We want to maximize [tex]x^3y^4z[/tex] subject to the constraint [tex]x+y+z=30[/tex].
The Lagrangian is
[tex]L(x,y,z,\lambda)=x^3y^4z-\lambda(x+y+z-30)[/tex]
with critical points where the derivatives vanish:
[tex]L_x=3x^2y^4z-\lambda=0[/tex]
[tex]L_y=4x^3y^3z-\lambda=0[/tex]
[tex]L_z=x^3y^4-\lambda=0[/tex]
[tex]L_\lambda=x+y+z-30=0[/tex]
[tex]\implies\lambda=3x^2y^4z=4x^3y^3z=x^3y^4[/tex]
We have
[tex]3x^2y^4z-4x^3y^3z=x^2y^3z(3y-4x)=0\implies\begin{cases}x=0,\text{ or}\\y=0,\text{ or}\\z=0,\text{ or}\\3y=4x\end{cases}[/tex]
[tex]3x^2y^4z-x^3y^4=x^2y^4(3z-x)=0\implies\begin{cases}x=0,\text{ or}\\y=0,\text{ or}\\3z=x\end{cases}[/tex]
[tex]4x^3y^3z-x^3y^4=x^3y^3(4z-y)=0\implies\begin{cases}x=0,\text{ or}\\y=0,\text{ or}4z=y\end{cases}[/tex]
Let's work with [tex]x=3z[/tex] and [tex]y=4z[/tex], for which we have
[tex]x+y+z=8z=30\implies z=\dfrac{15}4\implies\begin{cases}x=\frac{45}4\\y=15\end{cases}[/tex]
The smallest of these is C. 15/4.
Express the product of z1 and z2 in standard form given that [tex]z_{1} = -3[cos(\frac{-\pi }{4} )+isin(\frac{-\pi }{4} )][/tex] and [tex]z_{2} = 2\sqrt{2} [cos(\frac{-\pi }{2} )+isin(\frac{-\pi }{2} )][/tex]
Answer:
Solution : 6 + 6i
Step-by-step explanation:
[tex]-3\left[\cos \left(\frac{-\pi }{4})\right+i\sin \left(\frac{-\pi }{4}\right)\right]\cdot \:2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi }{2}\right)\right][/tex]
This is the expression we have to solve for. Now normally we could directly apply trivial identities and convert this into standard complex form, but as the expression is too large, it would be easier to convert into trigonometric form first ----- ( 1 )
( Multiply both expressions )
[tex]-6\sqrt{2}\left[\cos \left(\frac{-\pi }{4}+\frac{-\pi \:\:\:}{2}\right)+i\sin \left(\frac{-\pi \:}{4}+\frac{-\pi \:\:}{2}\right)\right][/tex]
( Simplify [tex]\left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)[/tex] for both [tex]\cos \left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)[/tex] and [tex]i\sin \left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)[/tex] )
[tex]\left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)[/tex] = [tex]\left(-\frac{3\pi }{4}\right)[/tex]
( Substitute )
[tex]-6\sqrt{2}\left(\cos \left(-\frac{3\pi }{4}\right)+i\sin \left(-\frac{3\pi }{4}\right)\right)[/tex]
Now that we have this in trigonometric form, let's convert into standard form by applying the following identities ----- ( 2 )
sin(π / 4) = √2 / 2 = cos(π / 4)
( Substitute )
[tex]-6\sqrt{2}\left(-\sqrt{2} / 2 -i\sqrt{2} / 2 )[/tex]
= [tex]-6\sqrt{2}\left(-\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)[/tex] = [tex]-\frac{\left(-\sqrt{2}-\sqrt{2}i\right)\cdot \:6\sqrt{2}}{2}[/tex]
= [tex]-3\sqrt{2}\left(-\sqrt{2}-\sqrt{2}i\right)[/tex] = [tex]-3\sqrt{2}\left(-\sqrt{2}\right)-\left(-3\sqrt{2}\right)\sqrt{2}i[/tex]
= [tex]3\sqrt{2}\sqrt{2}+3\sqrt{2}\sqrt{2}i:\quad 6+6i[/tex] - Therefore our solution is option a.
Fill in the following blanks to prove that n 2^1 n < 2^n n+1 < 2^(n+1) is Box 3 Options: True | False Next, assume that Box 4 Options: 1 < 2^1 k + 1 < 2^(k+1) k < 2^k as we attempt to prove Box 5 Options: k < 2^k k + 1 < 2^(k+1) 2 < 2^1 Therefore, we can conclude that Box 6 Options: k < 2^k k + 1 < 2^(k+1) 2^1 < 2^k k + 2 < 2^(k+2)
Answer:
see below
Step-by-step explanation:
n < 2^n
First let n=1
1 < 2^1
1 <2 This is true
Next, assume that
(k) < 2^(k)
as we attempt to prove that
(k+1) < 2^(k+1)
.
.
.
Therefore we can conclude that
k+1 < 2^(k+1)
Answer:
Step-by-step explanation:
Hello, please consider the following.
First, assume that n equals [tex]\boxed{1}[/tex]. Therefore, [tex]\boxed{1<2^1}[/tex] is [tex]\boxed{\text{True}}[/tex]
Next, assume that [tex]\boxed{k<2^k}[/tex], as we attempt to prove [tex]\boxed{k+1<2^{k+1}}[/tex]
Since .... Therefore, we can conclude that [tex]\boxed{k+1<2^{k+1}}[/tex]
The choice for the last box is confusing. Based on your feedback, we can assume that we are still in the step 2 though.
And the last step which is not included in your question is the conclusion where we can say that we prove that for any integer [tex]n\geq 1[/tex], we have [tex]n<2^n[/tex].
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
p(a) = 0.60, p(b) = 0.20, and p(a and b) = 0.15 what is p(a or b) choices: A. 0.12, B. 0.65, C. 0.40, or D. 0.80 (Note- This is on AP3X)
Answer:
[tex]p(a\ or\ b) = 0.65[/tex]
Step-by-step explanation:
Given
[tex]p(a) = 0.60[/tex]
[tex]p(b) = 0.20[/tex]
[tex]p(a\ and\ b) = 0.15[/tex]
Required
[tex]p(a\ or\ b)[/tex]
The relationship between the given parameters and the required parameters is as follows;
[tex]p(a\ and\ b) = p(a) + p(b) - p(a\ or\ b)[/tex]
Substitute values for the known parameters
[tex]0.15 = 0.60 + 0.20 - p(a\ or\ b)[/tex]
[tex]0.15 = 0.80 - p(a\ or\ b)[/tex]
Collect Like Terms
[tex]p(a\ or\ b) = 0.80 - 0.15[/tex]
[tex]p(a\ or\ b) = 0.65[/tex]
Hence;
[tex]p(a\ or\ b) = 0.65[/tex]
please solution this question now .thank you very much
Answer:
5/2
Step-by-step explanation:
Let u = sin(t). Then this is the integral ...
[tex]\displaystyle\int_0^{\frac{\pi}{2}}{5u}\,du=\left.\dfrac{5u^2}{2}\right|_0^{\frac{\pi}{2}}=\dfrac{5}{2}(\sin(\frac{\pi}{2})^2-\sin(0)^2)=\dfrac{5}{2}(1-0)=\boxed{\dfrac{5}{2}}[/tex]
If the true mean is 50 and we reject the hypothesis that μ = 50, what is the probability of Type II error? Hint: This is a trick question.
Answer:
Zero
Step-by-step explanation:
Given that:
the true mean is 50 and we reject the hypothesis that μ = 50
The probability of the Type II error will be zero, given that we reject the null hypothesis. This has nothing to do with if it is true or false.
Type II error is occurs when you accept a false null hypothesis. The probability of this error is denoted by beta which relies on sample size and population variance.
The probability of rejecting is equal to one minu beta. i.e it is the researchers goal to reject a false null hypothesis.
Let REPEAT TM = { | M is a TM, and for all s ∈ L(M), s = uv where u = v }. Show that REPEATTM is undecidable. Do not use Rice’s Theorem.
Answer:
Step-by-step explanation:
Let REPEAT [tex]_{TM[/tex]= { | M is a TM, and for all s ∈ L(M), s = uv where u = v }
To prove that REPEAT [tex]_{TM[/tex] is undecidable.
Let REPEAT [tex]_{TM[/tex] {| M is a TM that does not accept M}
Then, we form a TM u for L by applying TM v as a subroutine.
Assume Repeat is decidable
Let M be the algorithm that TM which decides the REPEATU = on input "s" simulate the M
Accept; if M ever enters the accept state
Reject; if M ever enters the reject state
U does not decide the REPEAT as it may loop over s
so REPEAT is undecidable
Karmen returned a bicycle to Earl's Bike Shop. The sales receipt showed a total paid price of $211.86, including the 7% sales tax. What was the cost of the bicycle without the sales tax? Any help would be very appreciated! Thank you very much!
Answer:
$198
Step-by-step explanation:
198x.07=13.86
198+13.86=211.86
Identify the sample space of the probability experiment and determine the number of outcomes in the sample space. Playing the game of roulette, where the wheel consists of slots numbered 00, 0, 1, 2, ..., To play the game, a metal ball is spun around the wheel and is allowed to fall into one of the numbered slots.a. The sample space is (00, 0}. b. The sample space is (00, 0, 1,2,., 33). c. The sample space is (00). d. The sample space is (1, 2,..., 33).
Answer:
The correct option is (B).
Step-by-step explanation:
It is provided that, in a game of roulette the wheel consists of slots numbered 00, 0, 1, 2, ..., 33.
The sample space of an experiment, is the set of all the possible outcomes of the random trials.
There are a total of 35 slots on the roulette wheel where the ball can land.
So, there are a total of 35 outcomes for one rotation of the wheel.
Then the sample space consists of all the 35 outcomes, i.e.
S = {00, 0, 1, 2, 3, ..., 33}
Thus, the correct option is (B).
Please help. I’ll mark you as brainliest if correct!
Answer:
(DNE,DNE)
Step-by-step explanation:
-24x-12y = -16. Equation one
6x +3y = 4. Equation two
Multiplying equation two with +4 gives
4(6x +3y = 4)
24x +12y = 16...result of equation two
-24x -12y= -16...
A careful observation to the following equation will help us notice that the both equation are same thing.
Multiplying minus to equation one gives
-(-24x-12y=-16)
24x+12y = 16.
Since the both equation are same, there is no solution to it.
A line passes through (-5, -3) and is parallel to -3x - 7y = 10. The equation of the line in slope-intercept form is _____
Answer:
-3x - 7y = 36
Step-by-step explanation:
The given line -3x - 7y = 10 has an infinite number of parallel lines, all of the form -3x - 7y = C.
If we want the equation of a line parallel to -3x - 7y = 10 that passes through (-5, -3), we substitute -5 for x in -3x - 7y = 10 and substitute -3 for y in -3x - 7y = 10:
-3(-5) - 7(-3) = C, or
15 + 21 = C, or C = 36
Then the desired equation is -3x - 7y = 36.
Answer Both Questions
Answer:is the first answer 15.875 and the second answer 17 x 28 ÷5
Step-by-step explanation:
A baseball player has a batting average of 0.26. What is the probability that he has exactly 2 hits in his next 7 at bats
Answer:
The probability is [tex]P(2) = 0.426[/tex]
Step-by-step explanation:
From the question we are told that
The probability of success is [tex]p = 0.26[/tex]
The number of hits is n = 7
Generally this probability follows a binomial distribution given there can only be two outcome i.e the probability of success and the probability of failure
The probability of failure is [tex]q = 1- p[/tex]
substituting values
[tex]q = 1 - 0.26[/tex]
[tex]q = 0.74[/tex]
Now the probability of exactly 2 hits in his next 7 at bats is mathematically evaluated as
[tex]P(2) = \left n} \atop {}} \right. C_2 *p^{2} * q^{n- 2}[/tex]
substituting values
[tex]P(2) = \left 7} \atop {}} \right. C_2 *p^{2} * q^{7- 2}[/tex]
Here [tex]\left 7} \atop {}} \right. C_2[/tex] means 7 combination 2 and using a calculator(reference calculator soup website) to compute, the value obtained is
[tex]\left 7} \atop {}} \right. C_2 =21[/tex]
So
[tex]P(2) = 21 *(0.26)^{2} * (0.74)^{5}[/tex]
[tex]P(2) = 0.426[/tex]
Hey! i've been working on these questions but I have no idea how to solve this one, could anybody help me? Thanks in advance!
Answer:
1) [tex]\boxed{p(x) = x^3-x^2+x-1}[/tex]
2) [tex]\boxed{p(x) = x^2+x-2}[/tex]
3) [tex]\boxed{p(x) =- 2x^2+2x+4}[/tex]
4) [tex]\boxed{p(x) = 2x^2+x-4}[/tex]
Step-by-step explanation:
Part (1)
[tex]p(x) = x^3-x^2+x-1[/tex]
As we have to determine it by ourselves, this is the polynomial having a degree of 3. p(x) with a degree of 3 means that the highest degree/exponent of x should be 3.
Part (2)
[tex]p(x) = x^2+x-2[/tex]
This can be the polynomial having the factor x-1 because if we put:
x - 1 = 0 => x = 1 in the above polynomial, it gives us a result of zero which shows us that (x-1) "is" a factor of the polynomial.
Part (3)
[tex]p(x) = -2x^2+2x+4[/tex]
This can be the polynomial for which p(0) = 4 and p(-1) = 0
Let's check:
[tex]p(0) =- 2(0)^2+2(0)+4\\p(0) = 0 + 0+4\\p(0) = 4[/tex]
[tex]p(-1)= -2(-1)^2+2(-1)+4\\p(-1) = -2(1)-2+4\\p(-1) = -2-2+4\\p(-1) = 0[/tex]
So, this is the required polynomial determined by "myself".
Part (4):
[tex]p(x) = 2x^2+x-4[/tex]
This is the polynomial having a remainder 6 when divided by (x-2)
Let's check:
Let x - 2 = 0 => x = 2
Putting in the above polynomial
[tex]p(x) = 2(2)^2+(2)-4\\Given \ that \ Remainder = 6\\6 = 2(4) +2-4\\6 = 8+2-4\\6 = 10-4\\6 = 6[/tex]
So, Proved that it has a remainder of 6 when divided by (x-2)
The graphs below have the same shape. Complete the equation of the blue
graph. Enter exponents using the caret (; for example, enter x2 as x^2.
This is equivalent to x^2+8x+13
======================================================
Explanation:
The vertex of f is at (0,0). The vertex of g is at (-4, -3). The vertex has moved 4 units to the left and 3 units down.
To shift to the left, we replace x with x+4. So we have f(x) = x^2 turn into f(x+4) = (x+4)^2 so far.
Then we subtract off 3 to move everything 3 units down. We have
g(x) = (x+4)^2-3
---------------------
Optionally we can expand things out like so
g(x) = (x+4)^2-3
g(x) = (x+4)(x+4)-3
g(x) = x(x+4)+4(x+4)-3
g(x) = x^2+4x+4x+16-3
g(x) = x^2+8x+13
Showing that (x+4)^2-3 is equivalent to x^2+8x+13
(16 points) Find the radius of convergence and the interval of convergence of the power series. g
Answer:
The equation to be solved is missing in the question.
I will explain power series and ways to find the radius and interval of convergence of a powers series in the attached image.
Step-by-step explanation:
Understand the power seriesFind radius of convergenceDetermine interval of convergenceTwice the difference of a number and 9 is 3. Use the variable b for the unknown number.
Answer:
b = 10.5
Step-by-step explanation:
2(b-9) = 3
then:
2*b + 2*-9 = 3
2b - 18 = 3
2b = 3 + 18
2b = 21
b = 21/2
b = 10.5
check:
2(10.5 - 9) = 3
2*1.5 = 3
Finding Side Lengths in a Right Triangle
What is the value of s?
15 units
С
5
B
15
S
D
Answer:
maybe it's 10.because c is 10,b is 10,and so as s.
hence s is 10 also.
Which expression simplifies to 7W+5?
. – 2w + 3 + 5W – 2
C. -3w + 5(2W + 1)
Cual es la respuesta
Answer:
[tex]\large \boxed{\mathrm{-3w + 5(2w + 1)}}[/tex]
Step-by-step explanation:
-2w + 3 + 5w - 2
Combine like terms.
3w + 1
-3w + 5(2w + 1)
Expand brackets.
-3w + 10w + 5
Combine like terms.
7w + 5
Answer:
The answer is C.
-3w +5(2w +1)
Step-by-step explanation:
Shyla's research shows that 8 empty cans make 1/4 pound of aluminum. Shyla wants to know how many cans does it take to make 5 pounds of aluminum. How many cans are there per pound of aluminum?
Answer:
They will need 160 cans to make 5 lbs
32 cans for 1 lbs
Step-by-step explanation:
We can use ratios to solve
8 cans x cans
--------------- = ---------------
1/4 lbs 5 lbs
Using cross products
8 * 5 = 1/4x
40 = 1/4 x
Multiply each side by 4
4 * 40 = 1/4 x * 4
160 =x
They will need 160 cans to make 5 lbs
8 cans x cans
--------------- = ---------------
1/4 lbs 1 lbs
Using cross products
8 * 1 = 1/4x
Multiply each side by 4
8*4 = x
32 cans for 1 lbs
Answer:
32 cans per pound of aluminum
160 cans per 5 pounds of aluminum
Step-by-step explanation:
will make it short and simple.
8 empty cans can make 1/4 pound of aluminum.
therefore... 8 x 4 = 32 cans per pound of aluminum.
Number of cans to make 5 pounds of aluminum = 32 x 5
= 160 cans per 5 pounds of aluminum
ΔABC is similar to ΔMNO. The scale factor from ΔMNO to ΔABC is 3∕2 . If the area of ΔMNO is 10 square units, what's the area of ΔABC? Question 12 options: A) 45 square units B) 90 square units C) 22.5 square units D) 15 square units
Answer:
The area of ΔABC= 6.667 square units
Step-by-step explanation:
ΔABC is similar to ΔMNO.
The scale factor from ΔMNO to ΔABC is 3∕2
the area of ΔMNO is 10 square units,
The area of ΔABC/the area of ΔMNO
= 2/3
The area of ΔABC/10= 2/3
The area of ΔABC= 2/3 * 10
The area of ΔABC= 20/3
The area of ΔABC= 6 2/3
The area of ΔABC= 6.667 square units
Answer:
22.5 square units
Step-by-step explanation:
i multiplied 10 by 2 to get 20 and went with the closest answer and got it right.
i dont know how to do math but i guess it worked
A survey of 1,565 households estimated that 72% of the households in a given state owned a television. What is the population? all the households in given state 1565 households surveyed 1127 households that owned televisions
Answer:
all the houses in given state
Step-by-step explanation:
edge 2021
Using sampling concepts, it is found that the population is given by:
All the households in given state.
What is a sampling?In a sampling, data is taken from a sample to be estimated for the entire population.
For example, if you want to find the proportion of New York State residents that are Buffalo Bills fans, surveying a sample of 1000 residents, the population is all New York State residents.
Hence, in this problem, the population is given by all the households in given state.
More can be learned about sampling concepts at https://brainly.com/question/25122507
Help ASAP Marly has to get some cavities filled at the dentist. The dentist charges a fee of $35 plus $43 per cavity. If Marly ends up having a bill of $164 and c represents the number of cavities, which of the following equations could be used to find how many cavities Marly had filled?
35 = 164 + 43c
164 = 35 - 43c
164 = 35c + 43
35 + 43c = 164
Answer:
the answer is d i believe.
Answer:
The answer is D I took the test the other person is right!
Step-by-step explanation:
If you’re good at statistics please help
Answer:
Step-by-step explanation:
probabilty distribution= interval of x/total area of the distribution
OR P(x)= frequency of x/total frequency(N)*the interval of x(w)
x f probabilty f/N*w
16 10 0.2
17 16 0.32
18 20 0.4
19 4 0.08
w is the width of the bar( interval) 17-16=1
N=10+16+20+4=50
( only need to draw histogram)
Please help . I’ll mark you as brainliest if correct!
Answer:
Stocks = $15,500
Bonds = $107,250
CD's = $47,250
Step-by-step explanation:
S + B + C = 170000
.0325S + .038B .067C = 7745
60,000 + C = b
S = $15,500
B = $107,250
C = $47,250
I’m struggling to understand this problem somebody please explain it to me thanks!!
ax-5d=3cx-2+7
Answer:
x = (5 +5d)/(a -3c)
Step-by-step explanation:
Maybe you're to solve for x.
__
This is a typical "3-step" linear equation.
First, you collect terms with the variable x on one side of the equation. You do that by subtracting from both sides the x-term you don't want where it is.
We choose to remove the 3cx term from the right side, so we subtract it from both sides.
ax -3cx -5d = 3cx -3cx +5 . . . . . . we have combined the constants, too
x(a -3c) -5d = 5 . . . . . . simplify and factor out x
Second, you remove any terms not containing x from the side of the equation with the x-terms. You do that by adding their opposite to both sides of the equation.
We need to remove the -5d term, so we add 5d to both sides.
x(a -3c) -5d +5d = 5 +5d
x(a -3c) = 5 +5d . . . . . . . . . . simplify
Third, we divide by the coefficient of x. We do that to both sides of the equation. We had to put parentheses around the terms on the right, because we're dividing the whole right side of the equation by (a-3c).
x(a -3c)/(a -3c) = (5 +5d)/(a -3c)
x = (5 +5d)/(a -3c)
The perimeter of a rectangular garden is 43.8 feet. It's length is 12.4t . What is it's width ?
Answer:5
Step-by-step explanation:
Find the Value of X 1. Solve for X algebraically. 2. Using complete sentences, describe your method for finding X.
The value of x using complete sentences is 40 degrees.
What is the angle sum property?The angle sum property of a triangle states that the sum of the interior angles of a triangle is 180 degrees. A right-angle triangle is a triangle that has a side opposite to the right angle the largest side and is referred to as the hypotenuse. The angle of a right angle is always 90 degrees.
We are given that;
The measure of angles 75,50 and 85
Now,
In triangle 1
50+75+y=180
y=180-125
y=55
In triangle 2
55+85+x=180
140+x=180
x=40
Therefore, by angle sum properties of triangle answer will be 40 degrees.
Learn more about the triangles;
https://brainly.com/question/2773823
#SPJ3
are:
4. Suppose that the distance of fly balls hit to the outfield (in baseball) is normally
distributed. We randomly sample 27 fly balls. Their recorded distances in feet
234, 310, 285, 249, 210, 311, 265, 290, 308,
254, 295, 287, 231, 302, 325, 308, 221, 237,
312, 277, 259, 223, 340, 204, 214, 303, 309
Let X be the distance of a fly ball.
Use Excel to calculate the following:
a. (1 pt) mean of the sample, x =
b. (1 pt) standard deviation of the sample, s =
C. (2 pts) Calculate the t-score at a 96% confidence level:
d. (2 pts) Calculate the Error Bound (EBM), using the formula, EBM =
(t)(s//n)
e. (1 pt) At 96% confidence level, provide the confidence interval (CI) for the
mean distance in feet of a fly ball.
hantor 92
D
Step-by-step explanation:
a. The mean can be found using the AVERAGE() function.
x = 272.7
b. The standard deviation can be found with the STDEV() function.
s = 39.9
c. The t-score can be found with the T.INV.2T() function. The confidence level is 0.04, and the degrees of freedom is 26.
t = 2.162
d. Find the lower and upper ends of the confidence interval.
Lower = 272.7 − 2.162 × 39.9 = 186.5
Upper = 272.7 + 2.162 × 39.9 = 358.9
Find the interquartile range of the following data set. Number of Points Scored at Ten Basketball Games 57 63 44 29 36 62 48 50 42 34 A.21 B.28 C.6 D.34
Answer:
total number(n)=10
divided the total number into two equal parts so
in one group of number =5
ln first phase group of number middle value =44
In second phase group of number middle value=50
then using formula,q1=44 q3=50
inter quartile range =q3_q1
=50-44
=6
therefore interquartile range =6
Answer: The answer is 6
An investigator claims, with 95 percent confidence, that the interval between 10 and 16 miles includes the mean commute distance for all California commuters. To have 95 percent confidence signifies that
Answer:
Hello the options to your question is missing below are the options
A) if sample means were obtained for a long series of samples, approximately 95 percent of all sample means would be between 10 and 16 miles
B.the unknown population mean is definitely between 10 and 16 miles
C.if these intervals were constructed for a long series of samples, approximately 95 percent would include the unknown mean commute distance for all Californians
D.the unknown population mean is between 10 and 16 miles with probability .95
Answer : if these intervals were constructed for a long series of samples, approximately 95 percent would include the unknown mean commute distance for all Californians ( c )
Step-by-step explanation:
95% confidence
interval = 10 to 16 miles
To have 95% confidence signifies that if these intervals were constructed for a long series of samples, approximately 95 percent would include the unknown mean commute distance for all Californians
confidence interval covers a range of samples/values in the interval and the higher the % of the confidence interval the more precise the interval is,
