Use the slope-intercept form of the linear equation to write an equation of the line with given slope and y-intercept.
Slope: -6/5 y intercept (0,8)

Answer:

5.625 litres

Step-by-step explanation:

1. We have to find how many litres of of lemon juice does a 1 litre jug of lemonade contains :

6 litres ÷ 1.6 litres = 3.75 litres

2. How many litres of lemon juice does a 1.5 litre bottle of lemonade contain?

= 3.75 litres × 1.5 litres

= 5.625 litres #

Answer:

A 1.5 litre bottle of lemonade contains 0.4 litre of lemon juice

Step-by-step explanation

let x be the litre of lemon juice in 1.5 litre of lemonade

litre of lemon juice in 6 litre of lemonade = 1.6

so , [tex]\frac{6}{1.6} = \frac{1.5}{x}[/tex]

    x = [tex]\frac{1.5 * 1.6}{6}[/tex]

    x=[tex]\frac{2.4}{6}[/tex]

    x = 0.4 litre

Answer: plz marl brainilist

3966

Step-by-step explanation:

(98 × 63 - 32 × 69

98 * 63) - (32 * 69)

Answer:

The cube root parent function:

Horizontally stretched by a factor of 4:

Translated 5 units right:

Translated 3 units up:

Answer:

28 blue marbles

Step-by-step explanation:

yellow: blue

8               4

To get to 56 yellow marbles multiply by 7  

yellow: blue

8*7           4*7

56             28

There will be 28 blue marbles

Answer:

X = 64

Step-by-step explanation:

All of the angles are right angles (because of the square at one of the angles shown above). This means each angle equals 90 degrees. If X + 26 = 90, then X = 64 because 90 - 26 = 64. I hope this helps!

Answer: X = 64

Step-by-step explanation:

Answer:

384

Step-by-step explanation:

Answer:

384 words

Step-by-step explanation:

Number of words typed in 1 minute = 48

So, number of words typed in 8 minutes

= Number of words typed in 1 minute × 8

= 48 × 8

= 384

So, Curtis types 384 words in 8 minutes.

9514 1404 393

Answer:

  (c)  On a coordinate plane, a dashed straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the left of the line is shaded.

Step-by-step explanation:

The x-coefficient is positive, so we can determine the shading from ...

  2x ... < ... (pay attention to the x-term and the inequality symbol)

That is, the solution region will have x values that are less than those on the (dashed) boundary line. Lower x-values are to the left, hence shading is on the left side of the boundary. (That's all you need to know here to make the correct choice.)

_____

Additional comment

If the choices are "above" or "below", then you will want to look at the y-term and the inequality symbol. If the coefficient of the variable of interest is negated (as it is for y here), then you need to consider the inequality symbol reversed: -y < ...   ⇔   y > .... Here, that means the shading is above the line. Since the slope of the line is positive, "left" and "above" are the same thing.

Answer:

c

Step-by-step explanation:

E2021

Answer:

Step-by-step explanation:

Slope of the given line: m=4/3

Slope of the perpendiclar : m'=-3/4 (the inverse of the opposed of m)

Equation of the perpendiclar line: (passing through (-7,2))

[tex]y-2=(x+7)*\dfrac{-3}{4} \ or\\\\ y=-\dfrac{3x}{4} -\dfrac{13}{4}[/tex]

Step-by-step explanation:

s=12km t=15m

15m--> km= 15/60= 0,25h

V=s/t

V=12km/0,25h

V= 48 km/h

Step-by-step explanation:

Given:

[tex]A=1.5\:\text{cm}^2×\left(\frac{1\:\text{m}^2}{10^4\:\text{cm}^2}\right)=1.5×10^{-4}\:\text{m}^2[/tex]

[tex]d = 2.0\:\text{mm} = 2.0×10^{-3}\:\text{mm}[/tex]

The charge stored in a capacitor is given by [tex]Q = CV.[/tex] In the case of a parallel-plate capacitor, its capacitance C is given by

[tex]C = \epsilon_0\dfrac{A}{d}[/tex]

where [tex]\epsilon_0[/tex] = permittivity of free space. The amount of charge stored in the capacitor is then

[tex]Q = \left(\epsilon_0\dfrac{A}{d}\right)V[/tex]

[tex]\:\:\:\:\:=\left[\dfrac{(8.85×10^{-12}\:\text{F/m})(1.5×10^{-4}\:\text{m}^2)}{(2.0×10^{-3}\:\text{m})}\right](12\:\text{V})[/tex]

[tex]\:\:\:\:\:=8.0×10^{-12}\:\text{C}[/tex]

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Answer:

  2.244

Step-by-step explanation:

Your answer looks like it may have a transcription error.

The period is reasonably computed as the difference of the x-values of the given points:

  period = 4.114 -1.870 = 2.244 . . . seconds

Answer:

4.5%

Step-by-step explanation:

The tax rate=(2152.6/47800)*100=4.5%

Answer:

C. 98

Step-by-step explanation:

The proposed regression equation is weight = b + width * m

R2 = 0.423

A.) What is the regression equation for this example?

The estimate for the y-intercepts is b= 2.3013 and the estimate for the slope is m= 0.7963

In general, we can symbolize the estimated regression equation as ^Y= b + m*Xi. For this example you have to replace it with the calculated values of the regression coefficients to obtain the estimated regression equation:

^Y= 2.3013 + 0.7963Xi

B.) What is the explanatory, or predictor, variable in this study?

The explanatory or predictor variable is the variable that is suspected to have an effect over the response variable. In this example the predictor variable is:

X: Width of a horseshoe crab (cm)

C.) If the researcher wanted to test whether there is a statistically significant relationship between these two variables, what would the test statistic be? Calculate it from the table above.

To test if the regression is significant, the parameter of study will be the slope of the regression equation, symbolically: β. If the slope is equal to zero "β=0" then there is no linear regression between the response and explanatory variable. If the slope is different from zero "β≠0" then the regression is significant and the explanatory variable affects the response variable.

The hypotheses are:

H₀: β=0

H₁: β≠0

α: 0.05

The value of the statistic under the null hypothesis is t= 8.48

D.) What can we say about the p-value?

This test is two-tailed and so is the p-value, remember that the p-value is the probabulity of obtaining a value as extreme as the value of the statistic under the null hypothesis. The distribution for this test is a t with n-2= 100-2= 98 degrees of freedom. You can calculate the p-value as:

P(t₉₈≤-8.48) + P(t₉₈≥8.48)= P(t₉₈ ≤ -8.48) + (1 - P(t₉₈ < 8.48) ≅ 0.00001

E.) Ultimately, the reason that we find test statistics is so that we can compare them to a null distribution. For regression, that is a t-distribution based on the degrees of freedom. With 98 degrees of freedom (100-2), we can safely say that the critical t (or the confidence multiplier) is what?

As mentioned before, this test is two tailed, meaning that the rejection region is divided in two:

Critical values ± = ± = ± 1.984

This means that you'll reject the null hypothesis when the statistic is t ≤ -1.984 or if the statistic is t ≥ 1.984-

F.) Find the confidence interval for the slope.

Using a 95% confidence level, the interval for the slope is:

[m ± Sm]

[0.7963 ± 1.984 * 0.0939]

[0.61; 0.98]

G.) Is there a statistically significant relationship? Answer with the test statistic and the confidence interval.

Yes, there is a significant relationship between the width and weight of the horseshoe crabs.

Using the critical value approach:

The calculated statistic is 8.48 and the critical value is ± 1.984, since the statistic is greater than the positive critical value, the decision is to reject the null hypothesis.

If you pay attention to the confidence interval, which was made at a confidence level complementary to the significance level of the hypothesis test, this interval [0.61; 0.98] doesn't include the "zero". Since the interval doesn't include the value of the parameter stated in the null hypothesis, you can conclude that this hypothesis is not true and therefore reject it.

Answer:

The company should use a mean of 12.37 ounces.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The distribution for the amount of beer dispensed by the machine follows a normal distribution with a standard deviation of 0.17 ounce.

This means that [tex]\sigma = 0.17[/tex]

The company can control the mean amount of beer dispensed by the machine. What value of the mean should the company use if it wants to guarantee that 98.5% of the bottles contain at least 12 ounces (the amount on the label)?

This is [tex]\mu[/tex], considering that when [tex]X = 12[/tex], Z has a p-value of [tex]1 - 0.985 = 0.015[/tex], so when [tex]X = 12, Z = -2.17[/tex].

Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-2.17 = \frac{12 - \mu}{0.17}[/tex]

[tex]12 - \mu = -2.17*0.17[/tex]

[tex]\mu = 12 + 2.17*0.17[/tex]

[tex]\mu = 12.37[/tex]

The company should use a mean of 12.37 ounces.

Answer:

2x-3

Step-by-step explanation:

f(x) = 3x-1

g(x)= x+2

(f-g) (x) = 3x-1 - (x+2)

Distribute the minus sign

             = 3x-1 -x-2

 Combine like terms

               = 3x-x -1-2

                =2x -3

Answer:

See explanation

Step-by-step explanation:

Given

[tex]A = (-1,1)[/tex]

[tex]B = (3,3)[/tex]

[tex]C =(4,-2)[/tex]

Solving (a): [tex]P(0,0) \to Q(1,3)[/tex]

This means that:

[tex](x,y) \to (x+1,y+2)[/tex]

So, we have:

[tex]A = (-1,1)[/tex]

[tex]A' = (-1 + 1,1+2)[/tex]

[tex]A' = (0,3)[/tex]

[tex]B = (3,3)[/tex]

[tex]B'= (3 + 1,3+2)[/tex]

[tex]B'= (4,5)[/tex]

[tex]C =(4,-2)[/tex]

[tex]C' = (4+1,-2+1)[/tex]

[tex]C' = (5,-1)[/tex]

Solving (b): [tex]P(0,-1) \to Q(4,-2)[/tex]

This means that:

[tex](x,y) \to (x+4,y-1)[/tex]

So, we have:

[tex]A = (-1,1)[/tex]

[tex]A' = (-1+4,1-1)[/tex]

[tex]A' = (3,0)[/tex]

[tex]B = (3,3)[/tex]

[tex]B'= (3+4,3-1)[/tex]

[tex]B'= (7,2)[/tex]

[tex]C =(4,-2)[/tex]

[tex]C' = (4+4,-2-1)[/tex]

[tex]C' = (8,-3)[/tex]

Solving (c): [tex]P(-1,-2) \to Q(-2,-2)[/tex]

This means that:

[tex](x,y) \to (x-1,y)[/tex]

So, we have:

[tex]A = (-1,1)[/tex]

[tex]A' = (-1-1,1)[/tex]

[tex]A' = (-2,1)[/tex]

[tex]B = (3,3)[/tex]

[tex]B'= (3-1,3)[/tex]

[tex]B'= (2,3)[/tex]

[tex]C =(4,-2)[/tex]

[tex]C'= (4-1,-2)[/tex]

[tex]C'= (3,-2)[/tex]

Answer B.ED

Step-by-step explanation:

The correct answer to the given question is "[tex]\bold{392.47\ < \mu <\ 427.53}[/tex],[tex]\bold{0.28 \ < P <\ 0.34}[/tex], and for Interpret results go to the C part.

Following are the solution to the given parts:

A)

[tex]\to \bold{(n) = 16}[/tex]

[tex]\to \bold{(\bar{X}) = 410}[/tex]

[tex]\to \bold{(\sigma) = 40}[/tex]

In the given question, we calculate [tex]90\%[/tex] of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

[tex]\to \bold{\bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}}[/tex]

[tex]\to \bold{C.I= 0.90}\\\\\to \bold{(\alpha) = 1 - 0.90 = 0.10}\\\\ \to \bold{\frac{\alpha}{2} = \frac{0.10}{2} = 0.05}\\\\ \to \bold{(df) = n-1 = 16-1 = 15}\\\\[/tex]

Using the t table we calculate [tex]t_{ \frac{\alpha}{2}} = 1.753[/tex]  When [tex]90\%[/tex] of the confidence interval:

[tex]\to \bold{410 \pm 1.753 \times \frac{40}{\sqrt{16}}}\\\\ \to \bold{410 \pm 17.53\\\\ \to392.47 < \mu < 427.53}[/tex]

So [tex]90\%[/tex] confidence interval for the mean weight of shipped homemade candies is between [tex]392.47\ \ and\ \ 427.53[/tex].

B)

[tex]\to \bold{(n) = 500}[/tex]

[tex]\to \bold{(X) = 155}[/tex]

[tex]\to \bold{(p') = \frac{X}{n} = \frac{155}{500} = 0.31}[/tex]

Here we need to calculate [tex]90\%[/tex] confidence interval for the true proportion of all college students who own a car which can be calculated as

[tex]\to \bold{p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}}[/tex]

[tex]\to \bold{C.I= 0.90}[/tex]

[tex]\to\bold{ (\alpha) = 0.10}[/tex]

[tex]\to\bold{ \frac{\alpha}{2} = 0.05}[/tex]

Using the Z-table we found [tex]\bold{Z_{\frac{\alpha}{2}} = 1.645}[/tex]

therefore [tex]90\%[/tex] the confidence interval for the genuine proportion of college students who possess a car is

[tex]\to \bold{0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}}\\\\ \to \bold{0.31 \pm 0.034}\\\\ \to \bold{0.276 < p < 0.344}[/tex]

So [tex]90\%[/tex] the confidence interval for the genuine proportion of college students who possess a car is between [tex]0.28 \ and\ 0.34.[/tex]

C)

Learn more about confidence intervals:  

brainly.com/question/24131141

Answer:

The percentage of people who prefer football is approximately the same for the right- and left-handed groups.

Step-by-step explanation:

The bar for the right-handed group representing soccer is between 10% and 20% (below 20%) while the bar for the left-handed group representing soccer is at 20%.

Percentage of left-handed group of people who prefer soccer is higher than the right-handed group who prefer soccer. Therefore, they don't have the same percentage.

Answer:

D

Step-by-step explanation:

;)

Answer:

Length:8

Width:5.5

Step-by-step explanation:

We're given area = 44m^2, and the formula for the area of a rectangle is the length multiplied by the width. So,

A = L * w = 44

We're given that the length is 3m shorter than 2 times the width, which is 2w - 3. "2w" is the same as "2 times the width", and the 3 is subtracted because it says 3m shorter than 2 times the width. So L = 2w - 3, and we can substitute that into our equation above.

(2w - 3)(w) = 44

2w^2 - 3w - 44 = 0

Use the quadratic formula here.

x = {3 ± √(-3)^2 - 4(-44)(2)}/2(2)

= {3 ± √9 + 352}/4

= (3 ± 19)/4

You'll get two answers, but remember, we're measuring the length of the sides of shapes, so it has to be positive. It's impossible to have negative lengths, so we're going to stick with the (3 + 19)/4 answer, which is 22/4, which is 5.5. However, we are not finished yet. This is just the width. Now we need to plug it into the equation for length, which was 2w - 3

2(5.5) - 3 = 11 - 3 = 8

The length is 8m and the width is 5.5m.

Answer/Step-by-step explanation:

Hola amigo. Mucho gusto. En Brainly.com puede responder a sus preguntas y obtener explicaciones exhaustivas. Esto le permite aprender de forma más inteligente.

Y... yo hablo pequeno español.

Step-by-step explanation:

[tex] \frac{ {c}^{2} - 4 }{c + 3} [/tex]

[tex] \frac{(c - 2)(c + 2)}{(c + 3)} [/tex]

Geometric figures are basically figures that have a boundary. The geometric figures and their real life examples are:

To determine the real life object of each geometric figure, we simply identify objects that have similar features as the geometric figure.

For instance, a rectangular prism has 6 rectangular faces; building blocks, some gift box and cabinets also have 6 rectangular faces.

So, these three real life objects can be used as examples of a rectangular prism.

When the above explanation is applied to the other geometric figures, we come up with the following list:

Read more about geometric figures at:

https://brainly.com/question/8430622

In the photo are a couple possible answers you could use.

Answer:

Here the answer is given as follows,

Answer:

16 is answer

Step-by-step explanation:

3(2)^2+4(1)^2= 3(4)+4(1)=12+4=16

Answer:-10

-3+-4+-3

-3-4=-7

-7+-3=-7-3

=-10

Answer:

(-3, -6)

Step-by-step explanation:

always start from the origin! Hope this helps!

9514 1404 393

Answer:

  C(-1, -4)

Step-by-step explanation:

We want ...

  AC/CB = 1/5

  5(C-A) = B-C . . . . multiply by 5CB

  6C = B +5A . . . . . add 5A-C

  C = (B +5A)/6 . . . divide by 6

  C = ((4, 6) +5(-2,-6))/6 = (4-10,6-30)/6 = (-6, -24)/6

  C = (-1, -4)

Given:

The five number summary of two data sets are given as:

a) 0, 4, 12, 14, 20

b) 2, 8, 14, 18, 20

To find:

The range for the outliers.

Solution:

We know that,

An observation is considered an outlier if it is below [tex]Q_1-1.5(IQR)[/tex]

An observation is considered an outlier if it is above [tex]Q_3+1.5(IQR)[/tex]

Where, IQR is the interquartile range and [tex]IQR=Q_3-Q_1[/tex].

The five number summary of two data sets are given as:

0, 4, 12, 14, 20

Here, [tex]Q_1=4[/tex] and [tex]Q_3=14[/tex].

Now,

[tex]IQR=14-4[/tex]

[tex]IQR=10[/tex]

The range for the outliers is:

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[4-1.5(10),14+1.5(10)][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[4-15,14+15][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[-11,29][/tex]

An observation is considered an outlier if it is below -11.

An observation is considered an outlier if it is above 29.

The five number summary of two data sets are given as:

2, 8, 14, 18, 20

Here, [tex]Q_1=8[/tex] and [tex]Q_3=18[/tex].

Now,

[tex]IQR=18-8[/tex]

[tex]IQR=10[/tex]

The range for the outliers is:

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[8-1.5(10),18+1.5(10)][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[8-15,18+15][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[-7,33][/tex]

An observation is considered an outlier if it is below -7.

An observation is considered an outlier if it is above 33.