The protons, neutrons, and electrons are the three subatomic particles. Although electrons orbit the nucleus in various energy levels or shells, protons and neutrons are found inside the nucleus.
The three essential subatomic particles that make up an atom are protons, neutrons, and electrons. The neutral neutrons, which have no charge, and protons, which have a positive charge, are both present in the nucleus. The atomic number and identity of an element are determined by the quantity of protons in an atom. Although being negatively charged, electrons circle the nucleus in various energy levels or shells. An atom's chemical characteristics and behaviour are determined by its electron configuration. While the protons and neutrons in the nucleus contribute to the atomic mass, the electrons in the outermost shell are engaged in chemical processes. Studying the characteristics of matter requires an understanding of how these subatomic particles are arranged.
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a sample of helium gas has a volume of 620. ml at a temperature of 500. k. if we decrease the temperature to 100. k while keeping the pressure constant, what will the new volume be?
The new volume of the helium gas sample will be 124 ml. This is due to the fact that when the temperature decreases while the pressure remains constant, the volume of a gas will increase.
According to Charles’s law, the volume of a given gas at a constant pressure is directly proportional to its absolute temperature. Therefore, a decrease in temperature, while holding constant the pressure of the helium gas, would result in a decrease in volume.
A constant pressure is the one under which the pressure of a substance remains unchanged as the temperature and/or volume of the substance change. Charles's law may be used to explain the properties of gases, particularly with constant pressure since it states that the volume of a given mass of a gas is directly proportional to its absolute temperature, provided that its pressure remains constant. It's written as:V1/T1 = V2/T2; whereV1 = 620 ml; T1 = 500K; T2 = 100KLet's put the values in the formula given above. The [tex][tex]620/T1 = V2/100V2 = 62,000/500V2 = 124 ml[/tex].[/tex]Therefore, the new volume of helium gas at a temperature of 100K would be 124 ml.
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Which concept accounts for the whole-number subscripts in chemical formulas?A. law of multiple proportionsB. Avogadro's lawC. conservation of energyD. conservation of matte
Answer:
A)law of multiple proportions
Explanation:
combining 50 ml of vinegar with 500 ml of milk causes the vinegar, which is an acid, to react with the milk. the milk sours and thickens, creating cottage cheese. what kind of change is this?
answer choices
chemical
mechanical
physical
potential
A chemical alteration has occurred. A new material, cottage cheese, with distinct qualities from the original milk and vinegar is produced when the acid in the vinegar and the proteins in the milk react.
The change described is a chemical change. When vinegar, which is an acid, is combined with milk, a reaction occurs between the acid and the proteins in the milk. This reaction causes the milk to sour and thickens, resulting in the formation of cottage cheese. This change cannot be easily reversed, and the resulting cottage cheese is a new substance with different properties than the original milk and vinegar. This is a chemical change because the molecules in the milk and vinegar are rearranged to form a new substance, which has different chemical and physical properties than the original substances. This process is different from a physical change, such as melting ice, which does not result in the formation of a new substance.
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How many milliliters of 1.58 M HCl are needed to react completely with 23.2 g of NaHCO3 (= 84.02 g/mol)?
HCl(aq) + NaHCO3(s) ? NaCl(s) + H2O(l) + CO2(g)
a. 175 mL
b. 536 mL
c. 276 mL
d. 572 mL
e. 638 mL
c. 276 mL of 1.58 M HCl.
To answer this question, we need to use the mole ratio between the two reactants: 1 mole of HCl for every 1 mole of NaHCO3.
In this case, we need 23.2 g of NaHCO3, which is equal to 0.273 moles (23.2 g / 84.02 g/mol).
Since we need 1 mole of HCl for every 1 mole of NaHCO3, we can calculate the number of moles of HCl needed with the following equation: 0.273 moles of NaHCO3 x 1 mole HCl/1 mole NaHCO3 = 0.273 moles of HCl.
Now we can use the molarity of HCl (1.58 M) to calculate the volume of HCl needed. 1.58 M HCl x 0.273 moles HCl/1 L HCl = 0.433 L HCl, or 433 mL of HCl. Therefore, the correct answer is c. 276 mL of 1.58 M HCl.
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The density of a substance is 1.63g/mL. What is the mass of 0.25L of the substance in grams? A. 4.075g B. 40.75g C. 407.5g D. 4075g
Answer:
Explanation: Use the formula density = mass divided by volume
so to get the answer multiply the density by the volume
Answer: 1.63 x (0.25x1000)
we multiply 0.25 by 1000 because we need to use volume in ml instead of L.
what is the mechanism of action for the citrate synthase 2-part reaction? a. hydrolysis followed by condesation b. condensation followed by hydrolysis c. decarboxylation followed by hydrolysis d. decarboxylation followed by condensation
The mechanism of action for the citrate synthase 2-part reaction is decarboxylation followed by condensation.
This reaction is the first and the most critical reaction of the Krebs cycle, which is also called the tricarboxylic acid cycle or the citric acid cycle. The Krebs cycle is a series of enzymatic reactions that occur in the mitochondria of eukaryotic cells.
The Krebs cycle is critical in the metabolic process because it oxidizes the pyruvate generated during glycolysis, produces ATP and reduces coenzymes, and ultimately prepares substrates for the electron transport chain. It is a cyclic reaction consisting of eight steps, with citrate synthase catalyzing the first reaction.
The reaction mechanism of citrate synthase is as follows:
Citrate synthase catalyzes the conversion of acetyl CoA and oxaloacetate to citrate by a decarboxylation reaction followed by a condensation reaction. The decarboxylation reaction is the first step, in which acetyl-CoA loses its acetyl group in the form of carbon dioxide (CO2), producing the four-carbon compound oxaloacetate. This reaction is irreversible and is the rate-limiting step of the cycle. Citrate synthase then catalyzes the condensation reaction, in which the acetyl group of acetyl-CoA is added to the oxaloacetate molecule to form citrate, a six-carbon compound.The mechanism of action for the citrate synthase 2-part reaction is, therefore, decarboxylation followed by condensation.
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Question.05: (3 mrks) Neon gas in luminous tubes radiates red light-the original "neon light." The standard gas containers used to fill the tubes have a volume of 1.0 L and store neon gas at a pressure of 101 kPa at 22 °C. A typical luminous neon tube contains enough neon gas to exert a pressure of 1.3 kPa at 19 °C. If all the gas from a standard container is allowed to expand until it exerts a pressure of 1.3 kPa at 19 °C, what will its final volume be? If Lilia's sister Amelia is adding this gas to luminous tubes that have an average volume of 500 mL, what is the approximate number of tubes she can fill?
Answer:
Answer: The final volume of the gas will be 8.07 L.
Approximate number of tubes Amelia can fill = 8.07 L/500 mL = 16.14 tubes.
please help and give an explanation i don’t get it
The mass (in grams) of water, H₂O produced from 6.00 moles of hydrogen gas, H₂, is 108 g (last option)
How do i determine the mass of water produced?We'll begin by obtaining the mole of water produced from the reaction. Details below:
2H₂(g) + O₂ -> 2H₂O
From the balanced equation above,
2 moles of H₂ reacted to produce 2 moles of H₂O
Therefore,
6 moles of H₂ will also react to produce 6 moles of H₂O
Finally, we shall determine the mass of water, H₂O produced. Details below:
Molar mass of water, H₂O = 18 g/mol Mole of water, H₂O = 6 molesMass of water, H₂O = ?Mole = mass / molar mass
6 = Mass of water, H₂O / 16
Cross multiply
Mass of water, H₂O = 6 × 18
Mass of water, H₂O = 108 g (last option)
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a 3-year-old child is drawing with a pen and calls it a pencil. when she tries to erase her drawing, she becomes confused about why it is not erasing. this new piece of information does not fit with her current understanding about what a pencil is and leads to . select one: a. equilibrium b. disequilibrium
A) Equilibrium
The 3-year-old child is experiencing disequilibrium when she tries to erase her drawing with a pen and it does not erase. This is because her current understanding of a pencil does not fit with the new piece of information that it does not erase. Equilibrium occurs when a person is able to process new information and integrate it into their current understanding.
According to Piaget's cognitive development theory, the process by which a child's existing ideas are disrupted is called disequilibrium, which is option B.
What is cognitive development theory?
Cognitive development theory is a comprehensive theory that explains how children learn and acquire knowledge. This theory was created by psychologist Jean Piaget, who believed that cognitive growth is a gradual and ongoing process. According to Piaget, cognitive development refers to the gradual progression of thought processes, including problem-solving, attention, perception, and memory, that arise from biological development and environmental interaction. The process by which a child's existing ideas are disrupted is called disequilibrium. According to Piaget, when new information is discovered that does not fit into a person's existing schema, he or she may become disoriented or confused. This is referred to as disequilibrium. As a result, the person is compelled to adjust or adapt their schema to accommodate the new information. When this is accomplished, the person returns to a state of equilibrium. In the situation mentioned above, the child has a mental picture of what a pencil is in her head, but the pen does not meet her expectations. The child is thrown into a state of disequilibrium as a result of this confusion. The child may need to revise her schema in order to include pens. She will then restore her equilibrium once she has completed the revision process.
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Classify each titration curve as representing a strong acid titrated with a strong base, a strong base titrated with a strong acid, a weak acid titrated with a strong base, a weak basetaed with a strong acid, or a polyprotic acid titrated with a strong base. Strong acid/Strong base/ strong base Weak acid strong base Weak base Polyprotic acid strong acid strong acid strong base mL of titrant mL of titrant mL of titrant mL of titrant mL of titrant
When it comes to titration, a titration curve is the representation of the change in pH with regards to the volume of titrant added.
The point of equivalence is where the stoichiometric amount of titrant reacts completely with the analyte being titrated.
There are several types of titration curves. Below are the classifications of each titration curve:
Strong acid titrated with a strong base. The titration curve for this scenario starts out with a pH of around 3.0, which is the pH of a strong acid. The pH rises until the equivalence point is reached. The pH then drops steeply after the equivalence point.
Strong base titrated with a strong acid. In this titration curve, the pH starts off around .11, which is the pH of a strong base. The pH drops rapidly until the equivalence point is reached. The pH then rises steeply after the equivalence point.
Weak acid titrated with a strong base. In this titration curve, the pH starts off slightly acidic due to the presence of the weak acid. The pH rises gradually until the equivalence point is reached. The pH then increases steeply after the equivalence point.
Weak base titrated with a strong acid. The pH starts off slightly basic in this titration curve due to the weak base. The pH decreases gradually until the equivalence point is reached. The pH then drops steeply after the equivalence point.
Polyprotic acid titrated with a strong base. In this titration curve, there are more than one equivalence point because the acid is capable of releasing more than one hydrogen ion.
Each equivalence point represents the point at which one mole of H+ is neutralized.
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oxalic acid, which is present in rhubarb, was found to consist of 26.68% c, 2.24% h, and 71.08% o by mass. find the empirical formula for oxalic acid.
The empirical formula for oxalic acid is C2H2O2.
Oxalic acid, which is present in rhubarb, was found to consist of 26.68% C, 2.24% H, and 71.08% O by mass.
What is the empirical formula for oxalic acid?Empirical formula is the simplest formula that represents the composition of a compound in terms of atoms, and it can be obtained by calculating the ratio of atoms of each element in the compound.
The empirical formula of oxalic acid can be found by assuming 100 g of the compound so that the mass percent can be expressed as grams of each element. In the next step, these grams will be converted into moles for each element using their molar mass. The empirical formula will then be the ratio of atoms for each element in the compound.
Let's find out the number of moles of each element in oxalic acid.
C = 26.68 g = 26.68 / 12.01 = 2.22 molH = 2.24 g = 2.24 / 1.01 = 2.22 molO = 71.08 g = 71.08 / 16.00 = 4.44 mol
As the atomic ratios are the same for all three elements, the empirical formula is C2H2O2, and this formula is also called the simplest formula for oxalic acid. The empirical formula for oxalic acid is C2H2O2.
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an unknown mineral sample scratches fluorite but cannot scratch apatite. what is the approximate hardness of this mineral?
According to the Mohs scale of hardness, the unidentified mineral sample's hardness can be calculated to be between 4 and 5 if it can scratch fluorite but not apatite.
The Mohs hardness scale, a qualitative scale with 1 being the softest (talc) and 10 being the hardest, rates minerals according to their relative hardness (diamond). The scale is determined by a material's capacity to scrape another mineral. Any mineral with a lower number on the scale can be scratched, while a mineral with a greater number cannot be scratched. The unknown mineral must have a hardness between 4 and 5, as it can scratch fluorite (hardness of 4) but not apatite (hardness of 5). based upon With this knowledge, it is possible to estimate that the unidentified mineral has a Mohs hardness of about 4.5.
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If 110 grams of potassium chloride are mixed with 100 grams of water at 20°C, how much will not dissolve?
76 grams of potassium chloride will not dissolve in 100 grams of water at 20°C.
What is the solubility of the potassium chloride?
The solubility of potassium chloride in water at 20°C is approximately 34 grams per 100 grams of water.
So, if 100 grams of water can dissolve 34 grams of potassium chloride, then the maximum amount of potassium chloride that can be dissolved in 100 grams of water at 20°C is 34 grams.
Therefore, the amount of potassium chloride that will not dissolve in 100 grams of water at 20°C is:
110 grams - 34 grams = 76 grams
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citation chaining is a process for finding more articles that may be relevant for your research topic. which of these would be a good starting point for this process?
A good starting point for citation chaining would be a relevant and well-cited article or book that directly relates to your research the topic.
This article or book should have a comprehensive bibliography or the reference list that you can use to find additional sources. By examining the references cited in the original article, you can identify the other articles and books that are likely to be relevant to your research. Then, you can examine the references in those articles to find even more sources, continuing the process until you have a comprehensive set of relevant sources for your research.
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Complete the sentences to explain at what p range the ionization state in the previous part exists Match the words in the left column to the appropriate blanks in the sentences on the right. Reset Help 2.10 4.07 7.40 9.47 protonated deprotonated The ionization state will occur at a pH range of to This ionization state occurs in this range because, when the pH is greater than the pKs (by more than one unit), the compound is at that location. When the pH is less than the pKa. the compound is at that location
The ionization state will occur at a pH range of 2.10 to 9.47. The ionization state occurs in this range because, when the pH is greater than the pKa, the compound is deprotonated and when pH is less than pKa , the compound is protonated at that location.
Here is how the sentences should be completed to explain at what pH range the ionization state in the previous part exists:pH range of 7.40 to 9.47.The ionization state will occur at a pH range of 7.40 to 9.47.This ionization state occurs in this range because when the pH is greater than the pKs (by more than one unit), the compound is at that location.
When the pH is less than the pKa, the compound is protonated, and when the pH is greater than the pKa, the compound is deprotonated.Ionization state is the state of a chemical compound with ionizable functional groups when an atom or molecule loses or gains electrons.
To form a cation, an atom or molecule loses electrons, while to form an anion, an atom or molecule gains electrons.
The complete question is given below:
Complete the sentences to explain at what p range the ionization state in the previous part exists.
Match the words given below to the appropriate.
Reset Help: (2.10, 4.07, 7.40, 9.47, protonated, deprotonated)
The ionization state will occur at a pH range of ____ to _____. This ionization state occurs in this range because, when the pH is greater than the pKs (by more than one unit), the compound is ______ at that location. When the pH is less than the pKa. the compound is ______ at that location
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At the resting membrane potential, the membrane is most permeable to ________, which moves ________ the cell due to its A) chloride : into B) potassium : into C) sodium : out of D) sodium : into E) potassium : out of
At the resting membrane potential, the membrane is most permeable to potassium ions (K+), which move out of the cell due to its concentration gradient and the negative charge inside the cell. Correct answer is option: E.
This movement of K+ ions out of the cell contributes to the negative resting membrane potential of approximately -70 mV in most cells. The resting membrane potential is maintained by the selective permeability of the cell membrane, which allows for the movement of certain ions across the membrane. In general, the membrane is less permeable to sodium (Na+) and chloride (Cl-) ions at rest, and the movement of these ions across the membrane is limited. Thus, option E "potassium" is the correct answer.
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a) Identify a possible mechanism. b) Define catalyst c) Determine the general order of the reaction. 4. For the reaction at equilibrium: 3Fe+410 Fe,0+4H a) Write the expression of the equilibrium constant. b) Show how the speed of the direct and indirect reaction changes, if the pressure increases 3 times. e) Argue whether the chemical equilibrium shifts when the pressure increases 3 times. (4 points)
3. a) One possible mechanism for this reaction is: 3 Fe + 4 H₂O ⇌ Fe₃O₄ + 4 H₂
b) A catalyst is a substance that increases the rate of a chemical reaction without undergoing any permanent chemical change itself.
c) second-order reaction.
4. a) The expression of the equilibrium constant for the given reaction is:
Kc = ([Fe₃O₄][H₂]⁴) / ([Fe]³[H₂O]⁴)
b) Increasing the pressure will favor the indirect reaction and slow down the direct reaction.
c) Since the indirect reaction is favored by the increased pressure, the chemical equilibrium will shift to the right, towards the product side.
How to express order of reaction?The method of initial rates involves measuring the initial rate of the reaction under different initial concentrations of the reactants. By comparing the initial rates, we can determine the order of the reaction with respect to each reactant.
Assuming that the rate law of the reaction is:
rate = k[Fe]^x[H₂O]^y
where k is the rate constant, and x and y are the orders of the reaction with respect to Fe and H2O, respectively.
Experimentally, measure the initial rate of the reaction under different initial concentrations of Fe and H₂O while keeping the concentration of the other reactant constant.
For example, suppose we measure the initial rates of the reaction at the following initial concentrations:
Experiment #1: [Fe] = 0.1 M, [H₂O] = 0.2 M, initial rate = 0.005 M/s
Experiment #2: [Fe] = 0.2 M, [H₂O] = 0.2 M, initial rate = 0.02 M/s
Experiment #3: [Fe] = 0.4 M, [H₂O] = 0.2 M, initial rate = 0.08 M/s
Use the rate data to determine the orders of the reaction with respect to Fe and H₂O. To do this, we compare the initial rates of the reaction under different initial concentrations of Fe and H₂O while keeping the concentration of the other reactant constant.
Suppose we double the concentration of Fe while keeping the concentration of H₂O constant. According to experiment 2 and experiment 1, the rate of the reaction doubles. This means that the order of the reaction with respect to Fe is 1.
Similarly, if we double the concentration of H₂O while keeping the concentration of Fe constant, we can see that the rate of the reaction doubles from experiment 1 to experiment 3. This means that the order of the reaction with respect to H₂O is also 1.
Therefore, the overall order of the reaction is the sum of the orders of the reactants, which is:
overall order = 1 + 1 = 2
Hence, the given reaction is a second-order reaction.
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The complete question is:
3. For the reaction at equilibrium: 3Fe+410 Fe,0+4H a) Identify a possible mechanism. b) Define catalyst c) Determine the general order of the reaction. 4. For the reaction at equilibrium: 3Fe+410 Fe,0+4H a) Write the expression of the equilibrium constant. b) Show how the speed of the direct and indirect reaction changes, if the pressure increases 3 times. e) Argue whether the chemical equilibrium shifts when the pressure increases 3 times. (4 points)
2 C2H6 + 7 O2 -> 4 CO2 + 6 H2O
Use the given equation for the following questions:
If 20 moles of fuel are combusted in the above equation, how many moles of O2 are consumed?
If 20 moles of fuel are combusted in the above equation, how many moles of CO2 are produced?
Answer:
Hope it's correct
Explanation:
2 mol of C2H6 = 7 mol of O2
So 20 mol of C2H6 = ? (20/2)*7 = 70 mol
PLS HELP!!!
Match the terms to the appropriate definitions or descriptions
1. - c. Absolute dating
2. - k. Zircon
3. - m. Meteorites
4.- h. Compression melting
5. - e. Relative dating
6. - a. An igneous intrusion
7. - g. Unconformity
8. - d. Index fossils
9. - f. The Grand Canyon
10.- b. Iguazu Falls in Argentina
11. -h. Yosemite Valley
12.- i. Carbon 14 dating
13.-c. Radiometric dating
What is Carbon 14 dating?Carbon 14 dating, also known as radiocarbon dating, is a technique used to determine the age of organic materials based on their content of the radioactive isotope carbon-14. Carbon-14 is a naturally occurring isotope of carbon that is formed in the upper atmosphere by the interaction of cosmic rays with nitrogen atoms. This carbon-14 is incorporated into carbon dioxide molecules, which are then taken up by plants during photosynthesis and subsequently passed on to animals that eat those plants.
When an organism dies, it stops taking in carbon-14, and the carbon-14 in its tissues begins to decay into nitrogen-14 at a known rate. By measuring the amount of carbon-14 that remains in the sample, scientists can determine how long it has been since the organism died.
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The enthalpy of vaporization for water is 40.7 kJ/mol. Water has a vapor pressure of 101.3 kPa at 100.0 °C. Using the Clausius-Clapeyron equation, what is the vapor pressure for methanol at 73.5°C? Give your answer in KPa, to the first decimal point.
Answer:
The Clausius-Clapeyron equation is given by:
ln(P2/P1) = -(ΔHvap/R) * (1/T2 - 1/T1)
where P1 and T1 are the vapor pressure and temperature of the substance at one point, P2 and T2 are the vapor pressure and temperature at another point, ΔHvap is the enthalpy of vaporization, and R is the gas constant.
We can use this equation to find the vapor pressure of methanol at 73.5°C, given the vapor pressure of water at 100.0°C.
First, we convert the temperatures to Kelvin:
T1 = 100.0°C = 373.2 K
T2 = 73.5°C = 346.7 K
Next, we substitute the values into the equation, along with the enthalpy of vaporization for methanol and the gas constant:
ln(P2/101.3 kPa) = -(35.2 kJ/mol / 8.314 J/(mol*K)) * (1/346.7 K - 1/373.2 K)
Simplifying, we get:
ln(P2/101.3 kPa) = -5.631
Taking the exponential of both sides, we get:
P2/101.3 kPa = e^(-5.631)
P2 = 101.3 kPa * e^(-5.631)
P2 = 2.784 kPa
Therefore, the vapor pressure of methanol at 73.5°C is approximately 2.784 kPa, to the first decimal point.
The equation for the combustion of propane is elven below
C}Hs (g) +
5
02 (g)
3
CO, (g) +
4
H20 (g)
a. Use the law of conservation of mass to balance the equation, and place the appropriate coefficients in front of each species in the equation.
b. For each molar quantity given in the table below, provide the number of moles of the other reactants or products
nocossarv for comolete reaction to ake Dace.
The coefficients that would balance the reaction equation is;
C3H8 + 5O2 → 3CO2 + 4H2O
How do you balance a reaction equation?
Here are the steps to balance a chemical equation:
Write the unbalanced chemical equation using the correct chemical formulas for the reactants and products.
Count the number of atoms of each element on both the reactant and product sides of the equation.
Start by balancing the atoms of the most complex or least common element in the equation, such as oxygen or hydrogen.
Balance the element by adding coefficients (whole numbers) in front of the formulas for the reactants or products.
Repeat this process for each element in the equation until the number of atoms of each element is equal on both sides.
Double-check your work by counting the number of atoms of each element and making sure they are balanced.
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The codons in mRNA specify the amino acids that are used to make a protein. Mark the following statement concerning translation TRUE or FALSE.
TRUE. The codons in mRNA, which are collections of three nucleotides, stand for certain amino acids that are combined to produce proteins during translation.
In order to create a protein, the information contained in mRNA must be deciphered during the process of translation. The genetic code that regulates the order in which amino acids are put together to make proteins is found in the sequence of nucleotides in mRNA known as codons. A codon is made up of three nucleotides, each of which stands for an amino acid or a stop signal that denotes the completion of protein synthesis. The ribosome scans the mRNA's codon sequence during translation and matches each codon with the appropriate amino acid. A functional protein is produced when a chain of amino acids that have been joined together by peptide bonds folds into a three-dimensional structure. Hence, the codons in mRNA play a critical role in determining the amino acid sequence of a protein.
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Phosphorus reacts with oxygen to form diphosphorus 4P(s)+5O2(g)⟶2P2O5(s) How many grams of P2O5 are formed when 7.65 g of phosphorus reacts with excess oxygen? Show the unit analysis used for the calculation by placing the correct components into the unit-factor slots.
17.51 g of P2O5 is formed when 7.65 g of phosphorus reacts with excess oxygen. Unit analysis used for the calculation:
What is unit analysis?Unit analysis or dimensional analysis is a mathematical method to convert one unit to another unit. It is based on the idea of multiplying by a conversion factor, which is a fraction in which the same quantity is expressed in two different units.
Balanced equation: 4P(s)+5O2(g)⟶2P2O5(s)
Molar mass of P = 30.97 g/mol
Molar mass of P2O5 = 141.94 g/mol
Number of moles of P = given mass / molar mass
Number of moles of P = 7.65 g / 30.97 g/mol
Number of moles of P = 0.24674 mol
Number of moles of P2O5 = (number of moles of P) / (4 mol of P produces 2 mol of P2O5)
Number of moles of P2O5 = 0.24674 mol / 2Number of moles of P2O5 = 0.12337 mol
Mass of P2O5 = number of moles of P2O5 × molar mass of P2O5
Mass of P2O5 = 0.12337 mol × 141.94 g/mol
Mass of P2O5 = 17.51
Thus, 17.51 g of P2O5 is formed when 7.65 g of phosphorus reacts with excess oxygen.
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True or False: The zeolite that you will make and use has repeating and alternating tetrahedral units of SiO4 and AlO4 bonding through the oxygen atoms.
The zeolite that you will make and use has repeating and alternating tetrahedral units of SiO4 and AlO4 bonding through the oxygen atoms. Therefore, the given statement is true.
Zeolites have repeating and alternating tetrahedral units of SiO4 and AlO4 bonding through the oxygen atoms.Zeolites are aluminosilicate minerals that are mostly found in volcanic rocks and soils.
They have a distinctive and extensive network of pores and channels. Zeolites are also used in ion exchange, adsorption, and catalysis processes as a result of their porous and chemically active structure. Zeolites are extensively employed in the separation, adsorption, and catalytic conversion of petroleum-based products, as well as in waste-water treatment processes. Zeolite is a naturally occurring mineral. However, it may also be synthesized in a laboratory. Zeolites are widely used in several applications due to their porous and chemically active structure.
These applications include gas separation, petroleum refining, catalysis, and water purification. They are used to adsorb impurities, filter out toxic gases, and remove radioactive particles from water.
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2Na + 2H2O → 2NaOH + H2
What is the total number of moles of hydrogen produced when 4 moles of sodium react completely?
A. 1 B. 2 C. 3 D. 4
When 4 moles of sodium fully react, 2 moles of hydrogen are produced as a whole. The right answer is B.
The balanced equation for the reaction between sodium and water is 2Na + 2H2O → 2NaOH + H2. This equation shows that 2 moles of sodium react with 2 moles of water to produce 1 mole of hydrogen gas.
If 4 moles of sodium react completely, we can calculate the amount of hydrogen produced by using stoichiometry. Since 2 moles of sodium produce 1 mole of hydrogen, 4 moles of sodium will produce 2 moles of hydrogen (4 moles Na x 1 mole H2 / 2 moles Na = 2 moles H2).
Therefore, the total number of moles of hydrogen produced when 4 moles of sodium react completely is 2 moles. The correct answer is B.
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which of these interactions might form between two polar molecules? [select all that apply.] group of answer choices hydrogen bonding dispersion forces dipole-dipole interactions
The following interactions might form between two polar molecules Hydrogen bonding Dipole-dipole interactions.
Hydrogen bonding is a type of attractive interaction that forms between a hydrogen atom and a highly electronegative atom (such as nitrogen, oxygen, or fluorine) on another molecule. As a result, two polar molecules can form hydrogen bonds. Dipole-dipole interactions occur between polar molecules when the positive end of one molecule is attracted to the negative end of another molecule. Hence, dipole-dipole interactions can also form between two polar molecules. Dispersion forces occur in all types of molecules, but they are not unique to polar molecules. Therefore, dispersion forces cannot form between two polar molecules. Conclusively, hydrogen bonding and dipole-dipole interactions are the interactions that might form between two polar molecules.
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what is the difference in the various bohr radii rn for the hydrogen atom, where n is the principle quantum number, a. between r1 and r2? b. between r5 and r2? c. between r5 and r6? d. between r10 and r11?
The principle quantum number (n) of an electron in an atom determines the size of its associated Bohr radius. Specifically, the Bohr radius is inversely proportional to n, meaning the higher the n, the smaller the Bohr radius. Therefore, the difference between Bohr radii will increase with increasing n.
a. Between r1 and r2: The difference between r1 and r2 is that r2 is half the size of r1, as n has increased from 1 to 2.
b. Between r5 and r2: The difference between r5 and r2 is that r5 is a fifth of the size of r2, as n has increased from 2 to 5.
c. Between r5 and r6: The difference between r5 and r6 is that r6 is a sixth of the size of r5, as n has increased from 5 to 6.
d. Between r10 and r11: The difference between r10 and r11 is that r11 is an eleventh of the size of r10, as n has increased from 10 to 11.
a. The difference between r1 and r2 is calculated by substituting n = 1 and n = 2 respectively into the expression for the Bohr radius.
b. The difference between r5 and r2 is calculated by substituting n = 2 and n = 5 respectively into the expression for the Bohr radius.
c. The difference between r5 and r6 is calculated by substituting n = 5 and n = 6 respectively into the expression for the Bohr radius.
d. The difference between r10 and r11 is calculated by substituting n = 10 and n = 11 respectively into the expression for the Bohr radius.
The Bohr radius is given by the expression r = n2ℏ2me4πϵ0 where n is the principal quantum number, ℏ is the reduced Planck constant, me is the mass of the electron, π is the mathematical constant pi, and ϵ0 is the vacuum permittivity.
We can use this expression to calculate the Bohr radius for different values of n, and then calculate the differences between the Bohr radii for different values of n.
For example, the difference between r1 and r2 is given byr2 - r1 = 22ℏ2me4πϵ0 - 12ℏ2me4πϵ0= 4ℏ2me4πϵ0
Similarly, the difference between r5 and r2 is given byr5 - r2 = 52ℏ2me4πϵ0 - 22ℏ2me4πϵ0= 21ℏ2me4πϵ0
The differences between r5 and r6, and between r10 and r11 can be calculated in the same way.
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photosystem ii receives replacement electrons from molecules of
Photosystem II receives replacement electrons from molecules of water (H2O) during the light-dependent reactions of photosynthesis.
Photosystem II (PSII) is a protein complex found in the thylakoid membrane of chloroplasts in photosynthetic organisms. It plays a critical role in the light-dependent reactions of photosynthesis by harnessing energy from sunlight to split water molecules into oxygen, protons, and electrons. The replacement electrons for PSII are derived from the oxidation of water molecules. This process, known as photolysis, involves the transfer of electrons from water molecules to PSII, replenishing the electrons lost during light-dependent reactions. As a result, water is converted into oxygen gas, which is released into the atmosphere as a byproduct of photosynthesis.
In summary, molecules of water provide the replacement electrons required by PSII to maintain the flow of electrons during the light-dependent reactions of photosynthesis.
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what relative masses of dimethyl amine and dimethyl ammonium chloride do you need to prepare a buffer solution of ph = 10.54?
To prepare a buffer solution of pH = 10.54, the relative masses of dimethyl amine and dimethyl ammonium chloride needed are 0.079 g and 0.067 g respectively.
A buffer solution is a solution that has the ability to resist changes in pH upon the addition of small amounts of acid or base. A buffer solution contains a weak acid and its conjugate base or a weak base and its conjugate acid. It can be prepared by mixing equal volumes of a weak acid and its conjugate base or a weak base and its conjugate acid.
Dimethyl amine is an organic compound with the formula (CH3)2NH. It is a weak base and can act as a proton acceptor. Dimethyl ammonium chloride is an organic compound with the formula (CH3)2NH2Cl. It is a salt of a weak base and a strong acid and can act as a proton donor.
Calculation of relative masses:
The pKa of dimethyl amine is 10.73.
To prepare a buffer solution of pH = 10.54,
the ratio of [A-]/[HA] should be 1/9.
Using the Henderson-Hasselbalch equation;
pH = pKa + log([A-]/[HA])10.54 = 10.73 + log([A-]/[HA])
log([A-]/[HA]) = -0.19[A-]/[HA] = 0.67/1.00
The sum of the masses of dimethyl amine and dimethyl ammonium chloride is 0.146 g. The ratio of their masses is 0.67:1.00.
So, the relative masses of dimethyl amine and dimethyl ammonium chloride needed are 0.079 g and 0.067 g respectively.
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What volume of 0.125 M HNO3, in milliliters, is required to react completely with 1.70 g of Ba(OH)2? 2 HNO3(aq) + Ba(OH)2(s) Ba(NO3)2(aq) + 2 H2O(l)
Answer:
What volume of 0.125 M HNO3, in milliliters, is required to react completely with 1.70 g of Ba(OH)2? 2 HNO3(aq) + Ba(OH)2(s) Ba(NO3)2(aq) + 2 H2O(l)
Explanation:
The complete and balanced chemical equation for the reaction of nitric acid
H
N
O
3
with barium hydroxide
B
a
(
O
H
)
3
is given by
2
H
N
O
3
(
a
q
)
+
B
a
(
O
H
)
2
→
B
a
(
N
O
3
)
2
(
a
q
)
+
2
H
2
O
(
a
q
)
The volume of a certain concentration of nitric acid
H
N
O
3
required to react with a particular amount of
B
a
(
O
H
)
2
is obtained by first calculating the number of moles of
H
N
O
3
using stoichiometry. Using the molar mass of
B
a
(
O
H
)
2
,
M
M
B
a
(
O
H
)
2
=
171.3
g
/
m
o
l
,
and the mole ratio
2
m
o
l
H
N
O
3
1
m
o
l
B
a
(
O
H
)
2
,
then
{eq}\begin{align} \rm moles\ of\ HNO_3...
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