Using range(1,101), make two list, one containing all even numbers and other containing all odd numbers. How can I do this on Python
Answers
Answer:
even = []
odd = []
for i in range(1,101):
if i % 2 == 0:
even.append(i)
else:
odd.append(i)
Using range(1,101), the list of even and odd number can be done in python as follows;
odd_numbers = []
even_numbers = []
for i in range(1, 101):
if i%2 == 0:
even_numbers.append(i)
else:
odd_numbers.append(i)
print(even_numbers)
print(odd_numbers)
The variable odd_numbers is initialise with an empty list
The variable even_numbers is initialise with an empty list.
Then we loop through the range 1 to 101 as required.
If the looped numbers is divided by 2 without a remainder then the number is appended to the empty list even_numbers.
Else if it has a remainder, the looped number are appended to the empty list, odd_numbers.
Then we print the even_numbers and odd_numbers.
learn more about python here; https://brainly.com/question/14157737?referrer=searchResults
