What are the values of m and 0 in the diagram below?

did u add the attachment of the the statements? cuz i dont see it.

Answer:

The volume of the sphere is 3053. 63 inches.

Step-by-step explanation:

Formula for volume of a sphere is : V = 4 /3 · π · r³

V = 4/3 · π · 9³

V ≈ 3053. 63

The volume of the sphere is 3053. 63 inches.

Answer:

[tex]Median = 15.80[/tex]

[tex]Mode = 15.20\ \&\ 15.25[/tex]

[tex]IQR = 2.35[/tex]

Step-by-step explanation:

Given

[tex]15.60,\ 18.75,\ 14.60,\ 15.80,\ 14.35,[/tex]

[tex]13.90,\ 17.50,\ 17.55,\ 13.80,\ 14.20,[/tex]

[tex]19.05,\ 15.35,\ 15.20,\ 19.45,\ 15.95,[/tex]

[tex]16.50,\ 16.30,\ 15.25,\ 15.05,\ 19.10,[/tex]

[tex]15.20,\ 16.22,\ 17.75,\ 18.40,\ 15.25.[/tex]

Solving (a): The median and the mode

First, we sort the data.

[tex]13.80,\ 13.90,\ 14.20,\ 14.35,\ 14.60,\ 15.05,\ 15.20,\ 15.20,\ 15.25,\ 15.25,[/tex]

[tex]15.35,\ 15.60,\ 15.80,\ 15.95,\ 16.22,\ 16.30,\ 16.50,\ 17.50,\ 17.55,\ 17.75,[/tex]

[tex]18.40,\ 18.75,\ 19.05,\ 19.10,\ 19.45.[/tex]

The median position is:

[tex]Median = \frac{n + 1}{2}th[/tex]

[tex]Median = \frac{25 + 1}{2}[/tex]

[tex]Median = \frac{26}{2}[/tex]

[tex]Median = 13th[/tex]

The 13th item is: 15.80

Hence:

[tex]Median = 15.80[/tex]

The modes are:

[tex]Mode = 15.20\ \&\ 15.25[/tex] --- they both have frequency of 2 while others occur once

Solving (b): The interquartile range

This is calculated as:

[tex]IQR = Q_3 - Q_1[/tex]

Since the median is at the 13th position, Q1 is:

[tex]Q_1 = \frac{1 + 13}{2}th[/tex]

[tex]Q_1 = \frac{14}{2}th[/tex]

[tex]Q_1 = 7th[/tex]

The 7th item is: 15.20

[tex]Q_1 = 15.20[/tex]

Similarly, Q3 is:

[tex]Q_3 = \frac{13+n}{2}[/tex]

[tex]Q_3 = \frac{13+25}{2}[/tex]

[tex]Q_3 = \frac{38}{2}[/tex]

[tex]Q_3 = 19th[/tex]

The 7th item is: 17.55

So:

[tex]Q_3 = 17.55[/tex]

Hence,

[tex]IQR = 17.55 - 15.20[/tex]

[tex]IQR = 2.35[/tex]

Step-by-step explanation:

hear is your answer in attachment

[tex]x= \pi[/tex]

Step-by-step explanation:

[tex]\cos^2x+\cos x+1=0[/tex]

Let [tex]u= \cos x[/tex]

Then [tex]u^2+2u+1=(u+1)^2=0[/tex]

or

[tex]\cos x = -1[/tex]

This gives us [tex]x= \pi[/tex] or all integer multiples of [tex]\pi (n \pi)[/tex]

Answer:

You need to add the numbers up

0.4 +0.2+0.1=0.7

1-0.7=0.3

Ans=0.3

Answer:

MATH

Dior H. asked • 01/13/21

graph the line with the slope 1/2 and y-intercept -2

i need help badly i am crying because its hard

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1 Expert Answer

By:

Raymond B. answered • 01/14/21

TUTOR 5 (1)

Math, microeconomics or criminal justice

ABOUT THIS TUTOR ›

y=mx + b is the standard slope intercept form for a line

m=1/2, b =-2

y=(1/2)x -2. y-intercept is -2 or the point (0,-2)

x intercept is found by setting y=0 and solving for x

0=(1/2)x - 2

(1/2)x = 2

x = 4 = the x intercept or (4,0)

plot the 2 intercepts (0,-2) and (4,0)

(4,0) is on the x axis, 4 units to the right of the origin (0,0)

(0,-2) is on the y axis, 2 units below the origin

once you plot those two points, draw a straight line connecting them. That's the graph of the line

9514 1404 393

Answer:

  (1 -x +√(x -1))/(x² -3x +2)

Step-by-step explanation:

Fill in the given function definition and simplify.

  [tex]\dfrac{f(x)-f(2)}{x-2}=\dfrac{\dfrac{1}{\sqrt{x-1}}-\dfrac{1}{\sqrt{2-1}}}{x-2}=\dfrac{1-\sqrt{x-1}}{(x-2)\sqrt{x-1}}\\\\=\dfrac{\sqrt{x-1}-x+1}{(x-2)(x-1)}=\boxed{\dfrac{\sqrt{x-1}-x+1}{x^2-3x+2}}[/tex]

Answer:

[tex]y = -\frac{1}{2}n + 15[/tex]

Step-by-step explanation:

Linear equation:

A linear equation has the following format:

[tex]y(n) = an + b[/tex]

In which a is the slope and b is the y-intercept.

When she plants 30 stalks, each plant yields 30 oz of beans. When she plants 34 stalks, each plant produces 28 oz of beans.

This means that we have these following two points: (30,30) and (34,28).

Finding the slope:

When we have two points, the slope is given by the change in the output y divided by the change in the input n.

Change in the output: 30 - 28 = 2.

Change in the input: 30 - 34 = -4. So

[tex]a = \frac{2}{-4} = -\frac{1}{2}[/tex]

So

[tex]y = -\frac{1}{2}n + b[/tex]

Finding b:

When [tex]n = 30, y = 30[/tex]. We replace this into the equation to find b. So

[tex]y = -\frac{1}{2}n + b[/tex]

[tex]b = -\frac{1}{2}(30) + 30[/tex]

[tex]b = -15 + 30 = 15[/tex]

So

[tex]y = -\frac{1}{2}n + 15[/tex]

Answer:

= 3.6

Step-by-step explanation:

Do you know how to find the volume of a cylinder? Like any prism, it's area of base x height, in this case the base is a circle of radius 1.2m.

Density is simply mass / volume (kg / m3 ).

clarify its 1.2 x 3 = 3.6

12400 / 3.6 = 3.444 occuring

Answer:

Do you mean in words?

Step-by-step explanation:

then it is

Two million,four hundred and seventy one thousand,three hundred and seventy two.

Answer:

2329

Step-by-step explanation:

2000 - 125 - 127 + 1719 - 356 - 782 = 2329

Answer:

Number of black balls=2

Total number of balls=3

Probability =2/3

Answer:

65%

Step-by-step explanation:

2080/3200times100%

Answer:

LHS×0=RHS×0

0=0

hence,proved

Answer:

x = 59,53445508

Tan(x) = 34/20

Step-by-step explanation:

Answer:

30÷20 degree x=n

Step-by-step explanation:

Mark me as brainliest

Answer:

hear is your answer in attachment please give me some thanks

Answer:

Option 1

Step-by-step explanation:

3x - 7y = -7y + 3x

They have simply been moved to opposite ends of the equation.

Step-by-step explanation:

the answer is in the above image

Solution :

a). P(X = x)

     =   [tex]$p(1-p)^x$[/tex]  for x = 0, 1, 2, ....

   P(x ≤ 3) = 0.837

b). Expectation = [tex]$\frac{(1-p)}{p}$[/tex]

                        = 1.7397

  Variance = [tex]$\frac{(1-p)}{p^2}$[/tex]

                 = 4.7663726

  Standard deviation = 2.1832

 Therefore, mean + standard deviation

                  = 1.7397 + 2.1832

                  = 3.9229

[tex]$P(x > 3.9229) = 0.1626$[/tex]

So the required P = 2 x 0.1626

                             = 0.325

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

[tex]\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}[/tex]

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

[tex]x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13[/tex]

[tex]x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88[/tex]

[tex]x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63[/tex]

[tex]x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38[/tex]

[tex]x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13[/tex]

So, the table becomes:

[tex]\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}[/tex]

Next, calculate the mean

[tex]\bar x = \frac{\sum fx}{\sum f}[/tex]

[tex]\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}[/tex]

[tex]\bar x = \frac{1845.73}{146}[/tex]

[tex]\bar x = 12.64[/tex]

Next, the sample variance is:

[tex]\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}[/tex]

So, we have:

[tex]\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}[/tex]

[tex]\sigma^2 = \frac{2393.6875}{145}[/tex]

[tex]\sigma^2 = 16.51[/tex]

The sample standard deviation is:

[tex]\sigma = \sqrt{\sigma^2}[/tex]

[tex]\sigma = \sqrt{16.51}[/tex]

[tex]\sigma = 4.06[/tex]

Answer:

* Giống nhau: đều là biểu hiện bằng tiền về lao động sống và lao động hóa trong quá trình sản xuất

* Khác nhau:

+ Về thời gian: chi phí sản xuất gắn liền với từng thời kỳ, còn giá thành sản phẩm gắn với thời hạn hoàn thành sản phẩm. ...

+ Có những chi phí được tính vào giá thành nhưng không được tính vào chi phí kỳ này.

+ Mối quan hệ chi phí và tính giá thành sản phẩm: Chi phí là cơ sở để tính giá thành, giá thành là thước đo chi phí sản xuất mà doanh nghiệp bỏ ra để có được khối lượng hoàn thành.

+ Có nhiều chi phí phát sinh trong kỳ nhưng chưa có sản phẩm hoàn thành do đó chưa có giá thành.

Step-by-step explanation:

Answer:

Markup amount: $54

New price with markup: $204

Step-by-step explanation:

36% markup to $150

We can find the amount of markup by finding 36% of 150.

36% of $150

Write 36% as a decimal and multiply it by the price

0.36(150) = $54

The amount of markup (36%) is equal to $54

When this is added to the original price, the new price is $150 + $54 = $204

Let me know if you have any questions!

Answer:

Step-by-step explanation:

The average cost for the training session provided he is a sports trainer can be computed as follows:

Let's assume that;

average cost = C(x)

the no. of session = x

Then:

[tex]C(x) = \dfrac{\text{Total cost}}{\text{no. \ of sessions}}[/tex]

[tex]C(x) = \dfrac{\text{80 + 40 + 15x}}{\text{x}}[/tex]

[tex]C(x) = \dfrac{\text{120+ 15x}}{\text{x}}[/tex]

Now, suppose the trainer wants the average cost C(x) to drop below $16;

Then, we have the following function:

[tex]\dfrac{120+15x}{x}\leq C(x)[/tex]

[tex]\dfrac{120+15x}{x}\leq16[/tex]

By cross multiply:

120 + 15x ≤ 16x

120 ≤ 16x - 15x

120 ≤ x

Therefore, the required no. of session, if the average cost should drop below $16, is 120.

Following are the solution to the required points:

        Total cost = C(x)

        Total session = x  

Then:

[tex]\to C(x)=\frac{\text{Total cost}}{\text{Total sessions}}=\frac{80+40+15x}{x}= \frac{120+15x}{x}[/tex]

[tex]\to \frac{120+15x}{x} \leq C(x)\\\\\to \frac{120+15x}{x} \leq 16\\\\[/tex]

By cross multiply:

[tex]\to 120 + 15x \leq 16x\\\\\to 120 \leq 16x - 15x\\\\ \to 120 \leq x[/tex]

As a result, if the average cost drops below $16, the required number of sessions is 120.

Learn more:

brainly.com/question/24859268

Answer:

I'm acutally not too sure on this but give me a moment to solve this

Step-by-step explanation:

Answer:

0.2 amps

Step-by-step explanation:

Given data

The formula V=IR is the formula for ohms law

Which state that  the voltage is directly proportional to the current and the resistance in an electric circuit

Now

R= 15 ohms

V= 3volts

V= IR

3= I*15

I= 3/15

I= 0.2 amps

Hence he current flowing is 0.2 amps

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30}}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex](4 {x}^{2} + 4x + 6)(7x + 5)[/tex]

[tex] = \: 7x(4 {x}^{2} + 4x + 6) + 5(4 {x}^{2} + 4x + 6)[/tex]

[tex] = \: 28 {x}^{3} + 28 {x}^{2} + 42x + 20 {x}^{2} + 20x + 30[/tex]

Combining like terms, we have

[tex] = \: 28 {x}^{3} + (28 {x}^{2} + 20 {x}^{2} ) + (42x + 20x) + 30[/tex]

[tex] = \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]

Answer:

1/6 * 1/2 = 1/12

Step-by-step explanation:

1 number on a 6 sided die is 1 out of 6 (1/6) and an even number (2,4,6) on a 6 sided die is 3/6 or 1/2 (always simplify when multiplying fractions)

so 1 times 1 = 1 and 6 times 2 = 12 making it 1/12

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: (x - 5)(x - 4) }}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\blue{Step-by-step\:explanation}}{\blue{:}}}}}[/tex]

[tex] {x}^{2} - 9x + 20[/tex]

[tex] = {x}^{2} - 4x - 5x + 20[/tex]

Taking "[tex]x[/tex]" as common from first two terms and "[tex]5[/tex]" from last two terms, we have

[tex] = x(x - 4) - 5(x - 4)[/tex]

Taking the factor [tex](x-4)[/tex] as common,

[tex] = (x - 5)(x - 4)[/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]