URGENT WHOEVER ANSWER CORRECT GETS BRAINLIEST ANSWER!!!!!! use the information in the table to calculate the ages of the meteorites. The half-life of potassium-40 is 1.3 billion years. Meteorite Initial Amount (g) Final Amount (g) 1 30 7.5 2 80 5 3 100 12.5 Use your calculations to answer the questions. How old is meteorite 1? How old is meteorite 2? How old is meteorite 3?

Answer:

i believe it is strong acids, strong bases, and salts.

Explanation:

Hope this helps : )

Answer:

The concentration of HA is the same as concentration of H3O+ and A- produced.

Explanation:

The dissociation equation is given below:

HA(aq) + H2O (l) —> H3O+(aq) + A-(aq)

From the reaction above, we can see that the acid is monoprotic acid i.e it has only 1 ionisable hydrogen atom.

Now, from the balanced equation, we can see that the acid produced equal concentration of H3O+ and A-.

This account for the reason why the bars for H3O+ and A- have the same height as the bar for HA.

Answer:

38g of Cr

Explanation:

Step 1:

The balanced equation for the reaction:

2K + CrBr2 —> 2KBr + Cr

Step 2:

Determination of the masses of K and CrBr2 that reacted and the mass of Cr produced from the balanced equation.

This is illustrated below:

Molar mass of K = 39g/mol

Mass of K from the balanced equation = 2 x 39 = 78g

Molar Mass of CrBr2 = 52 + (80x2) = 212g

Mass of CrBr2 from the balanced equation = 1 x 212 = 212g

Molar Mass of Cr = 52g/mol

Mass of Cr from the balanced equation = 1 x 52 = 52g

From the balanced equation above,

78g of K reacted with 212g of CrBr2 to produce 52g of Cr.

Step 3:

Determination of the limiting reactant.

This is illustrated below:

From the balanced equation above,

78g of K reacted with 212g of CrBr2.

Therefore, 57g of K will react with = (57 x 212)/78 = 154.92g of CrBr2.

From the above calculation, we can see that a lesser mass (i.e 154.92g) than what was given ( i.e 199g) of CrBr2 is needed to react completely with 57g of K. Therefore, K is the limiting reactant and CrBr2 is the excess reactant.

Step 4:

Determination of the mass of Cr produced by the reaction.

In this case, the limiting reactant will be use because it will give the maximum yield of Cr as all of it is used up in the reaction process. The limiting reactant is K and the mass of Cr produced is obtained as follow:

From the balanced equation above,

78g of K reacted to produce 52g of Cr.

Therefore, 57g of K will produce = (57 x 52)/78 = 38g of Cr.

Therefore, 38g of Cr is produced from the reaction.

Answer:

B :)

Explanation:

Trachea is were oxygen is entered :D (5 stars?)

Answer:

It is widely believed that Buddhism entered China via the Silk Road under the Han Dynasty. After trade and travel was established with the Yuezhi, who by that time were forced southward toward India, Yuezhi monks began to travel with the merchant caravans; preaching their religion along the Silk Road.

Explanation:

i got this from google

Answer:

I would say that the mutation has no effect on the organism, as it doesn't help or harm it.

hope this helps :)

Explanation:

Answer:

its a neutral

Explanation:

i did the test

Answer:

I believe the answer you're looking for is DNA, not sure though

Answer:

1. carboxylic acid

2. ether

3. aldehyde

4. ketone

5. amine

6. alcohol

Explanation:

Know the functional groups. If you would like me to teach you them let me know.

- Hope that helps! Please let me know if you need further explanation.

Answer:

8 kg mass

Explanation:

As we can see in the image the weight of mass 8 kgs has a large surface area as compared to the surface area of other masses. In general, it has been observed that a wide surface area has more surface particle for heat conduction. Hence, the rate of heat transfer is directly proportional to the surface area of heat conducting surface. Thus, the larger the surface area, the faster is the rate of heat conduction.

Hence, weight of mass 8Kg wil transfer heat a fast rate.

Answer: In CaF2, the oxidation number of Ca is +2

, and that of F is -1

. In H2SO4, the oxidation number of H is +1

, that of S is +6

, and that of O is -2

. In CaSO4, the oxidation number of Ca is +2

, that of S is +6

, and that of O is -2

. In HF, the oxidation number of H is +1

, and that of F is -1

Answer:

9.7 atm.

Explanation:

The following data were obtained from the question:

Initial pressure (P1) = 1 atm

Initial volume (V1) = 0.725 L

Final volume (V2) = 0.075 L

Final pressure (P2) =?

The final pressure can be obtained by using the Boyle's law equation since the temperature is constant. This is illustrated below:

P1V1 = P2V2

1 x 0.725 = P2 x 0.075

Divide both side by 0.075

P2 = 0.725 / 0.075

P2 = 9.7 atm.

Therefore, the new pressure is 9.7 atm.

Answer: PtF6

Explanation:  is one of seventeen known binary hexafluorides.

Answer:

The ISS provides a location in the relative safety of low Earth orbit to test spacecraft systems that will be required for long-duration missions to the Moon and Mars.

Explanation:

Answer:

V = 127.57 mL

Explanation:

In this case, we are having an acid base titration, and this, according to the overall reaction:

2H₃PO₄ + 3Ca(OH)₂ -----> Ca₃(PO₄)₂ + 6H₂O

This reaction was neutralized, so, it's a neutralization reaction, therefore, we can use the following expression for neutralization reactions:

n₁ = n₂  (1)

This is because, in the equivalence point, both moles of the reagents are the same. Now we need to do a relation between this and the actual moles that we have according to the overall reaction.

In this case, we have 2 moles of acid reacting with 3 moles of base, so, the equation (1) is re-written like this:

2n₁ = 3n₂   (2)

Knowing this, and that we have values of concentrations and volume, we can write the expression of moles in terms of molarity and volume:

n = M * V    replacing in (2):

2M₁V₁ = 3M₂V₂   From here, we can solve for V₂ which is the volume of the base:

V₂ = 2M₁V₁ / 3M₂   (3)

Now, all we have to do is replace the given values to obtain the volume of the base:

V₂ = 2 * 1.6 * 59.8 / 3 * 0.5

Answer:

[tex]V_{Ca(OH)_2}=0.287L=287mL[/tex]

Explanation:

Hello,

In this case, given the reaction:

[tex]2 H_3PO_4 + 3 Ca(OH)_2 \rightarrow Ca_3(PO_4)_2 + 6 H_2O[/tex]

We first compute the moles of phosphoric acid that are actually reacting given the volume (must be in litres) and the molarity:

[tex]n_{H_3PO_4 }=1.60\frac{mol}{L}*59.8mL*\frac{1L}{1000mL} =0.0957molH_3PO_4[/tex]

Next, we compute the moles of calcium hydroxide that are reacting by using the 3:2 molar ratio with phosphoric acid:

[tex]n_{Ca(OH)_2}=0.0957molH_3PO_4*\frac{3molCa(OH)_2}{2molH_3PO_4} =0.144molCa(OH)_2[/tex]

Finally, by knowing the 0.500 M of the calcium hydroxide solution we compute the required volume:

[tex]V_{Ca(OH)_2}=\frac{n_{Ca(OH)_2}}{M_{Ca(OH)_2}}=\frac{0.144mol}{0.500\frac{mol}{L} } \\ \\V_{Ca(OH)_2}=0.287L=287mL[/tex]

Best regards.

Answer:

7.56 x 10^13 J/mol

Explanation:

Binding energy = (Mass defect) × (velocity of light)² = (84 × 10^-5) × (3 × 10^8)^2 = 756 × 10^11 J = 7.56 × 10^13 J/mol

Hope this helps -Paige

Answer:

the answer is A heterogeneous solutions

Explanation:

Mixtures in two or more phases are heterogeneous mixtures. Examples include ice cubes in a drink, sand and water, and salt and oil. The liquid that is immiscible form heterogeneous mixtures. A good example is a mixture of oil and water.Jun 26, 2019

the answer is in the picture!

Answer:

The volume of the gas is 2.80 L.

Explanation:

An ideal gas is a theoretical gas that is considered to be made up of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The Pressure (P) of a gas on the walls of the container that contains it, the Volume (V) it occupies, the Temperature (T) at which it is located and the amount of substance it contains (number of moles, n) are related from the equation known as Equation of State of Ideal Gases:

P*V = n*R*T

where R is the constant of ideal gases.

In this case:

Replacing:

2 atm* V= 0.223 moles*0.0821 [tex]\frac{L*atm}{mol*K}[/tex]* 306 K

Solving:

[tex]V=\frac{0.223 moles*0.0821\frac{L*atm}{mol*K} * 306 K}{2 atm} \\[/tex]

V= 2.80 L

The volume of the gas is 2.80 L.

Answer : A

0,15 moles of NaOH -------in-------1000ml

x moles of NaOH ---------in-------100ml

x= 0,015 moles of NaOH

final volume =150ml

0,015 moles of NaOH -------in------150ml

x moles of NaOH ------in--------1000ml

x= 0,1 moles of NaOH

Answer: [tex]CO[/tex] is the limiting reagent and [tex]Fe_2O_3[/tex] is the excess reagent.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} Fe_2O_3=\frac{42.7g}{159.69g/mol}=0.267moles[/tex]

[tex]\text{Moles of} CO=\frac{13.2g}{28g/mol}=0.471moles[/tex]

The given balanced equation is :

[tex]Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)[/tex]

According to stoichiometry :

3 moles of [tex]CO[/tex] require = 1 mole of [tex]Fe_2O_3[/tex]

Thus 0.471 moles of [tex]CO[/tex] will require=[tex]\frac{1}{3}\times 0.471=0.157moles[/tex]  of [tex]Fe_2O_3[/tex]

As given amount of [tex]Fe_2O_3[/tex] is more than the required amount , it is the excess reagent.Thus [tex]CO[/tex] is the limiting reagent as it limits the formation of product.

Answer:

a) 29.0 years

b) 0.89 g

Explanation:

Using the formula

t1/2= t×ln2/ln(No/Nt)

Where

Nt= mass of radioactive isotope at time= t =0.953g

No= initial mass of radioactive isotope present= 1.000g

t= time taken for N mass of radioactive isotope to remain = 2 years

t1/2 = half-life of radioactive isotope= ???

Substituting the values

t1/2= 2 × ln2/ln(1.000/0.953)

t1/2= 2× 0.693/0.048

t1/2= 29 hours

b)

N= No(1/2)^t/t1/2

Where t= 5 years

N= 1.000(1/2)^5/29

N= 1.000(1/2)^0.17

N= 0.89g

Answer:

539.76 moles of O₂

Explanation:

Equation of reaction:

4Al + 3O₂ → 2Al₂O₃

From the equation of reaction above, 4 moles of Al will react with 3 moles of O₂

We can use mole-concept to find the number of moles of O₂.

4 moles of Al = 3moles of O₂

719.68 moles of Al = x moles of O₂

X = (3 × 719.68) / 4

X = 2159.04 / 4

X = 539.76 moles

539.76 moles of O₂ will react with 719.68 moles of Al

Answer:

[tex]n_{O_2}=959.57molO_2[/tex]

Explanation:

Hello,

In this case, given the reaction:

[tex]4Al (s) + 3O_2(g) \rightarrow 2Al_2O_3(s)[/tex]

Since aluminum and oxygen are in a 4:3 molar ratio, we compute the moles of oxygen that completely react as shown below:

[tex]n_{O_2}=719.68molAl*\frac{3molO_2}{4molAl} \\\\n_{O_2}=959.57molO_2[/tex]

Best regards.

Answer:

c,density is the measure of compactness in a substance. Liquid particles are close together however they aren't as close as the particles in solids.

Answer:

[tex]T1=166.66K[/tex]

Explanation:

According to Gay-Lussac’s law simply states that the ratio of the initial pressure and temperature is equal to the ratio of the final pressure and temperature for a gas of a fixed provided that the mass is kept at a constant volume.

Given:

Initial pressure, P1 = 1 atm

Final pressure, P2 = 1.5 atm

Final temperature, T2 = 250 K

The law can be applied using the below formula

P1T2 = P2T1

Then,

T1 = (P1T2)/P1 = (1*250)/(1.5) = 166.66 Kelvin.

[tex]T1=166.66K[/tex]

:

Answer:

[tex]T_1=166.7K[/tex]

Explanation:

Hello,

In this case, by applying the Gay-Lussac's law which help us to understand the pressure-temperature gas behavior via a directly proportional relationship:

[tex]\frac{P_1}{T_1} =\frac{P_2}{T_2}[/tex]

In such a way, as we are asked to compute the initial temperature knowing the initial pressure and final both temperature and pressure, so we solve for it:

[tex]T_1=\frac{T_2P_1}{P_2}=\frac{250K*1atm}{1.5atm} \\\\T_1=166.7K[/tex]

Best regards.

Answer:

CuFeS2

Explanation:

Calculate the moles of each substance by doing moles= mass/relative atomic mass. you should get 0.25 moles of copper and iron and 0.5 moles of sulfur. Then divide all of those numbers by 0.25 (as its the lowest value) you should get 1 for copper and iron and 2 for sulfur. This represents the ratio that they are in within the mineral.