Answer:
7
Step-by-step explanation:
Concepts:
Division: a system of distributing a collection of things into equal partsFractions: #s that represent a part of a wholeDividing Fractions: dividing a fraction by another fraction = multiplying the fraction by the inverse (reciprocal) of the other oneInverse Operations: operations that are opposite of each other (e.g. inverse of addition is subtraction)Solving:
1. First, let's set up the equation:
7/8 ÷ 1/8
2. We can get the reciprocal of 1/8 by doing the opposite of division; multiplication. 1/8 becomes 1 · 8, and that's equal to 8.
3. Now, since we know dividing a fraction by another one is exactly the same as multiplying the fraction by the reciprocal of the other, let's multiply 7/8 by the inverse of 1/8, which is 8.
7/8 · 8 = 56/8 = 7
Therefore, 7/8 divided by 1/8 is equal to 7.
What is the value of the expression: 4+42 +22
Answer:
84
Step-by-step explanation:
[tex]4^3+4^2+2^2= 64+16+4=84[/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\boxed{\mathsf{4^3 + 4^2 + 2^2}}[/tex]
[tex]\huge\boxed{\mathsf{4^3}}[/tex]
[tex]\huge\boxed{\mathsf{= 4 \times 4 \times 4}}[/tex]
[tex]\huge\boxed{\mathsf{= 16\times 4}}[/tex]
[tex]\huge\boxed{\mathsf{= \bf 64}}[/tex]
[tex]\huge\boxed{\mathsf{4^2}}[/tex]
[tex]\huge\boxed{\mathsf{= 4 \times 4}}[/tex]
[tex]\huge\boxed{\mathsf{= \bf 16}}[/tex]
[tex]\huge\boxed{\mathsf{2^2}}[/tex]
[tex]\huge\boxed{\mathsf{= 2 \times 2}}}[/tex]
[tex]\huge\boxed{\mathsf{= \bf 4}}[/tex]
[tex]\huge\boxed{\mathsf{= 64 + 16 + 4}}[/tex]
[tex]\huge\boxed{\mathsf{= 80 + 4}}[/tex]
[tex]\huge\boxed{\mathsf{= \bf 84}}[/tex]
[tex]\huge\boxed{\mathsf{Answer: 84}}\huge\checkmark[/tex]
[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]
find the radius of a circle for which an arc 6 cm long subtends an angle of 1/3 radians at the center?
plz some one can help to solve the question??
Step-by-step explanation:
Eueydhhdgdgdbdbddbdbhd
Answer:
Hello,
[tex]R=\dfrac{18}{\pi}\ (cm)[/tex]
Step-by-step explanation:
[tex]Formula: \ L=\theta*R\\[/tex]
[tex]R=\dfrac{6}{\dfrac{\pi}{3} } =\dfrac{6*3}{\pi} =\dfrac{18}{\pi}\ (cm)[/tex]
Help please and thank you
Answer:
x = y² - 7
Step-by-step explanation:
the inverse function is simply an exchange of x and y (and then the simplification happens to transform the whole expression back into a form y = ....)
what does the rational form of the ratio a:b look like
Answer:
a/b
Step-by-step explanation:
The rational form of a:b or simply a/b is in the simplest form.
Answer:
Step-by-step explanation:
the answer is option 2 from the above sheet
The price of 5 kg of rice is ₹83.75. How many kilograms of rice can you buy for ₹670?
Answer:
40 kg
Step-by-step explanation:
[tex]\frac{5}{83.75} :\frac{y}{670}[/tex]
y · 83.75 = 5 · 670
83.75y = 3350
83.75y ÷ 83.75 = 3350 ÷ 83.75
y = 40
The amount of rice you can buy for ₹670 is given by the equation
A = 40 kilograms
What is an Equation?
Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the amount of rice for ₹670 be A
Now , the equation will be
The amount for 5 kg of rice = ₹ 83.75
So , the amount for 1 kg of rice = amount for 5 kg of rice / 5
The amount for 1 kg of rice = 83.75 / 5
The amount for 1 kg of rice = ₹ 16.75
So , the amount of rice for ₹ 670 = 670 / amount for 1 kg of rice
The amount of rice for ₹ 670 = 670 / 16.75
The amount of rice for ₹ 670 = 40 kilograms
Therefore , the value of A is 40 kilograms
Hence , the amount of rice is 40 kg
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In this activity, you will create an equation for a function represented by a verbal description.
Vicky charged her phone’s battery to 100 percent. Then she took the phone off the charger. When her phone is off the charger, it loses 5 percent of its battery life every hour. What function models the percentage of battery life left in terms of the number of hours since Vicky took it off the charger?
What is the initial value of the function? Is it positive or negative? Explain your answer.
What is the function’s rate of change? Is it positive or negative? Explain your answer.
Answer:
1) The initial value of the function is the y-value when the x-value is zero. The number of hours is the x-value and the percentage of battery life left is the y-value. When the number of hours, x, is 0, the percentage of remaining battery life, y, is 100 percent. So, the initial value of the function is 100. The initial value is positive because the percentage of remaining battery life cannot be negative.
2) The rate of change is the rate at which the y-value changes with respect to a change in the x-value. When off the charger, the phone loses its battery life at a constant rate of 5 percent per hour. So, the function’s rate of change is -5. The rate of change is negative because the rate indicates that the percentage of remaining battery life decreases as the number of hours increases.
Step-by-step explanation: I just did the tutorial right now i hope this helps
Answer:
part a = The number of hours since Vicky took the phone off the charger is the independent quantity, so the variable x should represent it.
part b = The percentage of battery life left in hours is the dependent quantity, so the variable y should represent it.
part c = The initial value of the function is the y-value when the x-value is zero. The number of hours is the x-value and the percentage of battery life left is the y-value. When the number of hours, x, is 0, the percentage of remaining battery life, y, is 100 percent. So, the initial value of the function is 100. The initial value is positive because the percentage of remaining battery life cannot be negative.
part d = The rate of change is the rate at which the y-value changes with respect to a change in the x-value. When off the charger, the phone loses its battery life at a constant rate of 5 percent per hour. So, the function’s rate of change is -5. The rate of change is negative because the rate indicates that the percentage of remaining battery life decreases as the number of hours increases.
part e = The rate of change of the function, m, is -5, and the initial value of the function, b, is 100. Substitute the values of m and b in the equation y = mx + b. The equation of the function that models the phone’s remaining battery life in terms of the number of hours from the time Vicky took it off the charger is y = -5x + 100.
Step-by-step explanation:
All edmentum answers :)
If the area of a rectangular field is x2 – 3x + 4 units and the width is 2x – 3, then find the length of the rectangular field.
Answer:x²-3 x+4/ 2x-3 units
Step-by-step explanation:
Area = Length * Width sq. units
x^2 - 3x + 4 = Length * 2x - 3
=>Length = x^2- 3 x + 4/ 2 x − 3 units
lvan earned $8 each time he walks his neighbor's dog. he already walked the dog 5 times.
How many more times does her need to walk the dog to earn enough money to buy a game that costs $88
__? more times
What is the constant of proportionality in the equation x 2
—- = ——
Y 9
Answer:
The Constant is 9/2
Which inequality is represented by this graph?
OA. y<-1/5x+1
OB. y>= -1/5x+1
OC. y<= -1/5x+
OD. y>-1/5x+1
Answer:
Option A is correct
Step-by-step explanation:
Hope it is helpful....
One of the legs of a right triangle measures 12 cm and its hypotenuse measures 20
cm. Find the measure of the other leg. If necessary, round to the nearest tenth.
Answer:
cm
Submit Answer
attempt 1 out of 2
PLS HELP
Answer:
16
Step-by-step explanation:
First use the Pythagorean theorem a^2+b^2=c^2.
12^2+b^2=20^2. Solve the exponents: 144+b^2=400. Then, subtract the 144 from 400. That would be 256. Therefore b^2=256. Then you find the square root of 256=16.
Step-by-step explanation:
using pythogoras theory
hyp^2=opp^2+adj^2
you have been given the hyp and the opp so lets make the unknown x
20^2=12^2+x^2
400 =144+x^2
make x the subject of the formula
400-144=x^2
266=x^2
x=the square root of 266
f(x) = 2x + 7 with domain: x = {2, 3, 5, 9}
Answer:
2(2)+7=11
2(3)+7=13
2(4)+7=15
2(5)+7=17
2(9)+7=25
Step-by-step explanation:
2(2)+7
4+7=11
2(3)+7
6+7=13
2(4)+7
8+7=15
2(5)+7
10+7=17
2(9)+7
18+7=25
can someone pls help w finding the x and y intercepts of this?
y=x^2-2x
Answer:
y-intercept is 0, x-intercept is 0 and 1
Step-by-step explanation:
For y-intercept, x=0 :
[tex]{ \tt{y = {(0)}^{2} - 2(0) }} \\ { \tt{y = 0}}[/tex]
For x-intercept, y=0 :
[tex]{ \tt{0 = {2x}^{2} - 2x }} \\ { \tt{2x(x - 1) = 0}} \\ { \tt{x = 0 \: \: and \: \: 1}}[/tex]
(Picture) Could someone help me solve this I need to use Inverse Operations but I don't fully understand? I'll mark brainliest, 10 Points.
Answer:
[tex]x = - 8[/tex]
Step-by-step explanation:
First,Step write the given equation.
[tex] \frac{x}{2} + 7 = 3[/tex]
In Algebra, we learn how to solve for a missing term called a variable. We must use inverse operations to undo terms to isolate our variable. Inverse operations means that we do the opposite of the given.
Opposite of Addition is Subtraction, vice versa.Opposite of Multipication is Division, vice versa.For example, say we have a equation
[tex]x + 2 = 3[/tex]
We would subtract 2 from both sides. E.g( remember the golden rule of algebra). What we do to one side, we do the other. This applies when we solving for a variable.
This means that
[tex]x = 1[/tex]
And if we substitute 1 in for x, it is indeed true.
[tex]1 + 2 = 3 = 3[/tex]
Now, back to the question.
[tex] \frac{x}{2} + 7 = 3[/tex]
First, we subtract 7 from both sides to get rid of the 7 on the left side. Also remeber to undo terms that aren't included in the variable when solving these problems.
So now we got
[tex] \frac{x}{2} = - 4[/tex]
Then we multiply 2 by both sides since that the opposite of division.
[tex] \frac{x}{2} \times 2 = x = -4 \times 2 = - 8[/tex]
So this means that
[tex]x = - 8[/tex]
If we plug this in, this is true.
[tex] \frac{ - 8}{2} + 7 = 3[/tex]
Find m so that the equation msin²x+cos²x=m-1 has a solution on the interval (0;π/4)
msin²x+cos²x=m-1
since the interval are 0 and π/4
Therefore
msin²(0)+cos²(0)=m-1
m(0)+1=m-1
1=m-1
m=2
use π/4 now
msin²(π/4)+cos²(π/4)=m-1
m(1/2)+(1/2)=m-1
m+1=2(m-1)
m+1=2m-2
-m=-3
m=3
Therefore
m=2 or 3
find the angle measures given the figure is a rhombus.
Answer:
92
Step-by-step explanation:
180-88
What is the measure of m?
5
15
E
n
m = [?]
====================================================
Explanation:
The two smaller triangles are proportional, which lets us set up this equation
5/n = n/15
Cross multiplying leads to
5*15 = n*n
n^2 = 75
----------
Apply the pythagorean theorem on the smaller triangle on top, or on the right.
a^2+b^2 = c^2
5^2+n^2 = m^2
25+75 = m^2
100 = m^2
m^2 = 100
m = sqrt(100)
m = 10
The estimate obtained from a sample of which of the following sizes would most likely be closest to the actual parameter value of a population?
To obtain an estimate of a parameter of a population, we use confidence intervals.
Confidence intervals:
The larger the sample size, the closest the parameter estimate is to the value of the population, as the margin of error of confidence intervals is inversely proportional to the sample size, that is, a greater sample leads to a smaller margin of error.
Thus, you should select the highest sample size in the options.
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take a square of arbitary measure assuming its area is one square unit.divide it in to four equal parts and shade one of them.again take one shaded part of that square and shade one fourth of it.repeat the same process continuously and find the sum area of shaded region
Answer:
In recreational mathematics, a square array of numbers, usually positive integers, is called a magic square if the sums of the numbers in each row, each column, and both main diagonals are the same.[1][2] The order of the magic square is the number of integers along one side (n), and the constant sum is called the magic constant. If the array includes just the positive integers {\displaystyle 1,2,...,n^{2}}{\displaystyle 1,2,...,n^{2}}, the magic square is said to be normal. Some authors take magic square to mean normal magic square.[3]
The smallest (and unique up to rotation and reflection) non-trivial case of a magic square, order 3
Magic squares that include repeated entries do not fall under this definition and are referred to as trivial. Some well-known examples, including the Sagrada Família magic square and the Parker square are trivial in this sense. When all the rows and columns but not both diagonals sum to the magic constant we have semimagic squares (sometimes called orthomagic squares).
The mathematical study of magic squares typically deals with its construction, classification, and enumeration. Although completely general methods for producing all the magic squares of all orders do not exist, historically three general techniques have been discovered: by bordering method, by making composite magic squares, and by adding two preliminary squares. There are also more specific strategies like the continuous enumeration method that reproduces specific patterns. Magic squares are generally classified according to their order n as: odd if n is odd, evenly even (also referred to as "doubly even") if n is a multiple of 4, oddly even (also known as "singly even") if n is any other even number. This classification is based on different techniques required to construct odd, evenly even, and oddly even squares. Beside this, depending on further properties, magic squares are also classified as associative magic squares, pandiagonal magic squares, most-perfect magic squares, and so on. More challengingly, attempts have also been made to classify all the magic squares of a given order as transformations of a smaller set of squares. Except for n ≤ 5, the enumeration of higher order magic squares is still an open challenge. The enumeration of most-perfect magic squares of any order was only accomplished in the late 20th century.
Magic squares have a long history, dating back to at least 190 BCE in China. At various times they have acquired occult or mythical significance, and have appeared as symbols in works of art. In modern times they have been generalized a number of ways, including using extra or different constraints, multiplying instead of adding cells, using alternate shapes or more than two dimensions, and replacing numbers with shapes and addition with geometric operations.
The sum area of shaded region is [tex]\frac{1}{3}[/tex].
Summation formula for geometric progressionThe formula to find the sum of infinite geometric progression is
[tex]S_{n}=\frac{a_{1}(1-q^{n}) }{1-q} \ \ q \ne 1[/tex]
Given
S = [tex]\frac{1}{4} +\frac{1}{16} +\frac{1}{64} +.........[/tex]
Using geometric progression
S = [tex]\lim_{h \to \infty} [\frac{1}{4} +(\frac{1}{4} )^{2} +(\frac{1}{4} )^{3} +.........+(\frac{1}{4} )^{n}][/tex]
Using summation formula for geometric progression
[tex]S_{n}=\frac{a_{1}(1-q^{n}) }{1-q} \ \ q \ne 1[/tex]
= [tex]\lim_{h \to \infty} \frac{\frac{1}{4} (1-(\frac{1}{4} )^{n} }{1-\frac{1}{4} }[/tex]
= [tex]\lim_{h \to \infty} \frac{\frac{1}{4} (1-\frac{1}{4^{n} }) }{\frac{3}{4} }[/tex]
= [tex]\lim_{h\to \infty} \frac{1}{3}(1-\frac{1}{4^{n} } )[/tex]
[tex]\lim_{h\to \infty} \frac{1}{4^{n} }[/tex] = 0
S = [tex]\frac{1}{3}(1-0) = \frac{1}{3}[/tex]
The sum area of shaded region is [tex]\frac{1}{3}[/tex].
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Find X in the picture
The scores of James in his math test are 75, 78, 89, and 71. What score on the next test will make James’ average at least 80 ?
x > 87
x > 87
x < 87
x < 87
Answer: x ≥ 87
Step-by-step explanation:
Set the minimum score on the next test as x & calculate it:
[tex]\frac{75+78+89+71+x}{5} =80\\\\75+78+89+71+x=80(5)\\\\313+x=400\\\\x=400-313=87[/tex]
So they need at least a score of 87 for the average to be 80+.
Answer:
x ≥ 87
Step-by-step explanation:
HELP ME WITH THIS PLS IM FAILING REALLY BAD ITS PYTHAGOREAN THEOREM
Answer:
50 km
Step-by-step explanation:
c = √a^2+b^2
=√30^2+40^2
= √900 + 1600
=√2500
= 50 km
Answer:
50km
Step-by-step explanation:
cho tứ giác ABCD. Gọi M,N,P,Q là trung điểm của các cạnh AB, CD, AD, BC. Chứng minh rằng vecto MP = vecto QN, vecto MQ = vecto PN
Answer:
Step-by-step explanation:
Xét tam giác DAB có: P là trung điểm AD, M là trung điểm AB
=> MP là đường trung bình của tam giác DAB => MP//BD và MP=[tex]\frac{1}{2}[/tex]BD (1)
Xét tam giác DBC có: N là trung điểm DC, Q là trung điểm BC
=> QN là đường trung bình của tam giác DBC => QN//BD và QN=[tex]\frac{1}{2}[/tex]BD (2)
Từ (1) và (2) => vecto MP song song cùng chiều với vecto QN
và độ dài MP = độ dài QN = [tex]\frac{1}{2}[/tex]BD
=> vecto MP = vecto QN
Tương tự xét các tam giác DAC và tam giác ABC => vecto MQ = vecto PN
what value of x is in the solution set of -5-15>10+20x
Answer:
-3/2 >x
Step-by-step explanation:
-5-15>10+20x
Combine like terms
-20 > 10 +20x
Subtract 20 from each side
-20 -10 > 10+20x-10
-30> 20x
Divide by 20
-30/20 >20x/20
-3/2 >x
Answer:
-3/2 > x
Step-by-step explanation:
-5 - 15 > 10 + 20x
^ ^
-20
-20 > 10 + 20x
-10 -10
---------------------
-30 > 20x
----- -------
20 20
-3/2 > x
Hope this helped.
divide 12by8 and 4by3
The lengths of the sides of a triangle are 3, 3, 312. Can the tangle be a right triangle?
Answer:
Yes it can be right angle triangle
evaluate the expression. check all possible sets that the solution may belong in. 40-5^2
Answer:
15
Step-by-step explanation:
following PEMDAS, we don't have () so we move on to exponents
5^2 is equal to 5 x 5 which is 25
40-25=15
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\large\textsf{40 - 5}\mathsf{^2}\\\\\\\large\textsf{5}\mathsf{^2}\\\large\textsf{= 5}\times\large\textsf{5}\\\large\textsf{= \bf 25}\\\\\\\large\textsf{= 40 - 25}\\\\\\\large\textsf{= \bf 15}\\\\\\\\\\\\\boxed{\boxed{\huge\textsf{Therefore your answer is: \bf 15}}}\huge\checkmark[/tex]
[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\textsf{Amphitrite1040:)}[/tex]
Olivia is fixing her bicycle. She starts fixing it at 9:34 am and finishes at 1 pm. How much
time did she spend fixing her bicycle?
Answer:
3 hours 26 minutes
Step-by-step explanation:
26 minutes(9.34am to 10am)+3 hours(10am to 1pm)=3 hours 26 minutes
The total time that she spend fixing her bicycle is 3 hr 26 minutes
Calculating total timeGiven the following parameters
Time that Olivia starts fixing bicycle= 9:34 am
Time she finishes = 1pm
The total number of hours spent from 9:34am and 12:34pm is 3 hrs. The remaining minutes to 1 pm is 26 minutes.
Hence the total time that she spend fixing her bicycle is 3 hr 26 minutes
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Find the length of each side and the
perimeter.
(5n -17) cm
(2n + 1) cm
n cm
7n-16
Step-by-step explanation:
Sry can u give me the picture
Marla noticed that her friend Ron had three times as many pieces of candy as she did. She told him, "If you give me seven pieces of your candy, we'll have exactly the same number of pieces." Ron responded, "I didn't know that until you mentioned it. But I'll make you a deal: If you can show me how to solve this puzzle using algebra, I'll give you the seven pieces. "One minute later, Ron was shocked to see that Marla had solved it perfectly. Can you do the same?
Answer:
This question seems to be asking for the work, so I put it below.
Anyhow, Marla had 3.5 candies, and Ron had 10.5.
Step-by-step explanation:
x = 3x - 7 (lets set this as "a") { a = 3x - 7}
x + 7 = 3x -7 + 7
x + 7 = 3x
( x + 7 ) / 3 = 3/3x
( x + 7 ) / 3 = x = *(same as "a") {a}
( x + 7 ) / 3 = 3x - 7
( x + 7 ) / 3 * 3 = ( 3x - 7 ) * 3
x + 7 = 9x - 21
x - x + 7 = 9x - x - 21
7 = 8x - 21
7 + 21 = 8x - 21 + 21
28 = 8x
28 / 8 = 8/8x
3.5 = x
We can plug this back into the original equation and find that it is correct because:
x = 3x - 7
x = 3.5 =====
3.5 = 3( 3.5 ) - 7
3.5 = 10.5 - 7
3.5 = 3.5
Answer:
Marla has 7 and Ron has 21
Step-by-step explanation:
lets take
no. of candies Marla has as "x"
and no. of candies Ron has will be "3x"
Marla says if Ron gives her seven candies, they will have the same no. of candies
so your equation will be -
x + 7 = 3x - 7 (as Marla gets the candy, Ron loses the candy)
3x - x = 7 + 7
2x = 14
∴x = 7
and 3x = 3 x 7 = 21
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