What did Thomson’s and Rutherford’s experiments have in common? They both used charged particles in their experiments. They both used emission spectra to discover electron clouds. They both compared the atom to an indivisible sphere. They both discovered electron clouds.

Answers

Answer 1

Answer:

Both Thomson and Rutherford used charged particles in their experiments.

Explanation:

Answer 2
Theo both used charged particles

Related Questions

Which of the following could be used to convert chemical energy to heat energy?
a. a chair sitting still
c. a leaf absorbing sunlight
b. a battery powering a flashlight d. a rock hitting the ground

Answers

Answer:

C

Explanation:

Inside a battery there are chemical reactions. When the battery is powering a flashlight, this chemical energy gives a heat one.

your answer will be a battery powering a flashlight

A certain light bulb consumes 200J of electrical energy per second, but only emits 25J of light energy per second. Calculate the efficiency of this bulb.

Answers

Answer:

The answer is 12.5%

Explanation:

The efficiency of a light bulb is:

Light energy comes out of the bulb / Electrical energy that was put in

= 25J / 200J = 12.5%

12.5% it told me that it had to be 20 characters long to submit it so there

the particles in a gaseous substance can move easily because the____
a. particles are free to move
b. containing vessel is to big
c. force between them is weak
d. particles are moving with great speed​

Answers

Answer:

a option okkkkkkkkkkkkkk

Answer:

particles are free to move

if a source of sound waves is rabidly approaching a person the sound heard by the person appears to have?

Answers

Answer:

have a frequency. higher than the frequency actually produced by the source.

Explanation:

Answer:

If a source of sound waves is rapidly approaching a person, the sound heard by the person appears to have - a pitch lower than the original pitch.

PLS HELP. I WILL MARK U THE BRAINLIEST IF U ANSWER EVERYTHING STEP BY STEP AND CORRECTLY.

Answers

Answer:

Distance = 15m

Displacement = 5m

Explanation:

For distance add the values

For displacement use Pythagoras formula

15m and 5m is the answer
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