What is the answer for this

Answer:

2nd option

Step-by-step explanation:

Using the power rule

[tex]\frac{d}{dx}[/tex] (a[tex]x^{n}[/tex] ) = na[tex]x^{n-1}[/tex]

Given

f(x) = [tex]\frac{3}{2\sqrt[3]{x} }[/tex] = [tex]\frac{3}{2x^{\frac{1}{3} } }[/tex] = [tex]\frac{3}{2}[/tex] [tex]x^{-\frac{1}{3} }[/tex] , then

f'(x) = - [tex]\frac{1}{3}[/tex] × [tex]\frac{3}{2}[/tex] [tex]x^{-\frac{4}{3} }[/tex]

      = - [tex]\frac{1}{2}[/tex] × [tex]\frac{1}{x^{\frac{4}{3} } }[/tex]

      = - [tex]\frac{1}{2x^{\frac{4}{3} } }[/tex] = - [tex]\frac{1}{2\sqrt[3]{x^4} }[/tex] [ Note there should be a leading negative ]

Answer: it would be D

Step-by-step explanation: because the x intercept is zero and the equation solved is 6  

Formula given: [tex]y=x^{2} -x-6[/tex]

x      -3        -2        -1         0         1          2        3

y       6         0       -4         -6       -4        -4        0

when x = -2

[tex]=(-2)^{2} -(-2)-6[/tex]

[tex]=0[/tex]

when x = -1

[tex]=(-1)^{2} -(-1)-6[/tex]

[tex]=-4[/tex]

when x = 1

[tex]=(1)^{2} -(1)-6[/tex]

[tex]=-6[/tex]

when x = 2

[tex]=(2)^{2} -(2)-6[/tex]

[tex]=-4[/tex]

when x = 3

[tex]=(3)^{2} -(3)-6[/tex]

[tex]=0[/tex]

Answer:

-3          -2          -1          0          1          2          3

6            0          -4         -6         -6       -4          0

Step-by-step explanation:

One is given the following function;

[tex]y=x^2-x-6[/tex]

The problem asks one to evaluate the function for certain values, substitute these values in place of the variable (x) and simplify to evaluate the function.

[tex]-2\\\\(-2)^2-(-2)-6\\=4-(-2)-6\\=4+2-6\\=6-6\\=0[/tex]

[tex]-1\\\\(-1)^2-(-1)-6\\=1-(-1)-6\\=1+1-6\\=2-6\\=-4[/tex]

[tex]1\\\\(1)^2-(1)-6\\=1-(1)-6\\=1-1-6\\=0-6\\=-6[/tex]

[tex]2\\\\(2)^2-(2)-6\\=4-(2)-6\\=4-2-6\\=2-6\\=-4[/tex]

[tex]3\\\\(3)^2-(3)-6\\=9-(3)-6\\=9-3-6\\=6-6\\=0[/tex]

Answer:

See below.

Step-by-step explanation:

6. 3 times a number (x) is greater than 10

     3x > 10

7. A number (x) added by 4 is less than or equal to 7

    x+4[tex]\leq[/tex]7

8. 6 is less than a number (x) divided by 6

   6 < x/6

9. The ratio of 10 and a number (x) is greater than or equal to 5

      (10/x) [tex]\geq[/tex] 5

10.The sum of x and 7 is less than 4

     x + 7 < 4

Answer:

y = 2/3x + 1 1/3

Step-by-step explanation:

As y increases by 2, x increases by 3, so 2/3. The y - intercept is 1 and 1/3 so plus 1 1/3

Answer:

3/10

Step-by-step explanation:

=1/2 *3/5

= 1*3/2*5

= 3/10

hope it helps

Answer:

1/5

Step-by-step explanation:

20/100 or 1/5

Answer:

Step 1: Put the numbers in order.

1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 2: Find the median.

1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 3: Place parentheses around the numbers above and below the median.

Not necessary statistically, but it makes Q1 and Q3 easier to spot.

(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).

Step 4: Find Q1 and Q3

Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.

(1, 2, 5, 6, 7), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.

Step 5: Subtract Q1 from Q3 to find the interquartile range.

18 – 5 = 13.

Step-by-step explanation:

Answer:

Copper = x= 36.19

Step-by-step explanation:

The number of copper is unknown

Gold = 1/3

Silver = 1/5

Bronze =2/7

Copper = x

Total coins = 200

Gold = 1/3 of 200

= 1/3 × 200

= 200/3

= 66.67

Silver = 1/5 × 200

= 200/5

= 40

Bronze = 2/7 × 200

= 400/7

= 57.14

Total = gold + silver + bronze + copper

200 = 66.67 + 40 + 57.14 + x

200 = 163.81 + x

200 - 163.81 = x

x = 36.19

Copper = x= 36.19

Answer:(first term)

a=27(4th term)

T4= a x r^3 = 64

substituting a as 27 in T4

27 x r^3 = 64

r^3 = 64/27

r=4/3

so; a=27, r=4/3

using the general formula of geometric progression,

a x r^n-1

substitute:.

27 x 4/3^n-1

= 27(4/3)^n-1

Answer: (C) HOPE THIS HELPS!

Step-by-step explanation:

[tex] \frac{3}{2} + \frac{x}{3} = \frac{11}{6} [/tex]

[tex] \frac{x}{3} = \frac{11}{6} - \frac{3}{2} [/tex]

[tex] \frac{x}{3} = \frac{11 - 3 \times 3}{6} [/tex]

[tex] \frac{x}{3} = \frac{11 - 9}{6} [/tex]

[tex] \frac{x}{3} = \frac{2}{6} [/tex]

[tex] \frac{x}{3} = \frac{1}{3} [/tex]

[tex]x = \frac{3 \times 1}{3} [/tex]

[tex]x = 1[/tex]

Answer:

x = 1

Step-by-step explanation:

3/ 2 + x/ 3 = 11/ 6

taking LCM

(9 + 2x)/ 6 = 11/ 6

multpiying both sides by 6

9 + 2x = 11

subtracting btih sides by 9

2x = 11 - 9

2x = 2

dividing both by 2

x = 1

Answer:

65.5

Step-by-step explanation:

Answer:

y = (x + 1)²

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 1, 0) , then

y = a(x + 1)² + 0

To find a substitute (0, 1), the y- intercept into the equation

1 = a(0 + 1)² = a

y = (x + 1)²

Answer:

30°

Step-by-step explanation:

x = 180° -60°-90° = 30°

Answer:

2/15

Step-by-step explanation:

1/5 + 2/3

= 3/15 + 10/15

= 13/15

15/15 - 13/15

= 2/15

Answer:

X^2+7x+4

Step-by-step explanation:

Answer:

i wish i could tell you

Step-by-step explanation:

Answer:

- 10p2

Step-by-step explanation:

p(8p - 18 p)

p x -10p

ans = -10p2

Answer:  -10p²

This is the same as saying -10p^2

============================================

Explanation:

Both terms 8p² and -18p² are like terms.

We combine them in much the same way as 8-18 = -10, just with a p² attached to everything.

So 8p² - 18p²  = (8-18)p² = -10p²

The coefficient -10 is negative because we're subtracting small minus big. If it was the other way around, then we'd get a positive value.

Answer:

[tex]{ \tt{ {(5 {z}^{2} + 3z + 2)}^{2} }} \\ = (5 {z}^{2} + 3z + 2)(5 {z}^{2} + 3z + 2) \\ = (25 {z}^{4} + 30 {z}^{3} + 29 {z}^{2} + 12z + 4)[/tex]

Answer: I cant see the problem

Step-by-step explanation:

Answer:

Where is the question?

Step-by-step explanation:

Whole part = 2

Fractional part = 59/396

======================================================

Work Shown:

3 & 3/5 = 3 + 3/5

3 & 3/5 = 15/5 + 3/5

3 & 3/5 = 18/5

--------------------

4 & 8/9 = 4 + 8/9

4 & 8/9 = 36/9 + 8/9

4 & 8/9 = 44/9

--------------------

Now apply the rule that 1/(A/B) = B/A. We apply the reciprocal to the fraction A/B to get B/A

That means something like 1/(18/5) becomes 5/18

Also, 1 over (44/9) becomes 9/44

1 over (3/5) becomes 5/3

-------------------

We now have the following:

(5/18) + (9/44) + (5/3)

We'll come back to this later. But first need the LCD, which means we need the LCM of the denominators.

Write out the prime factorization of each denominator

The unique prime factors are: 2, 3, 11

The LCM is 2^2*3^3*11^1 = 1188, which is also the LCD

-------------------

We need to get each fraction to have the LCD

5/18 = (5/18)*(66/66) = 330/1188

9/44 = (9/44)*(27/27) = 243/1188

5/3 = (5/3)*(396/396) = 1980/1188

We can now add the fractions like so

(5/18) + (9/44) + (5/3)

(330/1188) + (243/1188) + (1980/1188)

(330+243+1980)/1188

2553/1188

-------------------

We're almost done. We just need to convert to a mixed number, aka mixed fraction

Using a calculator or long division, you should find that

2553/1188 = 2.1489898989899

approximately. Focus just on the stuff to the left of the decimal point. That's the whole part of the answer.

We can then say: 2553-1188*2 = 177

This forms the numerator of the fractional part. The denominator stays at the LCD 1188

That forms the fraction 177/1188. Divide both parts of that fraction by 3 to fully reduce it. You should get to 59/396

-------------------

So that's how we end up with the mixed number 2 & 59/396

Answer:

a) x = 8.29 cm

D) V = 1125.27 cm³

Step-by-step explanation:

a) We can solve the equation as follows:

[tex] 2x + 5x - 58 = 0 [/tex]

[tex] 2x + 5x = 58 [/tex]

[tex] x = \frac{58}{7} = 8.29 [/tex]

D) The volume of the box is given by:

[tex] V = l*w*h [/tex]

Where:

l: is the length

w: is the width

h: is the height

The length of the rectangular box is:

[tex] l = (2x + 5) cm = (2*8.29 + 5) cm = 21.58 cm [/tex]

The width is x = 8.29 cm.

And the height is:

[tex] h = (x - 2) cm = (8.29 - 2) cm = 6.29 cm [/tex]

Hence, the volume is:

[tex] V = l*w*h = (21.58*8.29*6.29) cm^{3} = 1125.27 cm^{3} [/tex]

I hope it helps you!        

Answer:

Alternate interior angles are on opposite sides of the transversal, and between the parallel lines

Step-by-step explanation:

Answer:

B. Point E

Step-by-step explanation:

Your point is (2,5) for the reptile house ((8,3) is extra unnecessary information) to find the house you go to the right 2 units and then 5 units up. The only one that matches is point E so therefore it's your answer.

Answer:

y = 3/4 x - 9/2

Step-by-step explanation:

Slope = 3/4

y = mx + b

y = 3/4x + b

0 = 3/4 (6) + b

0 = 18/4 + b

-9/2 = b

y = 3/4 x - 9/2

Answer:

37.8 x 13.2 =4988.6

28,5 + 22.1 = 50.6

Answer:

output = input - equation

y = x - 7

so 7 is your correct equation!!

Step-by-step explanation:

as u can see

When input x is subtracted from output y, we are getting answer 7

like here

imma gonna tell u how 7 is came

1-8=7

2-9=7

3-10=7

4-11=7

so 7 is our equation

its just a explanation okay

so we get our solution

•°• Y = X - 7

hope it may help you!!

mark as brainlist

Answer:

the maximum is 450 and the minimum is 0.

Step-by-step explanation:

We know that:

P(x, y) = 25*x + 45*y

First, is easy to see that as x and y increase, also does the value of P(x, y)

So we just need to find the largest and smallest possible values of these variables. We also can notice that the variable y is being multiplicated by a larger coefficient than x, so we prioritize larger values of y when we can.

We know that:

4x+y ≤ 16

x + y ≤10

x≥0

y≥0

Let's start with the second inequality, let's solve this for y:

y ≤ 10 - x

and from the first one we get:

y ≤ 16 - 4*x

Just to show that maximizing x does not work, let's do it:

from the second one, knowing that the minimum value of y is y = 0

we have that:

0 ≤ 16 - 4*x

Here the maximum value that y can take is x = 1

0 ≤ 16 - 4*1 = 0

So we can have the combination y = 0 and x = 1, when we maximize x (here we can see that we should not maximize x)

in this case we get:

P(1, 0) = 25*1 + 47*0 = 25

let's write again our inequalities:

y ≤ 10 - x

y ≤ 16 - 4*x

If now we take the minimum value of x, x = 0, we get:

y ≤ 10

y ≤ 16

Because the first one is more restrictive, we know that the maximum value that y can take (when x = 0) is y = 10

in this case we get:

P(0, 10) = 25*0 + 45*10 = 450

As expected, here is the actual maximum for the given restrictions.

For the minimum, we just need to take the two lowest possible values of x and y, which are the two given by the equalities on:

x≥0

y≥0

The smallest values are:

x = 0

y = 0

Replacing that in the equation we get:

P(0, 0) = 25*0 + 47*0 = 0

So the maximum is 450 and the minimum is 0. (with the given restrictions)

Answer:

What? Your not even done.

Step-by-step explanation: