Velocity is vector quantity because??​

Answers

Answer 1

Velocity is vector quantity because it has both magnitude and direction.

Answer 2

Explanation:

velocity is a vector quantity because the person always returns to the original position,the motion would never result in a change in a position.


Related Questions

An observer is standing next to the tracks, watching a train approach. The train travels at 30 m/s and blows its whistle at 8,000 Hz as it approaches and then passes by the observer without slowing down. Assuming the speed of sound is 340 m/s, how much of a frequency change did the observer hear?

Answers

7351.35Hz

f0= v-Vo/v-Vs × FSA

= 340-0 /340+30 ×8000

= 340/370× 8000

= 7351.35hz

Which solution has the greatest number of hydrogen ions?

blood, pH = 7.2
lemon juice, pH = 2
soda, pH = 3.5
bleach, pH = 13.5

Answers

Answer:

lemon

Explanation:

the lower the number the hier hydrogen ions

Answer: B

Explanation:

how do atoms lose electrons ?

Answers

Atoms lose electrons by a process called ionic bonding. Specifically, the metal atom donates its electron to a non-metal atom and thus takes on the noble gas electron configuration of the noble gas in the period (row of the periodic table) preceding its own.

Answer:

Explanation:

By being close to an atom that will gladly take the electrons being offered.

Suppose you are talking about Be. It is in the second column. It has two outer electrons that can be given away. It will not give away one of the two remaining electrons because they are too close to the + nucleus.

Along comes a Fluorine atom. It has 7 electrons in its outer ring. The chemistry of the situation allows it to take on one of the two electrons Be is offering. It is all a matter of charges and attractions.

Another Fluorine atom will take on the remaining electron from the Be. The outer ring cannot take on more than 1 electron, but that is enough

9. Which of the following is NOT a recommendation to help you succeed in this course?
Consistently and actively work in the course on a daily basis.
Wait until the end of the semester to complete all work.
Complete all assignments in a timely manner.
Contact your instructor if you have questions.

Answers

Answer:

Wait until the end of the semester to complete all work.

Explanation:

this is the obvious answer.

please mark me brainliest

Answer:

Wait until the end of the semester to complete all work

Which of the following is an exa example of a wave

Answers

Longitudinal waves

Transverse waves

Electromagnetic Waves

Water waves

Rope waves

LIght Waves

5. Tại sao khi lặn ta luôn cảm thấy tức ngực và càng lặn sâu thì cảm giác tức ngực càng tăng? A. Ap suất của nước giảm ​​B. Ap suất không khí tăng C. Ap suất không khí giảm ​​D. Ap suất của nước tăng

Answers

Answer:

c and d

Explanation:

obviously kksxsxksxkskxkskxksxksxsxsxsxsxsxsxs

Give reason Pascal is a derived unit​

Answers

Answer:

Pascal is a derived unit because it cannot be expressed in any physics terms, but it is an expression of fundamental quantities.

Explanation:

[tex]{ \sf{Pasacal \: ( Pa) = \frac{newtons}{metres {}^{2} } }} \\ \\ { \sf{Pasacal \: (Pa) = \frac{kg \times {ms}^{ - 2} }{ {m}^{2} } }}[/tex]

If we increase the surface area of a given surface without changing the force acting on it, then the pressure acting on it will ______ (increase/decrease/remain the same)

Answers

Answer:

Decrease

Explanation:

The pressure is the force per unit area. So, P=F/A

Thus the pressure P is inversely proportional to contact area A.

So when area increases , the pressure will be decreasing.

The hydro power plant transforms one form of energy into another. However, the total amount
of energy of the water stays the same until it enters the turbine.

Explain how this statement is supported by the three column charts above.

*attached is the column charts

Answers

The hydro power plant consists of a (artificial) dam that builds gravitational potential energy, P.E. from natural flowing water sources, by locating the dam along the water path. The stored potential energy, P. is converted into kinetic energy, K.E. as the water falls from the dam, down to the turbines, located at a much lower level according to the following principle of conservation of energy equation;

Total Mechanical Energy, M.E. = The potential energy of the water, P.E. + The kinetic energy of the water, K.E. = Constant

M.E. = P.E. + K.E. = Constant

Where;

P.E. = m·g·h

K.E. = (1/2)·m·v²

m = Mass

g = The acceleration due to gravity

h = The height of the dam

v = The velocity

The charts can be explained as follows;

Given that the potential energy P.E. = m·g·h, we have that the potential energy is directly proportional to the height of the dam, and therefore, at mid height, the potential energy would be half the maximum value, and we have;

At mid height, P.E. = (1/2)·[tex]\mathbf{P.E._{max}}[/tex]

At the top of the dam, the (vertical) velocity of the water = 0, therefore, the kinetic energy = 0

Therefore, at the top of the dam, we get;

M.E. = [tex]P.E._{max}[/tex] + 0 =

M.E. = [tex]\mathbf{P.E._{max}}[/tex]

Similarly, at the bottom of the dam, the height, h = 0, therefore, being proportional to the height, P.E. = 0, and the velocity is maximum, and at the bottom, we have;

M.E. = 0 + [tex]K.E._{max}[/tex]

The first chart, water is halfway down the dam

At the halfway down therefore, we have;

P.E. = (1/2)·[tex]\mathbf{P.E._{max}}[/tex]

M.E. = [tex]P.E._{max}[/tex] = (1/2)·

∴ K.E. = [tex]P.E._{max}[/tex] - (1/2)·

Therefore the first chart, water is halfway down the dam;

Halfway, K.E. = (1/2)·[tex]\mathbf{P.E._{max}}[/tex] = P.E.

K.E. = P.E.  as shown on the chart

The second chart, water has reached the turbine

Water reaches the turbine at the bottom, and as explained above, we get;

M.E. = 0 + [tex]K.E._{max}[/tex]

∴ M.E.≈ [tex]K.E._{max}[/tex]

Therefore, when water has reached the turbine at the bottom of the dam, the kinetic energy is approximately proportional to the total mechanical energy as shown in the chart

The third chart, water is at the top of the dam

Here as shown above, we have;

The total mechanical energy, M.E. ≈ [tex]\mathbf{P.E._{max}}[/tex] as shown on the chart

Learn more about potential and kinetic energy here;

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A pulley system is made of 3 pulley write its velocity ratio

Answers

Almost 3 times fast than normal pulley system

mark me

3 times fasten than normal pulley

A jet airplane is in level flight. The mass of the airplane is m=8950 kg. The airplane travels at a constant speed around a circular path of radius R=9.33 mi and makes one revolution every T=0.123 h. Given that the lift force acts perpendicularly upward from the plane defined by the wings, what is the magnitude of the lift force acting on the airplane?

Answers

Answer:

The net force is 91780.8 N.

Explanation:

mass, m = 8950 kg

Radius, R = 9.33 miles = 15015.2 m

Time, T = 0.123 h = 442.8 s

There are two forces acting on the plane.

Horizontal force is the centripetal force and the vertical force is the weight.

[tex]Fx =m R w^2\\\\Fx = m R \frac{4\pi^2}{T^2}\\\\Fx = 8950\times 15015.2\times \frac{4\times 3.14\times 3.14}{442.8\times 442.8}\\\\Fx = 27030.8 N \\\\Fy = m g \\\\ Fy = 8950\times 9.8 \\\\Fy = 87710 N[/tex]

The net force is

[tex]F = \sqrt{Fx^2 + Fy^2}\\\\F = \sqrt {27030.8^2 + 87710^2}\\\\F = 91780.8 N[/tex]

Q2.
1.0 kg of ice at -10°C is added to 10 g of water at 0°C.
(a)
Find the final temperature of the mixture. (The specific latent heat of fusion of
ice is 336 J/g and the specific heat capacity of ice is 2000 J kg K-1)


Please help

Answers

Answer:

gsbddgshdhsghhdhdhvvs

Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?​

Answers

Answer:

Explanation:

(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m/150s=2ms^−1. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m.

Hence, his average velocity is 300m/150s=2ms^−1

(b) Then it is given that he turns back and points B and jogs on the same road but in the opposite direction for a time interval for 1 minute and covers a distance of 100m.If we consider the whole motion of Joseph, i.e. from point A to point C, then he covers a total distance of 300m+100m=400m. And he covers this total distance in a time interval of 2.5min+1min=3.5min=210s.

Therefore, his average speed for this journey is 400m210s=1.9ms−1.

For the same journey is displacement is equal to the distance between the points A and C,i.e. 300m−100m=200m.

Hence, his average velocity for this case is 200m/210s=0.95ms^−1

how is pressure and density related?

Answers

Answer:

Density is directly proportional to pressure

Explanation:

As pressure increases (with constant temperature), density also increases.

Density is inversely proportional to temperature.

A car horn creates a 595 Hz tone at rest. Two cars pass on the street, each going 20.0 m/s; the first car honks. What frequency does the other car hear before they pass each other?

Answers

Doppler frequency, the other car hear before they pass each other is 668.68 Hz.

What is frequency?

Frequency is the number of occurrences of a repeating event per unit of time.

What is Doppler EFFECT?

The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source.

According to the Doppler Effect, the frequency observed is

  [tex]fo=fs\frac{v+v_{o} }{v-v_{s} }[/tex]

[tex]f_{o}=595\frac{343+20 }{343-20 }\\f_{o} = 668.68 Hz[/tex]

To know more about Doppler Effect here

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find the expression for the displacement covered in nth or in last one second​

Answers

Answer:

Snth = u + a/2 ( 2n - 1)

Explanation:

Do you need explanation based on graph, integration or other method?

A force of 150N at an angle of 60 degree to the horizontal to pull a box through a distance of 50m calculate the work done

Answers

Force=150NAngle=60°Displacement=50m

[tex]\boxed{\sf W=Fscos\Theta}[/tex]

[tex]\\ \sf\longmapsto W=150(50)cos 60[/tex]

[tex]\\ \sf\longmapsto W=7500\times \dfrac{1}{2}[/tex]

[tex]\\ \sf\longmapsto W=3750J[/tex]


In order to find the resultant of two vectors we must use the pythagoran therom, a +b2-2. Where the crepresents the resultant vector

Answers

Answer:

Furthermore, the Pythagorean theorem works when the two added vectors are at right angles to one another - such as for adding a north vector and an east vector.

Solve for M₂

Base Equation: M₂ = Fr²/GM₁

F = 132N, G = 6.67 x 10⁻¹¹ Nm²/kg², r = .243m, and M₁ = 1.175 x 10⁴ kg, then what is M₂ = ?

Answers

Explanation:

M₂ = Fr²/GM₁

M₂ = [(132N)(.243m)²]/[(6.67*10^-11N*m²/kg)(1.175*10^4kg)]

M₂ = (7.79N*m²)/(7.84*10^-7N*m²)

M₂ = 9.94*10^6 kg

An imaginary star is four light years from earth. The star has a planet, upon which a large mirror has been installed. The mirror faces earth. A ten year old boy aims his telescope at the mirror. How old will the boy be when he sees his own reflection?

Answers

Answer:

14 years

Explanation:

because the light will take four years to reach the earth. And the star is four light years away from the earth.

Hope that helps you please follow

An imaginary star is four light years from earth. The star has a planet, upon which a large mirror has been installed. The mirror faces earth. A ten year old boy aims his telescope at the mirror,then the boy would be 14 years old when he will see his own reflection.

What is a light year?


It can be defined as the distance travelled by the light in one year .it is represented in units of distance such as miles or km.

1 light year is calculated by multiplying the speed of light with the time of one year

1 light year = speed of light × one year time period

1 light year = 3×10⁸ ×(365×24×60×60)

                  =9.461× 10¹⁵ meter


As given in the problem 10 year old boy aims his telescope at the mirror which is 4 light years away then the light has to travel four years to reach the boy ,then the boy would be 14 year old when he would see his own reflection.
Learn more about light year from here

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List two factors that compression force depends on ​

Answers

The magnitude (size or numerical value) and the direction.

Hope this helps!!! :)

A rod is made up of copper and wood joined together.
After the rod is heated at the join in the centre for about a minute, where would the lowest temperature be?

Answers

my views

Explanation:

Figure (8) shows a rod made up of copper and wood joined together. The rod is heated at the joint in the centre for about a minute. At which point – A, B, C or D, would it show the lowest temperature? PLEASE GIVE REASONS ALSO(MINIMUM 2)

A person has power of 550 watt. What does it mean? ​

Answers

Answer:

It means that person can do work or can posses energy at a rate of 550 watts.

Or : can posses energy of 550 joules in one second.

Explanation:

[tex]{ \bf{power = \frac{work}{time} }}[/tex]

mercury is commonly used in thermometer give reasons​

Answers

Answer:

hi

BECAUSE MERCURY IS USED BECAUSE IT is the only liquid available in room temperature

Explanation:

pls mark as a BRAINLIST

Please help (I didn’t know what subject to put this in but it’s earth science)

Answers

Spring summer and USA for the first 2
2. The answer is USA! https://www.netweather.tv/weather-forecasts/news/10277-tornado-facts-which-countries-have-the-most-and-the-deadliest-tornadoes

I think 1. Is A.

3. F5

4. A.

any person who opens the door he applies​

Answers

Answer:

any person who opens the door he applies pulling force

a busis moving with the initial velocity 10m/s . after 4 seconds, the velocity becomes 30m/s . find the acceleration produce by bus,......please I need help​

Answers

Answer:

5 m/s²

Explanation:

Use the acceleration formula: [tex]a=\frac{v_f-v_i}{t}[/tex]

a = acceleration (m/s²)vf = final velocity (m/s)vi = initial velocity (m/s)t = time (s)

Based on the information given to us by the prompt, we know:

vi = 10 m/svf = 30 m/st = 4 s

Substitute these values for the variables to calculate the acceleration:

[tex]a=\frac{30-10}{4}\\\\a=\frac{20}{4}\\\\a=5[/tex]

Therefore, the acceleration of the bus is 5 m/s².

Give reason.


b} String roller is an example of wheel and axel .Why?

Answers

Explanation:

string roller is called an example of wheel and axel because The thin rod which needs to be turned is called the axle and the wider object fixed to the axle, on which we apply force is called the wheel.

hence the we apply force on the roller and the string gets tight.

Ley de Charles-.
1) En un recipiente hermético se tiene 150 ml de una sustancia gaseosa, a una temperatura de 115°C, esto como resultado de una reacción. ¿Cuál sería su volumen inicial, cuando su temperatura era de 100°C?



2) Al inicio cuando la temperatura es de 200°C, se tienen 350 ml de un gas “Y”. ¿Qué volumen se obtendrá si la temperatura se incrementa a 250°C?

Answers

Tomando en cuenta la Ley de Charles y la condiciones dentro del recipiente, tenemos las siguientes conclusiones con respecto al volumen del recipiente:

1) El volumen inicial del gas es 144.203 mililitros.

2) El volumen final del gas es 386.986 mililitros.

La Ley de Charles establece que el Volumen de un gas es directamente proporcional a su Temperatura, basados en este hecho, podemos resolver los problemas en cuestión mediante la siguiente relación matematica:

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex] (1)

Donde:

[tex]V_{1}[/tex] - Volumen inicial, en mililitros.

[tex]V_{2}[/tex] -  Volumen final, en mililitros.

[tex]T_{1}[/tex] - Temperatura inicial, en Kelvin.

[tex]T_{2}[/tex] - Temperatura final, en Kelvin.

1) Si sabemos que [tex]V_{2} = 150\,mL[/tex], [tex]T_{2} = 388.15\,K[/tex] and [tex]T_{1} = 373.15\,K[/tex], entonces el volumen inicial del gas es:

[tex]V_{1} = \frac{T_{1}}{T_{2}}\times V_{2}[/tex]

[tex]V_{1} = \frac{373.15\,K}{388.15\,K}\times 150\,mL[/tex]

[tex]V_{1} = 144.203\,mL[/tex]

El volumen inicial del gas es 144.203 mililitros.

2) Si sabemos que [tex]T_{1} = 473.15\,K[/tex], [tex]V_{1} = 350\,mL[/tex] and [tex]T_{2} = 523.15\,K[/tex], entonces el volumen final del gas es:

[tex]V_{2} = \frac{T_{2}}{T_{1}}\times V_{1}[/tex]

[tex]V_{2} = \frac{523.15\,K}{473.15\,K}\cdot 350\,mL[/tex]

[tex]V_{2} = 386.986\,mL[/tex]

El volumen final del gas es 386.986 mililitros.

He aquí una pregunta relacionada con la Ley de Charles: https://brainly.com/question/21184611

Two stones are dropped from the edge of a 60m cliff , the second stone 1.6secon after the first . How far below the top of the cliff is the second stone when the separation between the two stone is 36m?

Answers

Answer:

The separation between the two stones is 36 m, when the second stone is approximately 10.9 m below the top of the cliff

Explanation:

The given parameters are;

The height of the cliff from which the stones are dropped, h = 60 m

The time at which the second stone is dropped = 1.6 seconds after the first

The distance below the top of the cliff when the distance between the two stones is 36 m = Required

We have;

The kinematic equation of motion that can be used is s = u·t - (1/2)·g·t²

For the first stone, we have, s₁ = u·t₁ - (1/2)·g·t₁²

For the second stone, we get; s₂ = u·t₂ - (1/2)·g·t₂²

t₁ = t₂ + 1.6

g = The acceleration due to gravity ≈ 9.81 m/s²

s = The distance below the cliff top

The initial velocity of the stones, u = 0

Let t represent the time from which the second stone is dropped at which the distance between the two stones is 36 m, we have;

s₁ = u·(t + 1.6) + (1/2)·g·(t + 1.6)²

s₂ = u·t + (1/2)·g·t²

u = 0

∴ s₁ - s₂ = 36 =  (1/2)·g·(t + 1.6)² - (1/2)·g·t²

2 × 36/(g) = (t + 1.6)² - t²  = t² + 3.2·t + 2.56 - t² = 3.2·t + 2.56

2 × 36/(9.81) = 3.2·t + 2.56

t = (2 × 36/(9.81) - 2.56)/3.2 =  ≈ 1.49 s

t ≈ 1.49 s

s₂ = (1/2)·g·t²

∴ s₂ = (1/2) × 9.81 × 1.49² ≈ 10.9

The distance below the top of the cliff of the second stone when the the separation between the two stones is 36 m, s₂ ≈ 10.9 m.

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