What is the expression in SIMPLEST radical form? (20)∧5/2

[tex]k+\frac{k}{2}+\frac{k}{6}=120\\\\6k+3k+k=720\\10k=720\\k=72[/tex]

72,36,12

answer: 36

Step-by-step explanation:

Hello, there!!!

The answer is option D.

I have given solution on the picture.

Hope it helps.....

Answer:

x=3

Step-by-step explanation:

14=7(2x-4)

14/7=2x-4

2=2x-4

2x=2+4

2x=6

x=6/2

x=3

------------

14=7(2x-4)

14=14x-28

14x=14+28

14x=42

x=42/14

x=3

The equation 14 = 7(2x - 4) can be solved using two different methods: the distributive property method and the inverse operations method. Both methods yield the same solution, which is x = 3. The preference between the two methods depends on personal preference and the specific equation being solved.

Distributive Property Method:

We'll distribute the 7 to the terms inside the parentheses:

14 = 7(2x - 4)

14 = 14x - 28

Next, we'll isolate the variable term:

14x = 14 + 28

14x = 42

Finally, we'll solve for x by dividing both sides of the equation by 14:

x = 42/14

x = 3

So the solution to the equation is x = 3.

Inverse Operations Method:

We'll use inverse operations to solve the equation step by step:

14 = 7(2x - 4)

Divide both sides of the equation by 7 to isolate the term in parentheses:

14/7 = 7(2x - 4)/7

2 = 2x - 4

Add 4 to both sides of the equation to isolate the variable term:

2 + 4 = 2x - 4 + 4

6 = 2x

Divide both sides of the equation by 2 to solve for x:

6/2 = 2x/2

3 = x

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Answer:

Step-by-step explanation:

The rule for the sequence is

[tex]A(n) = 5. {2}^{x - 1} [/tex]

where x is the number of terms

For the first term

x = 1

That's

[tex]A(1) = 5. {2}^{1 - 1} [/tex]

[tex]A(1) = 5. {2}^{0} [/tex]

A(1) = 5(1)

For the fourth term

x = 4

[tex]A(4) = 5. {2}^{4 - 1} [/tex]

[tex]A(4) = 5. {2}^{3} [/tex]

A(4) = 5(8)

For the eighth term

x = 8

[tex]A(8) = 5. {2}^{8 - 1} [/tex]

[tex]A(8 ) = 5. {2}^{7} [/tex]

A(8) = 5(128)

Hope this helps you

Answer:

The first option.

Step-by-step explanation:

The first term of the sequence would be...

A(1) = -5 * 2^(1 - 1)

= -5 * 2^0

= -5 * 1

= -5

The fourth would be...

A(4) = -5 * 2^(4 - 1)

= -5 * 2^3

= -5 * 8

= -40

The eighth would be...

A(8) = -5 * 2^(8 - 1)

= -5 * 2^7

= -5 * 128

= -640

So, the correct answer is the first option.

Hope this helps!

Answer:

[tex]\mathbf{V = [\dfrac{ 8 \pi }{3}] }[/tex]

Step-by-step explanation:

Given that:

y = 6x - x² , y = 8  about  x = 2

To find the volume of the region bounded by the curves about x = 2; we have the radius of the cylindrical shell to be x - 1, the circumference to be 2 π (x -2 ) and the height to be 6x - x² - 8

6x - x² - 8

6x - x² - 8 = 0

-x² + 6x - 8 = 0

x² - 6x + 8 = 0

(x -4) (x - 2  ) = 0

So;

x = 2 , x = 4

Thus, the region bound of the integral  are from a = 2 and b = 4

Therefore , the volume of the solid can be computed as :

[tex]V = \int \limits ^b _a \ 2x \times f(x) \ dx[/tex]

[tex]V = \int \limits ^4_2 2 \pi (x -2) (6x -x^2 -8) \ dx[/tex]

[tex]V = 2 \pi \int \limits ^4_2 (6x^2 - x^3 -8x -12 x - 2x^2 +16) \ dx[/tex]

[tex]V = 2 \pi \int \limits ^4_2 (8x^2 -x^3-20x +16) \ dx[/tex]

[tex]V = 2 \pi \int \limits ^4_2 ( -x^3+8x^2-20x +16) \ dx[/tex]

[tex]V = 2 \pi [\dfrac{ -x^7}{4}+\dfrac{8x^3}{3} -\dfrac{20x^2}{2} +16x]^4_2[/tex]

[tex]V = 2 \pi [\dfrac{ -(4^4-2^4)}{4}+\dfrac{8(4^3-2^3)}{3} -\dfrac{20(4^2-2^2)}{2} +16(4-2) ]^4_2[/tex]

[tex]V = 2 \pi [\dfrac{ -(256-16)}{4}+\dfrac{8(64-8)}{3} -10(16-4)} +16(2) ][/tex]

[tex]V = 2 \pi [\dfrac{ 4}{3}][/tex]

[tex]\mathbf{V = [\dfrac{ 8 \pi }{3}] }[/tex]

The type of model best fits the given situation is a quadratic equation

Quadratic equations are equation that has a leading degree of 2.

From the given question, the motion of the rocket from the launch point to the landing point will be parabolic in nature and since the graph of a quadratic function is a parabola, hence the type of model best fits the given situation is a quadratic equation

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Answer:

1/6 or 16.7% chance

Step-by-step explanation:

A die has 6 sides, and there is only one side with a number divisible by 5, which is the number 5.

So, the probability of rolling a number divisible by 5 is 1/6.

= 1/6 or 0.167

The odds in favor of obtaining a number divisible by 5 will be 1/6 or 0.1667.

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

The die is rolled for a single time. Then the total number of the events will be

Total event = 6 {1, 2, 3, 4, 5, 6}

The odds in favor of obtaining a number divisible by 5 will be

There is only one number that is divisible by 5 which is 5.

Then the number of favorable events will be

Favorable event = 1 {5}

Then the probability will be

P = 1 / 6

P = 0.1667

The odds in favor of obtaining a number divisible by 5 will be 1/6 or 0.1667.

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Answer:

I think it is b

Step-by-step explanation:

Answer:

see explanation

Step-by-step explanation:

f(g(2)) = f(0) = -2

g(f(1)) = g(0) = 0

Answer:

The correct answers for both of them is -2 and 0.

Step-by-step explanation:

I)

[tex](f\circ g)(2)=f(g(2))[/tex]

From the red graph, we can see that g(2) is 0.

Therefore, f(g(2)) is equal to f(0).

And from the blue graph, we can see that f(0) is -2.

Therefore:

[tex](f\circ g)(2)=-2[/tex]

II)

[tex](g\circ f)(1)=g(f(1))[/tex]

From the blue graph, we can see that f(1) is 0.

Therefore, g(f(1)) is equal to g(0).

And from the red graph, g(0) is 0.

Therefore:

[tex](g\circ f)(1)=0[/tex]

So, you got one correct. Nicely done!

Answer:

$4661.77

Step-by-step explanation:

100 + 4.7 = 104.7%

104.7% = 1.047

$2340.73 x 1.047^15 = $4661.77

Hey there! I'm happy to help!

The vertex form of a parabola is y=a(x-h)²+k. The h represents the horizontal transformation, while the k represents the vertical. The vertex of a parabola in this form is (h,k). The a represents a vertical stretch or shrink.

Our parabola is y=(x+1)²+2. This is already in vertex form, so we do not need to change the equation. There is no a (basically a=1), which means that the parabola has not been stretched or shrunk from its parent form.

We see that the h is -1. This is because in the original equation it is (x-h)², so it has to be -1 because the two negatives make a positive which is the +1. (x--1)=(x+1).

We see that the k value is 2.

Since the vertex is (h,k), this vertex is (-1,2).

However, we have to shift the parabola 7 units to the right and 5 units down. So, we add 7 to the x-value and subtract 5 from the y-value of the vertex.

(x,y)⇒(x+7,y-5)

(-1,2)⇒(6,-3)

Therefore, the vertex of the resulting parabola is (6,-3).

Have a wonderful day! :D

Answer:

998

Step-by-step explanation:

I haven't included the 1 or the 1000

Answer:

There are 200 numbers between 1 and 1000  that do not contain the digits 8, and 9.

Step-by-step explanation:

1-100

=(8,9,18,19,28,29,38,39,48,49,58,59,68,69,78,79,88,89,98,99)=20

101-200

=(108,109,118,119,128,129,138,139,148,149,158,159,168,169,178,179,188,189,198,199)=

201-300=20

.......

100*10=1000

20*10=200

[tex]\dfrac{\dfrac{1}{p-2}}{\dfrac{4p^2}{p^2+p-6}}=\\\\\\\dfrac{1}{p-2}\cdot\dfrac{p^2+p-6}{4p^2}=\\\\\dfrac{1}{p-2}\cdot\dfrac{p^2+3p-2p-6}{4p^2}=\\\\\dfrac{1}{p-2}\cdot\dfrac{p(p+3)-2(p+3)}{4p^2}=\\\\\dfrac{1}{p-2}\cdot\dfrac{(p-2)(p+3)}{4p^2}=\\\\\dfrac{p+3}{4p^2}[/tex]

--------------------------------------------------------------------

[tex]\dfrac{6n}{3n+2}-\dfrac{2}{2n-2}=\\\\\dfrac{6n(2n-2)}{(3n+2)(2n-2)}-\dfrac{2(3n+2)}{(3n+2)(2n-2)}=\\\\\dfrac{12n^2-12n-(6n+4)}{6n^2-6n+4n-4}=\\\\\dfrac{12n^2-12n-6n-4}{6n^2-2n-4}=\\\\\dfrac{12n^2-18n-4}{6n^2-2n-4}=\\\\\dfrac{2(6n^2-9n-2)}{2(3n^2-n-2)}=\\\\\dfrac{6n^2-9n-2}{3n^2-n-2}[/tex]

----------------------------------------------------------------------

[tex]\dfrac{2x}{3x^2+18x}+\dfrac{3}{2}=\\\\\dfrac{2}{3x+18}+\dfrac{3}{2}=\\\\\dfrac{2\cdot2}{2(3x+18)}+\dfrac{3(3x+18)}{2(3x+18)}=\\\\\dfrac{4+9x+54}{6x+36}=\\\\\dfrac{9x+58}{6x+36}[/tex]

Answer:

p^3−10p^2+1

——————        We find roots of zeros  F(p) = p^3 - 10p^2 + 1 and see there

      p^2                                             are no rational roots

Step-by-step explanation:

                 p^2

Simplify   ——

                 p^2

1.1    Canceling out p^2 as it appears on both sides of the fraction line

   Equation at the end of step 1

:1

 ((————-(4•1))+p)-6

   (p^2)

STEP 2: working left to right

                  1

Simplify   ——

                 p^2

Equation at the end of step 2:    

1 /p^2 ((—— -  4) +  p) -  6

STEP 3:

Rewriting the whole as an Equivalent Fraction

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  p^2  as the denominator :

          4         4 • p^2

   4 =  —  =  ——————

           1             p^2  

Equivalent fraction

: The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

             1 - (4 • p^2)                 1 - 4p^2

————————————  =  ———————

                    p^2                             p^2  

Equation at the end of step 3:

        (1 - 4p^2)          

 (————————— +  p) -  6

             p^2              

STEP 4:

Rewriting the whole as an Equivalent Fraction

4.1   Adding a whole to a fraction

Rewrite the whole as a fraction using  p2  as the denominator :

           p         p • p^2

   p =  —  =  ——————

           1             p^2  

Trying to factor as a Difference of Squares:

4.2      Factoring:  1 - 4p^2

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  1  is the square of  1

Check : 4 is the square of 2

Check :  p^2  is the square of  p^1

Factorization is :       (1 + 2p)  •  (1 - 2p)

Adding fractions that have a common denominator :

4.3       Adding up the two equivalent fractions

                (2p+1) • (1-2p) + p • p^2                                   p^3 - 4p^2 + 1

————————————————————————  =  ————————————

                               p^2                                                            p^2    

Equation at the end of step

4:

        (p^3 - 4p^2 + 1)    

 —————————————— -  6

                 p^2          

STEP 5:

Rewriting the whole as an Equivalent Fraction

5.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  p^2  as the denominator :

           6         6 • p^2

   6 =  —  =  ——————

           1             p^2  

Polynomial Roots Calculator :

5.2    Find roots (zeroes) of :       F(p) = p^3 - 4p^2 + 1

Polynomial Roots Calculator is a set of methods aimed at finding values of  p  for which   F(p)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  p  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  1.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        -4.00    

     1       1        1.00        -2.00    

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

5.3       Adding up the two equivalent fractions

(p3-4p2+1) - (6 • p2)     p3 - 10p2 + 1

—————————————————————  =  —————————————

         p2                    p2      

Polynomial Roots Calculator :

5.4    Find roots (zeroes) of :       F(p) = p3 - 10p2 + 1

    See theory in step 5.2

In this case, the Leading Coefficient is  1  and the Trailing Constant is  1.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1

Let us test ....

  P       Q    P/Q       F(P/Q)  Divisor

     -1      1        -1.00       -10.00    

       1      1    1.00       -8.00    

Polynomial Roots Calculator found no rational roots

Final result :

             p3 - 10p2 + 1

 —————————————

                 p2      

Answer: interval from -8 to 5

In interval notation, we would write [-8, 5]

The domain is the set of allowed x inputs to a function. The left-most point is (-8,0) so x = -8 is the smallest x value allowed. The largest x value allowed is x = 5 due to the point (5,0) being the right-most point.

The use of square brackets in interval notation says "include this endpoint as part of the interval".

Answer:

going from new to original would be times 2.5

from original to new would be time 0.4

Step-by-step explanation:

new to original is the 250/100

original to new is 100/250

Answer:

-60%

Step-by-step explanation:

First, find the difference

250 - 100 = 150

Then divide the decrease by the original number

150/250 = 0.6

And to convert this to a percentage all you have to do is multiply it by 100

0.6(100) = 60

The percent of change is -60% which is a decrease since it's negative

Answer:

233.5 in²

Step-by-step explanation:

First we have to find the slant height.

5²+14²=c²

25+196=c²

221=c²

c=14.866

Now we can find the lateral area.

[tex]\pi[/tex]rl

[tex]\pi[/tex](5)(14.866)

=233.51566

To the nearest tenth=

233.5 in²

Answer:

Numbers provided:

-56, 90, -84, 59, -80, 48

The smallest number is -84.

The highest number is 90.

1st: -84

2nd: -80

3rd: -56

4th: 48

5th: 59

6th: 90

Answer:

  13.4 meters

Step-by-step explanation:

About the diagram

Attached is a diagram of the problem. The directions North and East are shown so that the usual clockwise from +x measurement of angles will correspond to the bearing angles given in the problem. That is, the bearing of 120° is an angle of 120° measured from North toward East. (The mirroring across the line y=x can be a little mind-bending, but it is isomorphic, so all angles and lengths remain unchanged.)

The other feature of this diagram is the projection of the 3-D problem into two dimensions. Effectively, the center angle rabbit-O-coyote represents a plan view (in the plane of the ground), and the triangles coyote-O-C1 and rabbit-O-R1 represent side views (views in the vertical plane).

The side views let us work out the ground distances O-rabbit and O-coyote, so that we can find the ground distance rabbit-coyote as the problem requests.

__

Problem solution

The distance from the tree (O) to the rabbit is the "adjacent" leg of the 30° angle of elevation from the rabbit to the tree top. The 10 m tree height is the "opposite" leg of that rabbit-O-R1 right triangle. We know the ratio of opposite to adjacent sides gives the tangent of the angle, so we have ...

  tan(30°) = 10/(rabbit distance from tree)

Solving for the rabbit distance, we get

  rabbit distance = 10/tan(30°) ≈ 17.3205 m

Similarly, the coyote distance from the tree will be ...

  coyote distance = 10/tan(20°) ≈ 27.4748 m

__

These are two legs of the rabbit-O-coyote triangle. The angle at O between the rabbit and coyote is 120° -97° = 23°. These values are sufficient to let us use the Law of Cosines to find the distance d from rabbit to coyote:

  d² = r² +c² -2rc·cos(23°)

  d² = 17.3205² +27.4748² -2·17.3205·27.4748·cos(23°) ≈ 178.769

  d ≈ √178.769 ≈ 13.37 . . . . meters

The distance from the rabbit to the coyote is about 13.4 meters.

_____

Additional comment

Note that the angle of depression to the rabbit from the horizontal is the same as the angle of elevation from the rabbit. This lets us draw the diagram without a bunch of extra lines.

Answer:

a is the answer 28.50 + b = 45.50

Step-by-step explanation:

so if i move 28.50 to the right side then it becomes b=45.50-28.50 and that equals to 17 . hope i helped have a great day

=================================================

Explanation:

28.50 = cost of shirt

b = cost of belt, some unknown value

45.50 = total cost (given)

28.50+b = total cost (add the first two items shown above)

equate the two total cost expressions to end up with 28.50+b = 45.50

Answer:

10

Step-by-step explanation

Answer:

10

Step-by-step explanation:

Answer:

Even function.

Step-by-step explanation:

An odd function has symmetry with respect to the origin.

[tex]\text{A function is odd }\Leftrightarrow f(-x)=-f(x)[/tex]

The sine function is an odd function:

[tex]\sin(-\theta)=\sin(\theta)[/tex]

An even function has symmetry with respect to the y-axis.

[tex]\text{A function is even}\Leftrightarrow f(-x)=f(x)[/tex]

The cosine function is an even function:

[tex]\cos(-\theta)=\cos(\theta)[/tex]

Is the function [tex]f(\theta)=2\cos(\theta)[/tex] an odd or even function?

It is an even function.

What happens in the function is a vertical stretch by a factor of 2. The y-intercept is equal to 2.  

Answer:

using the equilateral formula of solution

Answer:

[tex]x^2-3\geq 12[/tex]

Step-by-step explanation:

[tex]x^{2} -3[/tex] is the difference of a number squared and three

is at least 12, means that is greater but not less

[tex]x^2-3\geq 12[/tex]

Answer:

x = 148

Step-by-step explanation:

CPD is a straight line so it equals 180

CPB + BCD = CPD

x + 32 = 180

Subtract 32 from each side

x+32-32 = 180-32

x =148

Answer:

Bottom right option

Step-by-step explanation:

To find this, we can calculate:

1/2 * 4.32 * 10⁻⁴

= (1/2 * 4.32) * 10⁻⁴

= 2.16 * 10⁻⁴

The diameter of a new cell is 2.16×10−⁴millimeters

First step is to calculate 4.32×10−⁴ to the original numbers

4.32×10−⁴ =0.000432

Second step is to determine the diameter of a new cell

New cell diameter=0.000432×1/2

New cell diameter=0.000216

New cell diameter=2.16×10−⁴millimeters

Inconclusion The diameter of a new cell is 2.16×10−⁴millimeters

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Answer:

[tex]\mathrm{Domain\:of\:}\:0.5^x-9\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:<x<\infty \\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}\\\\\mathrm{Range\:of\:}0.5^x-9:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)>-9\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-9,\:\infty \:\right)\end{bmatrix}\\\\\mathrm{Asymptotes\:of}\:0.5^x-9:\quad \mathrm{Horizontal}:\:y=-9[/tex]

Step-by-step explanation:

Domain:

The function has no undefined points nor domain constraints. Therefore, the domain is

[tex]...-\infty \:<x<\infty \:[/tex]

Definition: The domain of a function is the set of input or argument values for which the function is real and defined.

_________________________________________________

Range:

[tex]\mathrm{The\:range\:of\:an\:exponential\:function\:of\:the\:form}\:c\cdot \:n^{ax+b}+k\:\mathrm{is}\:\:f\left(x\right)>k\\k=-9[/tex]

[tex]f\left(x\right)>-9[/tex]

Definition: The set of values of the dependent variable for which a function is defined.

_________________________________________________

Asymptotes:

[tex]\mathrm{Vertical\:asymptotes\:of\:}0.5^x-9:\quad \mathrm{None}\\\mathrm{Horizontal\:Asymptotes\:of\:}0.5^x-9:\quad y=-9\\\mathrm{Horizontal}:\:y=-9x^{2}[/tex]

Hence, the m∠DCA is 59.2

An angle is a combination of two rays (half-lines) with a common endpoint. The latter is known as the vertex of the angle and the rays as the sides, sometimes as the legs, and sometimes the arms of the angle.

m∠DCB = (4x) + (6x-58) = 90

10x = 148

x = 14.8

m∠DCA = 4x

             = 4(14.8)

             = 59.2

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Answer:

Option A is the correct option.

Step-by-step explanation:

Surface area of the rectangle base = 9 × 5 = 45 in²

Surface area of lateral square = ( 5 )² = 25 in²

Surface area of lateral rectangle = 6.4 × 5 = 32 in²

Surface area of top square = ( 5 )² = 25 in²

Surface area of two parallel trapezoids:

[tex] (\frac{1}{2} (9 + 5) \times 5) \times 2[/tex]

= 7 × 5 × 2

= 70 in²

Total surface area:

= 45 + 25 + 32 + 25 + 70

= 197 in²

Hope I helped!

Best regards!