What is the 100th term of the sequence with a1=222 and d=-5

Answers

Answer 1

Answer:

--273

Step-by-step explanation:

100th term is equal a1 + 99d so

100th term = 222 + (-5×99) = -273


Related Questions

6x-27=-3x

solve for x:D

Answers

Answer:

6×-27=-3×

+3×

9/9×=27/9

×=3


A rope is 9 1/2 meters long. How many pieces can be cut from the rope if
each piece is to be 1/4 meter?

Answers

A rope is 9 1/2 m long because 1/4 m that is your answer because I need points

Solve 2x + 6 > 20. OLA X> 18 B. X>7 O c. x


someone help por favor​

Answers

your answer would be x>7 or B :)

Answer:

2x+6>20

2x>20-6

2x/2>14/2

x>7

So your answer would be B

Nala and lily are playing a dice game where they score points. After one round, the ratio of nala point to lily's point is 7 to 9. If nala has 14 more points than lily, determine how many points lily has.

Answers

Answer:

Lily has 63 points and Nala has 49.

Step-by-step explanation:

Since Nala and Lily are playing a dice game where they score points, and after one round, the ratio of Nala's points to Lily's points is 7 to 9, if Nala has 14 more points than Lily, to determine how many points Lily has se you must perform the following calculation:

9 - 7 = 2

14/2 = 7

7 x 7 = 49

7 x 9 = 63

63 - 49 = 14

Therefore, Lily has 63 points and Nala has 49.

44
Match each ratio with its simplest form.
12:15
20:36
18:24

Pls answer ASAP I need to finish this today and I’m stuck

Answers

12 : 15 = 4 : 5

20 : 36 = 5 : 9

18 : 24 = 3 : 4

Can someone help me with this? i’m struggling urgent help please!!!!

Answers

Answer:

Similar by SAS

Step-by-step explanation:

If you multiply the two given sides by 3/2 you will get the sides for the large triangle

3/2  * 10 = 30 / 2 = 15

3/2 * 24 = 72 / 2 = 36

Therefore they are similar by SAS postulate for similarity. Notice that the right angle is between the legs of the triangle. That is the main qualification that allows you to use SAS for similarity.

Find the other two angles of both the triangles, if they were similar then the triangles are similar

279 students went on a field trip. Five buses were filled and 9 students traveled in cars. How many students were in each bus? PLEASEEEEE HELPPPPP ME you get 60 points i dont know if anyone cares but hey

Answers

Answer:

90 students.

Step-by-step explanation:

279-9=270, and 270 divided by 9 is 90.

y = x2
-2
What is the Domain:

Answers

Answer:

all real numbers

Step-by-step explanation:

The domain is the values that x can take

x can be any real number

Dan, Harry and Regan sell cars.
Dan sells x cars.
Harry sells 5 more cars than Dan.
Regan sells twice as many cars as Dan.
Write an expression, in terms of x, for the mean number of cars Dan, Harry and Regan sell.

Answers

Answer:

4X+5

Step-by-step explanation:

Dan : X

Harry: X+5

Regan: 2X

X+X+5+2X

Answer:

[tex]Mean = \frac{4x + 5}{3}[/tex]

Step-by-step explanation:

Given:

Dan sold = x

Harry sold 5 more than Dan, that is = x + 5

Regan sold twice as Dan = 2x

[tex]Mean = \frac{ Total \ cars \ sold}{number\ of \ them \ sold \ it }\\\\Mean = \frac{x + ( x+ 5) +2x }{3} = \frac{4x + 5}{3}[/tex]

What’s 1/2 + 1/3? Y’all please help me . And when or if you can give me the answer can you do step-by-step on how you did that so I can do it myself next time?

Answers

Hi! 1/2 + 1/3 is 5/6.

2 + 3 = 5
2 X 3 = 6

= 5/6

I hope this helped if I can help in anyway I would be happy to help you. Goodluck :)

[tex]\longrightarrow{\green{\frac{5}{6}}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex] \frac{1}{2} + \frac{1}{3} [/tex]

Since the denominators are unequal, we find the L.C.M (lowest common multiple) for both denominators.

The L. C. M for 2 and 3 is 6.

Now, multiply the L.C.M. with both numerator & denominator.

[tex] = \frac{1 \times 3}{2 \times 3} + \frac{1 \times 2}{3 \times 2} [/tex]

[tex]= \frac{3}{6} + \frac{2}{6} [/tex]

Now that the denominators are equal, we can add them.

[tex]= \frac{3 + 2}{6} \\ \\ = \frac{5}{6} [/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}[/tex]

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