Answer:
the last one, y=x-6
Step-by-step explanation:
it is the only answer with an x-intercept of 6. you did not provide the line, but I'm assuming it is y=-x.
The distribution of the number of apples trees a farmer can plant each day is bell-shaped and has a mean of 62 and a standard deviation of 8. Use the empirical rule to help you answer the following. What is the approximate percentage of trees planted between 38 and 68
Answer:
The empirical rule, the approximate percentage of trees planted between 38 and 68 is 99.7%.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean of 62, standard deviation of 8.
What is the approximate percentage of trees planted between 38 and 86?
38 = 62 - 3*8
86 = 62 + 3*8
So within 3 standard deviations of the mean, which, by the empirical rule, the approximate percentage of trees planted between 38 and 68 is 99.7%.
The first five terms of an arithmetic sequence are shown below:
20, 17, 14, 11, 8, . . .
Let n represent the term number and f(n) the term in the sequence.
Choose a function that represents the sequence.
The answer to this question is f(n) = -3 + 23
Now my question is, how do you find the solution? I was taught the explicit formula is f(n) = m(n) + b, but no matter how many times I've tried to plug in the numbers I cannot seem to get the right answer. Please help me and do show the entire process and the steps.
Answer:
The function represents the sequence is - 3 n + 23.
Step-by-step explanation:
20. 17, 14, 11, 8,......
Here, the first term is
a = 20
Common difference, d = -3
Let the nth term is Tn.
Tn = a + (n -1) d
Tn = 20 + (n -1) x (-3)
Tn = 20 - 3 n + 3
Tn = 23 - 3 n = - 3 n + 23
So, the function represents the sequence is - 3 n + 23.
Answer:
Y'all know what it is already, but I want points, so: f(n) = -3n + 23
Find the greatest common factor of 15 x²y³ and -18 x³yz .
Answer:
3 x² y¹
Step-by-step explanation:
15 x²y³ = 3. 5. x². y³
-18x³yz = -2. 3². x³. y¹. z¹
so, the GCF = 3. x². y¹
Answer:
Solution given:
15x²y³=3*5*x*x*y*y*y
-18x³yz=-3*2*3*x*x*x*y*z
over here common is
3*x*x*y
so
greatest common factor is 3x²y¹
.Solve : 3 / 8 (x-5) = 11 -7x
Answer:
1.74 or [tex]\frac{103}{59}[/tex]
Step-by-step explanation:
3(x-5) = 8 (11-7x)
3x-15=88-56x
59x=103
x = 1.74
Use the values in 9 = 2.2 and In 200 – 5.3 to find the approximate value of log, 200.
Answer:
2.409
Step-by-step explanation:
㏑ 9 = 2.2
ln 200 = 5.3
[tex]ln 9 = log_{e}9\\ln 200 = log_{e}200[/tex]
[tex]log_{9}200 = \frac{log_{e}200}{log_{e}9}[/tex]
= [tex]\frac{ln 200}{ln 9}[/tex]= [tex]\frac{5.3}{2.2}[/tex]
= 2.409
The approximate value of log 200 would be; 2.409
What is a logarithm?When we raise a number with an exponent, there comes a result.
Let's say you get a^b = c Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows [tex]b = \log_a(c)[/tex]'a' is called the base of this log function. We say that 'b' is the logarithm of 'c' to base 'a'
We have given the values in 9 = 2.2 and 200 – 5.3
We need to find the approximate value of log, 200.
Therefore,
㏑ 9 = 2.2
ln 200 = 5.3
[tex]ln 9 = log_{e}9\\\\ln 200 = log_{e}200[/tex]
Using the logarithm property;
[tex]log_{9}200 = \dfrac{log_{e}200}{log_{e}9}\\ = \dfrac{ln 200}{ln 9}\\ = \dfrac{5.3}{2.2}[/tex]
= 2.409
Hence, the approximate value of log, 200 would be; 2.409
Learn more about logarithm here:
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Long division: 2/ 2769
Answer:
1384.5
Step-by-step explanation
Diviseion is just the oppisite of multiplication so you can think to yourself that what times two equals 2769. If you multiply 1384.5 on a calculater you get 2769.
may y’all help me please and thank you?
Answer:
F
Step-by-step explanation:
4.85-4.15=0.7 divided by 2 = 0.35+4.15=4.5*25 cause 30-20=10 divided by 2=5+20=25*4.5=112. closest to that is 120
Solve the equation −96=3(8x)^(5/3).
Answer:
x= - 1
Step-by-step explanation:
Choose the best graph that represents the linear equation:
y + 3 = 0
Graph A
On a coordinate plane, a line goes through (0, 3) and (1, 3).
Graph B
On a coordinate plane, a line goes through (negative 3, 0) and (negative 3, 1).
Graph C
On a coordinate plane, a line goes through (0, negative 3) and (1, negative 3).
Graph D
On a coordinate plane, a line goes through (0, 0) and (1, negative 3).
a.
Graph A
c.
Graph C
b.
Graph B
d.
Graph D
PLEASE HELP!!! Please select the best answer from the choices provided
A
B
C
D
Graph B is the best graph that represents the linear equation
Answer:
m=2b=1y=2x+1
just enter it
The highway department is testing two types of reflecting paint for concrete bridge end pillars. The two kinds of paint are alike in every respect except that one other is yellow. The orange paint is applied to 12 bridges, and the yellow paint is applied to 12 bridges. After a period of 1 year, reflectometer readings were made end pillars. (A higher reading means better visibility.) For the orange paint, the mean reflectometer reading was x19.4, with standard deviation s1-2.5. For the mean was X2-6.5, with standard deviation S2-2.4. Based on these data, can we conclude that the yellow paint has less visibility after 1 year?
Use a 10% level What are we testing in this problem?
a. difference of means
b. single proportion
c. difference of proportions
d. single mean
e. paired difference
Answer:
a. difference of means
Step-by-step explanation:
Given that :
Mean , x = 9.4
Standard deviation, [tex]s.d_1[/tex] = 2.5
Number, [tex]n_1[/tex] = 12
Mean, y = 6.5
standard deviation, [tex]s.d_2[/tex] = 2.4
Number, [tex]n_2[/tex] = 12
The null hypothesis is : [tex]$H_0: \mu_1=\mu_2$[/tex]
The alternate hypothesis is : [tex]$H_1: \mu_1>\mu_2$[/tex]
Level of significance, [tex]\alpha[/tex] = 0.1
From the [tex]\text{standard normal table, right tailed,}[/tex] [tex]$t_{1/2}$[/tex] = 1.363
Since out test is right tailed.
Reject [tex]H_0[/tex], if [tex]$T_0>1.363$[/tex]
We use the test statics,
[tex]$t_0=\frac{(x-y)}{\sqrt{\frac{s.d_1}{n_1}+\frac{s.d_2}{n_2}}}$[/tex]
[tex]$t_0=\frac{(9.4-6.5)}{\sqrt{\frac{6.25}{12}+\frac{5.76}{12}}}$[/tex]
[tex]$t_0=2.899$[/tex]
[tex]$|t_0|=2.899$[/tex]
[tex]\text{Critical value}[/tex]
The value of [tex]$|t_{1/2}|$[/tex] with minimum [tex]$\left(n_1-1,n_2-1)$[/tex] that is 11 df is 1.363
We go [tex]$|t_0|=2.899$[/tex] and [tex]$|t_{1/2}|$[/tex] = 1.363
Decision making:
Since the value of [tex]|t_0|>|t_{1/2}|$[/tex] and we reject the [tex]H_0[/tex]
The p-value : right tail [tex]H_a:(p>2.8988)[/tex]
= 0.00724
Therefore the value of [tex]$p_{0.1} > 0.00724$[/tex], and so we reject the [tex]H_0[/tex]
Thus we are testing 'the difference of means" in this problem.
John's age 4 years ago, if he will be y years old in 5 years
9514 1404 393
Answer:
y -9
Step-by-step explanation:
From 4 years ago until 5 years from now, John will age 9 years. That is, his age 4 years ago is 9 years less than it will be in 5 years.
John's age 4 years ago is y-9 years.
Tell whether the following two triangles can be proven congruent through SAS.
A.Yes, the two triangles are congruent because they’re both right triangles.
B.Yes, the two triangles are congruent because two sides and their included angle are congruent in both triangles.
C.No, the two triangles can only be proven congruent through SSS.
D.No, the two triangles can only be proven congruent through AAA.
Answer:
C.No, the two triangles can only be proven congruent through SSS.
True or face dilations preserve angle measure
Answer:
True
Step-by-step explanation:
Required
Does dilation preserve angle measure?
When a point, side, line, or angle is dilated; the length of the line will be altered by the ratio or scale of dilation.
However, the measure of angle will remain the same.
Hence, the given statement is true.
Approximately 5% of workers in the US use public transportation to get to work. You randomly select 25 workers and ask if they use public transportation to get to work. Find the probability that exactly 2 workers say yes.
Answer:
0.2305 = 23.05% probability that exactly 2 workers say yes.
Step-by-step explanation:
For each worker, there are only two possible outcomes. Either they say yes, or they say no. The probability of a worker saying yes is independent of any other worker, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
5% of workers in the US use public transportation to get to work.
This means that [tex]p = 0.05[/tex]
You randomly select 25 workers
This means that [tex]n = 25[/tex]
Find the probability that exactly 2 workers say yes.
This is P(X = 2). So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 2) = C_{25,2}.(0.05)^{2}.(0.95)^{23} = 0.2305[/tex]
0.2305 = 23.05% probability that exactly 2 workers say yes.
Math algebra two plz show your work
Answer:
The answer is [tex]b=3, a=-2[/tex], and [tex]c=3[/tex].
Step-by-step explanation:
To solve this system of equations, start by solving for (a) in the third equation.
To solve for (a) in the third equation, add [tex]3b[/tex] to both sides of the equation, which will look like [tex]2a=-13+3b\\-a+b-c=2\\2a+3b-4c=-7[/tex]. Next, divide each term in [tex]2a=-13+3b[/tex] by 2 and simplify, which will look like [tex]\frac{2a}{2}=\frac{-13}{2} +\frac{3b}{2} \\-a+b-c=2\\2a+3b-4c=-7[/tex] = [tex]a=\frac{-13}{2} +\frac{3b}{2} \\-a+b-c=2\\2a+3b-4c=-7[/tex].
Then, replace all variables of (a) with [tex]-\frac{13}{2} +\frac{3b}{2}[/tex] in each equation and simplify, which will look like [tex]-13+6b-4c=-7\\-\frac{2c-13+b}{2}=2\\a=-\frac{13}{2}+\frac{3b}{2}[/tex].
The next step is to reorder [tex]-\frac{13}{2}[/tex] and [tex]\frac{3b}{2}[/tex], which will look like [tex]\frac{3b}{2}-\frac{13}{2}\\-13+6b-4c=-7\\-\frac{2c-13+b}{2} =2[/tex].
Then, solve for (b) in the second equation. To solve for (b) in the second equation start by moving all terms not containing (b) to the right side of the equation, which will look like [tex]6b=6+4c\\a=\frac{3b}{2}-\frac{13}{2} \\-\frac{2c-13+b}{2} =2[/tex]. Next, divide each term in ([tex]6b=6+4c[/tex]) and simplify, which will look like [tex]b=1+\frac{2c}{3} \\a=\frac{3b}{2} -\frac{13}{2\\}\\-\frac{2c-13+b}{2} =2[/tex].
Then, replace all variables of (b) with [tex]1+\frac{2c}{3}[/tex] in each equation and simplify, which will look like [tex]-\frac{2(2c-9)}{3}=2\\a=c-5\\b=1+\frac{2c}{3}[/tex].
The next step is to solve for (c) in the first equation. To solve for (c) in the first equation start by multiplying both sides of the equation by [tex]-\frac{3}{2}[/tex] and simplify, which will look like [tex]2c-9=-3\\a=c-5\\b=1+\frac{2c}{3}[/tex]. Then, move all terms not containing (c) to the right side of the equation, which will look like [tex]2c=6\\a=c-5\\b=1+\frac{2c}{3}[/tex]. Next, divide each term in [tex]2c=6[/tex] by 2 and simplify, which will look like [tex]c=3\\a=c-5\\b=1+\frac{2c}{3}[/tex].
Then, replace all variables of (c) with 3 in each equation and simplify, which will look like [tex]b=3\\a=-2\\c=3[/tex]. Finally, the list of all the solutions are [tex]b=3,a=-2[/tex], and [tex]c=3[/tex].
g A. (Points: 7) Compute (without using a calculator) 241^257 mod 12 B. (Points: 3) Compute Z*20 C. (Points: 6) Find the multiplicative inverse of 7 in Z19
Answer:
[tex]241^{257}\ mod\ 12 =1[/tex]
[tex]7 * 20 = 140[/tex]
[tex]\frac{1}{700}[/tex]
Step-by-step explanation:
Solving (a): 241^257 mod 12
To do this, we simply calculate [tex]241\ mod\ 12[/tex]
Because [tex]a\ mod\ b = a^n\ mod\ b[/tex]
The highest number less than or equal to 241 that is divisible by 12 is 240; So:
[tex]241\ mod\ 12 = 241- 240[/tex]
[tex]241\ mod\ 12 =1[/tex]
Hence:
[tex]241^{257}\ mod\ 12 =1[/tex]
Solving (b): 7 * 20
[tex]7 * 20 = 140[/tex]
Solving (c): Multiplicative inverse of 7 in 719
The position of 7 in 719 is 700
So, the required inverse is 1/700 ---- i.e. we simply divide 1 by the number
Which of the following is an even function?
g(x) = (x – 1)2 + 1
g(x) = 2x2 + 1
g(x) = 4x + 2
g(x) = 2x
Answer:
B. g(x) = 2x² + 1Step-by-step explanation:
Even function has following property:
g(x) = g(-x)It is easy to show this works with the second choice only. All the others don't work:
g(x) = (x - 1)² + 1g(-x) = (-x - 1)² + 1This is not correct as x - 1 ≠ -x - 1 so as their squares, so g(x) ≠ g(-x)
The last two choices are not even similarly.
Answer:
B. g(x) = 2x2 + 1
Correct on edge
The radius of a circle is 5 yd.
Answer the parts below. Make sure that you use the correct units in your answers.
If necessary, refer to the list of geometry formulas.
Answer:
Circumference =10 pi yard
Area =25 pi yard squared
Step-by-step explanation:
C=2*pi*r
Circumfrance =10 pi
A=pi r^2
Area =25 pi
For the estimate just sub in pi on the calculator for pi, then round to the hundreth.
Circumfrence= just the unit
Area= squared
Tara makes 30 cups of donut topping by mixing sugar and cinnamon. The ratio of sugar to cinnamon is 3:2
How much sugar did Tara use in the donut topping?
Answer:
18
Step-by-step explanation:
3:2 means 3/2 or 3÷2
but its better to leave it as
3/2
16. Risa wants to order business cards. A print-
ing company determines the cost (C) to
the customer using the following function,
where b the number of boxes of cards and
n= the number of ink colors.
C= $25.60b + $14.00b(n - 1)
If Risa orders 4 boxes of cards printed in 3
colors, how much will the cards cost?
OA. $214.40
OB. $168.00
C. $144.40
OD. $102.40
Answer:
A - $214.40
Step-by-step explanation:
Since b is the number of boxes of cards and n is the number of ink colors, and we're given the number of boxes of cards, and number of ink colors, we plug in:
4= b
and
3 = n
into the given equation to solve for C.
Using the order of operations we start inside our parentheses and work from there:
C= $25.60*4 + $14.00*4(3 - 1)
C= $25.60*4 + $14.00*4(2)
C= $102.40 + $112
C= $214.40
plz help with the task my child is trying to do
Answer:
7
Step-by-step explanation:
First, add all the cards.
[tex]2 + 5 + 7 + 8 + 9 = 31[/tex]
If we remove one card, the remaining four cards average will be 6, this means that the 4 remaning cards will average total will be at 24 because 6×4=24. So we need to find a value that will equal 24 if we remove that card.
The answer is 7 because
[tex] \frac{2 + 5 + 8 + 9}{4} = 6[/tex]
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Answer:
remove 7 to make the total be 6×4 = 24.
Step-by-step explanation:
The description "mean average" is redundant to no apparent purpose. "Mean" and "average" are the same thing: the total divided by the number of contributors.
If the mean of 4 cards is 6, then we require ...
6 = (total of 4 cards) ÷ 4
24 = total of 4 cards . . . . . . . multiply both sides of the equation by 4
__
We note that the total of all the cards shown is ...
2 + 5 + 7 + 8 + 9 = 31
In order to make the total be 24, we need to remove a card that has a value of ...
31 -24 = 7
Removing 7 will bring the total to 2 + 5 + 8 + 9 = 24, and the average to 24/4 = 6.
_____
Additional comment
It is worthwhile to remember the relationship between the total and the average and the number of contributors. This shows up a lot in problems involving adjusting an average or finding a value to give a certain average.
Formular for quadratic equation almighty formular
[tex]x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac } }{2a} [/tex]
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters, and a variance of 49 . If a random sample of 46 steel bolts is selected, what is the probability that the sample mean would differ from the population mean by more than 2 millimeters? Round your answer to four decimal places.
Answer:
0.0524 = 5.24% probability that the sample mean would differ from the population mean by more than 2 millimeters.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean diameter of 144 millimeters, and a variance of 49.
This means that [tex]\mu = 144, \sigma = \sqrt{49} = 7[/tex]
Sample of 46:
This means that [tex]n = 46, s = \frac{7}{\sqrt{46}}[/tex]
Wat is the probability that the sample mean would differ from the population mean by more than 2 millimeters?
Above 144 + 2 = 146 or below 144 - 2 = 142. Since the normal distribution is symmetric, these probabilities are equal, which means that we find one of them and multiply by two.
Probability the sample mean is below 142:
p-value of Z when X = 142, so:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{142 - 144}{\frac{7}{\sqrt{46}}}[/tex]
[tex]Z = -1.94[/tex]
[tex]Z = -1.94[/tex] has a p-value of 0.0262
2*0.0262 = 0.0524
0.0524 = 5.24% probability that the sample mean would differ from the population mean by more than 2 millimeters.
HW HELP ASAP PLZZZZZ
Answer:
p = 15/x
x= -3
Step-by-step explanation:
For the first problem, we can expand the equation to 4px+4=64
then simplify it to:
4px=60
then divide 4x from both sides of the equation
p=60/4x
then simplify:
p=15/x
For the second problem:
plug in -5 for p so the equation would look like
4(-5x +1)=64
simplify
-20x=60
x= -3
Hattie had $3,000 to invest and wants to earn 10.6% interest per year. She will put some of the money into an account that earns 12% per year and the rest into an account that earns 10% per year. How much money should she put into each account?
Answer:
900 at 12%
2100 at 10%
Step-by-step explanation:
Let x= amount invested at 12%
let y= amount invested at 10%
with that being said we can write the two equation
Equation 1: x+y=3000
Equation 2: 3000*.106=.12x+.1y
isolte x from equation 1
x= 3000-y
plug this into equation 2
318=.12(3000-y)+.1y
318=360-.12y+.1y
-42= -.02y
y= 2100
Plug this into equation 1
x+2100=3000
x=900
she should invest $900 into the account earning 12% interest and $2100 into the account earning 10% interest.
How to determine How much money should she put into each accountLet's denote the amount of money Hattie invests at 12% as \(x\) dollars, and the amount she invests at 10% as \(\$3000 - x\) dollars.
The formula for calculating interest is: \(\text{Interest} = \text{Principal} \times \text{Rate} \times \text{Time}\).
For the 12% account:
Interest_12% = \(x \times 0.12 \times 1\) (1 year)
For the 10% account:
Interest_10% = \((3000 - x) \times 0.10 \times 1\) (1 year)
Hattie wants to earn 10.6% interest on the total investment, so we can set up the equation:
\(\text{Total Interest} = \text{Interest}_12% + \text{Interest}_10%\)
\(3000 \times 0.106 = x \times 0.12 + (3000 - x) \times 0.10\)
Now, solve for \(x\):
\(318 = 0.12x + 300 - 0.10x\)
\(318 = 0.02x + 300\)
\(18 = 0.02x\)
\(x = 900\)
Hattie should invest $900 at 12% and \(3000 - 900 = 2100\) at 10%.
Therefore, she should invest $900 into the account earning 12% interest and $2100 into the account earning 10% interest.
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A line includes the points (0,2) and (1,6).
What is the equation of the line in slope-intercept form?
A student estimated based on the video that the ball left my hand 1.65 meters off the ground, and after 0.58 seconds the ball reached the maximum height of 3.26 meters. Use this information to find an equation of the form h = a ( t − t 1 ) 2 + h 1 for the height of the ball, in meters, after t seconds. h =
9514 1404 393
Answer:
h = -4.79(t -0.58)^2 +3.26
Step-by-step explanation:
The coordinates (t1, h1) are the time and height at the maximum. Then 'a' can be found from ...
h = a(t -t1)^2 +h1
1.65 = a(0 -0.58)^2 +3.26
-1.61 = 0.3364a . . . . . subtract 3.26
-4.786 = a . . . . . . . divide by the coefficient of a
The equation is ...
h = -4.79(t -0.58)^2 +3.26
The list of ingredients for chocolate brownies given at right will make 16 brownies. Use the list to decide how much of each ingredient is needed to make 6 brownies.
Given: Given that for 16 brownies we need
Butter- [tex]\frac{2}{3}[/tex] cups
unsweetened chocolate-5 ounces
sugar-1-1/2 cup
vanilla-2 teaspoons
eggs-2
flour- 1 cup
To find: The amount of ingredients to make 6 brownies.
Solution: The amount we need to make 6 brownies is,
Butter
[tex](\frac{2}{3}.16)/6\\=0.25125 cups[/tex]
unsweetened chocolate
[tex]\frac{5.6}{16}\\=\frac{30}{16}[/tex]ounces
sugar-0.5625 cup
vanilla-[tex]\frac{12}{16}[/tex]teaspoons
eggs-[tex]\frac{12}{16}[/tex]
flour- [tex]\frac{6}{16}[/tex] cup
I need help with this math
Answer:
[tex]PQ=6\frac{1}{2} =\frac{13}{2}[/tex]
[tex]|Q-P|=\frac{13}{2}[/tex]
[tex]|Q+4|=\frac{13}{2}[/tex]
[tex]Q+4=+-\frac{13}{2}[/tex]
[tex]Q=-4[/tex] ± [tex]\frac{13}{2}[/tex]
[tex]Q=\frac{21}{2} \times2\frac{1}{2}[/tex]
[tex]Answer: C)~2\frac{1}{2}[/tex]
------------------------
Each shirt = $12.25
so, x = shirts = 12.25 x
cost including shipping= 77.49
So,
12.25 x + 3.99=77.49
Answer: D)
-------------------------
hope it helps...
have a great day!!
Write each of the following numbers to 3 significant figures in exponential or scientific notation. Write each number with only one non-zero digit before the decimal point.
(i) 5590
(ii) 0.000498
(iii) 135000
(iv) 0.000438
Solution :
The significant figure of a number are defined as the positional notation of that number which are most reliable and are absolutely necessary to represent the quantity of something.
In the context, we have to express the given numbers into three significant figures in the form of scientific notation or in the exponential form :
(i). 5590 ----- [tex]$5.59 \times 10^3$[/tex]
(ii). 0.000498 ----- [tex]$4.98 \times 10^{-4}$[/tex]
(iii) 135000 ----- [tex]$1.35 \times 10^5$[/tex]
(iv) 0.000438 ----- [tex]$4.38 \times 10^{-4}$[/tex]