What is the 6th row of Pascal's triangle?

[tex]-\sqrt{-64}=-\sqrt{8^2\cdot (-1)}-8\sqrt{-1}=-8i[/tex]

Answer:

LOOK BELOW

Step-by-step explanation:

I would not call the explanation a formula

All you have to do to solve mean or average is add all of the numbers up and divide by the total amount of numbers

so for example

0,2,4,0,2,3,2,8,6  <-------- lets find the mean/average

0+2+4+2+3+2+8+6= 27/amount of numbers

amount of numbers=9

(count the zeros too!)

27/9=3

3 is the mean or average!!!

Answer:

Domain is all real numbers, x ≠ -5

Range is all real numbers, y ≠ 0

Step-by-step explanation:

Answer:

88 cm

Step-by-step explanation:

Perimeter = 2πr

=2(14)(22/7)

= 88 cm

Answer:

87.97cm

Step-by-step explanation:

This question is asking to solve for the circumference.

The formula for the circumference of a circle is:  [tex]\pi*diameter[/tex]

To work this out you would first need to multiply the radius of 14 by 2, this gives you 28cm. This is because the radius is half of the diameter.

The final step is to multiply pi by the diameter of 28, this gives you 87.97cm (87.9645943). This is because the formula for the circumference of a circle is [tex]\pi * diameter[/tex].

1) Multiply 14 by 2.

[tex]14*2=28[/tex]

2) Multiply pi by the diameter.

[tex]\pi*28^2=87.97 cm[/tex]

Answer:

kinetic energy body when it hits the ground is 98000 joule

1000joule = 1 kilojoule

, kinetic energy body when it hits the ground is 98  kilo-joule

Step-by-step explanation:

conservation of energy states that total energy of a system remains constant.

Potential energy of body = mgh

m = mass

g = gravitational pull = 9/8 m/s^2

h = height

kinetic energy = 1/2 mv^2

where v is the velocity of body

________________________________________

Total energy for this at any point is sum of potential energy and kinetic energy

total energy at height h

v= 0

PE = 250*9.8*40= 98,000

KE = 1/2 m0^2  = 0

total energy at when ball hits the ground

h=0

PE = 250*9.8*0 =

KE = 1/2 mv^2  

_______________________________________\

Applying conservation of energy

Total energy at height h = total energy at ground

98000 = KE

Thus, kinetic energy body when it hits the ground is 98000 joule

1000joule = 1 kilojoule

, kinetic energy body when it hits the ground is 98  kilo-joule

Answer:

a. [tex]\mathbf{P(Y \leq 60) = 0.3333}[/tex]

b. P(Y>50) = 0.8889

c. E(y) = 67.5 and  Standard deviation [tex]\sigma[/tex] = 12.99

Step-by-step explanation:

From the information given :

an automobile body paint shop, has determined that the painting time of automobiles is uniformly distributed and that the required time ranges between 45 minutes to [tex]1\frac{1}{2}[/tex]hours.

The objective is to determine  the probability that the painting time will be less than or equal to an hour?

since 60 minutes make an hour;

[tex]1\frac{1}{2}[/tex]hours = 60 +30 minutes = 90 minutes

Let Y be the painting time of the automobile; then,

the probability that  the painting time will be less than or equal to an hour ca be  computed as :

[tex]P(Y \leq 60) = \int ^{60}_{45} f(y) dy \\ \\ \\ P(Y \leq 60) = \int ^{60}_{45} \dfrac{1}{45} dy \\ \\ \\ P(Y \leq 60) = \dfrac{1}{45} \begin {pmatrix} x\end {pmatrix}^{60}_{45} \\ \\ \\ P(Y \leq 60) = \dfrac{60-45}{45 } \\ \\ \\ P(Y \leq 60) = \dfrac{15}{45} \\ \\ \\ P(Y \leq 60) = \dfrac{1}{3} \\ \\ \\ P(Y \leq 60) = 0.3333[/tex]

What is the probability that the painting time will be more than 50 minutes?

The probability that the painting will be more than 50 minutes is P(Y>50)

So;

[tex]P(Y>50) = \int \limits ^{90}_{50} f(y) dy[/tex]

[tex]P(Y>50) = \int \limits ^{90}_{50} \dfrac {1}{45} dy[/tex]

[tex]P(Y>50) = \dfrac{1}{45}[x]^{90}_{50}[/tex]

[tex]P(Y>50) = (\dfrac{90-50}{45})[/tex]

[tex]P(Y>50) = \dfrac{40}{45}[/tex]

P(Y>50) = 0.8889

Determine the expected painting time and its standard deviation.

Let consider E to be the expected painting time

Then :

[tex]E(y) = \int \limits ^{90}_{45} y f(y) dy \\ \\ \\ E(y) = \int \limits ^{90}_{45} y \dfrac{1}{45} dy \\ \\ \\ E(y) = \dfrac{1}{45} [\dfrac{y^2}{2}]^{90}_{45} \\ \\ \\ E(y) = \dfrac{1}{45}[\dfrac{(90^2-45^2)}{2}] \\ \\ \\ E(y) = \dfrac{1}{45} (\dfrac{6075}{2}) \\ \\ \\ E(y) = \dfrac{1}{45} \times 3037.8 \\ \\ \\ \mathbf{E(y) = 67.5}[/tex]

[tex]E(y^2) = \int \limits ^{90}_{45} y^2 f(y) dy \\ \\ \\ E(y^2) = \int \limits ^{90}_{45} y^2 \dfrac{1}{45} dy \\ \\ \\ E(y^2) = \dfrac{1}{45} [\dfrac{y^3}{3}]^{90}_{45} \\ \\ \\ E(y^2) = \dfrac{1}{45}[\dfrac{(90^3-45^3)}{3}] \\ \\ \\ E(y^2) = \dfrac{1}{45} (\dfrac{637875}{3}) \\ \\ \\ E(y^2) = \dfrac{1}{45} \times 2126.25 \\ \\ \\ \mathbf{E(y^2) = 4725}[/tex]

To determine the standard deviation, we need to first know what is the value of our variance,

So:

Variance [tex]\sigma^2[/tex] = E(x²) - [E(x)]²

Variance [tex]\sigma^2[/tex] = 4725 - (67.5)²

Variance [tex]\sigma^2[/tex] = 4725 - 4556.25

Variance [tex]\sigma^2[/tex] = 168.75

Standard deviation [tex]\sigma[/tex] = [tex]\sqrt{variance}[/tex]

Standard deviation [tex]\sigma[/tex] = [tex]\sqrt{168.75}[/tex]

Standard deviation [tex]\sigma[/tex] = 12.99

Answer:

Step-by-step explanation:

Given the equation solved by Ernesto expressed as [tex]\sqrt{\dfrac{1}{2}w+8}=-2[/tex], the extraneous solution obtained by Ernesto is shown below;

[tex]\sqrt{\dfrac{1}{2}w+8}=-2\\\\square\ both \ sides \ of \ the \ equation\\(\sqrt{\dfrac{1}{2}w+8})^2=(-2)^2\\\\\dfrac{1}{2}w+8 = 4\\\\Subtract \ 8 \ from \ both \ sides\\\\\dfrac{1}{2}w+8 - 8= 4- 8\\\\\dfrac{1}{2}w= -4\\\\multiply \ both \ sides \ by \ 2\\\\\dfrac{1}{2}w*2= -4*2\\\\w = -8[/tex]

Hence, the extraneous solution that Ernesto obtained is w = -8

Answer:

9hrs 11hrs 19hrs

Step-by-step explanation:

just took the quiz on edge 2020

Answer:

9 hours, 11 hours, 19 hours.

Answer:

The middle of the sailboat is approximately 268.8 feet from the shore.

Step-by-step explanation:

Let the distance from shore to the middle of the boat be represented by x, the angle of elevation of Sandra from the shore to the top of the boat mast  is 7°. Applying the required trigonometric function to this question, we have;

Tan θ = [tex]\frac{opposite}{adjacent}[/tex]

Tan 7° = [tex]\frac{23}{x}[/tex]

⇒  x = [tex]\frac{23}{Tan 7^{0} }[/tex]

       = [tex]\frac{23}{0.12279}[/tex]

      = 268.7515

∴ x = 268.8 feet

The middle of the sailboat is approximately 268.8 feet from the shore.

Answer:

Cody should run approximately 19.978 meters along the shore before jumping into the water in order to save the child.Thus,

Step-by-step explanation:

Consider the diagram below.

In this case we need to minimize the time it takes Cody to save the child.

Total time to save the child (T) = Time taken along the shore (A) + Time taken from the shore (B)

The formula to compute time is:

[tex]time=\frac{distance}{speed}[/tex]

Compute the time taken along the shore as follows:

[tex]A=\frac{x}{4}[/tex]

Compute the time taken from the shore as follows:

[tex]B=\frac{\sqrt{70^{2}+(40-x)^{2}}}{1.1}[/tex]

Then the total time taken to save the child is:

[tex]T=\frac{x}{4}+\frac{\sqrt{70^{2}+(40-x)^{2}}}{1.1}[/tex]

Differentiate T with respect to x as follows:

[tex]\frac{dT}{dx}=\frac{d}{dx}[\frac{x}{4}]+\frac{d}{dx}[\frac{\sqrt{70^{2}+(40-x)^{2}}}{1.1}][/tex]

    [tex]=\frac{1}{4}-\frac{1}{1.1}\cdot \frac{(40-x)}{\sqrt{70^{2}+(40-x)^{2}}}[/tex]

Equate the derivative to 0 to compute the value of x as follows:

                              [tex]\frac{dT}{dx}=0[/tex]

[tex]\frac{1}{4}-\frac{1}{1.1}\cdot \frac{(40-x)}{\sqrt{70^{2}+(40-x)^{2}}}=0\\\\\frac{1}{1.1}\cdot \frac{(40-x)}{\sqrt{70^{2}+(40-x)^{2}}}=\frac{1}{4}\\\\4\cdot (40-x)=1.1\cdot [\sqrt{70^{2}+(40-x)^{2}}]\\\\\{4\cdot (40-x)\}^{2}=\{1.1\cdot [\sqrt{70^{2}+(40-x)^{2}}]\}^{2}\\\\16\cdot (40-x)^{2}=1.21\cdot [70^{2}+(40-x)^{2}}]\\\\16\cdot (40-x)^{2}-1.21\cdot (40-x)^{2}=5929\\\\14.79\cdot (40-x)^{2}=5929\\\\(40-x)^{2}=400.88\\\\40-x\approx 20.022\\\\x\approx 40-20.022\\\\x\approx 19.978[/tex]

Thus, Cody should run approximately 19.978 meters along the shore before jumping into the water in order to save the child.

Answer:

x=8

Step-by-step explanation:

4:3=x:6

Multiply the first set by 2

4*2 : 3*2

8:6

That means x =8

Answer:

x= 4                x = -5

Step-by-step explanation:

3(x – 4)(x + 5) = 0

Using the zero product property

(x – 4)=0      (x + 5) = 0

x= 4                x = -5

What are the solutions to the equation 3(x – 4)(x + 5) = 0?

x = –4 or x = 5

x = 3, x = 4, or x = –5

x = 3, x = –4, or x = 5

x = 4 or x = –5

Answer:

D. x = 4 or x = –5

Step-by-step explanation:

Answer:

  $514.91

Step-by-step explanation:

You want to save a total of ...

  5 × $1235.78

You want to do this over a 12-month period. So, you want to save 1/12 of this total each month. The amount you're saving each month is ...

  5(1235.78)/12 = 514.908333... ≈ 514.91

You must save $514.91 each month to reach the goal.

Answer: $514.91

Step-by-step explanation:

($1,235.78)(5 months)=$6,178.90

6,178.90/12 months=$514.91

(just for clarity: the other person is right, just wanted to show a simpler way to achieve the answer. gl :)

Answer:

multiply length time width  

The vertical line test helps us see that we have a function. Note how it is not possible to draw a single straight line through more than one point on the curve. Any x input leads to exactly one y output. This graph passes the vertical line test. Therefore it is a function.

The function is not one-to-one because the graph fails the horizontal line test. Here it is possible to draw a single straight horizontal line through more than one point on the curve. The horizontal line through y = 2 is one example of many where the graph fails the horizontal line test, meaning the function is not one-to-one.

The term "one-to-one" means that each y value only pairs up with one x value. Here we have something like y = 2 pair up with multiple x values at the same time. This concept is useful when it comes to determining inverse functions.

Answer:

y = [tex]\frac{1}{4}[/tex] x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

y - 4 = [tex]\frac{1}{4}[/tex] (x - 8) ← distribute

y - 4 = [tex]\frac{1}4}[/tex] x - 2 ( add 4 to both sides )

y = [tex]\frac{1}{4}[/tex] x + 2 ← in slope- intercept form

Answer:

The measure of central tendency, mean and median are approximately equal for the boys indicating that the data of the boys is more evenly spread while standard deviation of the girls data is less than those of the boys indicating that the data for the girls is less widely spread.

Step-by-step explanation:

The given data are;

,             1       2       3      4     5      6       7    8      9      10

Girls,    50    32     15    56   81    50     18    81    22    55

Boys,   75     41     25    22    7     0      43    12    45    70

Sorting the data gives;

Girls,     15,   18,     22,   32,  50,   50,   55,  56,    81,  81

Boys,     0,     7,     12,     22, 25,    41,    43, 45,     70, 75

For the even numbered sample data size, the first quartile, Q₁ is found by sharing the data into two and finding the median of the left half which  gives;

10/2 = 5 on each half

The first quartile, Q₁, is the median of the left 5 data points which is the 3rd data point = 22 for girls and 12 for boys

The third quartile, Q₃, is found in similar method to be the 8th data point which is 56 for girls and 45 for boys

The median = 50 for girls and 33 for boys

Therefore, the interquartile ranges are;

IQR = 56 - 22 = 34 for girls, 45 - 12 = 33 for boys

We check for outliers.

Q₁ - 1.5×IQR = 22 - 1.5*34 = -29

Q₃ + 1.5×IQR = 56 + 1.5*34 = 107

We check the mean of both data samples as follows;

Average for the girls = 46

Average for the boys = 34

Standard deviation for girls = 23.99

Standard deviation for girls = 25.43

Therefore, the measure of central tendency is more accurate for the boys indicating that the data of the boys is more evenly spread while the data for the girls is less widely spread.

Answer:

[tex]a=-\frac{b}{2x}[/tex]

Step-by-step explanation:

The equation of a quadratic function is given as:

ax² + bx + c = 0

where a, b and c are the coefficient in the quadratic equation.

The axis of symmetry of the quadratic equation is given as:

[tex]x=-\frac{b}{2a}[/tex]

To get the equation for a, we have to make a the subject of formula:

[tex]x=-\frac{b}{2a}\\\\multiply\ both\ sides\ by \ 2a:\\\\x*2a=-\frac{b}{2a}*2a\\\\2ax=-b\\\\Divide\ through\ by\ 2a\\\\2ax/2a=-b/2a\\\\a=-\frac{b}{2x}[/tex]

The value of a when solved from x = -b/2a is;

a = -b/2x

We are given the formula for axis of symmetry of a quadratic equation to be;

x = -b/2a

Where;

a and b are coefficients in the quadratic equation

x represents the values along a vertical line on the coordinate plane.

Now, we want to solve for a which means we make it the subject of the equation;

Using multiplication property of equality, we multiply both sides by 2a to get;

2ax = -b

We now use division property of equality by dividing both sides by 2x to get;

a = -b/2x

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Answer:

-12°C

Step-by-step explanation:

6AM = 2°C

8AM= -2°C

10AM= -6°C

12AM= -8°C

2PM= -12°C

the temperature in degrees Celsius at 2:00 pm would be -14°C.

To find the temperature in degrees Celsius at 2:00 pm, we need to determine the number of hours that have passed from 6:00 am to 2:00 pm, and then calculate the temperature decrease accordingly.

From 6:00 am to 2:00 pm, a total of 8 hours have passed (6 hours from 6:00 am to 12:00 pm, and 2 hours from 12:00 pm to 2:00 pm).

Given that the temperature drops 2 degrees Celsius each hour, we can multiply the number of hours (8) by the rate of temperature decrease (2 degrees/hour):

Temperature decrease = 8 hours × 2 degrees/hour = 16 degrees

Starting with a temperature of 2°C at 6:00 am, if the temperature drops 16 degrees Celsius over 8 hours, we can subtract 16 from the initial temperature:

Temperature at 2:00 pm = 2°C - 16°C = -14°C

Therefore, the temperature in degrees Celsius at 2:00 pm would be -14°C.

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Answer:

first number after the decimal point

Step-by-step explanation:

after the decimal point is the tenths, hundredths, and thousandths place.

0.1 - tenths

0.09 - hundredths

0.006 - thousandths

Answer:

10

Step-by-step explanation:

How you find LCD (lowest common denominator) is that you have to look at the denominator (the bottom number) and try to find the lowest multiple between both of the numbers that is on the bottom (in this case it is 2 and 5). Sometimes you have to multiply both denominators together to get a LCD.

Example of multiplying two denominators together to get an LCD:

1/3 and 1/13 LCD is 39 because you multiply 3 and 13.

1/5 and 1/4 LCD is 20 because you multiply 5 and 4.

Answer:

Daily pay= $18

5 days pay = $90

Step-by-step explanation:

Archer's daily pay =p

Pay for 5 days= 5p

Gas = 1/2 of 5p

= 1/2 × 5p

= 5p/2

Water = $5

Balance = $40

5p = 5/2p + 5 + 40

5p - 5/2p = 45

10p -5p /2 = 45

5/2p = 45

p= 45÷ 5/2

= 45 × 2/5

= 90/5

P= $18

5p= 5 × $18

=$90

The equation to determine Archer's daily pay is

5p = 5/2p + 5 + 40

Divide both sides by 5

p = 5/2p + 45 ÷ 5

= (5/2p + 45) / 5

p= (5/2p + 45) / 5

Answer:

Step-by-step explanation:

we use cosine formula

2×15×10×cos(180-66)=15²+10²-AC²

-300 cos 66=225+100-AC²

AC²=325+300 cos 66

[tex]AC=\sqrt{325+300 cos 66} \approx 21.14 ~m/s[/tex]

The distance from A to C is 21.14. The correct option is A.

Trigonometry is the branch of mathematics which set up a relationship between the sides and angles of right-angle triangles.

Velocity is defined as the ratio of the distance moved by the object at a particular time. The velocity is a vector quantity so it needs both the magnitude and the direction.

Given that the velocity of a train relative to the ground is represented by the distance from A to B in the diagram. The velocity of a ball thrown inside the train at an angle of 66° relative to the train is represented by the distance from B to C.

The distance A to C will be calculated as,

2×15×10×cos(180-66)=15²+10²-AC²

-300 cos 66=225+100-AC²

AC=√(325+300 cos 66)

AC = 21.17 m/s

Therefore, the distance from A to C is 21.14. The correct option is A.

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Greetings from Brasil...

It is said that polygons are similar, so we can use the expression of similarity.

BIG/small = BIG/small

35/14 = 25/X

X = 10

But the scale factor is questioned. Just use one of the expressions. We conclude that the largest is 2.5 times the value of the smallest

35/14 OR 40/16 OR 25/10

-----------------------------------------------------------

BIG/small = BIG/small

25/5 = 40/Y

Y = 8

25/5 OR 25/5 OR 40/8

times the value of the smallest

Answer:

The y-values repeat in various functions (for example: quadratic function: y=x²; y=4 for x=2 and for x=-2)  

Answer:

500,000 pages

Step-by-step explanation:

1 / 5000 = 100 / x

x = 5000(100)

x = 500,000

Answer:

1892705 pages of text.

Step-by-step explanation:

g=Gallon

L=Liters

P=Pages

1L=5000p

1g=3.78541L

100g·3.78541L=378.541L

378.541L·5000=1892705

Answer:

93km/hr

Step-by-step explanation:

Using the formula Speed = Distance/Time. From the formula we can substitute for time as shown;

Time = Distance/Speed

Let the distance and speed  travelled by Mia be Dm ans Ds respectively

Distance travelled by Kirk be Km and and Ks respective.

Time taken be Mia to travel Tm = Dm/Sm

Time taken be Kirk to travel Tk = Dk/Sk

Since it takes the same length of time for both of them to travel, then Tm = Tk. Hence Dm/Sm = Dk/Sk

Given parameters

Dm = 558 kilometers

Dk = 522 kilometres

If Mia’s average driving speed is 6 kilometers per hour faster than Kirk’s, then Mia's driving speed Sm = 6 + Sk

Required

Mia’s average speed (Sm)

Since Dm/Sm = Dk/Sk

Substituting the given values to get Sk first we have;

558/6+Sk = 522/Sk

Cross multiply

558Sk = 522(6+Sk)

open the parenthesis

558Sk = 3132 + 522SK

558Sk-522Sk = 3312

36Sk =3132

Sk = 3132/36

Sk =87km/hr

SInce Sm = 6+Sk

Sm = 6+87

Sm = 93km/hr

Hence Mia's average speed is 93km/hr

Answer:21

Step-by-step explanation:

50-32.5=17.5

17.5/0.8=21.875

Answer:

The answer is 5

Step-by-step explanation:

divide 10 by two and get 5

Answer:

[tex]x = 5[/tex]

Step-by-step explanation:

We have the equation [tex]2x = 10[/tex], we can try and isolate x by dividing both sides by 2.

[tex]2x \div 2 = 10\div2\\x = 5[/tex]

Hope this helped!

Answer:

510 cm²

Step-by-step explanation:

To find how much construction paper is needed for the model, we calculate the total areas of each of its sides.

The area of the first triangular sides is A₁ = 15 cm × 5 cm = 75 cm²

The area of the second triangular sides is A₂ = 15 cm × 13 cm = 195 cm²

The area of the third triangular sides is A₃ = 15 cm × 12 cm = 180 cm²

The area of each triangular side is A₄ = 1/2 × 5 cm × 12 cm = 30 cm²

The area of the two triangular sides is A₅ = 2A₄ = 2 × 30 cm² = 60 cm²

The total surface area of a wedge of cheese is A = A₁ + A₂ + A₃ + A₅ = 75 cm² + 195 cm² + 180 cm² + 60 cm² = 510 cm²

So the amount of construction paper needed equals the total surface area of the wedge of cheese = 510 cm²

Answer:

510

Step-by-step explanation: