Recall that
tan(x) = sin(x)/cos(x)
and
sin(x) = x - x ³/6 + x ⁵/120 - x ⁷/5040 + …
cos(x) = 1 - x ²/2 + x ⁴/24 - x ⁶/720 + …
Truncate the series to three terms. Then
[tex]\displaystyle \lim_{x\to0}\frac{\tan(x)-x}{x^3} = \lim_{x\to0}\frac{\frac{x-x^3/6+x^5/120}{1-x^2/2+x^4/24}-x}{x^3} \\\\ = \lim_{x\to0}\left(\frac{x-x^3/6+x^5/120}{x^3-x^5/2+x^7/24}-\frac1{x^2}\right) \\\\ = \lim_{x\to0}\left(\frac{1-x^2/6+x^4/120}{x^2-x^4/2+x^6/24}-\frac1{x^2}\right) \\\\ = \lim_{x\to0}\left(\frac{1-x^2/6+x^4/120}{x^2\left(1-x^2/2+x^4/24\right)}-\frac1{x^2}\right) \\\\ = \lim_{x\to0}\left(\frac{1-x^2/6+x^4/120}{x^2\left(1-x^2/2+x^4/24\right)}-\frac{1-x^2/2+x^4/24}{x^2\left(1-x^2/2+x^4/24\right)}\right) \\\\ = \lim_{x\to0}\frac{x^2/3-x^4/30}{x^2\left(1-x^2/2+x^4/24\right)} \\\\ = \lim_{x\to0}\frac{1/3-x^2/30}{1-x^2/2+x^4/24} = \boxed{\frac13}[/tex]
A number has ........... number of factors but ........... number of multiple.
A number has fixed number of factors but infinite number of multiples
Ex:-
Take a number 12
It has factors 1,2,3,4,6,12
It is fixed.
But
It has multiples 12,24,36,48,60...
It is infinite
Define mean and median for a set of data
Answer:
The mean is the average number of a data set gotten by adding all the numbers then dividing by two.
the median is the middle number in a sorted set of data,either sorted in ascending order or descending order.
I hope this helps
To calculate mean:
• add up all the numbers,
• then divide by how many numbers there are.
Example:
Data: 5, 6, 10, 1
Add these all together, which is 22, then divide by 4 (because that is how many numbers there are), so:
the mean is 5.5
To calculate median:
Arrange your numbers in order.
Cross off numbers until you get to the middle.
If there is an even number of data, then find the two in the middle and find the middle of that.
Example:
Data: 5, 6, 10, 1
Arrange: 1, 5, 6, 10
So, the middle 2 are 5 and 6. In between these would be 5.5, so that is the median.
If the data was: 1, 5, 6, 8, 10,
then the median would be 6.
If 40 men working on a U.S. government project can complete the job in 100 hours, how many men would be required to complete the job in 80 hours?
Answer:50
Step-by-step explanation:(40x100):80
Answer: 50 workers
Let the ratio be
(40×100):80
= 400/80
= 50
Therefore 50 workers will complete the same work in 80 hours.
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What is the range of the function f(x) = 3x + 2 overthe interval -6 < x < 5?
Answer:
(-16, 17)
Step-by-step explanation:
The range of the function will be (-16, 17)
The range of function f(x) = 3x + 2 overthe interval -6 < x < 5 is (-13,14)
What is Range?The difference between the highest and lowest values.
The given function is f(x) = 3x + 2
f(x) equal tp three times of x plus two.
The given interval is minus six less than x less than five.
-6 < x < 5
Which means the x values are -5, -4, -3, -2, -1, 0, 1, 2,3,4
Plus in the function
f(-5)=-15+2=-13
f(-4)=-10
f(-3)=-9+2=-7
f(-2)=-6+2=-4
f(-1)=-3+2=-1
f(0)=0+2=2
f(1)=3+2=5
f(2)=6+2=8
f(3)=9+2=11
f(4)=12+2=14
Hence the range of function f(x) = 3x + 2 overthe interval -6 < x < 5 is (-13,14)
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a 800g boulder has a density of 8g/cm^3. What is the volume of the boulder?
Answer:
Below
Step-by-step explanation:
You can use this formula to calculate the volume of an object
Volume = Mass / Density
Plugging everything in...
Volume = 800g / 8 g/cm^3
= 100 cm^3
Hope this helps!
The volume of the boulder will be equal to 100 cubic centimeters.
What are volume and density?A substance's density is defined as its mass per unit volume. The density in other words can be defined as the ratio of mass and volume. Its unit will be kg per cubic meter.
The volume is defined as the space occupied by an object in three-dimensional geometry.
It is given that an 800g boulder has a density of 8g/cm^3. The volume will be calculated by using the formula below:-
Volume = Mass / Density
Volume = 800g / 8 g/cm^3
= 100 cm^3
Therefore, the volume of the boulder will be equal to 100 cubic centimeters.
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A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 6 students' scores on the exam after completing the course: 6,16,19,12,15,14.
Using these data, construct a 90% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal. Find the critical value that should be used in constructing the confidence interval.
Answer:
The critical value is [tex]T_c = 2.5706[/tex].
The 90% confidence interval for the average net change in a student's score after completing the course is (9.04, 18.30).
Step-by-step explanation:
Before building the confidence interval, we need to find the sample mean and the sample standard deviation:
Sample mean:
[tex]\overline{x} = \frac{6+16+19+12+15+14}{6} = 13.67[/tex]
Sample standard deviation:
[tex]s = \sqrt{\frac{(6-13.67)^2+(16-13.67)^2+(19-13.67)^2+(12-13.67)^2+(15-13.67)^2+(14-13.67)^2}{5}} = 4.4121[/tex]
Confidence interval:
We have the standard deviation for the sample, so the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 6 - 1 = 5
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 2.5706, that is, the critical value is [tex]T_c = 2.5706[/tex]
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.5706\frac{4.4121}{\sqrt{6}} = 4.63[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 13.67 - 4.63 = 9.04.
The upper end of the interval is the sample mean added to M. So it is 13.67 + 4.63 = 18.30.
The 90% confidence interval for the average net change in a student's score after completing the course is (9.04, 18.30).
simplify 27-{ 9+(12-5)÷4} with solution
Answer:
16.25
Step-by-step explanation:
first do 12 -5 = 7. then 7/4 = 1.75 then 9+1.75 = 10.75 and finally 27-10.75= 16.25
The volume of a rectangular prism (shown below) is 48x^3+56x^2+16x Answer the following questions:
(1) What are the dimensions of the prism?
(2) If x = 2, use the polynomial 48x^3+56x^2+16x to find the volume of the prism.
(3) If x = 2, use the factors found in part a to calculate each dimension.
(4) Using the dimensions found in part c, calculate the volume. Show all work.
Answer:
(a)
[tex]Length = 8x\\Width = 3x + 2\\Height = 2x + 1[/tex]
(b)
[tex]P(2) = 640[/tex]
(c)
[tex]Length= 16[/tex]
[tex]Width = 8[/tex]
[tex]Height =5[/tex]
(d)
[tex]Volume = 640[/tex]
Step-by-step explanation:
Given
[tex]P(x) = 48x^3 + 56x^2 + 16x[/tex]
Solving (a): The prism dimension
We have:
[tex]P(x) = 48x^3 + 56x^2 + 16x[/tex]
Factor out 8x
[tex]P(x) = 8x(6x^2 + 7x + 2)[/tex]
Expand 7x
[tex]P(x) = 8x(6x^2 + 4x + 3x + 2)[/tex]
Factorize
[tex]P(x) = 8x(2x(3x + 2) +1( 3x + 2))[/tex]
Factor out 3x + 2
[tex]P(x) = 8x(3x + 2)(2x + 1)[/tex]
So, the dimensions are:
[tex]Length = 8x\\Width = 3x + 2\\Height = 2x + 1[/tex]
Solving (b): The volume when [tex]x = 2[/tex]
We have:
[tex]P(x) = 48x^3 + 56x^2 + 16x[/tex]
[tex]P(2) = 48 * 2^3 + 56 * 2^2 + 16 * 2[/tex]
[tex]P(2) = 640[/tex]
Solving (c): The dimensions when [tex]x = 2[/tex]
We have:
[tex]Length = 8x\\Width = 3x + 2\\Height = 2x + 1[/tex]
Substitute 2 for x
[tex]Length=8*2[/tex]
[tex]Length= 16[/tex]
[tex]Width = 3*2+2[/tex]
[tex]Width = 8[/tex]
[tex]Height = 2*2 + 1[/tex]
[tex]Height =5[/tex]
So, we have:
[tex]Length= 16[/tex]
[tex]Width = 8[/tex]
[tex]Height =5[/tex]
Solving (d), the volume in (c)
We have:
[tex]Volume = Length * Width * Height[/tex]
[tex]Volume = 16 * 8 * 5[/tex]
[tex]Volume = 640[/tex]
Draw a graph of direct proportion, expressed by the formula: y=3x
Answer.
ANSWER
.......
21. SCALE FACTOR A regular nonagon has an area of 90 square feet. A similar
nonagon has an area of 25 square feet. What is the ratio of the perimeters of
the first nonagon to the second?
Answer:
The ratio of the perimeters of the first nonagon to the second is 3.6 to 1.
Step-by-step explanation:
Given that a regular nonagon has an area of 90 square feet, and a similar nonagon has an area of 25 square feet, to determine what is the ratio of the perimeters of the first nonagon to the second, the following calculation must be performed:
25 = 1
90 = X
90/25 = X
3.6 = X
Therefore, the ratio of the perimeters of the first nonagon to the second is 3.6 to 1.
Books, and then you have 44+45x=?
Answer:
45x=-44
x=-44/45
Step-by-step explanation:
is this a free question?
Read the image for instructions
Answer:
4 ther are 4 line symmetery
Answer:
two lines of symmetry
(a vertical and a horizontal)
How many times greater is
6.6 x 10^10
than
3 x 10^7
2.2
22
1000
2200
Answer:
2,200
Step-by-step explanation:
6.6 x 10^10
= 66,000,000,000
3 x 10^7
= 30,000,000
66,000,000,000 ÷ 30,000,000
2,200
Answer:
2200.
Step-by-step explanation:
6.6 / 3 * 10^10/10^7
= 2.2 * 10^3
= 2200
Find the standard deviation for the following group of data items.
9, 11, 11, 16
The standard deviation for the given data items is 2.6
The standard deviation of the given data items can be calculated by taking the square root of the variance.
Variance is a measure of variability and it is calculated by taking the average of squared deviations from the mean.
Hence, we will first determine the mean of the given data items.
Mean is simply the average of the numbers.
Therefore mean of the given data items is
[tex]Mean = \frac{9+11+11+16}{4}[/tex]
[tex]Mean = \frac{47}{4}[/tex]
Mean = 11.75
Now, for the variance of the data
[tex]Variance = \frac{(9-11.75)^{2}+(11-11.75)^{2}+(11-11.75)^{2}+(16-11.75)^{2} }{4}[/tex]
[tex]Variance = \frac{(-2.75)^{2}+(-0.75)^{2}+(-0.75)^{2}+(4.25)^{2} }{4}[/tex]
[tex]Variance = \frac{7.5625+0.5625+0.5625+18.0625}{4}[/tex]
[tex]Variance = \frac{26.75}{4}\\[/tex]
∴ Variance = 6.6875
But,
Standard deviation [tex]= \sqrt{Varinace}[/tex]
∴Standard deviation [tex]=\sqrt{6.6875}[/tex]
Standard deviation = 2.586
Standard deviation ≅ 2.6
Hence, the standard deviation for the given data items is 2.6
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Complete the table using the equation w = m + 4
Answer:
5+4 = 9
6+4 = 10
7+4 =11
Step-by-step explanation:
Answer:
(5,9)
(6,10)
(7,11)
Step-by-step explanation:
w = m + 4
when m = 5,
w = 5 + 4 = 9
when m = 6
w = 6 + 4 = 10
when m = 7
w = 7 + 4 = 11
A random number generator is used to create a list of 300 single digit numbers
Help.. what does Y=
Answer:
The answer is B. 3
Step-by-step explanation:
The right angle points at side C which is the biggest side of a triangle and the smallest side is half of what side C is which is 3
Please help me to find this answer
Step-by-step explanation:
angle of a triangle is 180, therefore to get the remaining one, subtract the sum of the two knows from 180, also for the second one; angle on a straight line is as well 180, since you have fine the interior one, subtract it from 180 to get the second answer
Answer:
so angles in a triangle add up to 180,
32+50+m<MQP=180
82+m<MQP=180
m<MQP=180-82
=98°
and angles on a straight line add up to 180 therefore
m<MQR=180-m<MQP
=180-98
=82
I hope this helps and if you don't understand feel free to ask
Will mercury with a density of 13.6 g/mL float or sink?
Mercury will sink
(sorry if Im wrong)
Answer:
Sink.
Step-by-step explanation:
Mercury is a quicksilver and hence will sink.
what should be added to 780629 so that the sum is exactly divisible by 493?
Answer:
283
Step-by-step explanation:
Given problem is based on divisibilityy,
= 780629/493
quotient = 1583
remainder = 210
So,Add 283 with remainder (210) to get 493
= 283+210
= 493
There for 283 should be added to 780629 so that the sum is exactly divisible by 493
The problem has come from division .
First divide them
[tex]\\ \sf\longmapsto \dfrac{480629}{493}[/tex]
[tex]\\ \sf\longmapsto Remainder=210[/tex]
[tex]\\ \sf\longmapsto Quiotent=1583[/tex]
Now We have to add x to the remainder by which it will be 493
[tex]\\ \sf\longmapsto x+210=493[/tex]
[tex]\\ \sf\longmapsto x=493-210[/tex]
[tex]\\ \sf\longmapsto x=283[/tex]
Hi! I'd appreciate if you could help me on this question.
Liam is buying bottles of soda in packages that contain 8 bottles each. If the total number of sodas Liam bough t was between 45 and 50, how many did he buy? Explain your answer.
Answer:
48
Step-by-step explanation:
We need to find the multiples of 8
8,16,24,32,40,48
48 is between 45 and 50 so he must have bought 48
Answer:
6 bottles
Step-by-step explanation:
For this question we need to know the multiple of 8 which are:
8 x 1 = 8
8 x 2 = 16
8 x 3 = 24
8 x 4 = 32
8 x 5 = 40
8 x 6 = 48
8 x 7 = 56
There is only one multiple, which is greater than 45 but less than 50, which is 8x6 l.
This means he bought 6 bottles.
Answered by g a u t h m a t h
Prove that: sec⁴B - sec²B = tan⁴B + tan²B.
Step-by-step explanation:
sec⁴B - sec²B = sec²B(sec²B - 1)
= (1 + tan²B)(tan²B)
= tan⁴B + tan²B
= Right-hand side (Proven)
PLS HELP
Find an equation of the line with a y-intercept of -3 and an x-intercept of -4.5
Answer:
y = - [tex]\frac{2}{3}[/tex] x - 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (0, - 3) and (x₂, y₂ ) = (- 4.5, 0 ) ← coordinates of intercepts
m = [tex]\frac{0-(-3)}{-4.5-0}[/tex] = [tex]\frac{0+3}{-4.5-0}[/tex] = [tex]\frac{3}{-4.5}[/tex] = - [tex]\frac{2}{3}[/tex]
The line crosses the y- axis at (0, - 3 ) ⇒ c = - 3
y = - [tex]\frac{2}{3}[/tex] x - 3 ← equation of line
Find the missing segment in the image below
If you get a raise from $12 per hour to $15 per hour, what is the percent change?
Answer:
25%
Step-by-step explanation:
Formula to calculate the percent change :-
Change in distance from $12 per hour to $15 per hours = 15-12=3 per hour
Previous value = $12 per hour
Now, the percent change will be :_
Hence, the percent change for from $12 per hour to $15 per hour= 25%
(I copied this answer from JeanaShupp from question-11653373 [no links])
Find the value of x.
A. 57
B. 72
C. 90
D. 124
Answer:
90
Step-by-step explanation:
Angle Formed by Two Chords= 1/2(SUM of Intercepted Arcs)
105 = 1/2 (120+x)
210 = 120+x
Subtract 120 from each side
210-120 = x
90 =x
The value of Intercepted Arcs x will be 90. so option C is correct.
What is the relation between line perpendicular to chord from the center of circle?If the considered circle has center O and chord AB, then if there is perpendicular from O to AB at point C, then that point C is bisecting(dividing in two equal parts) the line segment AB.
Or
|AC| = |CB|
Angle Formed by Two Chords= 1/2 (Sum of Intercepted Arcs)
105 = 1/2 (120+x)
210 = 120+x
Subtract 120 from each side;
210-120 = x
90 =x
Hence, the value of Intercepted Arcs x will be 90. so option C is correct.
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I need help with C,D,E,F,G thank you
Answer:
D = 120 Degrees , E : x = 14 , F: <JHK = 21, G: Summplementary Angle is 96 Degrees
Step-by-step explanation:
4X+2X = 180
6X=180
X=30
<ABD = 4X = 4(30) = 120
Select the expression that has a value of 13.
9 + 3 x (2 ÷ 3) + 6
(9 + 3) x 2 ÷ 3 + 6
9 − (3 x 2) ÷ 3 + 6
(9 + 3 x 2) ÷ 3 + 6
Answer:
9 − (3 x 2) ÷ 3 + 6 is the answer
What percentage of area is above the mean on a normal curve?
Group of answer choices
34%
68%
97.35%
50%
Answer:
z=0
50%
Step-by-step explanation:
?
What is the equation of a parabola whose focus is (-4, -1)
and whose directrix is
y = -5?
x²
y = + x – 1
8
o
y = -
x²
--X+1
8
y?
x =
+ у - 1
8
y2
X = -
8 Y+1
Answer:
1st option,
y = x²/8 + x - 1
Answered by GAUTHMATH
