

2. The product obtained from the reaction can be seen as follow:

HCI + Zn —> ZnCl2 + H2

The above equation can be balance as follow:

There are 2 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl as shown below:

2HCI + Zn —> ZnCl2 + H2

Answer:

0.9612 g

Explanation:

First we calculate how many moles are there in 3.00 g of CCl₃F, using its molar mass:

Now, we need to calculate how many grams of N₂O would have that same number of molecules, or in other words, the same amount of moles.

Thus we calculate how many grams would 0.0218 moles of N₂O weigh, using the molar mass of N₂O :

The  mass of dinitrogen monoxide is 0.9612 g

The number of  moles are there in 3.00 g of CCl₃F, using its molar mass:

= 3.00 g CCl₃F ÷ 137.37 g/mol

= 0.0218 mol CCl₃F

Now the mass should be

=[ 0.0218 mol N₂O ×  44.013 g/mol

= 0.9612 g N₂O

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Answer:

dunno

Explanation: