What does the greater unit rate or slope mean in terms of the situation? What can you conclude from this?

Answer:

1/5

Step-by-step explanation:

8/40->4/20->2-10->1/5

Hope this helps!

Answer:

1\5

Step-by-step explanation:

8/40 = 4/20 = 2/10 = 1/5

  3/4÷ 2/3=   3/4*3/2= 9/8= mixed fraction 1  1/8 pounds.

Answer:

A≈376.99yd²

d= 10yd

h = 7yd

hope it helps

Answer:

15d² + 7d - 4

Step-by-step explanation:

Distribute

(5d + 4)(3d -1)

5d (3d - 1) + 4(3d - 1)

Distribute

15d² - 5d + 4(3d- 1)

Distribute

15d² - 5d + 12d- 4

Simplify

15d² + 7d - 4

Answer:

24

Step-by-step explanation:

x/2-3x/4+5x/8=9

Or,(4*x-2*3x+5x)/8=9. (taking LCM)

Or, (4x-6x+5x)/8=9

Or, 3x=9*8

Or, x = 72/3

so, x=24.

Answer:

-43

Step-by-step explanation:

f(x) = -2x^2+2x-3

Let x = 5

f(5) =-2(5)^2+2(5)-3

     = -2(25)+10-3

     =-50+10-3

     = -43

Answer:

C or 14.8

Step-by-step explanation:

You just find the mean.

Arrange the numbers, add them then divide by the amount of numbers.

Hope it helps c:

Answer

what's the question?

Step-by-step explanation:

looks like your question is missing information

Answer: I think the answer is D

Step-by-step explanation:

Answer:

D is the answer (The last option)

Step-by-step explanation:

Answer:

The perimeter of the triangle is 40.

Step-by-step explanation:

The sum of legs for a right triangle is 12:

[tex] a + b = 21 [/tex]

[tex] a = 21 - b [/tex]   (1)

And their product is:

[tex] a*b = 40 [/tex]   (2)

By entering eq (1) into (2) we have:

[tex] (21 - b)b = 40 [/tex]                          

[tex] 21b - b^{2} - 40 = 0 [/tex]  

We can find the value of "b" by solving the above quadratic equation.

[tex] b_{1} = 2.1 [/tex]

[tex] b_{2} = 18.9 [/tex]

Since the two values satisfy the equation, we can use either of them to find "a". We will use b₁.      

[tex] a = 21 - 2.1 = 18.9 [/tex]                                                                              

Now, the hypotenuse of the right triangle is given by:

[tex] h = \sqrt{a^{2} + b^{2}} = \sqrt{(18.9)^{2} + (2.1)^{2}} = 19 [/tex]

Hence, the perimeter is:

[tex] P = a + b + h = 18.9 + 2.1 + 19 = 40 [/tex]

Therefore, the perimeter of the triangle is 40.

I hope it helps you!          

Answer: (0;2)

3x + 2y = 4 | * (-5)

4x + 5y = 10 | * 2

-15x - 10y = -20

8x + 10y = 20

-15x - 10y + 8x + 10y = 20 - 20

x = 0

0 + 2y = 4

2y = 4

y = 2

(0; 2)

Answer:

$1,890

Step-by-step explanation:

To find the amount, we use the compound interest formula here

we have this as;

A = P(1 + r/n)^nt

Where ;

P is the amount invested which is $1,800

r is the interest rate which is 3.3% annually (3.3/100 = 0.033)

n is the number of times yearly interest is compounded which is 1 time yearly

t is the number of years which is 1.5 years

substituting these values, we have

A = 1800( 1 + 0.033)^(1 * 1.5)

A = 1,890

Answer:

 T

              fold it up =t

Step-by-step explanation:

Answer:

3 / 16

Step-by-step explanation:

Let The total amount = x

Fraction eaten on first day = 1/4x

Fraction left = x - 1/4x = 3/4x

Fraction of amount left eaten on second day = 3/4 of 3/4x

3/4 * 3/4x = 9/16x

Fraction left :

3/4x - 9/16x = (12x - 9x) /16 = 3/16x

Hence, fraction left = 3/16

9514 1404 393

Explanation:

An exterior angle is equal to the sum of the remote interior angles. Define ∠PQR = 2q, and ∠QPR = 2p. The purpose of this is to let us use a single character to represent the angle, instead of 4 characters.

The above relation tells us ...

  ∠PRS = ∠PQR +∠QPR = 2q +2p

Then ...

  ∠TRS = (1/2)∠PRS = (1/2)(2q +2p) = q +p

and

  ∠TRS = ∠TQR +∠QTR . . . . . exterior is sum of remote interior

  q +p = (1/2)(2q) +∠QTR . . . . substitute for ∠TRS and ∠TQR

  p = ∠QTR = 1/2(∠QPR) . . . . . subtract q

__

For triangle ABC, draw line DE parallel to BC through point A. Put point D on the same side of point A that point B is on the side of the median from vertex A. Then we have congruent alternate interior angles DAB and ABC, as well as EAC and ACB. The angle sum theorem tells you that ...

  ∠DAB +∠BAC +∠CAE = ∠DAE . . . . a straight angle = 180°

Substituting the congruent angles, this gives ...

  ∠ABC +∠BAC +∠ACB = 180° . . . . . the desired relation

Since this is a right triangle, we can use the Pythagorean Theorem.

Pythagorean Theorem: a^2 + b^2 = c^2

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 147

b = sqrt(147) = 7 sqrt(3) miles

Hope this helps!

Answer:

y = -4x + 2

Step-by-step explanation:

The formula for slope is: y = mx + b

Where m is slope and b is when the line intersects the y-axis.

Plug in:

y = -4x + 2

The two is the point in the line, and -4 is the slope.

Hope this helps.

Answer:

Option D

Step-by-step explanation:

From the table attached,

Ordered pairs to be plotted → (1, 472.08), (2, 454.26), (3, 444.95), (4, 439.49), (5, 436.55)

By using linear regression calculator,

Equation of the regression line → y = -8.583x + 475.215

Option D will be the answer.

Answer:

Step-by-step explanation:

A positive cubic function graphed in the coordinate plane tends from lower left to upper right while a negative cubic function tends from the upper left to lower right. That graph is D (graph A is the positive cubic. Note the difference between "lower left to upper right" and "upper left to lower right")

Answer:

the diameter form for your help today with the app

Step-by-step explanation:

pa brain less

Answer:

let b union b be

B={2,4,6,8} and B= {1,2,3,4,5}

then B union B = {1,2,3,4,5,6,8}

Step-by-step explanation:

Venn diagram of b union b is in the attachment

Hope it is helpful to you

Answer:

C. 1.05 x 10^7

Step-by-step explanation:

1.75x10^4 x 600

=1050 x 10^4

=1.05 x 10^7

Answer:

2.6 x 5

Step-by-step explanation:

2.6 x 5 is 13 x 15.25 is 198.25 and you can't go any higher than that or it will go over 200 so the dimensions that give the greatest area would be 2.6 and 5, good luck

Answer:

[tex]\angle PRQ = 80[/tex]

Step-by-step explanation:

Given

[tex]\angle SPR = 145^o[/tex]

[tex]\angle POT = 115^o[/tex]

See attachment

Required

Find [tex]\angle PRO[/tex]

First, calculate [tex]\angle RPO[/tex]

[tex]\angle RPO + \angle SPR = 180[/tex] --- angle on a straight line

So, we have:

[tex]\angle RPO + 145 = 180[/tex]

Collect like terms

[tex]\angle RPO = 180 - 145[/tex]

[tex]\angle RPO = 35[/tex]

Next, calculate PQR

[tex]\angle POR + \angle POT = 180[/tex]

So, we have:

[tex]\angle POR + 115 = 180[/tex]

Collect like terms

[tex]\angle POR = 180-115[/tex]

[tex]\angle POR = 65[/tex]

So, PRO is calculated as:

[tex]\angle PRO + \angle POR + \angle RPO = 180[/tex] --- angles in a triangle

So, we have:

[tex]\angle PRO + 65 + 35= 180[/tex]

[tex]\angle PRO + 100= 180[/tex]

Collect like terms

[tex]\angle PRO = 180-100[/tex]

[tex]\angle PRO = 80[/tex]

Answer:

3. If that doesn't work, try 1/3

Step-by-step explanation:

Figure A has a length of 9 and figure B has a length of 3. 9 divided by 3 is 3.

Answer:

La diferencia del tiempo total de carrera entre el jugador 1 y 2 es 0.0[tex]\overline 3[/tex] minutos

Step-by-step explanation:

Primera vuelta;

El tiempo de vuelta del jugador 1 = 2,32 minutos

El tiempo de vuelta del jugador 2 = 18 segundos más que el del jugador 1

Por lo tanto, el tiempo de vuelta del jugador 2 = (2,32 + 18/60) minutos = 2,62 minutos

Segunda vuelta

El tiempo de vuelta del jugador 1 = 2,52 minutos

El tiempo de vuelta del jugador 2 = 20 segundos menos que el del jugador 1

Por lo tanto, el tiempo de vuelta del jugador 2 = (2.52 - 20/60) minutos = 2.18[tex]\overline 6[/tex] minutos

Tercera vuelta

El tiempo de vuelta del jugador 1 = 2,18 minutos

El tiempo de vuelta del jugador 2 = 2,18 minutos

El tiempo de vuelta total del jugador 1 = (2,32 + 2,52 + 2,18) minutos = 7,02 minutos

El tiempo de vuelta total del jugador 2 = (2,62 + 164/75 + 2,18) minutos = 524/75 minutos = 6.98[tex]\overline 6[/tex] minutos

La diferencia del tiempo total de carrera = (7.02 - 524/75) minutos = (1/30) minutos = 0.0[tex]\overline 3[/tex] minutos

Answer:

A prism is a polyhedron with two parallel, congruent faces called bases that are polygons

Answer:

90

Step-by-step explanation:

Answer:

[tex] \cos(60) = \frac{9}{a} \\ \frac{1}{2} = \frac{9}{a} \\ a = 18 \\ \\ \\ \tan(60) = \frac{b}{9} \\ \sqrt{3} = \frac{b}{9} \\ b = 9 \sqrt{3} [/tex]

I hope I helped you ^_^