What are the solutions to the system of equations? {y=2x2+6x−10 y=−x+5

Answer:

30 =x

Step-by-step explanation:

The angles are correcting angle and corresponding angles are equal when the lines are parallel

55 = x+25

Subtract 25 from each side

55-25 = x+25

30 =x

Answer:

18.45

Step-by-step explanation:

I used a calculator

they don't share any points

that's one thing, but I don't know what your options are of course.

see screenshot for illustration of the inequalities

note: you may need to leave off the pi term if your teacher just wants to know what goes in the green box

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Work Shown:

C = 2*pi*r

C = 2*r*pi

C = 2*5*pi

C = 10pi

Answer:

5/3 x 5/3 x 5/3

125/27

5^3/3^3

3 x (5/3)

Step-by-step explanation:

(5/3)^3 = 5×5×5/3×3×3 = 125/27.

In the diagram, ∠5 is adjacent to ∠EHD.

Angle

Angles are formed when two rays intersect at a point. An angle is also formed when to lines intersect each other, thereby the two lines share a common endpoint.

Adjacent angles are two angles that have a common side and a common vertex (corner point). They are placed side by side to each other.

In the diagram, ∠5 is adjacent to ∠EHD.

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Answer:

Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:

1) [tex]\frac{a + i\,b}{c + i\,d}[/tex]   Given.

2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.

3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex]   Existence of additive inverse/Definition of division.

4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex]   [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]  

5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex]  Distributive and commutative properties.

6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.

7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.

8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

Step-by-step explanation:

Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:

1) [tex]\frac{a + i\,b}{c + i\,d}[/tex]   Given.

2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.

3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex]   Existence of additive inverse/Definition of division.

4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex]   [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]  

5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex]  Distributive and commutative properties.

6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.

7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.

8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

Answer:

The additive inverse of -61 is 61. For additive inverse just reverse the sign.

Answer:

x = 1

Step-by-step explanation:

5x - (4x - 1) = 2

Let's get rid of the parenthesis

Multiply whatever is in the parenthesis by -1 since there is a minus sign before it

5x - 4x + 1 = 2

Move common terms to one side, so subtract 1 from both sides

5x - 4x + 1 = 2

           -  1  - 1

5x - 4x = 1

Subtract the 5x by 4x

x = 1

Answer:

x = 1

Step-by-step explanation:

5x - (4x - 1) = 2

5x - 4x + 1 = 2  {Distribute property  (-1) is distributed with 4x  and (-1)}

Combine like terms

x + 1 = 2

Subtract 1 from both sides

x = 2 - 1

x = 1

The net cost after discounts will be $ 2,450.

Given that Economy Hardware Store ordered items retailing for $ 2,500, and they received a chain discount of 5/20/2, the following calculation must be performed to find the net cost, knowing that the net cost is equal to the initial cost minus the discounts made about it:

First, the discount percentage must be calculated.

5/20/2 = X

4/2 = X

2 = X

Then, this percentage must be subtracted from the initial value.

2500 x (1-0.02) = X

2500 x 0.98 = X

2450 = X

Therefore, the net cost after discounts will be $ 2,450.

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Answer:

b or d

Step-by-step explanation:

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Answer:

A

Step-by-step explanation:

A mode is the value that appears most frequently in the data set because there is not more than one of any number the data set has no mode.

This triangle has base 16 therefore the sides must be 17cm and 17 cm

When we make a altitude it divides it into two right triangles and there is a property in which the altitude of the isoceles triangle divides the base in 2 equal halves

So the side of the right triangle will be x , 8 , 17

Using pythgoreus theorem

x²+8²=17²

x = √225

x = 15

So the altitude is 15 cm

Must click thanks and mark brainliest

Answer:

4, 8, 16, 32, 64

Step-by-step explanation:

The nth term of a geometric sequence is

[tex]a_{n}[/tex] = a₁[tex](r)^{n-1}[/tex]

Given

a₇ = 256 and a₁₀ = 2048 , then

a₁ [tex]r^{6}[/tex] = 256 → (1)

a₁ [tex]r^{9}[/tex] = 2048 → (2)

Divide (2) by (1)

[tex]\frac{a_{1}r^{9} }{a_{1}r^{6} }[/tex] = [tex]\frac{2048}{256}[/tex]

r³ = 8 ( take the cube root of both sides )

r = [tex]\sqrt[3]{8}[/tex] = 2

Substitute r = 2 into (1)

a₁ × [tex]2^{6}[/tex] = 256

a₁ × 64 = 256 ( divide both sides by 64 )

a₁ = 4

Then

a₁ = 4

a₂ = 2a₁ = 2 × 4 = 8

a₃ = 2a₂ = 2 × 8 = 16

a₄ = 2a₃ = 2 × 16 = 32

a₅ = 2a₄ = 2 × 32 = 64

Answer:

12

Step-by-step explanation:

Add 10l to 12l to13l to11l to 14l=60l the divide 60l by the number of houses which will be 12 and there is your correct answer

Answer:

Starting with the first one, we need to convert both of the equations into slope-intercept form. y = -2x + 5 is already in that form, now we just need to do it to 4x + 2y = 10.

2y = -4x + 10

y = -2x +5

Since both equations give the same line, the first one has infinite solutions.

Now onto the second one. Once again, the first step is to convert both of the equations into slope-intercept form.  

x = 26 - 3y becomes

3y = -x + 26

y = -1/3x + 26/3  

2x + 6y = 22 becomes

6y = -2x + 22

y = -1/3 x + 22/6

Since the slopes of these two lines are the same, that means that they are parallel, meaning that this one has no solutions.  

Now the third one. We do the same steps.  

5x + 4y = 6 becomes

4y = -5x + 6

y = -5/4x + 1.5

10x - 2y = 7 becomes

2y = 10x - 7

y = 5x - 3.5

Since these two equations are completely different, that means that this system has one solution.

Now the fourth one. We do the same steps again.  

x + 2y = 3 becomes

2y = -x + 3

y = -0.5x + 1.5

4x + 8y = 15 becomes

8y = -4x + 15

y = -1/2x + 15/8

Once again, since these two lines have the same slopes, that means that they are parallel, meaning that this one has no solutions.  

Now the fifth one.  

3x + 4y = 17 becomes

4y = -3x + 17

y = -3/4x + 17/4

-6x = 10y - 39 becomes

10y = -6x + 39

y = -3/5x + 3.9

Since these equations are completely different, there is a single solution.  

Last one!

x + 5y = 24 becomes

5y = -x + 24

y = -1/5x + 24/5

5x = 12 - y becomes

y = -5x +12

Since these equations are completely different, this system has a single solution.

Step-by-step explanation:

hope this helps you out:)

Answer:

$2/ hat

Step-by-step explanation:

Find the unit rate:

$ to hats

8 to 4

Divide by four to get the unit rate; over 1

2 to 1

So, $2 per hat

Hope this helps!

Answer:

m BC = 100

Step-by-step explanation:

Since the angle is at the center, the arc has the same measurement as the angle

m BC = 100

Answer:

-12x-9+50-5=0

-12x+41-5=0

-12x+36=0

-12x=0-36

x= -36/-12

x = 3 Answer...

hope it helps

Answer:

[tex]x=3[/tex]

Step-by-step explanation:

[tex]3(-4x - 3) + 50 - 5= 0[/tex]

⇒ Subtract 50- 5 from both sides:-

[tex]3\left(-4x-3\right)+50-5-\left(50-5\right)=0-\left(50-5\right)[/tex]

[tex]3\left(-4x-3\right)=-45[/tex]

⇒ Divide both sides by 3:-

[tex]\frac{3\left(-4x-3\right)}{3}=\frac{-45}{3}[/tex]

[tex]-4x-3=-15[/tex]

⇒ Add 3 to both sides:-

[tex]-4x-3+3=-15+3[/tex]

[tex]-4x=-12[/tex]

⇒ Divide both sides by -4:-

[tex]\frac{-4x}{-4}=\frac{-12}{-4}[/tex]

[tex]x=3[/tex]

OAmalOHopeO

[tex] \large \tt{{❃ \: S \: O \: L \: U \: T \: I \: O \: N : }}[/tex]

[tex] \large{ \tt{❁ \:x + x + 98 = 180 \degree \: [ Sum\: of \: angle \: of \: a \: triangle ]}}[/tex]

[tex] \large{ \tt{⟶2x + 98 \degree= 180 \degree}}[/tex]

[tex] \large{ \tt{⟶ \: 2x = 180 \degree - 98 \degree}}[/tex]

[tex] \large{ \tt{⟶ \: 2x = 82 \degree}}[/tex]

[tex] \large{ \tt{ ⟶x = \frac{82 \degree}{2} }}[/tex]

[tex] \large{ \tt{⟶ \: x = 41 \degree}}[/tex]

[tex] \large{ \tt{ ↔\angle \: 1 = x \degree = \boxed{41 \degree}}}[/tex] [ Being alternate angles ]

- Alternate angles are the non-adjacent interiors pair of angles lying to the opposite side of a transversal when it intersects two straight line segments. Alternate angles form ' Z ' shape.

Answer:

[tex]\angle 1 + \angle 2 = 180^o[/tex]

Step-by-step explanation:

Given

[tex]\angle 1[/tex] and [tex]\angle 2[/tex]

Required

The relationship between them [tex]\angle 1[/tex] and [tex]\angle 2[/tex]

From the question, we understand that [tex]\angle 1[/tex] and [tex]\angle 2[/tex] are supplementary

Supplementary angles add up to 180.

So, the relationship between [tex]\angle 1[/tex] and [tex]\angle 2[/tex] is:

[tex]\angle 1 + \angle 2 = 180^o[/tex]

Answer:

x = 55°

Step-by-step explanation:

The sum of the angles in a triangle is 180°.

x + 75 + 50 = 180

x + 125 = 180

x = 55

Therefore, x = 55°.

Answer:

x = 55

Step-by-step explanation:

the angles of a triangle add up to 180 degrees. So far we have 125 taken up.

We do 180 - 125 = 55.

x = 55

First go to the y intercept (or the b in y=mx+b) look for the slope and plot the points on the graph they're talking about e.g. #23 the y-intercept is 6 go to the 6 on the y axis, and then look at the slope (x), so it goes up and over to the right since it's positive by 1

Answer:

In 26 seconds to complete a transaction, 2 products are being purchased.

Step-by-step explanation:

1 item  = 9 seconds

Time taken in all to check out = 8 seconds

Time taken to shop = 26 seconds

Now as check out process takes 8 seconds, so the

Time left to ACTUALLY SHOP =  Total Time  - Time Used to check out

                                                  = 26 seconds = 8 seconds = 18 seconds

Shopping of 1 item = 8 seconds

Shopping of 2 items  = 2 x ( Time taken in 1 item) = 2 x  9 = 18 seconds

So, in 18 seconds, 2 clothing item can be selected.

Hence,in 26 seconds to complete a transaction, 2 products are being purchased.

Answer:

i think you just extend the coordinates to the side, except the right point, by 3, and then the bottom ones go down by 3, and the top one goes up by 3

Step-by-step explanation:

Answer: its going to be 3 dollars and 67 cents

Step-by-step explanation:

Answer:

30.80

Step-by-step explanation:

We can use a ratio to solve

4 tickets              7 tickets

-------------------  = ----------------

17.60 dollars           x dollars

Using cross products

4x = 17.60 * 7

4x =123.2

Divide each side by 4

4x/4 = 123.2/4

x=30.8

Part 1

[tex]\left(\frac{g}{h}\right)(x) = \frac{g(x)}{h(x)}\\\\\left(\frac{g}{h}\right)(x) = \frac{3x-5}{-2x^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{3(3)-5}{-2(3)^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{4}{-11}\\\\\left(\frac{g}{h}\right)(3) = -\frac{4}{11}\\\\[/tex]

Answer:  -4/11

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Part 2

Set the denominator function equal to zero and solve for x to find which values to kick out of the domain.

[tex]h(x) = 0\\\\-2x^2+7 = 0\\\\7 = 2x^2\\\\2x^2 = 7\\\\x^2 = 7/2\\\\x^2 = 3.5\\\\x = \sqrt{3.5} \ \text{ or } x = -\sqrt{3.5}\\\\[/tex]

This shows that if x is equal to either of those values, then the denominator h(x) will be zero. These are the values to kick out of the domain to prevent a division by zero error. Any other value of x is valid in the domain.

Answer: [tex]x = \sqrt{3.5} \text{ and } x = -\sqrt{3.5}\\\\[/tex]

Answer:

-26 sqrt(3)

Step-by-step explanation:

-12 sqrt(12) - 2 sqrt(3)

Rewriting

-12 sqrt(4*3) - 2 sqrt(3)

We know sqrt(ab) = sqrt(a)sqrt(b)

-12 sqrt(4)sqrt(3) - 2 sqrt(3)

-12 (2) sqrt(3) - 2 sqrt(3)

-24 sqrt(3) - 2 sqrt(3)

-26 sqrt(3)

Answer:

x=1

Step-by-step explanation:

log_4(x + 3) + log_4x = 1

We know that loga(b) + loga(c) = loga(bc)

log_4(x + 3)x = 1

Raise each side to the base of 4

4^log_4(x + 3)x = 4^1

(x+3)x = 4

x^2 +3x = 4

Subtract 4 from each side

x^2 +3x -4 = 0

Factor

(x+4) (x-1) =0

Using the zero product property

x= -4  x=1

But x cannot be negative since logs cannot be negative

x=1

Answer:

A..  x = 1.

Step-by-step explanation:

log_4(x + 3) + log_4x = 1

log_4 x(x + 3) = log_4 4

Removing the logs:

x(x + 3) = 4

x^2 + 3x - 4 = 0

(x + 4)(x - 1) = 0

x = 1, -4.

We can ignore the -4 as there is no log of a negative.

(a) The IQR for the males' data is 12, because Q3 is at 15 and Q1 is at 3.

(b) The difference between the median values of each data set is 4 because 10-6 = 4

(c) For the males' data, the median would be a better measure of center, since the data is skewed right. For the females' data, the mean would be a better measure of center, because the data is pretty balanced (except for the outlier).

(d) Maybe a superhero movie had their opening night one day of this month, which would explain the outlier.