In the figure below, triangle ABC is similar to triangle PQR:
A right triangle ABC with right angle at B and base BC is drawn. Length of AB is 4, length of BC is 2. A similar right triangle; triangle PQR, which is triangle ABC enlarged and reflected across a horizontal line, is drawn near it. The right angle is at Q. Angle A is congruent to angle P and angle C is congruent to angle R. The length of QR is 12.
What is the length of side PQ?
48
24
40
18
Answer:
24
Step-by-step explanation:
Since the triangles are similar the side lengths must be proportional
2/12 = 4/PQ cross multiply expressions
2PQ = 48 divide both sides by 2
PQ = 24
Can someone help me with this question?
Answer:
y = ± 15
Step-by-step explanation:
Given
y² = 225 ( take the square root of both sides )
[tex]\sqrt{y^2}[/tex] = ± [tex]\sqrt{225}[/tex]
y = ± 15
That is y = 15, y = - 15
Since 15 × 15 = 225 and - 15 × - 15 = 225
y² = 225
y = √225
y = 15
y²= 225
y = √225
y = -15
y = ±15
Therefore values of y are 15 and -15
Must click thanks and mark brainliest
HELP PLEASE SO I CAN MOVE ON
find the measure of the indicated angle to the nearest degree
Answer:
16
Step-by-step explanation:
[tex] \tan(x) = \frac{13}{46} [/tex]
[tex] \tan {}^{ - 1} ( \frac{13}{46} ) = 16[/tex]
Find each of the following products
a) 6x * (-2y)
Answer ) -12xy
Step-by-step explanation:
6x × (-2y) = -12xy thank youplease please please help me out somebody!!!!!!!
Find the midpoint of the line segment joining (–4, –2) and (2, 8).
SHOW HOW YOU GOT IT please
Answer:
(-1,3)
Step-by-step explanation:
Using midpoint formula, we have
x=(-4+2)/2=-1
y=(-2+8)/2=3
A right triangle has a 12in base and an 8in height. What is the area of the triangle, in in??
Answer:
48
Step-by-step explanation:
using the formula 1/2 b*h
8*12=96
96/2=48
The eighth term of a linear sequence is 26. The term-to-term rule is 'add 3
Work out the fourth term of the sequence.
Explain the method you used to solve this problem.
Let a be first term
[tex]\\ \rm\longmapsto a_8=a+7d[/tex]
[tex]\\ \rm\longmapsto 26=a+7(3)[/tex]
[tex]\\ \rm\longmapsto a=26-21[/tex]
[tex]\\ \rm\longmapsto a=5[/tex]
Now
[tex]\\ \rm\longmapsto a_4=a+3d[/tex]
[tex]\\ \rm\longmapsto a_4=5+3(3)[/tex]
[tex]\\ \rm\longmapsto a_4=5+9[/tex]
[tex]\\ \rm\longmapsto a_4=14[/tex]
ASAP!! I'll mark you as BRAINLIEST Please help me out here I would really appreciate <3
Answer:
d) 16, 19, 14 + x
e) x + 20, 30, 33, 15, y - 20, x+x+20=60 and James would be 20.
f) 13
g) 120
Step-by-step explanation:
D.
(1) 14 + 2 = 16
(2) 14 + 5 = 19
(3) 14 + x
E.
(1) x + 20
(2) 10 + 20 = 30
(3) 13 + 20 = 33
(4) 35 - 20 = 15
(5) y - 20
(6) x + (x + 20) = 60 | 2x + 20 = 60 | 2x = 40 | x = 20
F.
200 - 148 = 52
52 / 4 = 13 each
G.
500 + 100 = 600
600 / 5 = 120 without the discount
Hope this helps!
what is the graph of the following function??
PLEASE HELP!!
Answer:
umm it's a piecewise function and I think the graph is correct I don't really understand what you mean by what is the "graph" of the following function since the graph is already there...
Step-by-step explanation:
Pls Help, Thanks
According to the partial construction shown, what is the next step in constructing a line perpendicular to a point on the line?
Place compass at point D, and draw an arc that intersects the arc above line DF.
Place compass at point F, and draw an arc that intersects the arc above line DF.
Place compass at point P, and draw an arc above line DF
Place compass at point P, and draw an arc below line DF
Step-by-step explanation:
First draw a lign segment like DF
Next keep the point on D make an arc by increasing the length of compass
As same keep the point on F make an arc lile same as before
Next there is apoint name it as any meeting on drew arc
connect it to the point with P
Does anyone know the answer plz ?
Answer:
x = 5; y = 5
Step-by-step explanation:
One angle is a right angle, so its measure is 90 degrees.
One angle measures 45 degrees, so the unknown angle must also measure 45 degrees.
x and y are opposite two 45-degree angles, so x = y.
In a 45-45-90 triangle, the ratio of the lengths of the sides is
1 : 1 : sqrt(2)
We have
x : y : 5sqrt(2)
x/1 = 5sqrt(2)/sqrt(2)
x = 5
y = 5
Square root of 64 + cube root of 64 is
Answer:
12
Step-by-step explanation:
[tex]\sqrt{64}[/tex] + [tex]\sqrt[3]{64}[/tex]
= 8 + 4
= 12
Square root of 64 = [tex] \sf \sqrt{64} = \sqrt{8 \times 8} = \boxed{\bf 8}[/tex]
Cube root of 64 = [tex] \sf \sqrt[3]{64} = \sqrt[3]{4 \times 4 \times 4} = \boxed{ \bf4}[/tex]
So,
Square root of 64 + Cube root of 64
[tex] = \sf \sqrt{64} + \sqrt[3]{64} \\ \sf = 8 + 4 \\ = \boxed{ \bf12}[/tex]
12 is the answer of the question asked.
____________
Hope it helps.
RainbowSalt2222
(-2 1/2) to the second power
Answer:
6.25
Step-by-step explanation:
[tex](-2\frac{1}{2})^2\\\\(-\frac{5}{2} )^2\\\\(\frac{5}{2})^2\\\\\frac{5^2}{2^2}\\\\\frac{25}{4}\\\\\boxed{6\frac{1}{4}}\text{ or } 6.25[/tex]
Hope this helps.
Translate the following into an algebraic expression:
The number that is 75% of one less than a number n.
Answer:
X = 0.75 ( 1- n )
Step-by-step explanation:
let X = the number one less than n gives (1-n)
75% of (1-n) = 0.75*(1-n) = 0.75(1-n)
In conclusion: X = 0.75 ( 1- n )
please answer this for me really struggling thanks
Answer:
Just agree on having ice cream
Step-by-step explanation:
solve the equation - 2(3x+5/x+2) -5(x+2/3x-5) = 3 , where x unequal -2 and x unequal 5/3
it's urgent
please quys
with solution
Answer:
Step-by-step explanation:
(a - b)(a + b) =a² - b²
(3x + 5)(3x -5) =(3x)² - 5² = 9x² - 25
(x +2)(x+2) = (x+ 2)² = x²+ 2*2*x+2² = x² + 4x + 4
(x+2)(3x -5 ) = x*3x - 5*x +2*3x +2*(-5)
= 3x² -5x +6x -10
= 3x² + x - 10
[tex]\frac{2*(3x+5)}{x+2}-\frac{5(x+2)}{3x-5}=3\\\\\frac{2*(3x+5)*(3x-5)}{(x+2)(3x-5)}-\frac{5*(x+2)(x+2)}{(3x-5)(x+2)}=3\\\\\frac{2*(9x^{2}-25)-5(x^{2}+4x+4)}{(3x-5)(x+2)}=3[/tex]
[tex]\frac{18x^{2}-25-5x^{2}-20x-20}{3x^{2}+x-10}=3\\\\\frac{18x^{2}-5x^{2}-20x - 25-20}{3x^{2}+x-10}=3\\\\[/tex]
13x² - 20x - 45 = 3*(3x² + x - 10)
13x² - 20x - 45 =9x² + 3x - 30
13x² - 9x² -20x - 3x - 45 + 30 = 0
4x² - 23x - 15 = 0
An older person is 7 years older than five times the age of a younger person. The sum of their ages is 37. Find their ages.
Answer:
older person: 32 yrs younger person: 5 yrs
Step-by-step explanation:
older person age: o
younger person age: y
o=5y+7
o+y=37
Solve with substitution:
5y+7+y=37
6y+7=37
6y=30
y=5
Plug back in:
o+5=37
o=32
I NEED HELP
THERE ARE TWO OTHER QUESTIONS AS WELL
Answer:
Please find attached the drawing of ABCD, A'B'C'D', and A''B''C''D'', created with MS Excel
Step-by-step explanation:
The given composition of transformation is [tex]r_{y-axis} \ \circ \ r_{x = - 4}[/tex]
The transformation on the right, [tex]r_{x = - 4}[/tex], is carried out first as follows;
The point A with coordinate (-7, 7) reflected across the line x = -4, gives;
A(-7, 7) [tex]r_{x = - 4}[/tex] → A'(-1, 7)
Similarly, we have;
B(-5, 7) [tex]r_{x = - 4}[/tex] → B'(-3, 7)
C(-5, 1) [tex]r_{x = - 4}[/tex] → C'(-3, 1)
D(-7, 1) [tex]r_{x = - 4}[/tex] → D'(-1, 1)
Therefore, the image of the given rectangle after reflection across the lie, x = -4, is A'(-1, 7), B'(-3, 7), C'(-3, 1), and D'(-1, 1)
The second transformation, [tex]r_{y-axis}[/tex], is found as follows;
(x, y) [tex]r_{y-axis}[/tex] → (x, -y)
Therefore, we have;
A'(-1, 7) [tex]r_{y-axis}[/tex] → A''(-1, -7)
B'(-3, 7) [tex]r_{y-axis}[/tex] → B''(-3, -7)
C'(-3, 1) [tex]r_{y-axis}[/tex] → C''(-3, -1)
D'(-1, 1) [tex]r_{y-axis}[/tex] → D''(-1, -1)
The points ABCD, A'B'C'D', and A''B''C''D'' are plotted on MS Excel and the points joined with straight lines to form the drawing of the triangles as shown in the attached figure.
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
Answer:
300 yd³
Step-by-step explanation:
Volume = lwh
l = 6
w = 5
h = 10
so, 6×5×10 = 300 yd³
3/2x + 7/2 = 2x what is the solution to the equation
Answer:
x=7
Step-by-step explanation:
3/2x + 7/2 = 2x
Subtract 3/2x from each side
3/2x -3/2x + 7/2 = 2x-3/2x
7/2 = 2x -3/2x
Get a common denominator
7/2 = 4/2x - 3/2x
7/2 = 1/2 x
Multiply each side by 2
7/2 *2 = 1/2x*2
7 =x
Answer:
x=7
Step-by-step explanation:
im smart
We want to factor the following expression: (x 3)^2 14(x 3) 49(x 3) 2 14(x 3) 49(, x, plus, 3, ), squared, plus, 14, (, x, plus, 3, ), plus, 49 We can factor the expression as (U V)^2(U V) 2 (, U, plus, V, ), squared where UUU and VVV are either constant integers or single-variable expressions. 1) What are UUU and VVV
Answer:
[tex]U = x[/tex]
[tex]V=10[/tex]
Step-by-step explanation:
Given
[tex](x +3)^2 + 14(x + 3) + 49 = (U + V)^2[/tex]
Required
Find U and V
We have:
[tex](x +3)^2 + 14(x + 3) + 49 = (U + V)^2[/tex]
Expand
[tex]x^2 + 6x + 9 + 14x + 42 + 49 = (U + V)^2[/tex]
Collect like terms
[tex]x^2 + 6x + 14x + 9 + 42 + 49 = (U + V)^2[/tex]
[tex]x^2 + 20x + 100 = (U + V)^2[/tex]
Expand
[tex]x^2 + 10x + 10x + 100 = (U + V)^2[/tex]
Group
[tex][x^2 + 10x] + [10x + 100] = (U + V)^2[/tex]
Factorize each group
[tex]x[x + 10] + 10[x + 10] = (U + V)^2[/tex]
Factor out x + 10
[tex][x + 10][x + 10] = (U + V)^2[/tex]
So, we have:
[tex][x + 10]^2 = (U + V)^2[/tex]
By comparison
[tex]U = x[/tex]
[tex]V=10[/tex]
Can anyone help me with this?
Answer:
baba booey
Step-by-step explanation:
444
Asha found that a vertical line intersects the graph of x = StartAbsoluteValue y EndAbsoluteValue at two points. What can Asha conclude about x = StartAbsoluteValue y EndAbsoluteValue?
It is a function of x but not a relation.
It is a relation but not a function of x.
It is both a function of x and a relation.
It is neither a function of x nor a relation.
Answer:
what can i help u with
Step-by-step explanation:
The graph of x = |y| is as shown in the figure.
When we draw a vertical line, it intersects the graph at two points.
This means for the same value of x , we have two values of y.
Or in other words, for the same pre image, we have two images.
Hence it is not a function.
But for every value of x, we do have a value of y, hence it is a relation.
x = |y| is a relation but it is not a function
Answer:
:B
Step-by-step explanation:
hope that can help
17’4” multiply by 17’5”
2. Find the measure of angle L.
Answer:
∠ L ≈ 21.6°
Step-by-step explanation:
Using the Sine rule in the triangle
[tex]\frac{MN}{sinL}[/tex] = [tex]\frac{LM}{sinN}[/tex] , that is
[tex]\frac{34}{sinL}[/tex] = [tex]\frac{42}{sin27}[/tex] ( cross- multiply )
42 × sinL = 34 × sin27° ( divide both sides by 42 )
sinL = [tex]\frac{34sin27}{42}[/tex] , then
∠ L = [tex]sin^{-1}[/tex] ( [tex]\frac{34sin27}{42}[/tex] ) ≈ 21.6° ( to the nearest tenth )
what is the standardform of R(4, 0), m = 5
Answer:
No. of children Frequency
0. 5
1. 7
2. 11
3. 5
4. 6
5 3
6 3
Instructions: Find the value of the trigonometric ratio. Make sure to simplify the fraction if
needed.
х
34
16
30
Answer:
cos Z = 8/17
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos theta = opp / hyp
cos Z = 16/34
cos Z = 8/17
Solve the triangle. Round to the nearest tenth when neccesary or to the nearest minute as appropriate.
Answer:
Here is the detailed answer below
Step-by-step explanation:
Some food is able to keep 150 students fed at camp for 5 days,
How many days will the food last for if there are 100 students,
I know its 7.5 but why do people x the 150 and 5 i dont get it
Answer:
x=7.5
Step-by-step explanation:
s is for students
d is for days
150 s take 5 days to finish food
if there are 100 s how many days will the same amount of food take
so 150 students × 5 days = 750 equation 1
100 students × x days= 100x equation 2
750 from 1 = 100 x from 2
750÷100=x
x=7.5 days
I need help with this asap pls!!
Answer:
Answer is b
Step-by-step explanation:
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