Observe that
5/12 = 1/4 + 1/6
so that
tan(5π/12) = tan(π/4 + π/6)
Then
tan(5π/12) = sin(π/4 + π/6) / cos(π/4 + π/6)
… = (sin(π/4) cos(π/6) + cos(π/4) sin(π/6)) / (cos(π/4) cos(π/6) - sin(π/4) sin(π/6))
… = (cos(π/6) + sin(π/6)) / (cos(π/6) - sin(π/6))
(since sin(π/4) = cos(π/4) = 1/√2)
… = (√3/2 + 1/2) / (√3/2 - 1/2)
… = (√3 + 1) / (√3 - 1)
… = (√3 + 1) / (√3 - 1) × (√3 + 1) / (√3 + 1)
… = (√3 + 1)² / ((√3)² - 1²)
… = ((√3)² + 2√3 + 1²) / (3 - 1)
… = (3 + 2√3 + 1) / 2
… = (4 + 2√3) / 2
… = 2 + √3 … … … (C)
If you insist on using the half-angle identity, recall that
sin²(x) = (1 - cos(2x))/2
cos²(x) = (1 + cos(2x))/2
==> tan²(x) = (1 - cos(2x)) / (1 + cos(2x))
Let x = 5π/12. The angle x lies in the first quadrant, so we know tan(x) is positive.
==> tan(x) = +√[(1 - cos(2x)) / (1 + cos(2x))]
We also know
cos(2x) = cos(5π/6) = -√3/2
which means
tan(x) = tan(5π/12) = √[(1 - (-√3/2)) / (1 + (-√3/2))]
… = √[(1 + √3/2) / (1 - √3/2)]
… = √[(2 + √3) / (2 - √3)]
… = √[(2 + √3) / (2 - √3) × (2 + √3) / (2 + √3)]
… = √[(2 + √3)² / (2² - (√3)²)]
… = √[(2 + √3)² / (4 - 3)]
… = √[(2 + √3)²]
… = 2 + √3
The conjecture "if n is a whole number then 3n+1 is a prime number" is disapproved by which statement
Answer:
D
Step-by-step explanation:
Simply because 25 is divisible by 5.
Help pls!! I’m bad at geometry lol
Answer:
The perimeter of a shape is the length around it.
Step-by-step explanation:
We will be using the x and y values and add them together to find the total perimeter.
To do this, let's find all the values of the 2 axis:
(2 to 4) = 2
(1 to 3) = 2
(4 to 10) = 6
(3 to 1) = 2
(10 to 12) = 2
(1 to 8) = 7
(12 to 2) = 10
(8 to 1) = 7
We now add these values together which gives us 38. Don't forget to add the units afterwards (cm, m and so forth).
Find the value of that makes m
||
n.
m
n
xº
2xº
Scale the numerator and the denominator down by a factor of 3 (divide) to write a fraction equivalent to \frac{3}{12}
12
3
.
Answer:
[tex]\frac{1}{4}[/tex]
Step-by-step explanation:
Given
[tex]\frac{3}{12}[/tex] ← divide numerator and denominator by 3
= [tex]\frac{1}{4}[/tex]
What is one possible perimeter of the garden, in meters?
Answer:
24.1 is a possibility for the perimeter
Step-by-step explanation:
The third side between 12+0.5 and 12-0.5, or 12.5 and 11.5.
The third side is between 11.5 and 12.5.
Simce it isn't isosceles third side can't be 12.
So it's asking you to choose a number between 11.5 and 12.5 with the exclusiion of 12 for the third side measurement in meters.
So let's choose 11.6.
So the perimeter is just the sum of all side measurements.
11.6+12+0.5
11.6+0.5+12
12.1+12
24.1
24.1 is a possibility for the perimeter
The Vertices of a quadrilateral are A(4,-3),B(7,10),C(-8,2)and D(-1,-5).Find the length of each diagonal.Show me with the steps Please!
Answer:
13 and 17 units
Step-by-step explanation:
explaination is in pic.
The length of the diagonals of the quadrilateral AC and BD are 13 units and 17 units respectively, as per length between two points.
What is the length between two points in a plane?The length between two given points (x₁, y₁) and (x₂, y₂) will be:
√[(x₂ - x₁)² + (y₂ - y₁)²] units
Given, the vertices of a quadrilateral are A(4,-3),B(7,10),C(-8,2)and D(-1,-5).
Therefore, the diagonals of the quadrilateral will be AC and BD.
The coordinates of the diagonal AC are (4, - 3) and (- 8, 2).
Now, the length of the diagonal AC will be:
= √[(-8 - 4)² + (2 - (- 3))²] units
= √[(- 12)² + (5)²] units
= √[144 + 25] units
= √(169) units
= 13 units (length can't be negative)
Similarly, the coordinates of the diagonal BD are (7, 10) and (- 1, - 5).
Now, the length of the diagonal BD will be:
= √[(-1 - 7)² + (- 5 - 10)²] units
= √[(- 8)² + (- 15)²] units
= √[64 + 225] units
= √(289) units
= 17 units (length can't be negative)
Learn more about the length between two points on a plane here: https://brainly.com/question/14898312
#SPJ2
PLS HELP ME OB THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
Answer:
D. Positively skewed
Step-by-step explanation:
Create a triangle ABC of your choice. Using GeoGebra tools, construct the angle bisectors of ∠A and ∠B. Mark the intersection point of the angle bisectors, and label it point D.
Create a line through point D perpendicular to .
Find the intersection of line segment and the perpendicular line, and label it point E. With point D as the center, create a circle passing through point E.
Measure and label the radius of the inscribed circle of ΔABC on the diagram.
Take a screenshot of your result, and paste it below.
The steps to create attached screenshot of the inscribed circle of triangle ΔABC using GeoGebra tools includes;
1) Clicking on the Geometry link, under Powerful Math Apps group
2) On the opened Geometry page click on the Polygon icon and follow the instructions that come up, which is Select all vertices and then the first vertex (selected) again (a second time)
3) Once the triangle is created, select the Angle Bisector icon, under the Construct group; A message will appear, asking to Select three points or two lines, select three vertex, of the triangle created with a mouse click, with the vertex A in the center, such as BAC, or CAB a straight line representing the angle bisector of angle ∠A is created
4) Repeat the above to create the angle bisector of angle ∠B
5) Click on the Point button under the Basic Tools group, then click on the intersection of the two angle bisectors created above, the point will be automatically labelled point D
6) Click on the Perpendicular Line, icon under the Construct group, then click on point D, and then the line AB to draw the perpendicular from D to AB
7) Click on the point Point icon and then the intersection point of the perpendicular from D and AB to label the point E
8) Click on the Circle with Center basic tool and then points D and E above, to create the inscribed circle of triangle ΔABC
9) Select the Segment tool, then select the center of the circle and a point
on the circumference. Click on the label, from the pop up options, select
the label option AA then change the label of the segment created to Radius
and select Show Label and Show Value. The inscribed circle of ΔABC created with GeoGebra tools is attached
Learn more about GeoGebra hear;
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Answer:
Step-by-step explanation: from edmentum
In Exercises 51−56, the letters a, b, and c represent nonzero constants. Solve the equation for x
x + a = ¾
Answer:
x = ¾-a
Step-by-step explanation:
x + a = ¾
Subtract a from each side
x + a -a= ¾-a
x = ¾-a
▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓
[tex]x+a=\dfrac{3}{4}\\\\x=\dfrac{3}{4}-a\\\\x=\dfrac{3-4a}{4}[/tex]
▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓
solve for the measure of c pt 2 (18pts)
Answer:
d: 20
Step-by-step explanation:
alternative angle
One year ago, the ratio of Honey and Piyush ages was 2:3 respectively. After five years from now, this ratio becomes 4:5. How old is Piyush now?
Answer:
eşnatto eşmatoroorlfld
Answer:
Now , Piyush age =3+Honey age
Step-by-step explanation:
Honey age=x
Piyush age=y
1 year ago,Honey age=x-1
Piyush age=y-1
the ratio of Honey and Piyush age=2:3
x-1:y-1=2:3
x-1/y-1=2/3
3(x-1)=2(y-1)
3x-3=2y-2
3x-2y= -2+3
3x-2y=1 eq _1
after 5 years from now,
Honey age=x+5
Piyush age=y+5
the ratio of them=4:5
x+5/y+5=4/5
5(x+5) =4(y+5)
5x+25=4y+20
5x-4y=20-25
5x-4y=-5 _eq2
eq1and 2_
5x-4y= -5
3x-2y= 1
-
2x-2y=-6
x-y =-3
-y=-3-x
y=3+x
pleaseee help help
The sign at the tee off area for a hole on a golf course indicates the hole is 340
yards from the tee. The golfers drive went to the right. The caddie paced the
drive to be 230 yards. The yardage markers indicate the ball is still 175 yards
from the hole. Determine the angle the golfer went off line from the tee when they
drove the ball.
The angle the golfer went off line from the tee when they drove the ball
is [tex]\phi=28.2 \textdegree[/tex] because the cosine rule has been applied to calculate the angle
From the question we are told that:
Distance of hole from tee [tex]d_h=340yards[/tex]
Distance to the right [tex]d_r=230yards[/tex]
Ball distance from hole [tex]d_b=175 yard[/tex]
Given that the three points form a triangle x,y,z respectively
Where
[tex]d_h=xz[/tex]
[tex]d_r=xy[/tex]
[tex]d_b=yz[/tex]
Using Cosine Rule
[tex]yz^2=xy^2+xz^2-2(xy)(xz)cos\phi[/tex]
Therefore
[tex]cos\phi=\frac{yz^2}{xy^2+xz^2-2(xy)(xz)}[/tex]
[tex]cos\phi=\frac{(175)^2}{230^2+340^2-2(230)(340)}[/tex]
[tex]cos\phi=0.88[/tex]
[tex]\phi=28.2 \textdegree[/tex]
In conclusion the angle the golfer went off line from the tee when they
drove the ball is mathematically deducted and give as
[tex]\phi=28.2 \textdegree[/tex]
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Warren is on vacation and needs to arrange transportation. A rental car costs 40 dollars per day plus a one-time cost of 14 dollars for insurance. Construct a function C(x) that gives the total cost of renting a car for x days. C(x)=________.
If Warren has budgeted 254 dollars for the rental, how many days can he afford?
Answer:
C(x)=40x+14, 6 days
Step-by-step explanation:
C(x)= payment per day*x + initial payment. the payment per day is $40 while the initial payment is $14. so C(x)=40x+14.
C(x)=254=40x+14, 40x=240, x=6
PLEASE HELP DUE IN 15 MNUTES MARKING BRAINLIEST AND 15 POINTS YOU DONT HAVE TO EXPLAIN MUCH
Answer:
see below
Step-by-step explanation:
11a -2(x^2 -3)
Distribute
-2*x^2 -2(-3)
-2x^2 +6
11b 2x(x+4)
Distribute
2x*x +2x*4
2x^2 +8x
12 The perimeter is the sum of all sides
The top is equal to the bottom and the left side is equal to the right
x-10 + x+20+x-10+x+20
Combine like terms
4x +20
What is the equation of the graph shown?
Answer:
2y+3x-2=0
Step-by-step explanation:
The slope of the line is 3/2 and the equation of line is y=-1.5x+1
What is the solution set of { x | x <-5} n { x | x >5 }? Help needed!
Answer:
The Empty set............
Answer:
There is no solution for the intersection of these two sets, as they do not intersect! They don't have any numbers in common and thus form an empty set. The correct answer choice is option D. the empty set.
Step-by-step explanation:
The solution for { x | x <-5} is ---> x < -5
The solution for { x | x >5 } is ---> x > 5
If you placed the two sets on a number line close to each other, you would see that they do not intersect. Thus there is no solution for the intersection of set A and set B as defined in the given problem.
See the graph for better understanding. You see how there's an empty space or area between -5 and 5? Yeah, this is called the empty set which is option D from your answer choices.
Estimate the solution to the following system.
Answer:
(-150, 45)
Step-by-step explanation:
The solution to the system is where the two graphs intersect
My best guess from the graph is
(-150, 45)
Which expression is equal to the expression below?
(2x6)^4
Answer:
2^4 x 6^4
Step-by-step explanation:
could someone help me with these questions please i’m really confused
Answer:
C
Step-by-step explanation:
c
The hypotenuse of a right triangle measures nem and one of its legs measures o em.
Mnd the measure of the other leg. If necessary, round to the nearest tenth.
Sun
attempt to
Using Pythagorean theorem
[tex]\\ \sf\longmapsto P^2=H^2-B^2[/tex]
[tex]\\ \sf\longmapsto P^2=11^2-9^2[/tex]
[tex]\\ \sf\longmapsto P^2=121-81[/tex]
[tex]\\ \sf\longmapsto P^2=40[/tex]
[tex]\\ \sf\longmapsto P=\sqrt{40}[/tex]
[tex]\\ \sf\longmapsto P=6.2cm[/tex]
Step-by-step explanation:
Given,
Hypotenuse = 11 cm
Base (One of the given leg) = 9 cm
Therefore,
According to Pythagoras Theorem,
[tex] {base}^{2} + {height}^{2} = {hypotenuse}^{2} [/tex]
[tex] = > {(9)}^{2} + {height}^{2} = {(11)}^{2} [/tex]
[tex] = > {height}^{2} = {(11)}^{2} - {(9)}^{2} [/tex]
[tex] = > {height}^{2} = 121 - 81[/tex]
[tex] = > {height}^{2} = 4 0[/tex]
[tex] = > height = \sqrt{40} [/tex]
=> height = 6.3245553203
When rounded to nearest tenth,
=> height = 6.3
Hence,
Required length of other leg is 6.3 (Ans)
If the length of the shorter arc AB is 22cm and C is the center of the circle then the circumference of the circle
is:
Answer:
176 cmStep-by-step explanation:
The shorter arc is 22 cm.
Arc length formula:
s = πrθ/180Circumference formula:
C = 2πrUse the first formula to work out the value of C:
22 = πr*45/180πr/4 = 22πr = 88 2πr = 176C = 176 cmLength of arc=L=22cm
We know
[tex]\boxed{\sf L=\dfrac{\Theta}{360}\times πr}[/tex]
[tex]\\ \sf\longmapsto 22=\dfrac{45}{360}\times 2πr[/tex]
[tex]\\ \sf\longmapsto \dfrac{2πr}{8}=22[/tex]
[tex]\\ \sf\longmapsto {2πr=176}[/tex]
[tex]\\ \sf\longmapsto Circumference=176cm[/tex]
Based only on the given information, it is guaranteed that LN I MO.
L
Given: ALON
LM: NM
LO = NO
MO #MO
M
0
N
Answer:
true
Step-by-step explanation:
We are given that sides LM and NM, LO and NO, MO and MO are congruent. Since this describes 3 sides of the triangle, you can say ΔMNO is congruent to ΔMLO. From this, you can say ∠OMN is congruent to ∠OML. The two angles (∠OMN and ∠OML) form a straight line, meaning they add up to 180 degrees. We can write:
∠OMN + ∠OML = 180
And since ∠OMN = ∠OML, we can substitute and solve:
∠OMN + ∠OMN = 180
2∠OMN = 180
∠OML =∠OMN = 90
Since both these angles are 90 degrees, LN is perpendicular to MO by definition.
What is the slope of a line that passes through the points (-2, 4) and (-6, 12)?
Answer:-3\2
Step-by-step explanation:
slope is difference y axis by x axis
4-12/-2+6=-6/4=-3\2
What will be the first term of a geometric series which has its sum 280, common ratio 3 and the last term 189 ?
Answer:
b1=7
Step-by-step explanation:
If we deal with geometric series, we should use the formulas for it. If there is the last term, it is not infinite geometric series. The sum of geometric series which isn't infinite is equal to b1(r^n-1)/(r-1) where b1 is the first term and r is the common ratio.
So 280= b1(3^n-1)/(3-1)
560= b1(3^n-1)
560= b1*3^n-b1
Then express bn=b1*r^(n-1)
189= b1*3^(n-1)
189= b1*3^n*1/3
567= b1*3^n when
560= b1*3^n-b1
560=567-b1
b1=7
I need help, please come answer this
Answer:
[tex]8 \times \frac{15}{5} - (5 + 9) \\8 \times 3 - (14) \\ 24 - 14 \\ = 10[/tex]
I hope I helped you^_^
i don’t know what it is can someone help
Answer:
b
Step-by-step explanation:
I'LL GIVE BRAINLIEST !!! FASTER
Answer:
Option A
Step-by-step explanation:
angle a and angle are equal since the vertical lines are parallel and horizontal lines are not and a, b, c are corresponding angles
Which lists all of the shapes that are in a two-dimensional net of a square pyramid? 6 squares 4 triangles 1 square and 3 triangles 1 square and 4 triangles
Answer:
4 triangles and 1 square
Step-by-step explanation:
Required
The shapes in two-dimensional net of a square pyramid
To do this, I will attach an attachment of a 2D net of a square pyramid (see attachment)
From the attachment, we can see that:
The 2d shape of the pyramid is made of 4 triangles and 1 square
Answer:
D
Step-by-step explanation:
Kristian spends 45% of his $ 75 on a game. What is the price of the game
Answer:
The price of the game is 33.75
Step-by-step explanation:
45% of 75
.45 * 75
33.75
The price of the game is 33.75
If T is the midpoint of SU what are ST, TU, and SU?
a. ST = 7, TU = 63, and SU = 126
b. ST = 63, TU = 63, and SU = 126
c. ST = 80, TU = 80, and SU = 160
d. ST = 18, TU = 18, and SU = 36
Answer:
B
Step-by-step explanation:
As T is the midpoint of SU, ST=TU. 9x=5x+28, 4x=28, x=7. ST=TU=63 and SU=126
