Answer:
The objective of a protection scheme is to keep the power system stable by isolating only the components that are under fault, whilst leaving as much of the network as possible still in operation.
Explanation:
The devices that are used to protect the power systems from faults are called protection devices.
A gas tank is known to have a thickness of 0.5 inches and an internal pressure of 2.2 ksi. Assuming that the maximum allowable shear stress in the tank wall is 12 ksi, determine the necessary outer diameter for the tank. Assume that the tank is made of a cold drawn steel whose elastic modulus is 35000 ksi and whose Poisson ratio is 0.292. If y
Answer:
[tex]D_o=11.9inch[/tex]
Explanation:
From the question we are told that:
Thickness [tex]T=0.5[/tex]
Internal Pressure[tex]P=2.2Ksi[/tex]
Shear stress [tex]\sigma=12ksi[/tex]
Elastic modulus [tex]\gamma= 35000[/tex]
Generally the equation for shear stress is mathematically given by
[tex]\sigma=\frac{P*r_1}{2*t}[/tex]
Where
r_i=internal Radius
Therefore
[tex]12=\frac{2.2*r_1}{2*0.5}[/tex]
[tex]r_i=5.45[/tex]
Generally
[tex]r_o=r_1+t[/tex]
[tex]r_o=5.45+0.5[/tex]
[tex]r_o=5.95[/tex]
Generally the equation for outer diameter is mathematically given by
[tex]D_o=2r_o[/tex]
[tex]D_o=11.9inch[/tex]
Therefore
Assuming that the thin cylinder is subjected to integral Pressure
Outer Diameter is
[tex]D_o=11.9inch[/tex]
IAMURLORDANDSAVIORILiKENUGEETSHELLOLOL
Answer:
lol Jebus?
Explanation:
Answer:
addsa
sdadsa
Explanation:
dsads
Given : x² + 200x = 166400 The current park is a square, and the addition will increase the width by 200 meters to give the expanded park a total area of 166,400 square meters To Find : the side length of the current square park. Solution: x² + 200x = 166400 => x(x + 200) = 166400 166400 = 320 * 520 => (320)(320 + 200) = 166400 => x = 320 side length of the current square park. = 320 m Learn More: Which expression is a possible leading term for the polynomial ... brainly.In/question/13233517
Answer:
320 m
Explanation:
To find the side length of the current park, x, we solve the quadratic equation for the area of the park
x² + 200x = 166400
x² + 200x - 166400 = 0
We multiply -166400 by x² to get -166400x². We now find the factors of 166400x² that will add up to 200x. These factors are -320x and 520x
So, we re-write the expression as
x² + 200x - 166400 = 0
x² + 520x - 320x - 166400 = 0
We write out the factors of the expression,
x² + 520x - 320x - 320 × 520 = 0
Factorizing the expression, we have
x(x + 520) - 320(x + 520) = 0
(x + 520)(x - 320) = 0
x + 520 = 0 or x - 320 = 0
x = -520 or x = 320
Since x is not negative, we take the positive answer.
So, x = 320 m
Two engineers are to solve an actual heat transfer problem in a manufacturing facility. Engineer A makes the necessary simplifying assumptions and solves the problem analytically, while engineer B solves it numerically using a powerful software package. Engineer A claims he solved the problem exactly and, thus, his results are better, while engineer B claims that he used a more realistic model and, thus, his results are better. Will the experiments prove engineer B right
Answer:
Engineer A results will be more accurate
Explanation:
Analytical method is better than numerical method. Engineer A has used analytical method and therefore his results will be more accurate because he used simplified method. Engineer B has used software to solve the problem related to heat transfer his results will be approximate.
Doubling the diameter of a solid, cylindrical wire doubles its strength in tension.
True
False
Answer:
True ❤️
-Solid by solid can make Cylindrical wire doubles Strengths in tension
a video inspection snake is use
Answer:
very good thx
Explanation:
What are the assumptions made for air standard cycle analysis?
a.The working medium is prefect gas throughout i.e. it follows PV=mRT
b.The working medium does not undergo any chemical change throughout the cycle
c.The compression and expansion processes are reversible adiabatic i.e. there is no loss or gain in entropy.
d.All of above
Transients (surges) on a line can cause spikes or surges of energy that can damage delicate electronic components. A SPD device contains one or more ________________ than bypass and absorb the energy of the transient.
Answer:
I think ( MOV Metal oxide varistors )
Transients (surges) on a line can cause spikes or surges of energy that can damage delicate electronic components. A SPD device contains one or more MOV Metal oxide varistors than bypass and absorb the energy of the transient.
A shunt regulator utilizing a zener diode with an incremental resistance of 8 ohm is fed through an 82-Ohm resistor. If the raw supply changes by 1.0 V, what is the correspondig change in the regulated outut voltage?
Answer:
[tex]\triangle V_0=0.08V[/tex]
Explanation:
From the question we are told that:
Incremental resistance [tex]R=8ohms[/tex]
Resistor Feed [tex]R_f=82ohms[/tex]
Supply Change [tex]\triangle V=1[/tex]
Generally the equation for voltage rate of change is mathematically given by
[tex]\frac{dV_0}{dV}=\frca{R}{R_1r_3}[/tex]
Therefore
[tex]\triangle V_0=\triangle V*\frac{R}{R_fR}[/tex]
[tex]\triangle V_0=1*\frac{8}{8*82}[/tex]
[tex]\triangle V_0=0.08V[/tex]
The cars of a roller-coaster ride have a speed of 19.0 km/h as they pass over the top of the circular track. Neglect any friction and calculate their speed v when they reach the horizontal bottom position. At the top position, the radius of the circular path of their mass centers is 21 m, and all six cars have the same mass. What is v?
Complete Question
The cars of a roller-coaster ride have a speed of 19.0 km/h as they pass over the top of the circular track. Neglect any friction and calculate their speed v when they reach the horizontal bottom position. At the top position, the radius of the circular path of their mass centers is 21 m, and all six cars have the same mass.V = -18 m What is v?X km/h
Answer:
[tex]v=23.6m/s[/tex]
Explanation:
Velocity [tex]v_c=18.0km/h[/tex]
Radius [tex]r=21m[/tex]
initial velocity u[tex]u=19=>5.27778[/tex]
Generally the equation for Angle is mathematically given by
[tex]\theta=\frac{v_c}{2r}[/tex]
[tex]\theta=\frac{18}{2*21}[/tex]
[tex]\theta=0.45[/tex]
[tex]\theta=25.7831 \textdegree[/tex]
Generally
Height of mass
[tex]h=\frac{rsin\theta}{\theta}[/tex]
[tex]h=\frac{21sin25.78}{0.45}[/tex]
[tex]h=20.3m[/tex]
Generally the equation for Work Energy is mathematically given by
[tex]0.5mv_0^2+mgh=0.5mv^2[/tex]
Therefore
[tex]v=\sqrt{u^2+2gh}[/tex]
[tex]v=\sqrt{=5.27778^2+2*9.81*20.3}[/tex]
[tex]v=23.6m/s[/tex]
The maximum tensile force a solid, cylindrical wire can withstand increases as the thickness of the wire increases.
True
False
Tech A says that proper footwear may include both leather and steel-toed shoes. Tech B says that when working in the shop, you only need to wear safety glasses if you are doing something dangerous. Who is correct?
Answer:
Tech A is correct.
Explanation:
If a person is doing something dangerous in a shop, he should wear safety glasses to protect his eyes from danger and also wear leather shoes to protect himself from any electric shock. Leather boots will disconnect a person with direct earth and therefore he can save himself if he gets a electric shock.
USING THE ONTARIO BUILDING CODE TO SOLVE THESE QUESTIONS ARCH1013
Architectural Engineering
1. Calculate the minimum width and thickness of footings required to support walls of Cassidy House Elevation B. (1.5/4).
a)Footing width and thickness of exterior walls, if the floor joists span less than 4.9 m:
Cassidy is a Two-storey house, minimum thickness of footing (Table 9.15.3.4.)=
Two storeys of Brick veneer (9.15.3.5.) =
Adjusted Footing width for Cassidy House =
Thickness (9.15.3.8.)=
b)Assume that the house has a load bearing masonry interior wall that is 150mm thick supporting both first and second storey. Determine the minimum width and thickness required of its footing:
Min. thickness of footing for an interior wall that supports two floors (Table 9.15.3.4) =
Adjust for two storey of masonry wall (9.15.3.6.) =
Thickness =
2. Answer the following questions based on foundations details of Cassidy Elevation B. (1.5/4).
a)What is the maximum height of finished ground the foundation wall can support, if it is 2.5m high?
Table 9.15.4.2.A, Construction Notes
b) If you were to build this wall with 190mm thick ICF, what is the minimum vertical reinforcement required, using the height of foundation wall and ground found in earlier questions?
Table 9.15.4.B.
c) If you were to build this wall with unreinforced concrete blocks, what is the minimum thickness of the foundation wall?
Table 9.15.4.2.A.
3. Calculate the footing width of an external wall of a three storey wood frame brick veneered house. Assume it supports joists spanning 11.5m on first and second floors and 10m on third floor. (1/4)
9.15.2.4.B: use the formula;
W = w (εsjs/ storeys x 4.9)
If anyone has any Idea on how to do this or has any Architectural background please explain to me!
Elevation B: Page 13
Answer:
I cannot open the pdf file . There is some probem .So I dont know the answer
A pinion and gear pair is used to transmit a power of 5000 W. The teeth numbers of pinion
and gear are 20 and 50. The module is 5 mm, the pressure angle is 20o
and the face width is 45 mm. The
rotational speed of pinion is 300 rev/min. Both the pinion and the gear material are Nitralloy 135 Grade2 with a hardness of 277 Brinell. The quality standard number Qv is 5 and installation is open gearing
quality. Find the AGMA bending and contact stresses and the corresponding factors of safety for a
pinion life of 109
cycles and a reliability of 0.98
Answer:
mark me as a brainleast
Explanation:
209781
In heavy traffic areas you should wave pedestrians across the street if there is no crosswalk
In heavy traffic areas, you should wave pedestrians across the street if there is no crosswalk: False.
What is a crosswalk?A crosswalk can be defined as the marked or specially paved part of a road that is characterized by heavy traffic, so as to enable pedestrians have right of way to cross the street because drivers are required by traffic law to stop for them.
However, a driver or other road users in heavy traffic areas shouldn't wave pedestrians across the street if there is no crosswalk
Read more on traffic laws here: https://brainly.com/question/22768531
Elliptic curve cryptography is considered as the latest and probably the one with a future. Having seen RSA in earlier modules, in which ways do YOU think elliptic cryptography is more advanced than RSA. You may read other material or get this information from the internet to answer this question. But make sure to provide necessary references when you do cite others.
Answer:
The answer is below.
Explanation:
Some of the ways, how I think elliptic cryptography is more advanced than RSA are the following:
1. ECC - Elliptic Curve Cryptography uses smaller keys for the same level of security, particularly at greater levels of security.
2. ECC can work well and at a faster rate on a small-capacity device compared to RSA
3. It uses offer speedier SSL handshakes that enhance security
4. It offers fast signatures
5. It allows signatures to be computed in two stages, which enables lower latency than inverse throughput.
6. Relatively quick encryption and decryption
A bullet weighing 0.08 lb is fired with a horizontal velocity of 1800 ft/s into the lower end of a slender 23-lb bar of length L = 30 in. Knowing that h = 12 in. and that the bar is initially at rest. Determine the angular velocity of the bar immediately after the bullet becomes embedded.
Answer: hello attached below is the missing image the slender weight is different from what is in the question here so I worked with 23-Ib as requested in the question
answer
≈ 12.17 Rad/sec
Explanation:
weight of bullet ( Wb ) = 0.08 Ib
horizontal velocity = 1800 ft/s
Slender(Wr) = 23-Ib bar with
length ( L ) = 30
h = 12 inches
Vro = 0
Calculate the angular velocity of the bar immediately after the bullet becomes embedded
attached below is a detailed solution
6.708 = ( 0.05011 + 0.5011 ) w'
w' = 6.708 / 0.55121 ≈ 12.17 Rad/sec
If a cylindrical part with a length of 20 mm and a diameter of 20 mm is to be machined to a cylindrical part with 18 mm in diameter with the same length. The machine has a mechanical efficiency of 50% and a power of 80 kW. If the cutting rake angle is 0 degrees and the cutting tool is made of uncoated carbides and the cutting speed is 10 m/s. What material can we choose for the cylinder
Answer:
Titanium Alloy
Explanation:
Length ( L ) = 20 mm
D1 = 20 mm
d2 = 18 mm
l = 20 mm
Mechanical efficiency = 50%
power = 80 kW
cutting rake angle = 0°
cutting speed ( v ) = 10 m/s
Determine the material to be for the cylinder
In order to choose a material for the cylinder we have to calculate the cutting force
P = Fc * V
80 = Fc * 10 m/s
therefore Fc = 80 / 10 = 8 N
Hence the material we can use is Titanium Alloy due to low cutting force value
An ideal gas within a piston-cylinder assembly undergoes a Carnot refrigeration cycle. The isothermal compression occurs at 325 K from 2 bar to 4 bar. The isothermal expansion occurs at 250 K. Determine:
a. the coefficient of performance
b. the heat transfer to the gas during the isothermal expansion, in kj per kmol of gas
c. the magintude of the net work input, in kj per kmol of gas.
Answer:
a) [tex]\mu=3.3[/tex]
b) [tex]Q=1440.7KJ/Kmol[/tex]
c) [tex]W=1872.9KJ/Kmol[/tex]
Explanation:
From the question we are told that:
Initial Temperature [tex]T_1=325k[/tex]
initial Pressure [tex]P_1=2 bar[/tex]
Final Pressure [tex]P_2=4 bar[/tex]
iso-thermal expansion [tex]T_2=250k[/tex]
a)
Generally the equation for Coefficient of performance is mathematically given by
[tex]\mu=\frac{T_2}{T_1-T_2}[/tex]
[tex]\mu=\frac{250}{325-250}[/tex]
[tex]\mu=3.3[/tex]
b)
Generally the equation for Heat Expansion is mathematically given by
[tex]Q=RT_2 In(\frac{P_2}{P_1})[/tex]
Where
R=Gas constant
[tex]R=8.314462618[/tex]
Therefore
[tex]Q=8.314462618*250 In(\frac{4}{2})[/tex]
[tex]Q=1440.7KJ/Kmol[/tex]
c)
Generally the equation for work input is mathematically given by
[tex]W=RT_1 In(\frac{P_2}{P_1})[/tex]
[tex]W=8.314462618*250 In(\frac{4}{2})[/tex]
[tex]W=1872.9KJ/Kmol[/tex]
The coefficient of performance is 3.33, the heat transfer in the isothermal expansion is 1440.71kJ/K.mol and the work input is calculated as 1872.92kJ/K.mol
Given Data:
T1 = 325KP1 = 2 barP2 = 4 barT2 = 250KIsothermal expansion occurs at 250K.
a) The coefficient of performanceThis is calculated as
COP =[tex]\frac{T_2}{T_1-T_2}=\frac{250}{325-250} =3.33[/tex]
b) Heat Transfer in isothermal expansion[tex]Q = RT_2In(\frac{p_2}{p_1})[/tex]
Therefore; In isothermal process du = 0
R = 8.314 AkJ/K.mol
Q = 8.314 * 250 In(4/2)
Q = 1440.71kJ/K.mol
c) Work InputW[tex]_i_n[/tex]=[tex]RT_1In(\frac{p_2}{p_1})\\W_i_n=8.314*325In(4/2)\\W_i_n=1872.92kJ/K.mol[/tex]
The work input is 1872.92kJ/K.mol
Learn more on Carnot cycle here:
https://brainly.com/question/14983940
https://brainly.com/question/13170743
La iluminación de la superficie de un patio amplio es 1600 lx cuando el ángulo de elevación del sol 53°. Calcular la iluminación cuando el ángulo de elevación del Sol sea 37°
Answer:
I = 1205.69 Lx
Explanation:
The irradiation or intensity of the solar radiation on the earth is maximum for the vertical fire, with a value I₀
I = I₀ sin θ
in this case with the initial data we can calculate the initial irradiance
I₀ = [tex]\frac{I}{sin \ \theta }[/tex]
I₀ = 1600 /sin 53
I₀ = 2003.42 lx
for when the angle is θ = 37º
I = 2003.42 sin 37
I = 1205.69 Lx
Generally, the primary source of all water supply is said to be
A symmetric biplane having forward / aft wedge angles 2° is placed in supersonic
flow as shown below.
Estimate the lift and drag of this configuration by using the idea of method of
characteristics. (Recall v±0=const on different direction i.e left or right running waves)
%3D
The wave pattern on the biplane is shown in dashed lines.
(v,0)»=(28,0)
Answer:
you are good thx dedo please ❤️
Explanation:
please give me thx pls pls pls
If an elevator repairer observes that cables begin to fray after 15 years, what process might he or she use to create a maintenance schedule for their replacement? fallacious reasoning reductive reasoning inductive reasoning deductive reasoning
Answer:
inductive reasoning
Explanation:
Inductive reasoning is one of the type of reasoning method in which generalized consequences are derived from limited observations. By observing few data, general conclusions are drawn. The conclusions drawn are false in inductive reasoning. In the given situation, the conclusion drawn by the elevator repairer has been drawn by inductive reasoning. His observation of some cables led him to draw the conclusion about all the cables. The result of the reasoning is false.
Wave flow of an incompressible fluid into a solid surface follows a sinusoidal pattern. Flow is two-dimensional with the x-axis normal to the surface and y axis along the wall. The x component of the flow follows the pattern
u = Ax sin (2πt/T)
Determine the y-component of flow (v) and the convective and local components of the acceleration vector.
Answer:
sorry , for my point
Explanation:
Explain ROLAP, and list the reasons you would recommend its use in the relational database environment.
Answer:
ROLAP is a branch of OLAP that is used to contain Relational database ( RDB ). which is a very fast database ( quick process of queries )
Very fast to access and also fast in processing queries provides multidimensional view of data / supports multidimensional database schema with RDBMssupports large databasesExplanation:
ROLAP ( Relational On-line Analytical processing ) is a branch of OLAP that is used to contain Relational database ( RDB ).
Advantages of ROLAP ( reasons for the use of ROLAP )
Very fast to access ( fast in processing queries )provides multidimensional view of data / supports multidimensional database schema with RDBMssupports large databasesA force measuring instrument comes with a certificate of calibration that identifies two instrument errors and assigns each an uncertainty at 95% confidence over its range. Provide an estimate of the instrument design-stage uncertainty.
Resolution: 0.25 N
Range: 0 to 100 N
Linearity error: within 0.20 N over range
Hysteresis error: within 0.30 N over range
Answer:
[tex]U=\pm 0.382N[/tex]
Explanation:
From the question we are told that:
Resolution: 0.25 N
Range: 0 to 100 N
Linearity error: within 0.20 N over range
Hysteresis error: within 0.30 N over range
Generally the equation for Stage Uncertainty is mathematically given by
[tex]U=\sqrt{u_0^2+u_T^2}[/tex]
Where
[tex]u_0=Zero\ order\ uncertainty[/tex]
[tex]u_0=\pm 0.5*0.25[/tex]
[tex]u_0=\pm=0.125[/tex]
And
u_T=Total instrumental Uncertainty
[tex]u_T=\sqrt{l_e^2+h_e^2}[/tex]
Where
l_e=Error of linearity
h_e=Error due to hysteresis
Hence
[tex]u_T=\sqrt{0.20^2+0.30^2}[/tex]
[tex]u_T=\pm 0.36[/tex]
Therefore
[tex]U=\sqrt{(0.125)^2+0.36^2}[/tex]
[tex]U=\pm 0.382N[/tex]
A investor will invest in mutual fundwith a probability of 0.6, will invest in government fundwith a probability of 0.3, and will invest in both fundswith a probability of 0.15. Find the probability that the investor will invest in either mutual fundor government fund.
Answer:
0.75
Explanation:
From this question above we have the following information
A = probability of investment in mutual fund= 0.6
B = probability of investment in government fund = 0.3
C = probability of investing in both the mutual fund and the government= 0.15
Where to find the probability of this investor investing in either of these two
= Prob(a) + prob(b) - prob(c)
= 0.6 + 0.3 - 0.15
= 0.9 - 0.15
= 0.75
Block A hangs by a cord from spring balance D and is submerged in a liquid C contained in beaker B. The mass of the beaker is 1.20 kg; the mass of the liquid is 1.85 kg. Balance D reads 3.10 kg and balance E reads 7.50 kg. The volume of block A is 4.15 × 10−3 m3.
a) What is the density of the liquid?
b) What will the balance D read if block A is pulled up out of the liquid?
c) What will the balance E read if block A is pulled up out of the liquid?
Answer:
a) [tex]m_e= 3.05 Kg[/tex]
b) [tex]\rho=1072.3kg/m^3[/tex]
c) [tex]m_e= 3.05 Kg[/tex]
Explanation:
From the question we are told that:
Beaker Mass [tex]m_b=1.20[/tex]
Liquid Mass [tex]m_l=1.85[/tex]
Balance D:
Mass [tex]m_d=3.10[/tex]
Balance E:
Mass [tex]m_e=7.50[/tex]
Volume [tex]v=4.15*10^{-3}m^3[/tex]
a)
Generally the equation for Liquid's density is mathematically given by
[tex]m_e=m_b+m_l+(\rho*v)[/tex]
[tex]\rho=\frac{7.50-(1.2+1.85)}{4.15*10^{-3}}[/tex]
[tex]\rho=1072.3kg/m^3[/tex]
b)
Generally the equation for D's Reading at A pulled is mathematically given by
m_d = mass of block - mass of liquid displaced
[tex]m_d=m- (\rho *v )[/tex]
[tex]m=3.10+ (1072.30 *4.15*10^{-3}m^3 )[/tex]
[tex]m=18.10kg[/tex]
c)
Generally the equation for E's Reading at A pulled is mathematically given by
[tex]m_e=m_b+m_l[/tex]
[tex]m_e = 1.20 + 1.85[/tex]
[tex]m_e= 3.05 Kg[/tex]
9. What is a whip check?
Answer:
¿Cuál es el efecto látigo?
Es un grave desajuste entre la demanda real de un producto y la demanda de los actores intermediarios en la cadena de suministro
Explanation: espero que te yueda
An unconstrained 10mm thick plate of steel 100mm on a side with a 25mm diameter hole in the center is heated from 20 degrees C to 120 degrees C. The linear CTE is 12x10-6/⁰C. What is the final diameter of the hole
Answer:
The correct answer is "25.03 mm".
Explanation:
Given:
Thickness of plate,
= 10 mm
On a side,
= 100 mm
Diameter hole,
= 25 mm
Coefficient of thermal expansion,
CTE = [tex]12\times 10^{-6} /^{\circ} C[/tex]
Now,
⇒ [tex]D_i\times (12\times 10^{-6}) \Delta \theta = \Delta D[/tex]
= [tex]25\times 12\times 10^{-6} \Delta \theta[/tex]
= [tex]3\times 10^{-4} \Delta \theta[/tex]
= [tex]3\times 10^{-2}[/tex]
hence,
The final diameter of hole will be:
[tex]D_f=25.03 \ mm[/tex]
