Answer: -21x+35+11y
Step-by-step explanation:
7(-3x+5) +11y
7x-3 7x5
-21x+35+11y
you can't add, subtract, or anything with this, so this will be your final answer.
Use the drop-down menus to correctly relate each pair of numbers
manee help meh son
Answer:
Sorry for the late response, I had to have lunch.
1. >
2. =
3. <
4. >
Step-by-step explanation:
Have a great summer :)
In a right triangle, sin(40 - 2) = cos(32)'. What is the value of x?
O 10
O 15
O 20
O 25
Answer:
x = 25
Step-by-step explanation:
Correct question
In a right triangle Sin (40-x)=cos(3x) what is the value of x
Since Sin theta = Cos(90-theta)
Sin (40-x) = Sin(90-3x)
40 - x = 90 - 3x
-x+3x = 90 - 40
2x = 50
x = 25
Hence the value of x is 25
What is the length of arc AC?
Answer:
D - 10.9m
Step-by-step explanation:
I need help
Solve the expression when X =5;3(X+2)=
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {21}}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
[tex]3 \: ( \: x + 2 \: )[/tex]
Plugging in the value [tex]x = 5[/tex] in the above expression, we have
[tex] = 3\:( \: 5 + 2 \: )[/tex]
[tex] = 3 \: ( \: 7 \: )[/tex]
[tex] = 3 \times 7[/tex]
[tex] = 21[/tex]
Note:-[tex]\sf\pink{PEMDAS\: rule.}[/tex]
P = Parentheses
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction
[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35☂}}}}}[/tex]
The button on David's coat has a radius of 4
millimeters. What is the button's diameter?
Answer:
0.013
I think.
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
So there are two things that must be remembered.
The radius is half of the diamater. It is the distance from the side of a circle to its center.
The diamater is two times the radius. It is the distance from one side of the circle to the opposite side of the circle.
In this case, we know the radius is 4.
The radius is half of the diamamter, or the diamater is two times the radius.
This can be though of as:
2r=d
Or
1/2d=r
So lets plug 4 in for r:
2*4=d = 8=d
1/2d=4 = 2*1/2=4*2 = 1d=8
So using either of these formulas, we find d is equal to 8.
Hope this helps!
Point of intersection Question:
Mike has $9.85 in dimes and quarters. If there are 58 coins altogether,
how many dimes and how many quarters does Mike have? Use the point of intersection to find the answer. Explain how you used a formula to calculate the # of quarters and dimes
Answers:
He has 27 quarters and 31 dimes
=========================================================
Work Shown:
d = number of dimes
q = number of quarters
d+q = 58 since there are 58 coins of only these two types
d = 58-q
10d+25q = 985 .... note that 985 cents is $9.85
10(58-q)+25q = 985 .... replace d with 58-q
580-10q+25q = 985
15q+580 = 985
15q = 985-580
15q = 405
q = 405/15
q = 27 ..... Mike has 27 quarters
d = 58-q
d = 58-27
d = 31 .... Mike also has 31 dimes
-----------
As a way to check:
d+q = 31+27 = 58 so that works out
and
10d+25q = 10*31+25*27 = 310+675 = 985
so that works out as well. The answer is confirmed.
John invested $30000 in the bank for 4 years. At the end of the period, he had
$42520. Calculate
a. the interest earned
b. the rate per annum at which simple interest was earned to 1 decimal place.
Answer:
Rate = 10.4%
Step-by-step explanation:
Given :
P = $30000
A = $42520
Interest earned = 42520 - 30000 = $12520
Time = 4years
Find R
[tex]Interest = \frac{PRT}{100}[/tex]
[tex]12520 = \frac{30000 \times R \times 4}{100}\\\\12520 = 300 \times 4 \times R\\\\12520 = 1200 \times R\\\\R = \frac{12520}{1200}\\\\R = 10.43 \%[/tex]
Round to 1 decimal place, Rate = 10.4%
whats the answer to this
Answer:
its the 2nd one
hope that helps<3
Answer:
jhkkkhj
Step-by-step explanation:
jkjkjkjkj
NEED HELP ASAP Let the function f(x) have the form f(x) = Acos(x+C). To produce a graph that matches the one shown below, what must the value of C be?
Answer:
[tex]C = 2[/tex] (A)
Step-by-step explanation:
We assume the constant A is different than 0
We notice that the graph of the function intercepts the x-axis when x = -0.5
we know that cos(x) = 0 when x = π/2 or x = -π/2
thus, [tex]-0.5 + C = \pi /2[/tex] or [tex]-0.5 + C = -\pi /2[/tex]
then [tex]C = \pi /2 + 0.5 = 2[/tex] or [tex]C = -\pi /2 = 0.5 = -1[/tex]
so [tex]C = 2[/tex]
please help guys! i don’t wanna fail
Answer:
25: 6,000
26: 450
27: 70,000,000
28: 10,500
29: 3,052
30: (cant really see the exponent but I think its 10^5) 500,000
31: 9.87
32: 5.43
decompose 17x^3+7x^2-17x-7 divided by (x-1)^2(x+1)^2 into partial fraction
..........................................................................................................................................................................................................................................................................................................................................................................................................................................................
Need help with probabilities (math) plz
Answer:
What is your question for probabilities?
answer all the questions, just the answers, it's pythagorean theorem, plssss helpppp
Answer:
1. option c
2. option b
3. option b
Step-by-step explanation:
1 . option C
Square of longer side = sum of squares of other side
a)
5, 6 , 11
[tex]121 = 25 + 36\\does\ not \ satisfy[/tex]
b)
9, 12, 16
[tex]256 = 144 + 81\\Does\ not \ satisfy[/tex]
c)
7, 24, 25
[tex]625 = 576 + 49\\Does\ satisfy[/tex]
d)
12, 20, 25
[tex]625 = 400 + 144\\does \ not \ satisfy[/tex]
2. Option B
Square of longer side = sum of squares of other side
15 ² = 8 ² + r²
225 = 64 + r²
161 = r²
r = 12.688
r = 13ft
3 . Option b
To find length of AB, Use distance formula
[tex]AB = \sqrt{(x_2- x_1)^2 + (y_2 - y_1)^2}[/tex]
[tex]= \sqrt{(14-3)^2 + (6-1)^2}\\\\=\sqrt{11^2 + 5^2}\\\\=\sqrt{121 + 25}\\\\= \sqrt{146} \\= 12 \ ft[/tex]
hello i need help with these questions attached.
Answer:
Beep
Step-by-step explanation:
how to solve -4x+8y=-16
4x+3y=5
Answer:
X=2, y=-1
Step-by-step explanation:
-4x +8y=-16 equation 1
4x +3y=5 equation 2
11y=-11 add two equations to eliminate x
y=-1
solve for x by inputting y value into either equation
4x+3y=5
4x+3(-1)=5
4x-3=5
4x=8
x=2
Find the sum.
b/ b^2+4b+4 + 9/b^2+7b+10
Answer:
11b^3+14b^2+b+9
---------------------------
b2
Step-by-step explanation:
Find the IQR: (find the median, then find the median of the first group and then the next group. Now subtract big median minus the small median.) 20, 17, 16, 3, 7, 45
Answer:
13
Step-by-step explanation:
The IQR = Interquartile Range is the difference between the first and third quartile
Rearranged data set:
3, 7, 16, 17, 20, 45
Step 1
We find the first quartile = Q1
= 1/4(n + 1)th number
n = 6
= 1/4(6 + 1)th
= 1/4(7)th
= 1 3/4th number
This = 7
Step 2
We find the third quartile = Q3
= 3/4(n + 1)th number
n = 6
= 3/4(6 + 1)th
= 3/4(7)th
= 21/4th number
= 5 1/4 th number
This = 20
Step 3
IQR = Q3 - Q1
= 20 - 7
= 13
PLEASE HELP HURYYYYUUUUUHYYYYYYY
A
B
С
D
If mZACD = 70°, then mZBCD = [? ]°
Answer:
35 is correct
Step-by-step explanation:
hope this helps.
Answer:
35°
Step-by-step explanation:
Angle ACD is 70°. The little tick marks on the angle mean both sides of the split are the same amount. This means if you divide the angle in half, you will find out what both of them are equal to.
Can someone please help me out with this question
Answer:
C.
Step-by-step explanation:
A square is inscribed in an equilateral triangle that is inscribed in a circle.
A square is inscribed in an equilateral triangle that is inscribed in a circle. The square and circle are shaded.
Which represents the area of the shaded region?
area of the circle – area of the square – area of the triangle
area of the triangle – area of the square + area of the circle
area of the triangle + area of the square + area of the circle
area of the circle – area of the triangle + area of the square
The area of the shaded region is (area of the circle) - (area of the square) - (area of the triangle)
Option A is the correct answer
What is a triangle?A triangle is a 2-D figure with three sides and three angles.
The sum of the angles is 180 degrees.
We can have an obtuse triangle, an acute triangle, or a right triangle.
We have,
The shaded region consists of the area inside the circle but outside the square, as well as the area inside the equilateral triangle but outside the square.
Now,
The area of the circle is πr²
Since the square is inscribed in the circle, the diameter of the circle is equal to the diagonal of the square.
Let's say the side length of the square is s.
By the Pythagorean theorem,
s² + s² = (diameter)²
2s² = (2r)²
s² = r²
The area of the square is s² = r².
The area of an equilateral triangle with side length s is √(3)/4 x s².
Since the side length of the square is equal to the height of the equilateral triangle, the side length of the equilateral triangle is also equal to s.
The area of the shaded region.
= (area of the circle) - (area of the square) - (area of the triangle)
Thus,
The area of the shaded region is (area of the circle) - (area of the square) - (area of the triangle)
Learn more about triangles here:
https://brainly.com/question/25950519
#SPJ7
What is the surface area of the right cylinder below?
18
A. 1194 sq. units
B. 880 sq. units
C. 3104 sq. units
D. 1759 sq. units
The surface area of the cylinder is 1759 sq units.
What is surface area?The surface area is the total area covered by all the faces of a 3D object. It is always measured in square units.
Given that a cylinder with radius 10 units and height is 18 units, we need to determine the surface area of the cylinder,
The surface area of the cylinder = 2π × radius × (height + radius)
= 2 × 3.14 × 10 × (18+10)
= 1759
Hence, the surface area of the cylinder is 1759 sq units.
Learn more about surface area, click;
https://brainly.com/question/29298005
#SPJ7
Convert 23cm2 into mm2
Answer:
2300 mm^2
Step-by-step explanation:
Find the exact value of sin2Θ if tanΘ=[tex]\frac{-2\sqrt{5} }{5}[/tex] and 90 < Θ < 180.
Answer:
[tex]sin 2 \theta = \frac{4 \sqrt5}{9}[/tex]
Step-by-step explanation:
Identities used :
[tex]1. sin^2 \theta = 1 - cos^2\theta\\\\2. tan^2 \theta + 1 = sec^2 \theta\\\\3.cos \theta = \frac{1}{sec \theta} \\\\4. sin 2 \theta = 2 sin\theta cos\theta[/tex]
[tex]Given \ tan \theta = -\frac{2 \sqrt5}{5}\\[/tex]
[tex]we \ know \ tan ^2 \theta + 1 = sec^2\theta[/tex]
[tex](-\frac{2 \sqrt 5}{5})^2 + 1 = sec^2 \theta\\\\\frac{4 \times 5}{25 } + 1 = sec^2 \theta \\\\\frac{20 + 25}{ 25} = sec^2 \theta \\\\\frac{45}{25} = sec^2 \theta \\\\sec \theta = \sqrt{ \frac{45}{25}}\\\\sec \theta = \sqrt{ \frac{9 \times 5}{5 \times 5}} \\\\sec \theta = \frac{3 \sqrt {5}}{5}\\\\[/tex]
[tex]We \ know \ cos \theta = \frac{1}{ sec \theta}[/tex]
[tex]So , \cos \theta = \frac{5}{3 \sqrt5}[/tex]
[tex]Next \ sin^2 \theta = 1 - cos^2 \theta[/tex]
[tex]= 1 - (\frac{5}{3 \sqrt5})^2\\\\=1 - \frac{25}{9 \times 5}\\\\=1 - \frac{25}{45}\\\\=\frac{45 - 25}{45}\\\\=\frac{20}{45}\\\\=\frac{4}{9}[/tex]
[tex]sin \theta = \sqrt{ \frac{4}{9}} = \frac{2}{3}[/tex]
[tex]Find \ sin 2 \theta[/tex]
[tex]sin 2 \theta = 2 (sin \theta \times cos \theta)[/tex]
[tex]= 2 \times \frac{2}{3} \times \frac{5}{3\sqrt5}\\\\= \frac{4 \times \sqrt5 \times \sqrt5}{9 \times \sqrt 5}\\\\=\frac{4 \sqrt5}{9}[/tex]
6. Tumigil si Jasmin ng 150 araw sa Taguig City dahil naabutan siya ng travel ban. Ilang buwan siya nanatili roon? *
2. The average daily rainfall in London during April was 3.5 mm. How much rain fell during the month?
Answer:
105mm
Step-by-step explanation:
To find the rainfall during the month of April simply multiply the number of days in April times the average daily rainfall
Number of days in April: 30
Average daily rainfall: 3.5mm
Rainfall during the month = 30 * 3.5 = 105mm
What is the value of this expression when a = 7 and b = -4? 1201 - 6 3 OA. -6 OB. - 31 Oc. 37 D. 6
Answer:
OA . -6
Step-by-step explanation:
correct me if I'm wrong
what number represents the same amount as 4 tens+0 ones
Find the distance between the points given.
(-3,-4) and (0,0)
Answer: 5 Units
Step-by-step explanation:
?????????????????????
Answer:
[tex]\sqrt{x+6}[/tex]
Step-by-step explanation:
So, there are a few things we need to go over to graph a function,
When a number is outside of a root, it changes the y value. For example:
y=[tex]\sqrt{x}+6[/tex]
With the +6, y will always be 6 higher than normal.
If it was -6, then y will always be 6 lower than normal.
What if the number is inside the root? Well, it works a little differently.
Instead of changing the y value, it changes the x value. For example:
y=[tex]\sqrt{x+6}[/tex]
So if you put a number in for x, lets say -6, wht would you get?
You would get -6+6=0
The square root of 0 is 0, so when x=-6, y=0
Normally, x would have to equal 0 for the y value to be 0.
So basically, when we see the number isnide of the root, we can think the our x coordinate being subtracted by that number.
This makes since, because if we subtract the +6 from x:
x-(+6)= x-6, and -6 is our x coordinate.
If it was -6 at the start, this would also work:
x-(-6)= x+6. So our x coordinate would start at 6.
Now, lets look at our graph.
As we can see, the x values start at -6, and the y values starts at 0.
This eliminates A and D, since the +6 would change the y value, not the x.
Remember that x-6 would make x a postive 6.
x+6 however, would make x a negative 6.
So we need x+6 in a square root.
This eliminates B, since it has a x-6, making the x coordinate postive 6, not negative 6.
So c is our answer.
Hope this helps!