U
w
R
Which angles
are adjacent?
T
S
A. RWS and UWT
B. UWT and SWR
C. UWT and TWU
D. RWS and SWT
Answers
Answer:
D. RWS and SWT
Step-by-step explanation:
Adjacent angles have a common side and a common vertex but they don't overlaps each other
The two angles that has these requirements are :
RWS and SWT
The two angles are said to be adjacent angles when they share the common vertex and side.
So , adjacent angles are :
RWS and SWTOption D is the correct answer.
Related Questions
Each of 8 students reported the number of movies they saw in the past year. This is what they reported:
11, 17, 14, 11, 4, 7, 11, 11
Find the mean and median number of movies that the students saw.
If necessary, round your answers to the nearest tenth.
Answers
Answer:
10.75
11
Step-by-step explanation:
the mean is the average, so add up all of the values and divide by 8 because there are 8 values :
(11 + 17 + 14 + 11 + 4 + 7 + 11 + 11)/8 = 10.75
the median is the middle value when the numbers are written in ascending or descending order :
4, 7, 11, 11, 11, 11, 14, 17
we can cross out the values on the ends, to get to the middle. if we do this, we are left with 11, 11
find the average of these numbers :
which is 11.
the median is 11
the mode is 11
Need help please need it quick
Answers
Answer:
Choice A
Step-by-step explanation:
An arithmetic sequence is one which has an incremental change.
for our answer, our change is +5
what is x in 8 ^ (x - 1 ) = 16 ?
Please help.
Answers
Answer:
x=7/3
Step-by-step explanation:
8 ^ (x - 1 ) = 16
We need to rewrite 8 as 2^3 and 16 as 2^4
2^3 ^ (x - 1 ) = 2^4
We know that a^b^c = a^(b*c)
2^(3(x-1)) = 2^4
The bases are the same so the exponents are the same
3(x-1) = 4
Distribute
3x-3 = 4
Add 3 to each side
3x-3+3 = 4+3
3x = 7
Divide by 3
3x/3 = 7/3
x=7/3
Select the true statement about triangle ABC.
A. cos A = cos C
B. cos A = sin C
C. cos A = sin B
D. cos A = tan C
Answers
Answer:
B
Step-by-step explanation:
cosA = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{12}{13}[/tex]
cosC = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{5}{13}[/tex]
sinC = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{12}{13}[/tex]
tanC = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{AB}{BC}[/tex] = [tex]\frac{12}{5}[/tex]
Then
cosA = sinC → B
The graph of the function g(x) is given for #1 - 5.
1. Which of the following is the given function's
average rate of change on the interval PLS HELP. ASAP
Answers
Answer:
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The width of a rectangle is twice as long as the length. if the length is increased by 50% and the width is decreased by 20%, the perimeter becomes 248. find the width and length of the original rectangle.
Answers
Answer:
Step-by-step explanation:
The percents here make this more tricky than it originally seems to be. We'll make a table and see where it takes us:
original new
length
width
And we'll fill it in according to our rules given. Starting with the original, we are told that the width is twice as long as the length. We don't know the length, so we'll call that L, and if the width is twice that, the width is 2L:
original new
length L
width 2L
Now here's the tricky part. What I'm going to do is fill in the "new" column with the expressions and then we'll simplify them in the next step.
The length is increased by 50%. So we have 100% of the original length and we are adding another 50% to that:
original new
length L 100%L + 50%L
width 2L
The width is decreased by 20%, so we have 100% of 2L and we are subtracting 20% of 2L from that:
original new
length L 100%L + 50%L
width 2L 100%(2L) - 20%(2L)
And now we'll simplify that "new" column:
original new
length L 150%L = 1.5L
width 2L 80%(2L) = 160%L = 1.6L
Now we're ready for the perimeter part. The formula for the perimeter of a rectangle is P = 2L + 2w, so filling in from our "new" column, since 248 is the perimeter given for AFTER the rectangle's length and width are manipulated:
248 = 2(1.5L) + 2(1.6L) and
248 = 3L + 3.2L and
248 = 6.2L so
L = 40 and that means that w = 80 (because in the "original" column, the width is twice the length)
Find the expected value of the winnings
from a game that has the following
payout probability distribution:
Payout ($) 0 5
8
10
15
Probability 0.5 0.2 0.15 0.1 0.05
Expected Value = [?]
Answers
Multiply each payout by the corresponding probability and take the total:
E[X] = 0×0.5 + 5×0.2 + 8×0.15 + 10×0.1 + 15×0.05 = 3.95
The expected value = 3.92
What is expected value ?"It describes the average of a discrete set of variables based on their associated probabilities."
Formula of expected value:[tex]E(x)=\Sigma[ xP(x)][/tex]
Multiply each value of the random variable by its probability and add the products.
For given question,
We have been given a payout probability distribution.
We need to find the expected value of the winnings.
First we multiply each value of the random variable by its probability .
0 × 0.5 = 0
5 × 0.2 = 1
8 × 0.15 = 1.2
10 × 0.1 = 1
15 × 0.05 = 0.75
Now, we find the sum of above products.
0 + 1 + 1.2 + 1 + 0.75 = 3.95
By using the formula of expected value,
[tex]\Rightarrow E(x)=\Sigma[ xP(x)]\\\\\Rightarrow E(x)=3.92[/tex]
Therefore, the expected value = 3.92
Learn more about the expected value here:
https://brainly.com/question/18523098
#SPJ3
Use the expression, X^2-7
What is the value of the expression above when n=5
Answers
Answer:
18
Step-by-step explanation:
X^2 - 7 =
Since we need to evaluate the expression when X = 5, we replace X with 5.
= 5^2 - 7
Now, according to the correct order of operations, we need to do the exponent first. 5^2 = 5 * 5 = 25
= 25 - 7
Finally, we subtract.
= 18
Answer: 18
Help me to prove it
Answers
Answer:
see explanation
Step-by-step explanation:
Using the identities
cotA = [tex]\frac{1}{tanA}[/tex]
cot²A = cosec²A - 1
tan²A = sec²A - 1
Consider the left side
(cotA + tanA)² ← expand using FOIL
= cot²A + 2cotAtanA + tan²A
= cosec²A - 1 + 2 .[tex]\frac{1}{tanA}[/tex] . tanA + sec²A - 1
= cosec²A - 1 + 2 + sec²A - 1
= sec²A + cosec²A - 2 + 2
= sec²A + cosec²A
= right side, thus proven
HELP PLEASE!
Given that sin A=3/7, cos B=-2/5, and both AA and B are in quadrant II, find cos (A-B). Simplify to a single value and leave it in the form of a rational number.
Answers
First, recall that
cos(A - B) = cos(A) cos(B) + sin(A) sin(B)
so you just need to find cos(A) and sin(B).
Since both A and B end in the second quadrant, you know that
• cos(A) and cos(B) are both negative
• sin(A) and sin(B) are both positive
Then from the Pythagorean identity, you get
cos²(A) + sin²(A) = 1 ==> cos(A) = -√(1 - sin²(A)) = -2√10/7
cos²(B) + sin²(B) = 1 ==> sin(B) = +√(1 - cos²(B)) = √21/5
You'll end up with
cos(A - B) = (-2√10/7) (-2/5) + (3/7) (√21/5)
… = (4√10 + 3√21)/35
(which makes the last sentence in the question kind of confusing, because this expression doesn't get much simpler and it's certainly not a rational number)
The value of cos(A - B) is approximately 23/25
Given that A and B are in the second quadrant, we have
sin A = 3/7cos B = -2/5To find cos(A - B), we have to use trigonometric functions
cos(A - B) = cosAcosB + sinAsinB ...equation(i)
but
cos A[tex]cos^2A + sin^2A =1 \\cos^2A = 1 - sin^2A\\cos^2A = 1 - (\frac{3}{7})^2 = 1 - \frac{9}{49}= cosA= -\frac{2\sqrt{5} }{7}[/tex]
Having the value of cos A, let's solve for cosB
Cos Bcos B = -2/5
[tex]sin^2B = 1-cos^2B\\sin^2B = 1-(-\frac{2}{5})^2= 1-\frac{4}{25}\\sinB = \sqrt{\frac{21}{25} }=\frac{\sqrt{21} }{5}[/tex]
cos(A-B)substituting the values if sinA, cosA, sinB, cosB into equation(i) above;
[tex]cos(A-B)=cosAcosB+sinAsinB\\cos(A-B)=(-\frac{2\sqrt{5} }{7})(-\frac{2}{5})+(\frac{3}{7})(\frac{\sqrt{21} }{5})\\cos(A-B)=\frac{3\sqrt{21}+4\sqrt{5} }{35} \\cos(A-B) = 23/35[/tex]
The value of cos(A-B) is given above
Learn more on trigonometric functions here;
https://brainly.com/question/4326804
William wishes to view a frequency table for grouped data using his monthly credit card statements for the last 20 months, shown below. Construct the table for William using six classes. 1312, 1303, 809, 1477, 1263, 1444, 894, 1051, 1485, 1433, 1132, 1221, 1179, 945, 995, 1179, 1172, 1373, 906, 955 Provide your answer below: Lower Class Limit Upper Class Limit Frequency 809 1486
Answers
Frequency is the number of incidences of an occasion or value. A frequency table that displays the number of incidences of the goods and the number of times, and the further discussion can be defined as follows:
Lower class than adults who have little over two-thirds of a nationwide median's average household income.The higher class would include families with substantial wealth and biz incomes or where the primary breadwinner is utilized as a manager or a professional worker.Calculation:
[tex]lower\ \ \ \ \ \ \ \ \ upper \ \ \ \ \ \ \ \ \ frequency\\\\809\ \ \ \ \ \ \ \ \ 921 \ \ \ \ \ \ \ \ \ 3\\\\922 \ \ \ \ \ \ \ \ \ 1034 \ \ \ \ \ \ \ \ \ 3\\\\1035 \ \ \ \ \ \ \ \ \ 1147\ \ \ \ \ \ \ \ \ 2\\\\1148 \ \ \ \ \ \ \ \ \ 1260\ \ \ \ \ \ \ \ \ 4\\\\1261 \ \ \ \ \ \ \ \ \ 1373 \ \ \ \ \ \ \ \ \ 4\\\\1374 \ \ \ \ \ \ \ \ \ 1486\ \ \ \ \ \ \ \ \ 4[/tex]
Learn more:
brainly.com/question/18359774
A wind turbine has blades 50m in diameter and an overall height (to the highest point) of 125m. If it has four blades instead of three, create four equations modelling the height of a point on the tip for each of the four blades.
Answers
Answer:
Blade A : H(θ) = 75 + 50 sin θ
Blade B : H(θ) = 75 + 50 sin(θ + 90° )
Blade C : H(θ) = 75 + 50 sin( θ + 180° )
Blade D : H(θ) = 75 + 50 sin( θ + 270° )
Step-by-step explanation:
Given data :
Diameter of blade = 50 m
overall height = 125 m
The four blades : Blade A , Blade B, Blade C, Blade D all moves in same direction hence they make 90° to each other.
Lets assume The blades are standing at θ with the horizontal
The four equation modelling the heights :
Blade A : H(θ) = 75 + 50 sin θ
Blade B : H(θ) = 75 + 50 sin(θ + 90° )
Blade C : H(θ) = 75 + 50 sin( θ + 180° )
Blade D : H(θ) = 75 + 50 sin( θ + 270° )
What is the area of this triangle
Answers
Answer:
14
Step-by-step explanation:
7*4*1/2=14
Find the missing segment in the image below
Answers
Answer:
8? not sure tho....
Step-by-step explanation:
Which graphs are the graphs of even functions?
Answers
How do you write 50% as a fraction?
Answers
Answer:
[tex]\frac{1}{2}[/tex]
Step-by-step explanation:
Answer:
50% as a fraction would be 1/2
write 5 lcms of 100 and 120
Answers
Answer:
The LCM of 100 and 120 is 600.
The LCM of 5 and 120 is 120.
LCM of 5 and 100 is 100.
Step-by-step explanation:
I think this is the answer . If it is not sorry .
ASAP HELP!! PLEASEEEE!!
Answers
Answer:
Step-by-step explanation:
5.1, please this is just a guess from using my head to calculate
3. A rectangle has a length of 2x – 9 and a width of x2 + 3x – 4. What is the polynomial that models the area
of the rectangle?
Answers
Answer:
(C) 2x^3 - 3x^2 - 35x + 36
Step-by-step explanation:
First multiply 2x by x^2 + 3x - 4:
(2x)(x^2 + 3x - 4)
2x^3 + 6x^2 - 8x
Next multiply -9 by x^2 + 3x - 4:
(-9)(x^2 + 3x - 4)
-9x^2 - 27x +36
Now add the two polynomials by adding like terms:
(2x^3 + 6x^2 - 8x) + (-9x^2 - 27x +36)
2x^3 + 6x^2 - 9x^2 - 8x - 27x + 36
2x^3 - 3x^2 - 35x + 36
Hope this helps (●'◡'●)
What is 1/4 0.75 1/3 0.5 greatest to least
Answers
Answer:
1/4 = 1 ÷ 4 = 0.251/3 = 1 ÷ 3 ≈ 0.330.750.50.75 → 0.5 → 1/3(0.33) → 1/4(0.25)
HELP!!!!!
If anyone knows the answer please tell me as soon as possible PLEASE!!!!
Answers
Answer:
Plotting the points on graph and joining them gives a right angle triangle
Answer:
right angle triangle
Step-by-step explanation:
Slope = (Y1-Y2)/(X1-X2)
The slope of AC is 1/3. The slope of BC is -3. Therefore AC is perpendicular to BC (right angle).
Help please…..?!!!!!☺️
Answers
Answer:
Step-by-step explanation:
Sample space of die 1 = {1,2,2,3,3,4}
Sample space of die 2 = {1,3,4,5,6,8}.
The highest value that we get by rolling die 1 is 4 and die 2 is 8, which give the sum 12. So, we cannot have any other combinations other than this , as the highest value itself gives 12.
Rolling a sum of 12 with the dice = {(4,8) }
Probability = 1/36
if a=(p+q),b=(p-q)and c=qsquare -psquare, show that ab+c=0
Answers
Answer:
I think this is the ans
Step-by-step explanation:
ab+c=0
(p+q)(p-q)=0
p Square-q Square =0
0=p Square-q Square
Which expression is equivalent to 4-2 _ 2-3
Answers
Answer:
16
Step-by-step explanation:
First you calculate the value
(2)÷2^-2
Then you simplify
2^4
=16
Options:
Rotation
Reflection
Translation
Answers
Answer: Reflection
Step-by-step explanation: Please mark brainliest
PLEASE HELP QUICK 30 POINTS !!!!!!
Ryan wants to make a triangular deck. He wants each side to be a different length.
Select three lengths he could use to make a triangle:
Side 1:
Side 2:
Side 3:
:: 3 feet
:: 10 feet
.: 20 feet
:: 25 feet
:: 60 feet
Answers
Answer:
10 ft, 20ft and 25 ft.
Step-by-step explanation:
10 ft, 20ft and 25 ft.
This will make a triangle as 25 < (10 + 20).
Answer:
Solution given:
one side of a triangle must be less than the sum of two other side .
by making these sense:
3<10+20
10<20+3
20<10+3not true
these three side are not possible.
again
10<20+25
20<25+10
25<20+10
these three side are true so
required side are:
Side 1:10
Side 2:25
Side 3:20
Use special right triangle ratios to find the lengths of the other leg and the hypotenuse
Answers
Answer:
leg = 18
hypotenuse = 18 sqrt(2)
Step-by-step explanation:
We know that sin theta = opp side / hypotenuse
sin 45 = 18 / hyp
hyp sin 45 = 18
hyp = 18 / sin 45
hyp = 18 sqrt(2)
Since this is an isosceles triangle ( the two angles are the same measure), the two legs have to be the same length
leg = 18
the lengths of the other leg and the hypotenuse
is 18 units and 18[tex]\sqrt{2}[/tex]units respectively.
Answer:
Solution given:
Let <C=<B=45°
AB=18 units
BC=?
AC=?
again
By using
By usingspecial right triangle ratios
sin C=opposite/hypotenuse=AB/AC=18/AC
Sin 45=18/AC
AC=18/sin45
AC=hypotenuse=18[tex]\sqrt{2}[/tex]units
again
Tan A=opposite/adjacent=BC/AB=BC/18
Tan45=BC/18
BC=Tan45*18
BC=length of another leg=18 units.
The volumes of two similar solids are 512cm3 and 2197cm3. If the smaller solid has a surface are of 960cm2, find the surface area of the larger solid. Part 1: find the similarity ratio by taking the cube root of each volume. Show your work. Part 2: use your answer from part 1 to find the ratio of the surface areas. Show your work. Part 3: set up a proportion and solve to find the surface area of the larger solid.
Answers
Answer:
see below
Step-by-step explanation:
Part 1:
(512) ^ 1/3
-------------------
(2197) ^ 1/3
8
-----
13
The scale factor is 8:13
Part 2
The ratios of the areas is related by scale factor squared
8^2
-----
13^2
64
------
169
Part 3
64 960
------ = ----------------
169 SA larger
Using cross products
64 * SA = 169 * 960
64 SA = 162240
Divide each side by 64
64 SA/ 64 = 162240 / 64
SA = 2535
2535 cm^2
5/21 as a decimal rounded to 3 decimal places
Answers
[tex] \sf \: \frac{5}{21 } \: rounded \: to \: 3 \: decimal \: places \: is \: \boxed{ \underline{ \bf0.238}}. \\ \longrightarrow \sf \: Just \: divide \: 5 \: by \: 21 \: upto \: 3 \: decimal \: places \\ \sf \: to \: get \: the \: answer.[/tex]
HELP ME WITH THIS PLEASE PLEASE SHOW ME THE FORMULA FOR LETTER C
Answers
Answer:
Which subject is this . please tell
Answer:
see explanation
Step-by-step explanation:
1
(a)
Calculate slope m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ = (8, 3) and (x₂, y₂ ) = (10, 7)
m = [tex]\frac{7-3}{10-8}[/tex] = [tex]\frac{4}{2}[/tex] = 2
(b)
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{2}[/tex]
(c)
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - [tex]\frac{1}{2}[/tex] , then
y = - [tex]\frac{1}{2}[/tex] x + c ← is the partial equation
To find c substitute (8, 3) into the partial equation
3 = - 4 + c ⇒ c = 3 + 4 = 7
y = - [tex]\frac{1}{2}[/tex] x + 7 ← equation of perpendicular line
--------------------------------------------------------------------------
2
(a)
with (x₁, y₁ ) = (3, 5) and (x₂, y₂ ) = (4, 4)
m = [tex]\frac{4-5}{4-3}[/tex] = [tex]\frac{-1}{1}[/tex] = - 1
(b)
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{-1}[/tex] = 1
(c)
y = x + c ← is the partial equation
To find c substitute (3, 5) into the partial equation
5 = 3 + c ⇒ c = 5 - 3 = 2
y = x + 2 ← equation of perpendicular line
