What are the solutions of the equation 3x^2+6x-24=0

Answer:

5,000 + 800 + 20 + 9

Step-by-step explanation:

The definition of expanded form is to "write the value of each digit then add them together to find the sum." - study.com

That is exactly what we did above.

If we write it going up and down like below, we can pull the individual values:

5 000

8 00

2 0

9

I hope this helps!

Answer:

x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I

Step-by-step explanation:

1−2sin2  x≤−sin x    ⇒    (2sin x+1)(sin x−1)≥0

sin x≤−1/2    or    sin x≥1

−5π/6+2nπ≤x≤−π/6+2nπ    or    , n ϵ I x=(4n+1)π/2, n ϵ I⇒    -5π6+2nπ≤x≤-π6+2nπ    or    , n ϵ I x=4n+1π2, n ϵ I     (as sin x = 1 is valid only)

In general⇒    In general    x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I

Answer:

[tex]\boxed{\sf \bf \ \ -2i(6-7i)=-14-12i \ \ }[/tex]

Step-by-step explanation:

Hello, please consider the following.

[tex]-2i(6-7i)=-12i+14i^2=-14-12i[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

A

Step-by-step explanation:

Answer = A

Answer:

There is a significant difference in the systolic blood pressure measurements between the two arms.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

In this case a paired t-test is used to determine whether there is a difference in the systolic blood pressure measurements between the two arms.

The SPSS output is attached below.

(a)

The hypothesis for the test can be defined as follows:

H₀: There is no difference in the systolic blood pressure measurements between the two arms, i.e. d = 0.

Hₐ: There is a significant difference in the systolic blood pressure measurements between the two arms, i.e. d ≠ 0.

(b)

Consider the SPSS output.

The test statistic value is t = 0.871.

(c)

Consider the SPSS output.

The p-value of the test is:

p-value = 0.433.

(d)

The significance level of the test is, α = 0.05.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

p-value = 0.433 > α = 0.05

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

Thus, it can be concluded that there is a significant difference in the systolic blood pressure measurements between the two arms.

Answer:

bde

Step-by-step explanation:

Answer:

B: The histogram shows there were 22 students in the class.

D: The histogram is symmetrical.

E:The histogram has a peak.

F: The histogram shows the data is evenly distributed.

Step-by-step explanation:

edg 2020

Answer:

A

Step-by-step explanation:

[tex]f(f(3))=2\cdot3^2+1=19\\f(f(f(f(3))))=2\cdot19^2+1=723[/tex]

Answer:

Graph 2

Step-by-step explanation:

The equation x = t² - 3 is represented by exponential growth, ( t² ) so it's graph will be similar to the first graph, graph 1, in our options. Then again we have to consider the equation y = √t - 2, which will be similar to graph 4, but with a greater slope. This leaves us with a solution of graph b.

Answer:

  53

Step-by-step explanation:

Let's start with the given relation:

  2x -7 = (x+4) +5

  x = 16 . . . . . . . . . add 7-x

  3x +5 = 3(16) +5 = 53 . . . . . multiply by 3 and add 5

The value of 3x+5 is 53.

Step-by-step explanation:

Total catalysts = 10

Probability of 2 lower acidic catalysts = 2/10 = 1/5

Answer:

[tex]Probability = 0.068[/tex]

Step-by-step explanation:

Let P(S) represent the probability that stock market will go up in a day

Given

[tex]P(S) = 51\%[/tex]

Required

Determine the probability that stock will go up 4 consecutive days

Start by converting P(S) from percentage to decimal

[tex]P(S) = 51\%[/tex]

[tex]P(S) = \frac{51}{100}[/tex]

[tex]P(S) = 0.51[/tex]

The above expression represents the probability in a day;

For 4 days; we have:

[tex]Probability = P(S) * P(S) * P(S) * P(S)[/tex]

[tex]Probability = (P(S))^4[/tex]

Substitute 0.51 for P(S)

[tex]Probability = (0.51)^4[/tex]

[tex]Probability = 0.06765201[/tex]

[tex]Probability = 0.068[/tex] -- Approximated

Hence, the probability that stock will rise for 4 consecutive days is 0.068

Answer:

V = 523 in^3

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

V = 4/3 ( 3.14) * 5^3

V = 523.33333repeating

Rounding to the nearest inch^3

V = 523 in^3

Answer:

[tex] 523.6 {in}^{3} [/tex]

Step-by-step explanation:

[tex]v = \frac{4}{3} \pi {r}^{3} \\ = \frac{4}{3} \pi \times 5 \times 5 \times 5 \\ = 523.6 {in}^{3} [/tex]

Answer:

3 years

Step-by-step explanation:

A = P(1 + r)^t

A = I + P

A = 14,000 + 4,634 = 18,634

18,634 = 14,000(1 + 0.1)^t

18,634/14,000 = 1.1^t

log (18,634/14,000) = log 1.1^t

log (18,634/14,000) = t * log 1.1

t = [log (18,634/14000)]/(log 1.1)

t = 3

Answer:

The portfolio beta is  [tex]\alpha = 1.354[/tex]

Step-by-step explanation:

From the question we are told that

      The  first investment is [tex]i_1 = \$ 25,000[/tex]

       The  first  beta is  [tex]k = 0.8[/tex]

      The second investment is  [tex]i_2 = \$ 40,000[/tex]

       The  second  beta is  [tex]w = 1.7[/tex]

Generally the portfolio beta is mathematically represented as

           [tex]\alpha = \frac{ i_1 * k + i_2 * w }{ i_1 + i_2}[/tex]

substituting values

          [tex]\alpha = \frac{ (25000 * 0.8) + ( 40000* 1.7 ) }{40000 + 25000}[/tex]

          [tex]\alpha = 1.354[/tex]

Answer:

L = 29,550 mm (as per BS8110 the length is to the nearest 25)

Step-by-step explanation:

Lets make it so simple and easy.

Let A = 600mm

Let B = 300mm

Let C = 16 as number turns

Let d = 20mm

L = [tex]\sqrt{(3.14 * (600 - 20))^{2} + 300^{2}[/tex]  x 16

L = 29,550 mm (as per BS8110 the length is to the nearest 25)

Answer:

48

Step-by-step explanation:

Do 60*.80

60 represent the total points the test was worth

.80 represents the % number

The percentage is calculated by dividing the required value by the total value and multiplying by 100.

Required percentage value = a

total value = b

Percentage = a/b x 100

100% = 60

80% = 48

The points Salema earned are 48 points.

The percentage is calculated by dividing the required value by the total value and multiplying by 100.

Example:

Required percentage value = a

total value = b

Percentage = a/b x 100

Example:

50% = 50/100 = 1/2

25% = 25/100 = 1/4

20% = 20/100 = 1/5

10% = 10/100 = 1/10

We have,

Salema's score = 80%

Total score in the test = 60 points

Salema's score.

= 80% of 60 points

= 80/100 x 60

= 48

Thus,

The points Salema earned are 48 points.

Learn more about percentages here:

https://brainly.com/question/11403063

#SPJ2

Answer: m∠ATC = 54°

Step-by-step explanation:

Ok, we know that:

m∠ATB = 20° and  m∠BTD = 72°

then we must have that the angle between A and D, is equal to the sum of the angles between A and B, and B and D, or:

m∠ATD = m∠ATB + m∠BTD = 20° + 72° = 92°

Now, we also know that m∠CTD = 38°

And the angle:

m∠ATC  will be equal to the angle between A and D, minus the angle between C and D, or:

m∠ATC = m∠ATD - m∠CTD = 92° - 38° = 54°

Answer:

6.25

Step-by-step explanation:

(x-a)^2=x^2-2ax+a^2

2a=5

a=2.5

2.5 ^ 2 = 6.25

Answer:

A line segment has two endpoints. It contains these endpoints and all the points of the line between them. You can measure the length of a segment, but not of a line. Line segments are only a line that goes from one point to another, and lines go on forever. However, a line segment is also part of a line.

Hope this helps!

Answer:

[see below]

Step-by-step explanation:

A line is a straight path of points that has no start and no end. The line has an arrow on each end.

A line segment is part of a line. They have a start and an end. The line segments have a point on each end. You can use a line segment to make polygons and make calculations about them.

Hope this helps.

Answer:

The sample proportion of 'successful' people is [tex]\frac{3}{4}[/tex].

Step-by-step explanation:

The sample consist of 64 people and 48 of them are 'successful'. Hence, the proportion of 'successful' people is:

[tex]p = \frac{n}{N}[/tex]

Where:

[tex]N[/tex] - People that forms the sample, dimensionless.

[tex]n[/tex] - People classified as 'successful', dimensionless.

Given that [tex]n = 48[/tex] and [tex]N = 64[/tex], the sample proportion of 'successful' people is:

[tex]p = \frac{48}{64}[/tex]

[tex]p = \frac{3}{4}[/tex]

The sample proportion of 'successful' people is [tex]\frac{3}{4}[/tex].

Answer:

D) (-7,-4)

Step-by-step explanation:

Halfway from -2 to -12 is -7

Halfway from -3 to -5 is -4

Question Completion:

WACC = 10.0%

Opportunity cost = $100,000

Net equipment cost (depreciable basis) = $65,000

Straight-line deprec. rate for equipment = 33.333%  

Sales revenues, each year = $123,000

Operating costs (excl. deprec.), each year = $25,000

Tax rate = 35%

Answer:

Century Roofing

Project's NPV is: ($6,578)

Step-by-step explanation:

a) Data and Calculations:

WACC = 10.0%

Opportunity cost = $100,000

Net equipment cost (depreciable basis) = $65,000

Straight-line deprec. rate for equipment = 33.333%  

Sales revenues, each year = $123,000

Operating costs (excl. deprec.), each year = $25,000

Tax rate = 35%

Cash outflow in year 0 = $165,000 (Opportunity and new equipment costs)

Annual Cash inflow = $123,000 - $25,000 - $34,300 = $63,700

PV of annuity for 3 years at 10% = $158,422 ($63,700 x 2.487)

NPV = Cash inflow minus Cash outflow

= $158,422 - $165,000

= ($6,578)

Negative NPV

b) Since Century Roofing could have realized $100,000 from the sale of the building if it decides not to open the new warehouse, this opportunity cost is factored into the calculation of the Net Present Value.  It becomes a present cash outflow.  Century Roofing's opportunity cost is defined as the loss of $100,000 being the future return from the best alternative project when it chooses to build the new warehouse instead of selling off the building.

By the fundamental theorem of calculus,

[tex]E(t)=E(1)+\displaystyle\int_1^t E'(u)\,\mathrm du[/tex]

So we have

[tex]E(t)=92+\displaystyle\int_1^t(75-6u)\,\mathrm du[/tex]

[tex]E(t)=92+(75u-3u^2)\bigg|_1^t[/tex]

[tex]E(t)=20 + 75 t - 3 t^2[/tex]

Answer:

Step-by-step explanation:

Given:

x = 2cost,

t = (1/2)arccosx

y = 2sint

dy/dx = dy/dt . dt/dx

dy/dt = 2cost

dt/dx = -1/√(1 - x²)

dy/dx = -2cost/√(1 - x²)

Differentiate again to obtain d²y/dx²

d²y/dx² = 2sint/√(1 - x²) - 2xcost/(1 - x²)^(-3/2)

At t = π/4, we have

(√2)/√(1 - x²) - (√2)x(1 - x²)^(3/2)

Answer:

Step-by-step explanation:

Coordinates of the vertices of the given rectangle are,

A(-4, 5), B(-2, 5), C(-2,1) and D(-4, 1).

If the given rectangle ABCD is translated by 1 unit right and 4 units down,

Rule for the translation will be,

(x, y) → [(x + 1), (y - 4)]

Therefore, coordinates of A, B, C and D after translation will be,

A(-4, 5) → A'(-3, 1)

B(-2, 5) → B'(-1, 1)

C(-2, 1) → C'(-1, -3)

D(-4, 1) → D'(-3, -3)

Then A', B', C' and D' are reflected about the y-axis.

Rule for the reflection about y-axis will be,

(x, y) → (-x, y)

New coordinates after the reflection will be,

A'(-3, 1) → A"(3, 1)

B'(-1, 1) → B"(1, 1)

C'(-1, -3) → C"(1, -3)

D'(-3, -3) → D''(3, -3)

Finally these points are rotated 270° clockwise about the origin,

Rule to be followed,

(x, y) → (-y, x)

Therefore, new coordinates will be,

A"(3, 1) → A"'(-1, 3)

B"(1, 1) → B'"(-1, 1)

C"(1, -3) → C"'(3, 1)

D"(3, -3) → D"'(3, 3)

Answer:

The sum of the complex numbers will be - 28 - 4i

Step-by-step explanation:

We have the sum  −9−i−9−i + −5−i−5−i. Let's group like elements and simplify this expression,

−9−i−9−i + −5−i−5−i ( Group like terms )

- i - i - i - i - 9 - 9 - 5 - 5 ( Add like terms )

- i - i - i - i = - 4i, - 9 - 9 = - 18, and - 5 - 5 = - 10

- 18 - 10 = - 28 ( Substitute )

Solution : - 28 - 4i

Answer:

3/11

Step-by-step explanation:

From the above question, we have the following information

Total number of balls = 12

Number of white balls = 4

Number of blue balls = 3

Number of red balls = 5

We solve this question using combination formula

C(n, r) = nCr = n!/r!(n - r)!

We are told that 3 balls are drawn out at random.

The chance/probability of drawing out 3 balls = 12C3 = 12!/3! × (12 - 3)! = 12!/3! × 9!

= 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1/(3 × 2 × 1) × (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

= 220 ways

The chance of selecting 3 balls at random = 220

To find the chance that all the three balls are selected,

= [Chance of selecting (white ball) × Chance of selecting(blue ball) × Chance of selecting(red balls)]/ The chance/probability of drawing out 3 balls

Chance of selecting (white ball)= 4C1

Chance of selecting(blue ball) = 3C1 Chance of selecting(red balls) = 5C1

Hence,

= [4C1 × 3C1 × 5C1]/ 220

= 60/220

= 6/22

= 3/11

The chance that all three are selected is = 3/11

Answer:

a. 37 people respond "Yes"

b. 29 people respond "Yes"

c. 28 people respond "No"

Step-by-step explanation:

There was a sample of 46 oil industry executives who are selected for a questionnaire. There are total 46 executives so total number of answer will be either 46 or lesser. The questionnaire responses cannot be greater than 46. The possible responses can be 37 or 29 people responses "Yes" or 28 executive responses "No"

Answer:

x = 5

AC = 6

DC = 8

Step-by-step explanation:

∆ABC ~ ∆CDE

Therefore, [tex] \frac{AB}{ED} = \frac{AC}{DC} [/tex]

AB = 3

ED = 4

AC = x + 1

DC = x + 3

Plug in the values and solve for x:

[tex] \frac{3}{4} = \frac{x + 1}{x + 3} [/tex]

Cross multiply

[tex] 3(x + 3) = 4(x + 1) [/tex]

[tex] 3x + 9 = 4x + 4 [/tex]

[tex] 3x - 4x = -9 + 4 [/tex]

[tex] -x = -5 [/tex]

[tex] x = 5 [/tex]

Plug in the value of x and find AC and DC

AC = x + 1 = 5 + 1 = 6

DC = x + 3 = 5 + 3 = 8

Answer:

The conclusion about p using an absolute value inequality is  

   [tex]0.325 < p < 0.375[/tex]

Step-by-step explanation:

From the question we are told that

   The  sample proportion is  [tex]\r p = 0.35[/tex]

    The  margin of error is  [tex]E = 0.025[/tex]

The confidence interval is mathematically represented as

           [tex]\r p -E < p < \r p +E[/tex]

=>        [tex]0.35 - 0.025 < p < 0.35 + 0.025[/tex]

=>      [tex]0.325 < p < 0.375[/tex]