What is the area of a regular hexagon with perimeter 24? A) 8sqrt3 B) 12sqrt3 C) 16sqrt3 D) 24sqrt3

Answer:

69

Step-by-step explanation:

Answer:

h minus 20

Step-by-step explanation:

Answer:

a) ◇G = ◇H - T◇S wiĺl be negative.

b) It will be a spontaneous reaction.  

Explanation:

As ◇H is less than 0 and T◇S is greater than 0 so if we put it in the equation we would get the negative maximum result. And when the energies are with negative sign they are said to be spontaneous.

Answer:

x=4      or    x= - 16

Step-by-step explanation:

|x+6|

Now subtract 7 which equals to 3.

|x+6|-7=3

|x+6|=10

Now remove the mode by adding plus minus sign in the front of 10.

x+6=±10

x+6=10 or x+6=-10

x=4      or x=-16

Answer: x^2 + (x+2)(x-2)

Step-by-step explanation:

The caret ^ before the 2 indicates that the 2 is an exponent. It means "x squared"

If the keyboard doesn't allow exponents the caret is the thing to use.

The expression for the square of Lara’s age and the product of ages of Lara’s best friends is x² + (x-2)(x+2)

The first thing to do is to calculate the square of Lara's age and this will be:

= x × x = x²

The product of the ages of Lara’s best friends will be (x-2)(x+2).

Therefore, the expression that can be used to calculate the square of Lara’s age and the product of ages of Lara’s best friends is x² + (x-2)(x+2)

Read related link on:

https://brainly.com/question/16592251

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  [tex]\sqrt{x+7}-\sqrt{x^2+2x-15}[/tex]  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

Answer:

5

12

0

range

Step-by-step explanation:

i just did it, these are the right answers.

Answer:

5,12,0, and the last answer is range

Step-by-step explanation:

Did it on Edge2021. Hope this helps!

18 + 4 ÷ 2 − 8

Following PEDMAS, divide first:

18 + 2 -8

Now add and subtract to get the final answer:

18+2 = 20

20-8 = 12

The answer is 12

Answer:

12

Step-by-step explanation:

Answer:

h(x + 1) = (x+3)(x-1)

Step-by-step explanation:

Simply plug the value of x+1 into the equation for x.

h(x) = x^2 - 4

h(x + 1) = (x + 1)^2 - 4

h(x + 1) = x^2 + 2x + 1 - 4

h(x + 1) = x^2 + 2x - 3

h(x + 1) = (x+3)(x-1)

Cheers.

Answer:

h(t)= t² - 2t -3

Step-by-step explanation:

h(x+1)= x²-4 is the given function

We can write it x²-4 as:

Substituting x+1  with  t. Then function is:

or

Answer:

y > 9

Step-by-step explanation:

The range of a function is the interval of all possible y-values that make the function true.

Here, one way to figure this out is to look at a graph of the function (see attachment).

From the graph, we can see that y-values approach very closely the value 9 and then the line rises beyond 9 forever. Thus, we can conclude that the range for f(x) is y > 9.

~ an aesthetics lover

Answer:

The correct option is;

Left object volume = right object volume

Step-by-step explanation:

The shapes given in the question are two circular cones that have equal base radius and equal height

The formula for the volume, V of a circular cone = 1/3 × Base area × Height

The base area of the two shapes are for the left A = π·r², for the right A = π·r²

The heights are the same, therefore, the volume are;

For the left

[tex]V_{left}[/tex] = 1/3×π·r²×h

For the right

[tex]V_{right}[/tex] = 1/3×π·r²×h

Which shows that

1/3×π·r²×h  = 1/3×π·r²×h and [tex]V_{left}[/tex]  = [tex]V_{right}[/tex], therefore, the volumes are equal and the correct option is left object volume = right object volume.

Answer:

140°

Step-by-step explanation:

The circle has a central angle of 80. This means that the arc it intercepts is also 80°. Therefore, the rest of the circle not intercepted by the arc is 360-80=280°

Remember that inscribed angles have one-half of the arc-length it intercepts. We can see that Angle C intercepts the entire circle except for the arc intercepted by Angle O. Therefore, the arc intercepted by Angle C is 280°. This means that Angle C is the half of 280, or 140°.

Answer:

[tex]\huge\boxed{B) x = 20}[/tex]

Step-by-step explanation:

50 * 5x = 5000

Dividing both sides by 50

=> 5x = 5000/50

=> 5x = 100

Dividing both sides by 5

=> x = 20

Answer:

the answer is B

Step-by-step explanation:

X: (x)50=20

Answer: Tuesday, July 9 (correct me if I'm wrong)

Step-by-step explanation:

Jen goes every other day, so she goes every odd day.

Terry goes every third day, so Jen and Terry go together every six days.

Six days later is Sunday June 9, then Saturday June 15, then Friday Jun 21, then Thursday June 27, then Wednesday July 3.

Carlos only comes Mondays and Tuesday, so the next six days would be Tuesday July 9.

Answer:

Tessa has 3 ice-cream scoops

Step-by-step explanation:

Answer: The two choices with the square root of 2 will have irrational answers

Step-by-step explanation: By definition:

As long As you have normal fractions, you have rational numbers.

Square roots of "perfect squares" 4, 9, 16, 25, etc. can be rational numbers. The square roots of anything else and pi will be irrational.

The exponent 7 tells us how many copies of "8" are being multiplied together.

The expression 8*8*8 is equal to 8^3, while 8*8*8*8 = 8^4

Multiplying 8^3 and 8^4 will have us add the exponents to get 8^7. The base stays at 8 the entire time.

The rule is a^b*a^c = a^(b+c) where the base is 'a' the entire time.

Answer:

8^ 7

Step-by-step explanation:

(8*8*8) * (8*8*8*8)

There are 3 8's times 4 8's

8^3 * 8^4

We know that a^b * a^c = a^ (b+c)

8 ^ ( 3+4)

8^ 7

Answer:

sqrt of (m-7) = n+3

m = (n+3)^2 + 7 or m= n^2 + 6n + 16

sqrt of (m)-7 = n+3

m = (n+10)^2 or m =n^2 + 20n + 100

Step-by-step explanation:

(2) move the constants to the other side, and square

or  (1) square and move constants

then you can solve for m

Answer:

[tex]n^2+6n+16[/tex]

Step-by-step explanation:

I'm going to assume you meant [tex]\sqrt{m-7} = n+3[/tex], not  [tex]\sqrt{m} - 7 = n+3[/tex].

[tex](\sqrt{m-7}) ^2 = (n+3)^2\\\\(\sqrt{m-7}^2) = (n+3)^2\\\\(m-7)^{\frac{2}{2} } = (n+3)^2\\\\m - 7 = (n+3)^2\\\\m - 7 = n^2 + 2n\cdot3 + 3^2\\\\m - 7 = n^2 + 6n + 9\\\\m - 7 + 7 = n^2 + 6n + 9 + 7\\\\m = n^2 + 6n + 16[/tex]

Hope this helped!

Answer:

the length of DB is 17 in

Step-by-step explanation:

Consider the sketch attached.

We will draw an imaginary line from point C to met line AB at point E.

A right-angled triangle will now be formed between points CBE.

The dimensions of the right-angled triangle will be:

CB = 10 in

CE= 8 in

EB = unknown

We will now proceed to find out the length of side EB using the Pythagoras' theorem.

[tex]EB =\sqrt{CB^2 -CE^2} \\EB =\sqrt{10^2 -8^2} \\EB = 6 in[/tex]

From the shape, we can find out that another right-angled triangle is made between points DAB.

The dimensions of the triangle are:

DA= 8in

AB = 9 in + 6 in = 15 in

DB = unknown.

We will now proceed to find out the length of side DB using the Pythagoras' theorem.

[tex]DB =\sqrt{AD^2 +AB^2} \\DB =\sqrt{8^2 +15^2} \\DB = 17 in[/tex]

Therefore, the length of DB is 17 in

Answer:

240 inches cubed

Step-by-step explanation:

Volume equals length times width times height. Imagine the net is folded into its shape. The product of the base, 6 x 10 = 60, and the height, 4, equals 240. Remember that each square accounts for two inches. Hope this helps.

Answer:

1. EF = 65m

2. DF = 73m

Step-by-step explanation:

1. EF = height of the building = h = 33 / tan 27 = 65m

2. DF = sqrt (65² + 33²) = 73m

The building is 64.76 meters long and 73 meters far from the top of the building to the tip of the shadow.

From the triangle DEF, we find the value of EF by using tan function.

tan function is a ratio of opposite side and adjacent side.

tan(27)= 33/FE

0.5095 = 33/FE

Apply cross multiplication:

FE=33/0.5095

FE=64.76

Now DF is the hypotenuse, we find it by using pythagoras theorem.

DF²=DE²+EF²

DF²=33²+64.76²

DF²=1089+4193.85

DF²=5282.85

Take square root on both sides:

DF=72.68

In a triangle the the sum of three angles is 180 degrees.

∠D + 27 +90 =180

∠D + 117 =180

Subtract 117 from both sides:

∠D =63 degrees.

Hence, the building is 64.76 meters long and 73 meters far from the top of the building to the tip of the shadow.

To learn more on trigonometry click:

https://brainly.com/question/25122835

#SPJ4

[tex]k+\frac{k}{2}+\frac{k}{6}=120\\\\6k+3k+k=720\\10k=720\\k=72[/tex]

72,36,12

answer: 36

Answer:

[tex]3 + 3^2 + 3^3 ...+ 3^n = \frac{3(3^n - 1)}{2}[/tex]

Step-by-step explanation:

Given

[tex]3 + 3^2 + 3^3 ...+ 3^n[/tex]

Required

Show that the sum of the series is [tex]\frac{3(3^{n}-1)}{2}[/tex]

The above shows the sum of a geometric series and this will be calculated as shown below;

[tex]S_n = \frac{a(r^n - 1)}{r - 1}[/tex]

Where

a = First term;

[tex]a = 3[/tex]

r = common ratio

[tex]r = \frac{3^2}{3} = \frac{3^3}{3^2}[/tex]

[tex]r = 3[/tex]

Substitute 3 for r and 3 for a in the formula above;

[tex]S_n = \frac{a(r^n - 1)}{r - 1}[/tex] becomes

[tex]S_n = \frac{3(3^n - 1)}{3 - 1}[/tex]

[tex]S_n = \frac{3(3^n - 1)}{2}[/tex]

Hence;

[tex]3 + 3^2 + 3^3 ...+ 3^n = \frac{3(3^n - 1)}{2}[/tex]

Explanation : If 66 is a factor of this unknown value, then 22 must be as well considering that 22 is a factor off 66. Let's say that this large value is 330. It is a multiple of 66, as 66 [tex]*[/tex] 5 = 330. At the same time 22 [tex]*[/tex] 15 = 330, so 330 is a multiple of 22 as well - or vice versa, 12 is a factor of 330.

We can also tell that 15, 22 fit into 330 through another approach. 22 [tex]*[/tex] 3 = 66, and 66 [tex]*[/tex] 5 = 330, so 5 [tex]*[/tex] 3 = 15 - the same value. This proves that 22 will always be a factor of a value that is the factor of 66.

Answer:

convert them to decimasls

Step-by-step explanation:

convert thhem to decimals to make it easier

Answer:

1/2 2/4 4/8 6/12 9/18

Step-by-step explanation:

Answer:

In 7, seven kids checked out 7. [tex]7*7=49[/tex] (Correct answer because 49 is the biggest number here)

In 1, only two kids checked out 1. [tex]1 *2=2[/tex] (Wrong answer because 2 is lower than 49)

In 4, only eight kids checked out 4. [tex]4*8=32[/tex] (Wrong answer because 32 is lower than 49)

In 12, only two kids checked out 12. [tex]12*2=24[/tex] (Wrong answer because 24 is lower than 49)

So 7 is the correct answer because [tex]7*7=49[/tex] is the greatest equation here.

The 0 and 11 number book is the typical book one student checked out.

Given, the dot plot shows the no. of book  each student checked out from the library last month.

Since each dot represent a different student, so clearly from the dot plot the 8 number book is checked out by the most of the students because it has most of the dots.

Since the number 0 and 11 has only one dot it represent that only 1 student checked out these books last month.

Hence the 0 and 11 number book is the typical book one student checked out.

For more details on dot plot follow the link:

https://brainly.com/question/4398979

Answer:  see proof below

Step-by-step explanation:

You will need the following identities to prove this:

[tex]\tan\ (\alpha-\beta)=\dfrac{\tan \alpha-\tan \beta}{1+\tan \alpha\cdot \tan \beta}[/tex]

[tex]\cos\ 2\alpha=\cos^2 \alpha-\sin^2\alpha[/tex]

LHS → RHS

[tex]\dfrac{2\tan\ (45^o-A)}{1+\tan^2\ (45^o-A)}\\\\\\=\dfrac{2\bigg(\dfrac{\tan\ 45^o-\tan\ A}{1+\tan\ 45^o\cdot \tan\ A}\bigg)}{1+\bigg(\dfrac{\tan\ 45^o-\tan\ A}{1+\tan\ 45^o\cdot \tan\ A}\bigg)^2}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan\ A}{1+\tan\ A}\bigg)}{1+\bigg(\dfrac{1-\tan\ A}{1+\tan\ A}\bigg)^2}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{1+\bigg(\dfrac{1-2\tan\A+\tan^2 A}{1+2\tan A+\tan^2A}\bigg)}\\[/tex]

[tex]=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\dfrac{(1+2\tan A+\tan^2A)+(1-2\tan A+\tan^2 A)}{1+2\tan A+\tan^2A}}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\dfrac{2+2\tan^2A}{1+2\tan A+\tan^2A}}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{2\bigg(\dfrac{1+\tan^2A}{(1+\tan A)^2}\bigg)}\\\\\\=\dfrac{\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\bigg(\dfrac{1+\tan^2A}{(1+\tan A)^2}\bigg)}[/tex]

[tex]=\dfrac{1-\tan A}{1+\tan A}}\times \dfrac{(1+\tan A)^2}{1+\tan^2A}\\\\\\=\dfrac{1-\tan^2 A}{1+\tan^2 A}\\\\\\=\dfrac{1-\dfrac{\sin^2 A}{\cos^2 A}}{1+\dfrac{\sin^2 A}{\cos^2 A}}\\\\\\=\dfrac{\bigg(\dfrac{\cos^2 A-\sin^2 A}{\cos^2 A}\bigg)}{\bigg(\dfrac{\cos^2 A+\sin^2 A}{\cos^2 A}\bigg)}\\\\\\=\dfrac{\cos^2 A-\sin^2 A}{\cos^2 A+\sin^2 A}\\\\\\=\dfrac{\cos^2 A-\sin^2 A}{1}\\\\\\=\cos^2 A-\sin^2 A\\\\\\=\cos 2A[/tex]

cos 2A = cos 2A   [tex]\checkmark[/tex]

Answer:

x = a + 8

Step-by-step explanation:

x = The number that is 40% more than five more than a number a.

x = 40% more than 5 (plus a)

5 * 0.6 = 3

5+3 = 8

x = a + 8

Answer:

d = √8

d ≈ 2.82843

Step-by-step explanation:

Distance Formula: [tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Simply plug in our coordinates into the distance formula:

[tex]d = \sqrt{(-3 + 5)^2+(-8 + 6)^2}[/tex]

[tex]d = \sqrt{(2)^2+(-2)^2}[/tex]

[tex]d = \sqrt{4+4}[/tex]

[tex]d = \sqrt{8}[/tex]

To find the decimal, simply evaluate the square root:

√8 = 2.82843

Answer:

Step-by-step explanation:

Let the points be A and B

A ( - 5 , - 6 ) ⇒ ( x₁ , y₁ )

B ( -3 , - 8 )⇒( x₂ , y₂ )

Now, let's find the distance between these two points:

AB = [tex] \mathsf{ \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }[/tex]

Plug the values

⇒[tex] \mathsf{ \sqrt{( - 3 - ( - 5) )^{2} + {( - 8 - ( - 6))}^{2} } }[/tex]

When there is a ( - ) in front of an expression in parentheses, change the sign of each term in the expression

⇒[tex] \mathsf{ \sqrt{ {( - 3 + 5)}^{2} + {( - 8 + 6)}^{2} } }[/tex]

Calculate

⇒[tex] \mathsf{ \sqrt{ {(2)}^{2} + {( - 2)}^{2} } }[/tex]

Evaluate the power

⇒[tex] \mathsf{ \sqrt{4 + 4} }[/tex]

Add the numbers

⇒[tex] \mathsf{\sqrt{8} }[/tex]

Simplify the radical expression

⇒[tex] \mathsf{ \sqrt{2 \times 2 \times 2}} [/tex]

⇒[tex] \mathsf{2 \sqrt{2} }[/tex] units

Hope I helped!

Best regards!

Answer:

The probability of 3 students having blood type A is 1.23 , having blood type B is 0.3 and having blood type AB is 0.12

Step-by-step explanation: