Answer:
la respuesta esta abajo
Step-by-step explanation:
a) Sea x el número del artículo x mientras que y representa el número del artículo y.
Dado que cada cantidad de artículo x requiere 2 horas de trabajo de perforación, mientras que cada cantidad de artículo y requiere 5 horas de trabajo de perforación. Hay un máximo de 40 horas disponibles, por tanto el modelo se da como:
2x + 5y ≤ 40
b) La trama se trazó utilizando la herramienta gráfica en línea de geogebra.
c) Para 10 unidades de X y 5 unidades de y:
2 (10) + 5 (5) = 45> 40
Por lo tanto, esto no sería posible porque requerirá 45 horas de perforación, lo que es más que el máximo de 40 horas disponibles.
The ratio of boys to girls in a class is 3:5. There are 32 students in the class. How many students are girls?
Answer:
20 girls
Step-by-step explanation:
boys : girls : total
3 5 3+5 = 8
There are 32 students
32/8 = 4
Multiply each term by 4
boys : girls : total
3*4 5*4 8*4
12 20 32
There are 20 girls
Answer: 20 girls
Step-by-step explanation:
So boys to girls is 3 to 5
It asks for girls in class
Suppose there were 8 people in class, 5/8 of the people would be girls
It states that 32 people are in the class, so do 32 x 5/8 to get 20 girls
I WILL GIVE YOU BRAINLIEST AS SOON AS I CAN, PLEASE HELP!
Answer:
1. The given equation is presented as follows;
[tex]3^{2 \cdot x - 1} = \dfrac{1}{9}[/tex]
The above equation can be rewritten as follows;
[tex]3^{2 \cdot x - 1} = 3^{-2}[/tex]...(1)
Therefore, taking logarithm to base 3 of both sides of the equation, the above equation can be rewritten without an exponent as follows;
[tex]log_3 \left (3^{2 \cdot x - 1} \right) =log_3\left(\dfrac{1}{9} \right) = log_3 \left( 3^{-2} \right)[/tex]...(2)
2. Inverse relationship of exponents is given as follows;
(1/a)ˣ = a⁻ˣ
Therefore, we have;
1/9 = 1/(3²) = (3²)⁻¹ = 3⁻²
Taking log of both sides of [tex]\left (3^{2 \cdot x - 1} = \dfrac{1}{9} = 3 ^{-2}\right)[/tex] gives;
[tex]log_3 \left (3^{2 \cdot x - 1} \right)= log_3 \left( 3^{-2} \right)[/tex]
From logarithm rules, we have;
From equation (2), we have;
[tex](2 \cdot x - 1) \cdot log_3 3 = -2 \cdot log_3 3[/tex]
Therefore, the equation can be simplified by dividing both sides by the common factor, [tex]log_3 3[/tex], as follows;
[tex]\dfrac{(2 \cdot x - 1) \cdot log_3 3 }{log_3 3} = \dfrac{-2 \cdot log_3 3}{log_3 3}[/tex]
Therefore, we get;
2·x - 1 = -2...(3)
3. Solving 2·x - 1 = -2, gives;
2·x - 1 = -2
2·x = -2 + 1 = -1
x = -1/2 = -0.5
x = -0.5
EQUATION 3
The given equation is presented as follows;
[tex]125^{x - 1} = 5^x[/tex]
1. By the property of exponents, we have;
[tex]\left(a^b \right)^x = a^{b \times x}[/tex]
125 = 5³
Therefore, we get;
[tex]125^{x - 1}= \left(5^3\right)^{x - 1} = 5^{3\times (x - 1)} = 5^{(3\times x - 3)}[/tex]
[tex]125^{x - 1}= 5^{(3\times x - 3)}[/tex]
2. Given that we can rewrite the given equation as follows;
[tex]125^{x - 1} = 5^{(3\times x - 3)} = 5^x[/tex]
Therefore;
[tex]5^{(3\times x - 3)} = 5^x[/tex]
Both sides of the equation are given in powers of 5, therefore, the appropriate base logarithm to use on both sides to rewrite the equation is logarithm to base 5
3. Using logarithm, by applying logarithm to both sides, we get;
[tex]log_5 \left (5^{(3\times x - 3)} \right) = log_5 \left(5^x \right)[/tex]
[tex](3\times x - 3) \cdot log_5 5 = x \cdot log_5 5[/tex]
Dividing both sides by log₅5 gives;
[tex]\dfrac{ (3\times x - 3) \cdot log_5 5}{log_5 5} = \dfrac{ x \cdot log_5 5}{log_5 5}[/tex]
∴ 3 × x - 3 = x
3 × x - x = 3
2·x = 3
x = 3/2 = 1.5
x = 1.5
Step-by-step explanation:
Let U be the universal set, where: U = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 , 11 , 12 , 13 , 14 , 15 , 16 , 17 } Let sets A , B , and C be subsets of U , where: A = { 2 , 3 , 5 , 6 , 7 } B = { 1 , 3 , 9 , 10 , 11 , 14 } C = { 5 , 9 , 12 , 13 , 15 }
Answer:
16 elements
0 elements
Step-by-step explanation:
U = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 , 11 , 12 , 13 , 14 , 15 , 16 , 17 }
Let sets A , B , and C be subsets of U , where:
A = { 2 , 3 , 5 , 6 , 7 }
B = { 1 , 3 , 9 , 10 , 11 , 14 }
C = { 5 , 9 , 12 , 13 , 15 }
(A U B U C) = elements in either A, or B or C
(A U B U C) = {1,2,3,5,6,7,9,10,11,12,13,14,15}
(A U B U C) n (A U B U C) = elements on both intersecting set ; this will contain the same set as (A U B U C) are the same.
Number of elements = 13
(A n B n C) = elements occurring in both A, B and C
(A n B n C) = {} = empty set
(A n B n C) n (A n B n C) = {} = 0
In a three-digit number, the hundreds digit is one half of the tens digit. The tens digit is
twice the one's digit. If the sum of the digits is eight, find the number.
Answer:
242
Step-by-step explanation:
Rule out anything above five from being the ones number as it wouldn't be possible to be doubled for the tens.
After that it is just trial and error putting 1,2,3,4 in the tens and following the word equation.
121 = doesn't equal 8
363= doesn't
484 = doesn't
thats leaves 242 which follows the pattern and equals 8
What is the common difference for this arithmetic sequence? 45,39,33,27,21,...
Answer:
I expect the correct answer
_6
.
Answer:
6
Step-by-step explanation:
because if u minus 39 from 45 u get six and same for the others
39.341 × 0.72 = _____
Answer:
28.32552
Step-by-step explanation:
39.331×0.72=28.32552
y = 4x + 5 ; y = x - 4
Answer:
(- 3, - 7 )
Step-by-step explanation:
Given the 2 equations
y = 4x + 5 → (1)
y = x - 4 → (2)
Substitute y = 4x + 5 into (2)
4x + 5 = x - 4 ( subtract x from both sides )
3x + 5 = - 4 ( subtract 5 from both sides )
3x = - 9 ( divide both sides by 3 )
x = - 3
Substitute x = - 3 into either of the 2 equations and evaluate for y
Substituting into (2)
y = x - 4 = - 3 - 4 = - 7
solution is (- 3, - 7 )
write one eighth as a decimal
Answer:
0.125
Step-by-step explanation
one eighth = 1/8
Divide the numerator by denominator and the answer is 0.125
What is the following quotient?
StartFraction 6 minus 3 (RootIndex 3 StartRoot 6 EndRoot) Over RootIndex 3 StartRoot 9 EndRoot EndFraction
2 (RootIndex 3 StartRoot 3 EndRoot) minus RootIndex 3 StartRoot 18 EndRoot
2 (RootIndex 3 StartRoot 3 EndRoot) minus 3 (RootIndex 3 StartRoot 2 EndRoot)
3 (RootIndex 3 StartRoot 3 EndRoot) minus RootIndex 3 StartRoot 18 EndRoot
3 (RootIndex 3 StartRoot 3 EndRoot) minus 3 (RootIndex 3 StartRoot 2 EndRoot)
Answer:
A.[tex]2(3^{\frac{1}{3}})-\sqrt[3]{18}[/tex]
Step-by-step explanation:
We are given that
[tex]\frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}})[/tex]
We have to find the quotient.
[tex]\frac{6}{\sqrt[3]{9}}-3(\frac{\sqrt[3]{6}}{\sqrt[3]{9}})[/tex]
[tex]\frac{2\times 3}{\sqrt[3]{3^2}}-3(\frac{\sqrt[3]{3\times 2}}{\sqrt[3]{3^2}})[/tex]
[tex]2\times\frac{3}{3^{\frac{2}{3}}}-3(\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3^{\frac{2}{3}}})[/tex]
Using the property
[tex](ab)^n=a^n\cdot b^n[/tex]
[tex]2\times 3^{1-\frac{2}{3}}-3(2^{\frac{1}{3}}\times 3^{\frac{1}{3}-\frac{2}{3}})[/tex]
Using the property
[tex]\frac{a^x}{a^y}=a^{x-y}[/tex]
[tex]2(3^{\frac{1}{3}})-3(2^{\frac{1}{3}}\times 3^{-\frac{1}{3}})[/tex]
[tex]2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{1-\frac{1}{3}}[/tex]
[tex]2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{\frac{2}{3}}[/tex]
[tex]2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{3^2}[/tex]
[tex]2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{9}[/tex]
[tex]2(3^{\frac{1}{3}})-\sqrt[3]{2\times 9}[/tex]
[tex]2(3^{\frac{1}{3}})-\sqrt[3]{18}[/tex]
Hence, the quotient of [tex]\frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}})[/tex] is given by
[tex]2(3^{\frac{1}{3}})-\sqrt[3]{18}[/tex]
Option A is correct.
Answer:
A
Step-by-step explanation:
please help me :)))))))))))))))))
Answer:
A
Step-by-step explanation:
third angle=180-(35+73)=180-108=72°
Question 7 of 10 Classify the following triangle. Check all that apply. 6 D A. Scalene D B. Right C. Obtuse D. Isosceles E. Acute F. Equilateral
Answer:
Right angle triangle
Acute
Step-by-step explanation
1 right angle/90 degrees
2 acute angles
a) Find csc ∅, given that cot ∅ = -7/2 and cos ∅ < 0
b) Find cot ∅, given that cos ∅ = 15/17 and ∅ is in Quadrant IV
Answer:
a) csc∅ = √53/2
b) cot ∅ = 15/√514
Step-by-step explanation:
a) The value of cot ∅ = -7/2
cos ∅ < 0
We note that cos(∅) is less than 0 in Quadrant II and III, and cot(∅) is less than 0 in the Quadrant II, therefore, we have;
∅ is in the Quadrant II
csc∅ = (√((-7)² + 2²))/2 =√53/2 ≈ 3.64
csc∅ = √53/2
b) cos∅ 15/17
∅ is in Quadrant IV
∴ cot ∅ = 15/(√(15² + 17²)) = 15/√514 ≈ 0.662
cot ∅ = 15/√514
If a ⋆ b = ab² - a²b, then 2 ⋆ 3 = i don't kno the answer
Hello,
We know that :
a * b = ab² - a²b
We know that : 2 * 3 = 6 but we want to try this formula.
We have :
a = 2 and b = 3
So :
2 * 3
= 2 * 3² - 2² * 3
= 2 * 9 - 4 * 3
= 18 - 12
= 6
It works :)
2 to the negative 3 power times how much is 2 to the negative 1 power? Does the answer match your answer from question 3b? Why or why not?
Answer: 2^-3 = 1/8
2^-1 = 1/2
you have to multiply 2^-3 by 4 to get to 2^-1
Step-by-step explanation:
which equation can be used to represent the statement?
The sum of one-sixth of a number and negative two is equal to negative two-thirds.
a) 1/6+n=2+2/3
b)1/6+n= -2+(-2/3)
c)1/6n+2= -2/3
d)1/6n-2= -2/3
Answer:
its option d
Step-by-step explanation:
hope it helps
The expression \sqrt[3]{3}\cdot \sqrt[5]{3^6}
3
3
⋅
5
3
6
is equivalent to
By simplifying the given expression, the expression [tex]\sqrt[3]{3}[/tex] * [tex]\sqrt[5]{3^6}[/tex] is equivalent to [tex]3^(23/15).[/tex]
How to find equivalent valueTo simplify the given expression, combine the two radicals using the property of exponentiation.
First, simplify the expression inside the second radical:
√[5]{[tex]3^6[/tex]}
Since the index is 5, rewrite the expression as:
[tex](3^6)^(1/5)[/tex]
Using the property of exponentiation, multiply the exponents:
[tex]3^(6/5)[/tex]
Now combine this result with the first radical:
[tex]3\sqrt3 * 3^(6/5)[/tex]
Since ∛3 can be written as [tex]3^(1/3)[/tex], rewrite the expression as:
[tex]3^(1/3) * 3^(6/5)[/tex]
To multiply two numbers with the same base, add the exponents:
[tex]3^(1/3 + 6/5)[/tex]
To simplify further, we need a common denominator for the fractions:
[tex]3^(5/15 + 18/15)[/tex]
Combining the fractions:
[tex]3^(23/15)[/tex]
Therefore, the given expression is equivalent to [tex]3^(23/15).[/tex]
Learn more on equivalent on https://brainly.com/question/2972832
#SPJ3
Nathan dove −4 feet into a pool. Jenny dove deeper into the same pool. Which could represent the depth that Jenny dove?
A −5 feet
B −3 feet
C 2 feet
D 6 feet
Combine these radicals. -6v100 + V36
Answer:
-54
Step-by-step explanation:
[tex]-6\sqrt{100} +\sqrt{36}[/tex]
-6 * 10 + 6
-60 + 6
= -54
100 = 50 *2
= 25 * 2 * 2
= 5 * 5 * 2 * 2
= [tex]5^{2} *2^{2}[/tex]
5 * 2 = 10
~~~~~~~~~~
36 = 6 * 6 = 3 * 3 * 2 * 2 = 3^2 ^ 2^2
3*2 = 6
Set up an en equation and use it to solve for x
Answer:
x = 30
Step-by-step explanation:
The 2 angles lie on a straight line and sum to 180° , then
x - 3 + 153 = 180
x + 150 = 180 ( subtract 150 from both sides )
x = 30
Answer:
x = 30
Step-by-step explanation:
180° = total
153° = part
180° - 153° = 27°
Then use the equation to find the value of x
(x - 3) = 27
(x + 3) = +3 Add 3 to both sides!
x = 30
tapes that usually cost $8 each are on sale for 30% off what is the price for a tape on sale?
Answer:
$5.6
Step-by-step explanation:
Answer:
8*30/100= 2.4
so present cost = 8.0 - 2.4 = $ 5.6
Step-by-step explanation:
Which definition best describes vertical angles?
O A. A pair of angles whose sum is 180°
B. A pair of angles that combine to form a straight angle
C. A pair of angles whose sum is 90°
D. A pair of opposite angles formed by intersecting lines
SUBM
Which of the following expressions are equivalent to -45 +12?
Choose all answers that apply:
A 3(-15+4)
B
5(-50 + 12)
None of the above
3 (- 15 + 4) = -45 + 12
This is the answer
When 345 is multiplied by a power of 10 the number of zeros in the product is related to the power of 10. Explain how the number of zeros relates to the power of 10.
Answer:
The Number of Zeroes In The Results is Always equal To the Powers of 10.
Step-by-step explanation:
Example:-
345*[tex]10^{2}[/tex] = 34500
345*[tex]10^{5}[/tex] = 34500000
345*[tex]10^{7}[/tex] = 3450000000
345*[tex]10^{8}[/tex] = 34500000000
(In the Above examples, There is All The Numbers of Zeroes In The Results is equal To the Powers of 10)
Please help me I really need help
771.05 m³ is tge answer brudah !!
In a class, there are 87 students
in the class, and 38 are boys. What is
the probability that a girl is selected
randomly to represent the class in a
debate?
Answer:
49/87 = .56 = 56%
Step-by-step explanation:
Answer:
56%
Step-by-step explanation:
What is in ? Record the measurement.
Answer:
In could be mean inches? otherwise there is not enough context to know sorry :/
Step-by-step explanation:
Answer:the answer is 90
Alguien me ayuda Gracias
1) Se lanza un dado la probabilidad de que caiga un número
mayor que 5 es: 26,66%
V o F
2) Se lanza un dado, la probabilidad de que caiga un número mayor que 2 es: 56,66%
V o F
3) En una caja hay 12 pelotas de igual tamaño, de las cuales 7 son azules y 5 blancas.
La probabilidad de que al extraer una esta sea blanca es: 40,66%
V o F
4) Un matrimonio desea tener 3 hijos. La probabilidad de obtener:
Dos varones y una hembra es: 47,5%
V o F
5) Un matrimonio desea tener 3 hijos. La probabilidad de obtener dos varones y dos hembras es: 50%
V o F
Answer:
1) V
2) V
3) V
4) V
5) V
Step-by-step explanation:
PLEASE HELP!!!!!! A linear function has a y-intercept of -12 and a slope of 3/2. What is the equation of the line?
A. Y= 3/2x - 12
B. Y= 3/2x + 12
C. Y= 2/3x - 12
D. Y= -12x - 3/2
Answer:
A, y = 3x/2 - 12
Step-by-step explanation:
Use the equation y = mx + b.
m = 3/2
b = -12
y = 3x/2 - 12
Answer:
Here is your Answer
Step-by-step explanation:
Its A
A. Y = 3/2x - 12
What is 5 7/8 - 1 1/8
Answer to this equation:
4 3/4
Answer:
4.75
Step-by-step explanation:
This is what I got. have a nice day:)
Anita can exercise for 20 minutes on her lunch break and 30 minutes after work on her 5 work days. She exercises 35 minutes on the weekend. How many hours per week does Anita exercise? 4 hours per week 4 hours per week 4 hours per week 5 hours per week
Answer:
4 3/4 hours per week
Step-by-step explanation: